Answer:
x > 3
Step-by-step explanation:
distribute the 7 so parentheses are removed:
21 + 42x > 147
subtract 21 from each side:
42x > 126
x > 126/42
x > 3
A linear function has an x-intercept of 8 and a y-intercept of 4 . which of these is an equation of the linear function?
The linear function is y = (-1/2)x + 4.
What is a linear function?
A linear function whose graph is a straight line and which is represented by an equation of the form y = ax + b where a and b are constants, a does not equal zero, and x is any real number.
Here, we have
Given,
A linear function has an x-intercept of 8 and a y-intercept of 4.
So, The two points on the line are (8, 0) and (0, 4).
Now, slope(m) = (4 - 0)/(0 - 8).
slope(m) = -4/8.
slope(m) = -1/2.
As it has a y-intercept of 4 it is the value of b, In y = mx + b.
Hence, the linear function is y = (-1/2)x + 4.
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find the area enclosed by the curve x = t2 − 3t, y = t and the y-axis.
The area under the curve is \(\frac{6 \sqrt{3}}{5}\).
Consider the following parametric equations:\($$x=t^2-3 t \text { and } y=\sqrt{t} \text { and the } y \text {-axis. }$$\)
The objective is to find area enclosed by the curve using the formula.
The area under the curve is given by parametric equations x=f(t), y=g(t), and is traversed once as t increases from α to β, then the formula for calculating the area under the curve:
\($$A=\int_\alpha^\beta g(t) f^{\prime}(t) d t$$\)
The curve has intersects with y-axis. so x=0
\($$\begin{aligned}t^2-3 t & =0 \\t(t-3) & =0 \\t & =0 \text { or } t=3\end{aligned}$$\)
Now we have to draw the graph,
Let f(t)=\(t^2-3 t, g(t)=\sqrt{t}$\)
Differentiate the curve f(t) with respect to t.
\(f^{\prime}(t)=2 t-3\)
Now, find the area under the curve use the above formula.
\(\begin{aligned}A & =\int_0^3(\sqrt{t})(2 t-3) d t \\& =\int_0^3(2 t \sqrt{t}-3 \sqrt{t}) d t \\& =\int_0^3\left(2 t^{\frac{3}{2}}-3 t^{\frac{1}{2}}\right) d t \\& =\left[2 \frac{t^{\frac{5}{2}}}{\frac{5}{2}}-3 \frac{t^{\frac{3}{2}}}{\frac{3}{2}}\right]_0^3 \\& \left.\left.=\left[\frac{4 t^{\frac{5}{2}}}{5}-2 t^{\frac{3}{2}}\right]_0^3\right]^{\frac{5}{2}}\right] \\\\\end{aligned}$$\)
\(& =\left[\frac{4(3)^{\frac{5}{2}}}{5}-2(3)^{\frac{3}{2}}\right]-\left[\frac{4(0)^{\frac{5}{2}}}{5}-2(0)^{\frac{3}{2}}\right]\)
\($\begin{aligned}& =\left[\frac{4(3)^{\frac{5}{2}}}{5}-2(3)^{\frac{3}{2}}\right]-\left[\frac{4(0)^{\frac{5}{2}}}{5}-2(0)^{\frac{3}{2}}\right] \\& =\frac{4(3)^{\frac{5}{2}}}{5}-2(3)^{\frac{3}{2}}-0 \\& =\frac{6 \sqrt{3}}{5}\end{aligned}\)
Therefore, the area of the curve is \(\frac{6 \sqrt{3}}{5}\).
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The shape is composed of three squares and two semicircles. Select all the expressions that correctly calculate the perimeter of the shape.
The expression that correctly calculates the perimeter of the shape is given as follows:
P = 2(6s + πr).
In which:
s is the side length of the square.r is the radius of the semicircle.How to obtain the perimeter of the square?The perimeter of a square of side length s is given as follows:
P = 4s.
Hence, for three squares, the perimeter is given as follows:
P = 3 x 4s
P = 12s.
How to obtain the perimeter of a semi-circle?The perimeter, which is the circumference of a semicircle of radius r, is given by the equation presented as follows:
C = πr.
