6 less than half of r : translate into expression

Answer:

i think its n-5

Step-by-step explanation:

hope this helps any

Answer:

√[n - 10]

Step-by-step explanation:

Write this:  √[n - 10]

Answer:

This is an english server

Answer:

x=6

Step-by-step explanation:

3(6)+1=18+1=19.

The range of the distribution is the parameter that is required to convert a computer-generated random variable into a uniform random variable. Below are more than 100 words explaining this in detail:A uniform random variable is a random variable with a probability distribution function that is uniform across all possible values.

The probability density function of a uniform distribution is constant over the range of values of the variable. Therefore, it has equal probability of taking any value within the range of values that it is defined.The process of converting a computer-generated random variable into a uniform random variable is known as uniform random number generation. The process of uniform random number generation is an important aspect of computer simulation and statistical analysis of data.

It is used to generate random numbers that follow a uniform distribution, which is a common distribution in many applications.The range of the distribution is the parameter that is required to convert a computer-generated random variable into a uniform random variable. This is because the range of the distribution defines the possible values that the variable can take. By mapping the computer-generated random variable to the range of the uniform distribution, we can convert it into a uniform random variable.

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The true statements are:

Each ticket costs $12.25. (option b)

The one-time processing fee costs $3.75. (option c)

A linear equation is an equation with a single variable raised to the power of one.

y = mx + c

m = variable cost

c = fixed cost

Fixed cost is a cost that remains constant regardless of the number of tickets bought. Variable cost is a cost that changes with the number of tickets bought.

C = 12.25n + 3.75

Where:

12.25 - variable cost - cost of each ticket. This cost increases with the number of tickets that is purchased. As more tickets are purchased, the cost increases by 12.25.

3.75 - fixed cost - one time online processing fee. This is because this payment is made once and it does not increase with the number of tickets bought.

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Using trigonometric function the value of x is 51.3°.

What is trigonometric function?

The functions of an angle in a triangle are known as trigonometric functions, commonly referred to as circular functions. In other words, these trig functions provide the relationship between a triangle's angles and sides. There are five fundamental trigonometric functions: sine, cosine, tangent, cotangent, secant, and cosecant.

Here Let us take the given right triangle as ABC.

∠A = x , ∠B = 90° and AB = 25 , AC= 40

Now using Cosine ratio then

Cos  A = \(\frac{adjacent}{hypotenuse}\)

=> cos x = \(\frac{25}{40}\)

=> cos x = \(\frac{5}{8}\)

=> x = \(cos^{-1}\frac{5}{8}\)

=> x = 51.3°

Hence the value of x is 51.3°.

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Answer: Isabella has 4 more photos than the other photo albums. So, Isabella has more pages than the number on one page in the example problem.

Step-by-step explanation: 3 divided by 36 equals 12. 12 times 3 = 36

The number of photos on one of these pages is more than the number on one page in the example problem because Isabella's photo album contains 4 more photos.

Arithmetic operations can also be specified by adding, subtracting, dividing, and multiplying built-in functions.

* Multiplication operation: Multiplies values on either side of the operator

For example 4*2 = 8

/ Division operation: Divides left-hand operand by right-hand operand

For example 4/2 = 2

We have been given that Isabella filled 3 more pages with 36 photos which she evenly divided between the pages.

As per the given condition,

36 divided by 3

⇒ 36 / 3 = 12

Here 12 times 3 is equal to 36

Therefore, Isabella's photo album contains 4 more photos. The number of pages in Isabella is greater than the number on one page in the example problem.

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It is FALSE to state that if a researcher is interested determining if there is a relationship betweenethnicity and job type, then a Chi- Square Goodness of Fit test can be   used.

A Chi-Square Goodness of Fit test is not   appropriate for determining the relationship between ethnicity and job type.

This test is used to assess thedistribution of categorical variables within a single population or sample,   comparing observed frequencies with expected frequencies.

To examine the relationship between ethnicity and job type, a Chi-Square test of independence   or another suitable statistical test, such as logistic regression,would be more appropriate.

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Finite-state machines for given inputs: (a) 0s multiple of 3: 3-state machine. (b) At least four 1s: 4-state machine. (c) Exactly one 1: 2-state machine. (d) Begins with 000: 3-state machine. (e) Second is 0, fourth is 1: 4-state machine. (f) 01 pairs or 2 1s + 0s: 3-state machine. (g) Ends in 110: 3-state machine.

