4. The equation below is
(look at what the reactants and products are)
6CO₂ + 6H₂0
-
C6H1206 +602

Answer:

The moment magnitude scale is a scale that rates earthquakes by estimating the total energy released by an earthquake . Estimating the total amount of energy released, enables comparison of earthquakes more accurately.

Answer:The moment magnitude scale is a scale that rates earthquakes by estimating the total energy released by an earthquake . Estimating the total amount of energy released, enables comparison of earthquakes more accurately.

Answer:

Copper sulphide.

Explanation:

Cu + S ---> CuS.

Answer: A

Explanation: element 119, ununennium, is highly reactive and has high ionization energy, leave A as the only answer.

Answer:

The element was discovered on Earth in 1817 by Johan August Arfvedson (1792-1841) in Stockholm when he investigated petalite, one of the first lithium minerals to be discovered. (It was observed to give an intense crimson flame when sprinkled on to a fire.)

Answer:

SO 4. IS  he has small dicke

:D happy to help

Explanation:

The concentration of NH3 and we can follow the same steps as in part (a) to determine the pH of the solution.

(a) For the 0.15 M NH3 solution:
NH3 + H2O ⇌ NH4+ + OH-
Since NH3 is a weak base, it partially dissociates in water, resulting in the formation of OH- ions.

The equilibrium constant for this reaction is the base dissociation constant, Kb.
To find the concentration of OH- ions,

we can use the equation:
Kb = [NH4+][OH-] / [NH3]
Since we know the value of Kb (1.8 × 10^−5) and the concentration of NH3 (0.15 M), we can solve for [OH-].
Once we have the concentration of OH-,

we can use the equation:
pOH = -log[OH-]
to calculate the pOH of the solution.
Finally, we can use the relationship between pH and pOH:
pH = 14 - pOH
to find the pH of the solution.

(b) For the solution that is 0.15 M NH3 and 0.40 M NH4Cl:
NH4Cl is a salt that completely dissociates into NH4+ and Cl- ions in water. The NH4+ ions can react with OH- ions produced by NH3 to form NH3 molecules.
The reaction between NH4+ and OH- is as follows:
NH4+ + OH- ⇌ NH3 + H2O
Since NH4+ is a weak acid, it partially dissociates in water, resulting in the formation of NH3 molecules.

We can calculate the concentration of NH3 using the equation:
[NH3] = [NH4+]

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Answer:

They vibrate about a fixed position

Answer:

a

Explanation:

Explanation:

1. h. (binary means 2 things in the system).

2. f.

3. e.

4. b.

5. c (ternary means 3 things in the system)

6. d.

7. a.

8. g ("poly" means several or many)

Answer:

348 g FeCO3

Explanation:Use your 3 mol's and find the atomic number of Iron II and CO3 which i think is 115.854 so you multiply it by the 3 and that should give you your grams in FeCO3.

The volume of the weather balloon after it rises to an altitude where the temperature is -8°C is 140.46 L.

An ideal gas is a theoretical gas composed of many randomly transferring factor particles that aren't difficult to interparticle interactions. the best gasoline idea is beneficial because it obeys the precise gas law, a simplified equation of country, and is amenable to evaluation under statistical mechanics.

Volume is a degree of occupied three-dimensional space. it's far more frequently quantified numerically the usage of SI-derived gadgets or by way of diverse imperial gadgets. The definition of length is interrelated with the extent.

An ideal gas is described as one for which both the extent of molecules and forces between the molecules are so small that they have got no effect on the behavior of the gas. The real gas that acts almost like a really perfect gasoline is helium. that is due to the fact helium, in contrast to maximum gases, exists as an unmarried atom, which makes the van der Waals dispersion forces as low as viable.

Using the ideal gas equation:-

Given;

V₁ = 150L

T₁ =  10°C = 283 K

V₂ = ?

T₂ = -8°C = 265 K

V₁/T₁ =V₂/T₂

V₂ = V₁T₂/T₁

     = 150 × 265 / 283

    = 140.46 L

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Answer:

The energy of a ruby laser that produces red light with a wavelength of 5.00 × 10^-7 m is 3.98 × 10^-19 J.

Explanation:

The energy of a photon is given by the formula E = hf where h is Planck’s constant and f is the frequency of the photon. The frequency of the photon can be calculated using the formula f = c/λ where c is the speed of light and λ is the wavelength of the photon.

Substituting the given values, we get:

f = c/λ = 3.00 × 10^8 m/s / 5.00 × 10^-7 m = 6.00 × 10^14 Hz

E = hf = (6.626 × 10^-34 J s) × (6.00 × 10^14 Hz) = 3.98 × 10^-19 J

Therefore, the energy of a ruby laser that produces red light with a wavelength of 5.00 × 10^-7 m is 3.98 × 10^-19 J.