Hence the perimeter of two semicircles is given as follows:
C = 2πr.
How to obtain the perimeter of the shape?The perimeter of the entire shape is given by the sum of the perimeter of each shape, hence:
P = 12s + 2πr.
P = 2(6s + πr).
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PLEASE ANSWER QUICK I WILL MARK YOU BRAINLIST
f(-x)=|x|+6
Answer:
x+6
Step-by-step explanation:
to find f(-x) plug in -x for all the values of x in the equation
since the absolute value of -x is x you get x+6
a. Write an equation for the line in slope-intercept form.
Given the points (-1, 2) and (3,-4)
3x+2y+1=0
hopefully this helps
Answer: y = -(2/3)x + 0.5
Step-by-step explanation:
The form of a straight line in slope-intercept form is y=mx+b. m is the slope an b is the y intercept.
We can calculate m, the slope, from the two points given. From that we can calculate b by using one of the two points in the equation.
Slope (m) is the change in y divided by the change in x. For these two points we can find the x change (3 -(-1)) = 4 (the distance between -1 and 3). The change in y is (-4-2) = -6. The slope is therefore (-6/4), or -3/2.
y = (-3/2)x + b
No enter either point for x and y and calculate b.
2 = -(3/2)*(-1) + b
2 = +(3/2) + b
b = 0.5
y = -(2/3)x + 0.5
Find the value of x. Assume that segments that appear to be tangent are tangent. * Round to the nearest tenth (one decimal place)* 17 X 15 x=00-0 X
Answer:
\(x = \sqrt{ {17}^{2} - {15}^{2} } = \sqrt{289 - 225} = \sqrt{64} = 8\)
So x = 8 = 8.0
A sample of n=12 scores has a mean of M=8. What is the ΣX value for this sample?
A sample of n=15 scores has a mean of 10 and another sample of n=10 scores has a mean of 8 . If the two samples are combined, what is the mean for the combined samples?
A researcher has a sample of scores. To correct an earlier mistake the researcher adds 6 points to each score in the sample and finds the mean to be M=14.
a. What was the value for the mean before 3 points were added to each score?
b. The researcher then realizes that she instead needs to multiply each score by 4. Using the original scores, she multiplies each by 4 and finds the mean to be M=32. What was the value of the mean prior to multiplying each score by 4 points?
A sample of n=11 scores has a mean of M=22. If one score with a value of X=18 is removed from the sample, what is the value of the new sample mean?
A population of N=10 scores has a mean of μ=24. After one new score is added, the new population has a mean of μ=34. What is the value of the score that was added?
The answer is 1. The ΣX for a sample of n=12 scores with M=8 is 96, 2. The mean for combined samples of n=15 (mean=10) and n=10 (mean=8) is 9.33, 3a. The original mean before adding 6 points is 8, 3b. The original mean before multiplying scores by 4 is 8, 4. The new sample means after removing X=18 is 22.5, and 5. The score added to a population with μ=24 to achieve μ=34 is 34.
1. For any sample, we can find the sum of the scores (ΣX) by multiplying the mean by the number of scores. So in this case:ΣX = M * nΣX = 8 * 12ΣX = 96Therefore, the ΣX value for this sample is 96.
2. To find the mean of the combined samples, we can use the formula: Mean of combined samples = (n1 * mean1 + n2 * mean2) / (n1 + n2) = Mean of combined samples = (15 * 10 + 10 * 8) / (15 + 10) = Mean of combined samples = 9.33. Therefore, the mean for the combined samples is 9.33.
3. a: We can use the formula for shifting the mean to find the original mean: M1 = M2 - kM1 = 14 - 6M1 = 8. Therefore, the value for the mean before 3 points were added to each score is 8. b. The researcher then realizes that she instead needs to multiply each score by 4. Using the original scores, she multiplies each by 4 and finds the mean to be M=32. We can again use the formula for shifting the mean to find the original mean: M1 = M2 / kM1 = 32 / 4M1 = 8. Therefore, the value of the mean prior to multiplying each score by 4 points is 8.