To construct finite-state machines that act as recognizers for the given inputs, we can follow these guidelines:

(a) For the set of all strings where the number of 0s is a multiple of 3, we can use a finite-state machine with three states. Start with the initial state, and transition to the next state whenever a 0 is encountered. After three transitions, go back to the initial state. If the machine ends in the accepting state, output 1.
(b) For the set of all strings containing at least four 1s, we can use a finite-state machine with four states. Start with the initial state, and transition to the next state whenever a 1 is encountered. If the machine enters the final state after four transitions, output 1.

(c) For the set of all strings containing exactly one 1, we can use a finite-state machine with two states. Start with the initial state and transition to the final state when the first 1 is encountered. Output 1 only if the final state is reached.

(d) For the set of all strings beginning with 000, we can use a finite-state machine with three states. Start with the initial state and transition to the next state whenever a 0 is encountered. If the machine reaches the final state after three transitions, output 1.

(e) For the set of all strings where the second input is 0 and the fourth input is 1, we can use a finite-state machine with four states. Start with the initial state and transition to the next state based on the inputs. Output 1 only if the machine reaches the final state.

(f) For the set of all strings consisting entirely of any number (including none) of 01 pairs or consisting entirely of two 1s followed by any number (including none) of 0s, we can use a finite-state machine with three states. Start with the initial state and transition based on the inputs. Output 1 only if the final state is reached.

(g) For the set of all strings ending in 110, we can use a finite-state machine with three states. Start with the initial state and transition based on the inputs. Output 1 only if the final state is reached.

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Finite-state machines (FSMs) can be constructed to act as recognizers for specific patterns in input strings. These are examples of how to construct FSMs as recognizers for different patterns in input strings. Each FSM is designed to produce an output of 1 when the input received matches the description provided.

Let's consider the given cases and construct FSMs for each one.

(a) The set of all strings where the number of Os is a multiple of 3:
To construct an FSM for this, we can keep track of the number of Os encountered so far. Initially, set the count to zero. When an O is encountered, increment the count by one. If the count becomes a multiple of 3, the FSM outputs 1; otherwise, it outputs 0. Reset the count to zero whenever a 1 is encountered.

(b) The set of all strings containing at least four 1s:
To create an FSM for this, we can keep track of the number of 1s encountered so far. Initially, set the count to zero. When a 1 is encountered, increment the count by one. If the count becomes equal to or greater than four, the FSM outputs 1; otherwise, it outputs 0.

(c) The set of all strings containing exactly one 1:
To build an FSM for this, we can have two states: a "no 1 encountered" state and a "1 encountered" state. Initially, start in the "no 1 encountered" state. Whenever a 1 is encountered, transition to the "1 encountered" state. If another 1 is encountered in the "1 encountered" state, transition to a third "more than one 1 encountered" state. In this case, the FSM outputs 0. Otherwise, if no additional 1s are encountered, the FSM outputs 1.

(d) The set of all strings beginning with 000:
To create an FSM for this, start in an initial state. When a 0 is encountered, transition to a second state. If two consecutive 0s are encountered in the second state, transition to a third state. Finally, if a third 0 is encountered in the third state, the FSM outputs 1; otherwise, it outputs 0.

(e) The set of all strings where the second input is 0 and the fourth input is 1:
To construct an FSM for this, start in an initial state. When the first input is read, transition to a second state. In the second state, transition to a third state if the second input is 0. In the third state, transition to a fourth state if the third input is not 0. Finally, in the fourth state, if the fourth input is 1, the FSM outputs 1; otherwise, it outputs 0.

(f) The set of all strings consisting entirely of any number (including none) of 01 pairs or consisting entirely of two Is followed by any number (including none) of Os:
To create an FSM for this, we can have multiple states to represent different scenarios. We start in an initial state and transition to a second state when a 0 is encountered. In the second state, transition back to the initial state if a 1 is encountered. If a 1 is encountered in the initial state, transition to a third state. In the third state, transition to a fourth state if an O is encountered. Finally, if an O is encountered in the fourth state, the FSM outputs 1; otherwise, it outputs 0.

(g) The set of all strings ending in 110:
To construct an FSM for this, start in an initial state. Transition to a second state if a 1 is encountered. In the second state, transition to a third state if a 1 is encountered again. Finally, if a 0 is encountered in the third state, the FSM outputs 1; otherwise, it outputs 0.

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Answer:

\(\huge \boxed{49x^2 y^2 -126x^2 y +81x^2}\)

Step-by-step explanation:

\(\sf (9x - 7xy)^2\)

Expanding brackets.

\(\sf (9x - 7xy)(9x-7xy)\)

Applying the FOIL method.

