7 is a solution to the equation 3n + 9 = 33.
true or false

Answer:

f(4) = -55

Step-by-step explanation:

Given

f(1) = 5

f(n) = -2f(n-1) - 5

If you substitute n with 4 you get:

f(n) = -2f(n-1) - 5

f(4) = -2f(4-1) - 5

     = -2f(3) - 5

This shows that you have to calculate the value of f(3) before we can get the value of f(4). To calculate f(3) we have to know f(2) and to calculate f(2) we have to know f(1), which is given.

Let's start from the bottom.

f(1) = 5

f(2) = -2f(n-1) - 5

     = -2f(2-1) - 5

     = -2f(1) - 5      // substitute f(1) with the value 5 (given)

     = -2(5) - 5

     = -15

f(3) = -2f(n-1) - 5

     = -2f(3-1) - 5

     = -2f(2) - 5      

     = -2(-15) - 5

     = 25

Now we can finally calculate f(4)!

f(4) = -2f(n-1) - 5

     = -2f(4-1) - 5

     = -2f(3) - 5      

     = -2(25) - 5

     = -55

Answer:

1096.6

Step-by-step explanation:

The answer would be 1096.63316, but since you are rounding to the nearest tenth, then your answer would be 1096.6.

Answer:

1096.6.

Step-by-step explanation:

e = about 2.7

2.7^7is about 1046

The conversion of 150 pounds weight in kilograms 68.039.

What is meant by weight?

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Answer:

-8g+16-12t is the answer

Step-by-step explanation:

multiply everything by 4

Some alkenes have geometric cis-trans isomers because of the presence of a double bond between two carbon atoms. In a carbon-carbon double bond, the carbon atoms are connected to two different groups of atoms, which can be oriented differently in space. In the cis configuration, the two substituent groups on each carbon atom are on the same side of the double bond, while in the trans configuration, the two substituent groups on each carbon atom are on opposite sides of the double bond.

The cis-trans isomerism arises due to the restricted rotation around the carbon-carbon double bond. In the case of cis isomers, the substituent groups are too bulky to rotate around the double bond, and they remain on the same side of the double bond. In contrast, in the trans isomers, the substituent groups are oriented on opposite sides of the double bond, which allows them to rotate freely around the bond.

The presence of cis-trans isomers has important consequences for the physical and chemical properties of alkenes, including their reactivity, solubility, and melting points. The two isomers can have different properties and can exhibit different biological activities, making them important targets for drug design and synthesis.

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Answer:

Step-by-step explanation:

(-3, 2) and (2, -3)

(-3 - 2)/(2 + 3) = -5/5 = -1

answer is b

y=47,916.666 dollar after 25 years

librarian salary =25000 dollar in 2000

librarian salary=30500 dollar in 2006

in 6 years increment is 30500 - 25000= 5500dollar

in one year increment is 5500/6= 916.666

m= 916.666 each year

b= 25000

y=mx+b

y=916.666*25+25000      given x=25

y=47,916.666 dollar after 25 years

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Answer:

7z²+3z

Step-by-step explanation:

z(7z+3)

7z²+3z

Answer:

Step-by-step explanation:

\(z(7z+3)\\\)

Expand

\(\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\\\a=z,\:b=7z,\:c=3\\\\=z\times\:7z+z\times\:3\\\\=7zz+3z\\\\7zz=7z^2\\\\=7z^2+3z\)

Answer: Your welcome!

Step-by-step explanation:

Part A: g ≤ 3.772

Part B: The graph of the inequality would be a simple line on a number line, starting from 0 and extending to the right, with a dotted line at x = 3.772.

Part C: In Part A, I solved the inequality to find g. By subtracting 0.6 from both sides of the equation, I was able to isolate g and solve for its value, which is g ≤ 3.772. In Part B, I explained that a graph of this inequality would be a simple line on a number line, starting from 0 and extending to the right, with a dotted line at x = 3.772. This would indicate that all values of g that are less than or equal to 3.772 are valid solutions to the inequality.

Thanks! :) #BO

The numerical coefficient in -7yz²  from the expression 5x⁶+3xy-7yz²+2y/z   is  -7 .

A Numerical Coefficient in an Algebraic Expression is defined as the integer value which is written along with the variable .

For Example : the numerical coefficient in 7xy is 7 , and in -5x is -5 as 7 and 5 are the only numerical value along with the variable y and x respectively.

In the question ;

the given Algebraic Expression is 5x⁶+3xy-7yz²+2y/z  

the numerical coefficient in -7yz² is -7 , as -7 is the only  numerical value in -7yz² .

Therefore , the numerical coefficient in -7yz²  from the expression 5x⁶+3xy-7yz²+2y/z   is  -7 . the correct option is (d) -7 .