4. To find the new sample mean, we need to remove the score and adjust the mean accordingly. We can use the formula: New mean = (ΣX - X) / (n - 1)New mean = (ΣX - 18) / 10. Given that the original mean is 22, we can solve for ΣX:22 = ΣX / 1122 * 11 = ΣX243 = ΣX. Now we can plug in to find the new mean: New mean = (243 - 18) / 10 = New mean = 22.5. Therefore, the value of the new sample mean is 22.5.
5. We can use the formula for adding a score to a population to find the value of the added score: N μ = ΣX / NN * μ = ΣX / N + 1. Given that N = 10 and μ = 24 for the original population, we can solve for ΣX:10 * 24 = ΣX240 = ΣX. Now we can use the new mean and the formula to solve for the added score:11 * 34 = 240 + X / 11274 = 240 + XX = 34. Therefore, the value of the score that was added is 34.
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The answer provides solutions to the various statistical maths problems that involve calculations of mean and sum of scores. These problems explore the understanding of the concept of mean, summation and basic operations.
Explanation:To answer these questions, you'll need to understand basic concepts of statistics, specifically the calculation of means, and summation of scores (ΣX). So, let's break them down one by one:
For a sample of n=12 scores with a mean of M=8, the ΣX or sum value of scores would be the product of the number of elements and the mean, which is n*M = 12*8 = 96. When combining two sample sizes, to find the mean, you would calculate the sum of the scores of each sample, then divide by the total number of elements in both samples. Therefore, ΣX = n*M = (15*10) + (10*8) = 230. The total sample size, n, is 15+10=25. The mean for the combined samples would be 230/25 = 9.2. a. If the researcher adds 6 points to each score in the sample and finds the mean to be M=14 or M’, then value for the mean before 3 points were added to each score would be M’-6 = 14-6 = 8. b. If then each score is multiplied by 4 and the mean becomes M=32 or M’, then the mean before this multiplication would be M’/4 = 32/4 = 8. For a sample of n=11 scores with a mean of M=22, if one score with a value of X=18 is removed, the new sample size would be n-1 = 11-1 = 10. The new sum of scores would be ΣX - X = n*M - X = 11*22 - 18 = 222. Therefore, the mean of the new sample would be new ΣX / new n = 222/10 = 22.2. If a population of N=10 scores has a mean of μ=24, and one new score changes the mean to μ=34, then the total of the scores for the new population would be μ*n = 34*11 = 374. The total for the old population would be μ*n = 24*10 = 240. The value of the new score added would then be new total - old total = 374 - 240 = 134.Learn more about Statistics here:
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Helpppppppppp :) please y’all question 3 and 4
Answer:
3) = C (0.505)
4) = B (4.32 kilograms)
Step-by-step explanation:
0.505 is in-between 0.482 and 0.51
1.08 X 4 = 4.32
Answer:
3. C. 0.505 gram
4. B. 4.32 kilograms
Lisa is a waitress at the diner in town. She earns a daily wage of $60, plus tips that are equal to 20% of the total cost of the dinners she serves. What was the total cost of the dinners she served if she earned $275 on Friday?
$1075 is the total cost of the dinners she served if she earned $275 on Friday
What is Percentage?percentage, a relative value indicating hundredth parts of any quantity.
Given that Lisa earns a daily wage of $60,
Tips that are equal to 20% of the total cost of the dinners she serves
We can write this as 60+20/100x.
The total cost of the dinners she served if she earned $275 on Friday
is given by
275=60+0.2x
Subtract 60 on both sides
275-60=0.2x
215=0.2x
Divide both sides by 0.2
215/0.2=x
1075=x
Hence, $1075 is the total cost of the dinners she served if she earned $275 on Friday
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Jake is traveling 12 mph in his boat. After 3 hours. How far will he have traveled?.
Jake will have traveled 36 miles in his boat after 3 hours at a speed of 12 mph.
What is Distance?
Distance is defined as the space between two points in space.
To find out how far Jake will have traveled after 3 hours, we can use the formula:
distance = speed x time
where speed is the rate at which Jake is traveling and time is the duration of the travel. In this case, the speed is 12 mph and the time is 3 hours.