\(\sf 9x(9x-7xy)-7xy(9x-7xy)\)

\(\sf 81x^2 -63x^2 y -63x^2 y+49x^2 y^2\)

Combining like terms.

\(\sf 81x^2 -126x^2 y+49x^2 y^2\)

Answer:

So, we can check step by step.

2x^2-7x+5=0

So, 2x^2-2x-5x+5=0 is correct

2x(x-1)=2x^2-2x, 5(x-1)=-5x + 5= 0, that step is correct

(I'll skip the next step)

2x-5=0,

2x=5

x=5/2, NOT 2/5

The other one is correct

Sorry if this seems a bit vague!

\(\\ \rm\Rrightarrow 2x^2-7x+5=0\)

\(\\ \rm\Rrightarrow 2x^2-2x-5x+5=0\)

\(\\ \rm\Rrightarrow 2x(x-1)-5(x-1)=0\)

\(\\ \rm\Rrightarrow (2x-5)(x-1)=0\)

\(\\ \rm\Rrightarrow x=5/2,1\)

Lauren written 2/5 instead of 5/2

Let's verify once more

Answer:

\(\left[\begin{array}{ccc}1&2\\6&7\end{array}\right]\cdot \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}0\\-10\end{array}\right]\)

Step-by-step explanation:

The system of equation in matrix form is defined by following vector formula:

\(\vec A \cdot \vec x = \vec b\) (1)

Where:

\(\vec A\) - Matrix of coefficients.

\(\vec x\) - Column vector of variables.

\(\vec b\) - Column vector of results.

If we know that \(x + 2\cdot y = 0\) and \(6\cdot x + 7\cdot y = -10\), then the system of equations in matrix form is:

\(\vec A = \left[\begin{array}{ccc}1&2\\6&7\end{array}\right]\), \(\vec x = \left[\begin{array}{ccc}x\\y\end{array}\right]\), \(\vec b = \left[\begin{array}{ccc}0\\-10\end{array}\right]\)

Then,

\(\left[\begin{array}{ccc}1&2\\6&7\end{array}\right]\cdot \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}0\\-10\end{array}\right]\)

Answer:

what do u need help with

Step-by-step explanation:

Answer:

B: -2 3/4 < -1 1/2

Hope this helps!

If you can give brainly ill apreciate it

Answer:

B or C

Step-by-step explanation:

negatives are bigger but Still smaller if u get what I mean

Answer:

x = 2.5

Step-by-step explanation:

2x² + 7x – 30 = 0

(2x – 5) (x + 6) = 0

2x – 5 = 0 or x + 6 = 0

2x = 5 or x = –6

x = 5/2 or x = –6

x = 2.5 or x = –6

Given that h^(-1)(11) = 4, the corresponding input and output values of the original function h are x = 4 and h(4) = 11.

The notation h^(-1)(11) represents the inverse of the function h evaluated at the input value 11. In other words, it gives us the input value that would produce an output of 11 when fed into the inverse function.

Since h^(-1)(11) = 4, we know that when 11 is inputted into the inverse function h^(-1), it yields an output of 4.

To find the corresponding input and output values for the original function h, we need to swap the input and output values of the inverse function. Thus, the input value for the function h is x = 4, and the output value is h(4) = 11.

Therefore, when 4 is inputted into the original function h, it produces an output of 11.

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Step-by-step explanation:

180(n-2)/n=90 ( this is the solution for the 90)

cross multiplying

180n-360=90n

180n-90n=360

90n=360

90n/90=360/90

n=4, the number of sides for the polygon with 90° is 4 sides

Solution for 100°

180(n-2)/n=100

180n-360=100n

180n-100n=360

80n=360

80n/80=360/80

n=4.5

Same applies to the rest 110°,125° ,150°,175°

The Proof for p₁ − 2p₃ − · · · − (n − 3)pₙ₋₁ = 2 is shown below .

In the question ,

it is given that ,

the the number of vertices of Tree T is \(p_{i}\) ,

we have to prove that p₁ − p₃ − 2p₄ − · · · − (n − 3)pₙ₋₁ = 2 ,

First note that \(p_{i}\) = 0 for i ≥ n (a vertex can have degree at most n − 1, which happens for the

star K₁ , ₙ₋₁).

Using the data that tree T has n vertices and (n − 1) edges, we have

p₁ + p₂ + p₃ + · · · + pₙ₋₁ = n               ....equation(1)

and

p₁ + 2p₂ + 3p₃ + · · · + (n − 1)pₙ₋₁ = 2(n − 1)      ......equation(2)

Subtracting the equation(2) from twice the equation(1) , we obtain

p₁ − 2p₃ − · · · − (n − 3)pₙ₋₁ = 2.