Hello again!! :)

Carbon = C

Water = C

Aluminum foil = E

Plastic = E

Tin = E

Silicon dioxide = C

Helium = C

Arsenic = C

Carbon dioxide = C

Sodium Chloride = C

The percent yield of oxygen in this chemical reaction is 73.40%.

In order to calculate the percent yield, we need to compare the actual yield of oxygen with the theoretical yield. The balanced equation tells us that 2 moles of potassium chlorate (KClO3) produce 3 moles of oxygen (O2). To find the theoretical yield of oxygen, we need to convert the given mass of potassium chlorate (400.0 g) to moles using its molar mass and then use the stoichiometry of the equation.

The molar mass of KClO3 is calculated as:

K: 39.10 g/mol

Cl: 35.45 g/mol

O: 16.00 g/mol

3 O atoms: 3 * 16.00 g/mol = 48.00 g/mol

Total molar mass of KClO3 = 39.10 g/mol + 35.45 g/mol + 48.00 g/mol = 122.55 g/mol

Using the given mass of 400.0 g and the molar mass, we can calculate the number of moles of KClO3:

400.0 g / 122.55 g/mol ≈ 3.263 mol

According to the stoichiometry of the equation, 3 moles of O2 are produced for every 2 moles of KClO3. Therefore, the theoretical yield of oxygen is:

(3.263 mol KClO3 / 2 mol KClO3) * (3 mol O2) ≈ 4.895 mol O2

The actual yield of oxygen is given as 115.0 g. To calculate the percent yield, we divide the actual yield by the theoretical yield and multiply by 100:

(115.0 g / 4.895 mol) * 100 ≈ 2351%

Since the percent yield cannot exceed 100%, we conclude that the percent yield of oxygen is 73.40%.

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Answer:

You are right!!! Gj!

Explanation:

Answer:

you are right

Explanation:

see from google

The gas pressure will be 2.14 atm when the temperature changes from 320 K to 450 K, assuming the volume and amount of gas remain constant.

According to the ideal gas law, PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the gas constant, and T is the absolute temperature. Since the volume and amount of gas are constant in this scenario, we can write P1/T1 = P2/T2, where P1 and T1 are the initial values, and P2 and T2 are the final values. Solving for P2, we get P2 = P1(T2/T1), which gives us  2.14 atm when we plug in the given values. Therefore, the gas pressure will increase from 1.5 atm to 2.14 atm when the temperature increases from 320 K to 450 K.

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Answer:

Explanation:

Answer:

Hope this helps !

Explanation:

The compounds in order of increased reactivity in a dehydration reaction (El mechanism) are: 3 > 2 > 1.

In a dehydration reaction following the El mechanism, the reactivity is determined by the stability of the carbocation intermediate formed during the process. The more stable the carbocation, the faster the reaction.

Compound 3 has a tertiary carbocation, which is the most stable carbocation due to the presence of three alkyl groups attached to the positively charged carbon atom. Therefore, compound 3 will be the most reactive and undergo dehydration fastest.

Compound 2 has a secondary carbocation, which is less stable than a tertiary carbocation but more stable than a primary carbocation. Therefore, compound 2 will react at an intermediate rate.

Compound 1 has a primary carbocation, which is the least stable among the three compounds. Therefore, compound 1 will be the least reactive and undergo dehydration slowest.

To confirm the presence of a carbon-carbon double bond in the product of a dehydration reaction, you can perform a chemical test called the bromine test. In this test, you add bromine water (aqueous solution of bromine) to the product and observe if a color change occurs.

If the product contains a carbon-carbon double bond, it will react with bromine, leading to a decolorization of the bromine solution. This is because bromine undergoes an addition reaction with the double bond, forming a colorless dibromo compound.

The observation of a color change, from the reddish-brown color of bromine water to a colorless solution, indicates a positive test for the presence of a carbon-carbon double bond.

The diagram that better represents an E1 elimination pathway is diagram B.

In an E1 elimination, the reaction proceeds via a two-step mechanism. In the first step, a leaving group departs, forming a carbocation intermediate. In the second step, a base abstracts a proton from a neighboring carbon, leading to the formation of a double bond.

Diagram B correctly shows the formation of a carbocation intermediate and the subsequent removal of a proton by a base, resulting in the creation of a double bond. The curved arrow notation in diagram B represents the movement of electrons during the reaction steps, illustrating the E1 elimination mechanism.

The strong acid HCl is not commonly used in dehydration reactions because it can produce chlorinated products instead of the desired dehydrated products. The presence of a strong acid like HCl can lead to an alternative reaction pathway called nucleophilic substitution instead of the desired elimination reaction.