So, the distance traveled after 3 hours is:
distance = 12 mph x 3 hours = 36 miles
Therefore, Jake will have traveled 36 miles in his boat after 3 hours at a speed of 12 mph.
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Please help me thank you
Write an equation to determine the measures of both angles
Determine the measure of ∠1 Label your answer
Determine the measure of ∠2 Label your answer
Answer:
Angles of:
1 = 87 degree, 2= 62 degree
Step-by-step explanation:
Here, we have a Vertically opposite angle so equate both the equations and get the value of x. then substitute the value of x in both equations.
hope it helps!
3/4 - 1/8 how much is it? help me please
Answer:5/8
Step-by-step explanation:
\(\begin{gathered} \boxed{ \sf \frac{3}{4} - \frac{1}{8}} = \\ \\ \sf \frac{8 \div 4 \times 3 - 8 \div 8 \times 1}{8} = \\ \\ \sf\frac{6 - 1}{8} = \\ \\ \sf \boxed{ \sf\frac{5}{8}} \end{gathered}\)
Therefore, the result of this subtraction of fractions is five eighths.
How to subtract unlike fractions:
Heterogeneous fractions are fractions that have different denominators.
To subtract heterogeneous fractions we follow these steps:
We find the common denominator, which is the least common multiple of the denominators. We divide the common denominator by the other denominator and multiply by the numerator.We will write the above results as numerators with the subtraction sign between them.We subtract the numerators.We simplify the result if possible.The Alpha.the weights of newborn baby boys born at a local hospital are believed to have a normal distribution with a mean weight of 3245 grams and a standard deviation of 625 grams. if a newborn baby boy born at the local hospital is randomly selected, find the probability that the weight will be greater than 2620 grams. round your answer to four decimal places.
The probability that the weight of a randomly selected newborn baby boy born at the local hospital will be greater than 2620 grams is 0.9099 (rounded to four decimal places).
The probability can be calculated using the standard normal distribution as follows:
P(Z > (2620 - 3245) / 625) = P(Z > -1.335)
Using a standard normal distribution table, we find that the probability of Z being greater than -1.335 is 0.9099.
We use the standard normal distribution because we know the mean and standard deviation of the population of newborn baby boys' weights. We convert the raw score of 2620 grams to a z-score, which tells us how many standard deviations the raw score is away from the mean.
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PLEASE HELP 25 MINUTES LEFT
38
Marlene wrote an arithmetic sequence where al
=
8 and the common difference is -3.
What is a rule for the nth term of this sequence?
Answer:
D
Step-by-step explanation:
The nth term of an arithmetic sequence is
\(a_{n}\) = a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 8 and d = - 3 , then
\(a_{n}\) = 8 - 3(n - 1) = 8 - 3n + 3 = - 3n + 11 → D
Using the distributive property, which of the following is the expanded form of −14(−8x+12y)
?
Using the distributive property, the expanded form of (−1/4)(−8x+12y) is c) 2x - 3y.
The distributive property states that when you multiply a number or a variable expression by a sum or a difference, you can distribute the multiplication over each term within the parentheses.
So, to expand the expression (−1/4)(−8x+12y), we can apply the distributive property by multiplying -1/4 to each term inside the parentheses:
(−1/4)(−8x+12y) = (−1/4) × (−8x) + (−1/4) × (12y)
= (1/4) × 8x − (1/3) × 12y
= 2x − 3y
Therefore, the expanded form of (−1/4)(−8x+12y) is 2x − 3y. Hence, the correct answer is (c) 2x-3y.
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which is true about the product of 3/8 and7/2?
The product is greater than 3/8 and less than 7/2
The product is greater than 7/2
The product is less than 3/8
8
The product is greater than 1/8 and less than 1/2
Answer:
The answer is "The product is greater than 3/8 and less than 7/2"
Step-by-step explanation:
This is because the product of 3/8 and 7/2 is 21/16.
When you simplify 21/16, you get 1 and 5/16 which is greater than 3/8 but less than 7/2, which simplified is 3 and 1/2.