(When n = 2 we have p₁ = 2.)

Therefore , it is proved that p₁ − 2p₃ − · · · − (n − 3)pₙ₋₁ = 2    .

The given question is incomplete , the complete question is

Let T be a tree with n vertices, n ≥ 2. For a positive integer i, let pi be the number of vertices of T of degree i .  Prove that

p₁ − 2p₃ − · · · − (n − 3)pₙ₋₁ = 2.

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The length of the segment MF will be 6 units.

What is coordinate geometry?

A coordinate plane is a 2D plane that is formed by the intersection of two perpendicular lines known as the x-axis and y-axis. A coordinate system in geometry is a method for determining the positions of the points by using one or more numbers or coordinates.

Given that M is the midpoint of CF for the points c(4,10) and f(10,10). To calculate the segment MF first let us calculate the midpoint M.

M = [ ( x₁ + x₂ ) / 2, ( y₁ + y₂ ) / 2 ]

M = [( 4 + 10 ) /2 , ( 10+10 ) / 2]

M = ( 7, 10)

The length of the segment MF will be:-

D = √ [ ( y₂ - y₁ )² + ( x₂ - x₁ )² ]

D = √ [ ( 10-10 )² + ( 10 - 4 )² ]

D = √36

D = 6

Therefore, the length of the segment MF will be 6 units.

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The quadratic inequality defined on the graph is given as follows:

y ≥ 2/3(x + 3)² - 24.

The coordinates of the vertex of the quadratic function are given as follows:

(-3, -24).

Hence the quadratic function is given as follows:

y = a(x + 3)² - 24.

In which a is the leading coefficient.

When x = 3, y = 0, hence the leading coefficient a is obtained as follows:

0 = a(3 + 3)² - 24

36a = 24

a = 24/36

a = 2/3.

Hence:

y = 2/3(x + 3)² - 24.

The quadratic function has a solid curve, and the values above it are pained, hence the inequality is given as follows:

y ≥ 2/3(x + 3)² - 24.

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Answer: Where is the triangle?

Step-by-step explanation: Brainliest pls:)

When a washer and a dryer cost $995 combined. If  the washer cost $45 more than the dryer, then the cost of the dryer is $475

The combined cost of a washer and a dryer = $995

Consider the cost of a dryer as x

The washer cost $45 more than the dryer.

The cost of the washer = x+45

Then the equation will be

x+x+45 = 995

2x+45 = 995

2x = 950

x = 950/2

x = 475

The cost of the dryer is $475

Hence, when a washer and a dryer cost $995 combined. If  the washer cost $45 more than the dryer, then the cost of the dryer is $475

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Answer:

by search in Goggle and by re-read

Answer:

Step-by-step explanation      a=0.32

The required simplified value of x in the given expression is 8.

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

Here,
2.8x + 10 + 5.7x = 70+x

Simplifying,
8.5x + 10 = 70 + x
8.5x - x = 70 - 10
7.5x  = 60
x = 60 / 7.5
x = 8

Thus, the required simplified value of x in the given expression is 8.

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Answer:

Number of ways we can choose the four students who must ride in the car = 3060 ways

Step-by-step explanation:

This is a combination question.

The number of selections of "r" objects from the given "n" objects is denoted by;

C(n,r), and is given by;

C(n, r) = n!/[r!(n - r)!]

In this question, n = 18 and r = 4

Thus;

C(18, 4) = 18!/[4!(18 - 4)!]

C(18,4) = 3060

Number of ways we can choose the four students who must ride in the car = 3060 ways

Answer: x is the variable

Step-by-step explanation:

Anytime you see a letter in an expression it is a variable. Remember this, this is incredibly important. Good luck!

The required, Triangle ABC ≅ triangle CDA formed in rhombus ABCD by SAS congruency postulate.

In congruent geometry, the shapes that are so identical. can be superimposed to themselves.

Here,
Consider the ABCD rhombus, the sides of a rhombus are equal,
Now, Consider Triangle ABC and triangle CDA,
1. AC = AC [because AC is the common side between the two triangles]
2. ∠D = ∠C  [because opposite angles of a rhombus is equal]
3. AD = BC   [equal sides of rhombus]

So, Triangle ABC ≅ triangle CDA, by SAS congruency postulate.

Thus, Triangle ABC ≅ triangle CDA formed in rhombus ABCD by SAS congruency postulate.

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Answer:I believe this answer is they did not have enough troops to attack the USSR

Step-by-step explanation:

I