The given question is incomplete , the complete question is

In the expression 5x⁶+3xy-7yz²+2y/z  , which of the following choices is the numerical coefficient in -7yz²  ?

(a) 2

(b) 3

(c) 5

(d) -7

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Answer:

After 4 seconds the the ball will hit the ground

that is the correct answer

a) The probability that two automobiles will arrive at the parking lot in a given hour is 0.1404.

b) The number of automobiles coming at the two entries is independent at 0.1247.

Given that there are two entries to a parking lot. Cars arrive at entry I at an average of 3 per hour, and entry II at an average of 4 per hour, according to a Poisson distribution.

a) Assuming that the number of cars coming at each parking lot is independent, we have a total number of vehicles arriving X is Poisson for parameter 3 + 4 = 7 X is Poisson Distribution with mean = 7 the possibility that a total of 2 automobiles will appear at the parking garage in a given hour

= P(X = 2) = 0.1404

b) The probability that less than three automobiles will arrive at the parking lot in a given hour,

= P(X < 2)

= P(0) + P(1)

= 0.1247

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The difference between the largest and smallest number of dimes that could be in the bank is 100.

Let's assume the number of nickels in the piggy bank is N, the number of dimes is D, and the number of quarters is Q.

From the given information, we can form two equations based on the number of coins and the total value:

Equation 1: N + D + Q = 100 (total number of coins)

Equation 2: 0.05N + 0.10D + 0.25Q = 8.35 (total value in dollars)

Now, let's determine the range for the number of dimes, D.

To find the smallest number of dimes, we maximize the number of nickels and quarters, which minimizes the number of dimes. Let's assume all remaining coins (100 - D) are nickels:

Equation 1: D + Q = 100 - N

Equation 2: 0.10D + 0.25Q = 8.35 - 0.05N

Since we want to minimize D, let's consider the maximum values for N and Q. Assuming all remaining coins are nickels, we have N = 100 - D - Q.

Plugging in these values, we get:

0.10D + 0.25Q = 8.35 - 0.05(100 - D - Q)

0.10D + 0.25Q = 8.35 - 5 + 0.05D + 0.05Q

0.05D + 0.20Q = 3.35

To simplify, we multiply the equation by 20:

D + 4Q = 67

The largest value for Q would be when D = 0. Therefore, if we assume all remaining coins are quarters, we have:

D = 0

Q = (100 - D) = 100

So, the largest number of quarters is 100, and the largest number of dimes is 0.

To find the largest value for D, we maximize the number of dimes. Assuming all remaining coins are nickels:

N = 100 - D - Q

Plugging this into Equation 2:

0.10D + 0.25Q = 8.35 - 0.05(100 - D - Q)

0.10D + 0.25Q = 8.35 - 5 + 0.05D + 0.05Q

0.05D + 0.20Q = 3.35

Multiplying by 20:

D + 4Q = 67

The smallest value for Q would be when D = 100. Therefore, if we assume all remaining coins are quarters, we have:

D = 100

Q = (100 - D) = 0

So, the smallest number of quarters is 0, and the smallest number of dimes is 100.

The difference between the largest and smallest number of dimes is:

100 (largest) - 0 (smallest) = 100.

Therefore, the difference between the largest and smallest number of dimes that could be in the bank is 100.

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Step-by-step explanation:

3 units right = x + 3

12 units down = y - 12

E = (-5, 4) -> E' (-2, -8)

F = (-5, 9) -> F' (-2, -3)

G = (1, 9) -> G' (4, -3)

H = (1, 4) -> G' (4, -8)

Answer:

6) -30

7) -5

Step-by-step explanation:

6)

x = 5 y = 3 z = -2

xyz = 5 x 3 x -2 = 15 x -2 = -30

7)

x = 5 y = 3 z = -2

xyz/ 6 = -30/6 = -5

Answer:

Draw the graph of line x=5 , which would be vertical line passing through (5,0) . Since x is less than but not equal to 5 , make it a dotted line and shade the region to the left.

Step-by-step explanation:

The area of carpet required to cover all visible surfaces of the podium is 21.53 m^2.

We are given that;

The base of the podium has a radius = 1.5 m

Now,

A. we can find the area of each circular top:

A1 = π(1.5)^2 A1 = 7.07 m^2

A2 = π(1.1)^2 A2 = 3.8 m^2

A3 = π(0.7)^2 A3 = 1.54 m^2

To find the total area of the top surface, we need to add these areas:

AT = A1 + A2 + A3 AT = 7.07 + 3.8 + 1.54 AT = 12.41 m^2

B. we can find the area of each cylindrical side:

A1 = 2π(1.5)(0.25) A1 = 2.36 m^2

A2 = 2π(1.1)(0.5) A2 = 3.46 m^2

A3 = 2π(0.7)(0.75) A3 = 3.3 m^2

To find the total area of all vertical surfaces, we need to add these areas:

AV = A1 + A2 + A3 AV = 2.36 + 3.46 + 3.3 AV = 9.12 m^2

C. To find the area of carpet required to cover all visible surfaces of the podium, we need to add the areas found in parts (a) and (b):

ATotal = AT + AV ATotal = 12.41 + 9.12 ATotal = 21.53 m^2

Therefore, by area the answer will be 21.53 m^2.