Answer:
The product is greater than 3/8 and less than 7/2
Step-by-step explanation:
The number is greater than 3/8
It is greater than 1/8 but not less than 1/2
This number is less than 7/2
A kennel has 90 dogs in total, some are puppies and some are adult dogs. The ratio
of puppies to adult dogs in a kennel is 3:2. How many adult dogs are there?
Answer:
36
Step-by-step explanation:
90÷5=18
18×2=36
We multiply two because the ration for adults is 2
I will give you branilest!
Answer:
ran throught a cal is
Step-by-step explanation:
Slope (m) =
ΔY /ΔX =1/3 =0.33333333333333
Which equation matches this table?
X 1 2 3 7 8
Y 6 12 18 42 48
A. y = x ÷ 6
B. y, = , x, - 6
C. y = 6x
D. y, = , x, + 6
Answer:
y=6x
Step-by-step explanation:
if u times x by 6 you get the y number underneath
for example:
x=1
y=6
so 1×6=6
x=2
y=12
so 2×6=12
For x = 0
x+5 3
3x 2x
+
can be written in the form
Work out the values of a, b and c.
ax + b
CX
X +
X
where a, b and care integers,
all less than 20.
I need this answered
What property of operations will be used to simplify the product of a binomial and trinomial? *
Answer:
Distributive property.
Step-by-step explanation:
A distributive property is a rule that states that, multiplying two factors such as a binomial and trinomial would give the same result as multiplying the sum of two addends by the other factor.
Hence, the distributive property is used to simplify the product of a binomial and trinomial.
For example, let's find the product of (2x + 4)(5x² + 3x + 10)
First of all, we would distribute trinomial into each of the term in the binomial.
2x(5x² + 3x + 10) + 4(5x² + 3x + 10)
Distributing the monomial into the trinomial, we have;
2x(5x²) + 2x(3x) + 2(10) + 4(5x²) + 4x(3x) + 4(10)
Expanding the bracket, we have;
10x³ + 6x² + 10 + 20x² + 12x² + 40
Collecting like terms, we have;
10x³ + (6x² + 20x² + 12x²) + 10 + 40
10x³ + 38x² + 50
Therefore, (2x + 4)(5x² + 3x + 10) = 10x³ + 38x² + 50
expressions that are tested by the if statement are called ______
Expressions that are tested by the 'if' statement is called conditions.
A condition is an expression that evaluates to either 'True' or 'False', and it determines whether the code block within the 'if' statement is executed. The 'if' statement allows the program to make decisions and execute different codes based on whether the condition is 'true' or 'false'. For example, in Python, an 'if' statement might look like this:
if x > 10:
print("x is greater than 10")
In this example, the condition being tested is 'x > 10', which will evaluate as 'True' or 'False' depending on the value of x. If the condition is 'True', then the code block within the 'if' statement (in this case, the print statement) will be executed. If the condition is 'False', then the code block within the 'if' statement will be skipped.
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21 = 4x - 9 - x
what is x?
Answer:
x = 10
Step-by-step explanation:
21 = 4x - 9 - x
21 = 3x - 9
30 = 3x
10 = x
Answer:
x = 10
Step-by-step explanation:
Given
21 = 4x - 9 - x, that is
21 = 3x - 9 ( add 9 to both sides )
30 = 3x ( divide both sides by 3 )
10 = x
n= 4/5 (m+7)
help please (solve for m)
Answer: Its not possible.
Step-by-step explanation:There aer two vairables. Whats the value of N
Hey there!
n = 4/5(m + 7)
n = 4/5(1m + 7)
n = 4/5(1m) + 4/5(7)
n = 4/5m + 28/5
n = 4/5m + 5.6
Thus, your answer is probably:
n = 4/5m + 5.6 or n = 4/5m + 28/5
Good luck on your assignment & enjoy your day!
~Amphitrite1040:)
Find the smallest value of p which is a counterexample to the statement below. If p is prime, then p² + p + 1 is also prime.
The smallest value of prime number, p used as counterexample to the statement p² + p + 1 is p = 7
How to find the counterexample of the statementCounterexample refers to instance that will make a statement false hence we look for values that will not hold true with the statement:
p² + p + 1
Where p = 2
2² + 2 + 1 = 7
Where p = 3
3² + 3 + 1 = 13
Where p = 5
5² + 5 + 1 = 31
Where p = 7
7² + 7 + 1 = 57
57 is not a prime number and hence the counterexample
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On thursday, what fraction of the time from 8:00 a.m. to 2:15 p.m. is gerald scheduled to be in class?
Gerald is scheduled to be in class for 45/93 of the time from 8:00 a.m. to 2:15 p.m. on Thursday.
To determine the fraction of time Gerald is scheduled to be in class, calculation of the duration of his class and divide it by the total duration from 8:00 a.m. to 2:15 p.m.
Step 1: Calculate the duration of Gerald's class:
The class starts at 8:30 a.m. and ends at 12:00 p.m. To find the duration, we subtract the start time from the end time:
12:00 p.m. - 8:30 a.m. = 3 hours and 30 minutes.
Step 2: Calculate the total duration from 8:00 a.m. to 2:15 p.m.:
To find the duration, we subtract the start time from the end time:
2:15 p.m. - 8:00 a.m. = 6 hours and 15 minutes.
Step 3: Calculate the fraction of time Gerald is scheduled to be in class:
To find the fraction, we divide the duration of Gerald's class by the total duration:
3 hours and 30 minutes / 6 hours and 15 minutes = 210 minutes / 375 minutes.
To simplify the fraction, divide both the numerator and denominator by their greatest common divisor, which is 15:
210 minutes ÷ 15 / 375 minutes ÷ 15 = 14 / 25.
Therefore, Gerald is scheduled to be in class for 14/25 of the time from 8:00 a.m. to 2:15 p.m. on Thursday.
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r+b=7
3.75r+2.75b=22.25
Answer:
Step-by-step explanation:
hello :
r+b=7... (*)
3.75r+2.75b=22.25.... (**)
use (*) : r = 7 - b
put this value in (**) :
3.75(7 - b)+2.75b = 22.25
26.25 -375b +2.75b = 22.5
-375b +2.75b = 22.5 - 26.25
- b = -3.75
so : b = 3.75
but : r = 7 - b
r = 7 - 3.75
r = 3.25
- Find the finite difference approximation for a Neumann {BC}\left(\frac{d f}{d x}\right) at node n (right {BC} ) to O\left(h^{2}\right).
The finite difference approximation for a Neumann boundary condition, \(\left(\frac{df}{dx}\right)\), at node \(n\) (right boundary) to \(O(h^2)\) is given by
\(\left(\frac{df}{dx}\right)_n \approx \frac{f_{n-2} - 4f_{n-1} + 3f_n}{2h}\),
where \(f_{n-2}\), \(f_{n-1}\), and \(f_n\) represent the function values at nodes \(n-2\), \(n-1\), and \(n\) respectively, and \(h\) represents the spacing between the nodes.
To derive this approximation, we start with the Taylor series expansion of \(f_{n-1}\) and \(f_n\) around \(x_n\):
\(f_{n-1} = f_n - hf'_n + \frac{h^2}{2}f''_n - \frac{h^3}{6}f'''_n + \mathcal{O}(h^4)\),
\(f_{n-2} = f_n - 2hf'_n + 2h^2f''_n - \frac{4h^3}{3}f'''_n + \mathcal{O}(h^4)\).
By subtracting \(4f_{n-1}\) and adding \(3f_n\) from the second equation, we eliminate the first-order derivative term and retain the second-order derivative term. Dividing the result by \(2h\) gives us the desired finite difference approximation to \(O(h^2)\).
In conclusion, the finite difference approximation for a Neumann boundary condition, \(\left(\frac{df}{dx}\right)\), at node \(n\) (right boundary) to \(O(h^2)\) is \(\left(\frac{df}{dx}\right)_n \approx \frac{f_{n-2} - 4f_{n-1} + 3f_n}{2h}\). This approximation is obtained by manipulating the Taylor series expansion of \(f_{n-1}\) and \(f_n\) to eliminate the first-order derivative term and retain the second-order derivative term, resulting in a second-order accurate approximation.
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