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Answer:

A rotation ____on the coordinate plane________ a figure around a fixed point called the center of

___rotation_____________.

The possible 3rd degree binomial with a constant term of 888 is x^3 + 2x^2 + 3x + 888, for the given one degree of freedom.

To find a 3rd degree binomial with a constant term of 888, we can start by writing the general form of a 3rd degree binomial: ax^3 + bx^2 + cx + d.

Since we want the constant term to be 888, we can set d = 888.

Now, we need to choose values for a, b, and c. We have one degree of freedom, so we can choose any values for a, b, and c as long as they satisfy the condition of being a 3rd degree binomial.

For example, let's choose a = 1, b = 2, and c = 3.

Therefore, a possible 3rd degree binomial with a constant term of 888 is x^3 + 2x^2 + 3x + 888.

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Answer: 6 units

Step-by-step explanation:

The formula for the volume of a cylinder is V = πr²h, where V is the volume, r is the radius, and h is the height.

In this case, we know that the radius (r) of the cylinder is 5, and the volume (V) is 150π. Substituting these values into the formula, we get:

150π = π(5²)h

Simplifying the equation, we get:

150 = 25h

Dividing both sides by 25, we get:

h = 6

Therefore, the height of the cylinder is 6 units.

Answer:

55 degrees

Step-by-step explanation:

a straight line always equals 180 degrees so to find the missing degree you go 180 - 125 which is 55 for the line to equal 180

Answer:

The temperature for Sunday was -2.3F

Step-by-step explanation:

When we have a set of N values:

{x₁, x₂, ..., xₙ}

The mean is given by:

\(M = \frac{x_1 + x_2 + ... + x_n}{N}\)

In this case, we have the set:

{-5.3F, 3.6F, 6.7F, 0F, 10F, -4.3F, X}

Where X is Sunday's temperature.

So we have a set of 7 values, and we know that the mean of this set is 1.2F

Then we have the equation:

\(1.2F = \frac{-5.3F + 3.6F + 6.7F + 0F + 10F - 4.3F + X}{7}\)

If we multiply both sides by 7, we get:

\(1.2F*7 = 8.4F =-5.3F + 3.6F + 6.7F + 0F + 10F - 4.3F + X\)

Now we can just solve this for X

8.4F + 5.3F - 3.6F - 6.7F - 10F + 4.3F = X

-2.3F = X

The temperature for Sunday was -2.3F

The angle of reflection for the ray leaving mirror 2 will be 41 degrees, as this is equal to the angle of incidence for the ray striking mirror 2.

The angle of incidence is the angle between the incoming ray and the surface of the mirror, and the angle of reflection is the angle between the reflected ray and the surface of the mirror.

In the given scenario, a ray of light strikes mirror 1 with an angle of incidence of 41 degrees.

The angle of reflection can be calculated using the law of reflection, which states that the angle of incidence is equal to the angle of reflection.

Therefore, the angle of reflection of the ray when it leaves mirror 1 will be 41 degrees.

However, the ray of light continues its journey and strikes mirror 2.

When this happens, the angle of incidence is the angle between the reflected ray from mirror 1 and the surface of mirror 2.

The angle of reflection for the ray leaving mirror 2 can be calculated using the same law of reflection.

The angle of reflection will be equal to the angle of incidence, which is 41 degrees.

The angle of reflection is a crucial concept in understanding the reflection of light and is used in various applications such as mirrors, prisms, and lenses.

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Your answer would be 1/x^2 -6

Answer:

x is equal to -3, and y is equal to eight fifths, or 1.6

Step-by-step explanation:

Solving by elimination means to add or subtract one of the equations from the other, eliminating one of their common terms.

Because both of the provided ones have the term 5y (and no other y terms), let's use subtraction:

   3x + 5y = -1

- ( x + 5y = 5 )

   2x + 0 = -6

Which we can solve pretty quick:

2x = -6

x = -3

We can now solve either of the original equations for y:

x + 5y = 5

-3 + 5y = 5

5y = 8

y = 8/5, or 1.6

To make sure we're correct, let's test our results in the other equation:

3x + 5y = -1

3 × -3 + 5 × 8/5 = -1

-9 + 8 = -1

-1 = -1

So we're good!

The answer to the system of equations is (-7/11, 23/11), which stands for the intersection of the two lines.

It has one or more variables, and based on the values of the variables, it can either be true or false. Equations are frequently employed in a wide range of mathematical applications, from straightforward algebraic equations to more intricate differential equations used in calculus and physics. Equations are used to depict relationships between various mathematical objects or values. An essential part of addressing algebraic problems is to solve equations to determine the values of the variables that make the equation true.

given

We can solve one equation for one variable and then insert the expression into the second equation to apply the substitution method. For instance, we can resolve the first equation for y as follows:

y = 2x + 6

After that, we may enter the following expression in place of y in the second equation:

2x + 6 = -9x - 1

Then, we may find x:

11x = -7

x = -7/11

We may use one of the original equations to obtain the value of y once we have determined the value of x:

y = 2(-7/11) + 6 = 23/11

The answer to the system of equations is (-7/11, 23/11), which stands for the intersection of the two lines.

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Answer:

Where is the graph of this question?

In terms of probability, we can say that the probability of selecting a coffee maker with a defective cord is 5.0% or 0.05. The percentage of coffee makers with a defective cord.

To find the probability of a coffee maker having a defective cord, we'll use the given information about faulty switches and defective cords.

We know that:
1. 6.0% of coffee makers have either a faulty switch or a defective cord.
2. 1.5% have a faulty switch.
3. 0.5% have both defects.

Using the formula for the probability of the union of two events (A or B) - P(A ∪ B) = P(A) + P(B) - P(A ∩ B), where A represents the event of a faulty switch, B represents the event of a defective cord, and A ∩ B represents both defects:

P(A ∪ B) = 6.0% (either a faulty switch or a defective cord)
P(A) = 1.5% (faulty switch)
P(A ∩ B) = 0.5% (both defects)

We need to find P(B), the probability of a coffee maker having a defective cord.

Using the formula, we can write:
6.0% = 1.5% + P(B) - 0.5%

Now, we'll solve for P(B):
6.0% = 1.0% + P(B)
P(B) = 6.0% - 1.0%
P(B) = 5.0%

Therefore, the probability (percent) of a coffee maker having a defective cord is 5.0%.

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a. The equilibrium solution (y = 0) is stable.

b. The limit of \(\( y(t) \)\) as \(\( t \)\) approaches infinity is 0.

A function's derivative with respect to an independent variable is what is referred to as differentiation. In calculus, differentiation can be used to calculate the function per unit change in the independent variable. Let y = f(x) represent the function of x.

The nonlinear differential equation is given as:

\(\( \frac{{dy}}{{dt}} = -y^2 \)\)

a) Classifying Equilibrium Solutions:

To find the equilibrium solutions, we set the derivative equal to zero:

\(\( -y^2 = 0 \)\)

The only solution is (y = 0). Therefore, the equilibrium solution is (y = 0).

To classify the stability of the equilibrium solution, we examine the sign of the derivative \(\( \frac{{dy}}{{dt}} \)\) around the equilibrium point.

For \(\( y < 0 \), \( \frac{{dy}}{{dt}} > 0 \)\), indicating that the function is increasing and moving away from the equilibrium solution.

For \(\( y > 0 \), \( \frac{{dy}}{{dt}} < 0 \)\), indicating that the function is decreasing and moving towards the equilibrium solution.

Hence, the equilibrium solution (y = 0) is stable.

b) Determining the Limit:

Given that \(\( y(0) = 2 \)\), we need to determine the limit of \(\( y(t) \) as \( t \)\) approaches infinity, if it exists.

The differential equation \(\( \frac{{dy}}{{dt}} = -y^2 \)\) can be separated and solved:

\(\( \frac{{dy}}{{y^2}} = -dt \)\)

Integrating both sides:

\(\( \int \frac{{dy}}{{y^2}} = -\int dt \)\)

\(\( -\frac{1}{y} = -t + C \)\)

Simplifying, we have:

\(\( \frac{1}{y} = t + C \)\)

Rearranging the equation:

\(\( y = \frac{1}{t + C} \)\)

Since we are given \(\( y(0) = 2 \)\), we can substitute this into the equation to find the value of (C):

\(\( 2 = \frac{1}{0 + C} \)\)

Solving for \(\( C \)\), we get \(\( C = \frac{1}{2} \)\).

Therefore, the solution to the differential equation is:

\(\( y = \frac{1}{t + \frac{1}{2}} \)\)

Taking the limit as (t) approaches infinity:

\(\( \lim_{{t \to \infty}} \frac{1}{t + \frac{1}{2}} = 0 \)\)

Hence, the limit of \(\( y(t) \)\) as \(\( t \)\) approaches infinity is 0.

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