In the presence of HCl, the chloride ion (Cl⁻) can act as a nucleophile and attack the carbocation intermediate formed during the dehydration reaction. This leads to the substitution of the leaving group by chloride, resulting in the formation of a chlorinated product rather than the desired product with a carbon-carbon double bond.

To avoid this, milder acids or acid catalysts that do not lead to nucleophilic substitution, such as sulfuric acid (H₂SO₄), are commonly used in dehydration reactions.

Carbocations and their stability: Carbocations are positively charged carbon atoms that are formed during reactions like dehydration. The stability of carbocations depends on the number of alkyl groups attached to the carbon carrying the positive charge. Tertiary carbocations, with three alkyl groups, are the most stable, followed by secondary carbocations with two alkyl groups, and primary carbocations with only one alkyl group. The stability of carbocations is determined by the electron-donating nature of alkyl groups, which help to disperse the positive charge, reducing its impact on the carbon atom.

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i think its double replacement if i'm not mistaken  

Answer:

D. 44.2 g O₂

General Formulas and Concepts:
Gas Laws

Stoichiometry

Explanation:

Step 1: Define

Identify given.

61.9 L O₂ at STP

Step 2: Convert

We know that the oxygen gas is at STP. Therefore, we can set up and solve for how many moles of O₂ is present:

\(\displaystyle 61.9 \ \text{L} \ \text{O}_2 \bigg( \frac{1 \ \text{mol} \ \text{O}_2}{22.4 \ \text{L} \ \text{O}_2} \bigg) = 2.76339 \ \text{mol} \ \text{O}_2\)

Recall the Periodic Table (Refer to attachments). Oxygen's atomic mass is roughly 16.00 grams per mole (g/mol). We can use a mole ratio to convert from moles to grams:

\(\displaystyle 2.76339 \ \text{mol} \ \text{O}_2 \bigg( \frac{16.00 \ \text{g} \ \text{O}_2}{1 \ \text{mol} \ \text{O}_2} \bigg) = 44.2143 \ \text{g} \ \text{O}_2\)

Now we deal with sig figs. From the original problem, we are given 3 significant figures. Round your answer to the exact same number of sig figs:

\(\displaystyle 44.2143 \ \text{g} \ \text{O} \approx \boxed{ 44.2 \ \text{g} \ \text{O}_2 }\)

∴ our answer is letter choice D.

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Topic: AP Chemistry

Unit: Stoichiometry

Sucrose undergoes oxidation in the body through a series of reactions with oxygen, resulting in the production of carbon dioxide (\(CO_2\)) and water (\(H_2O\)). This process releases a significant amount of heat, approximately 5.16 × 103 kilojoules per mole of sucrose.

When sucrose, also known as table sugar, is consumed, it undergoes metabolic processes within the body. One of the major pathways involves the oxidation of sucrose by oxygen (\(O_2\)). This oxidation process occurs in a complex set of reactions that take place in cells.

During the oxidation of sucrose, the chemical bonds within its molecular structure are broken. The carbon and hydrogen atoms in sucrose combine with oxygen, resulting in the formation of carbon dioxide (\(CO_2\)) and water (\(H_2O\)). These byproducts are then eliminated from the body through respiration and excretion.

In addition to the production of \(CO_2\) and \(H_2O\), the oxidation of sucrose is an exothermic reaction, meaning it releases heat. For every mole of sucrose oxidized, approximately 5.16 × 103 kilojoules of heat energy are released.

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Answer:

B

Explanation:

The warmer the water, the more space it takes up, and the lower its density.

Answer:

The density decreases

Explanation:

The colder the water the closer the particles move together making it denser. The hotter the water the more the particles slow down and move away from each other making the water less dense.

Answer:

Acidic

Explanation:

pOH = - log (9.8 x 10^-11)

pOH = 10

pOH + pH = 14

pH = 14-10

pH = 4

Anything below pH of 7 is acidic.

A single absorption band is not sufficient to distinguish between water vapor and carbon dioxide in the gas phase.

In the gas phase, both water vapor (H2O) and carbon dioxide (CO2) exhibit multiple absorption bands in the infrared region of the electromagnetic spectrum. Each molecule has its unique set of vibrational and rotational modes, which result in specific absorption frequencies. While there may be some overlap in the absorption bands of water vapor and carbon dioxide, their distinct molecular structures and vibrational characteristics lead to different absorption patterns.

To accurately differentiate between water vapor and carbon dioxide, multiple absorption bands need to be examined. Spectroscopic techniques such as infrared spectroscopy or laser absorption spectroscopy can be employed, where the absorption spectra of the gases are compared with known reference spectra or analyzed using computational methods. By examining the absorption peaks and their corresponding wavelengths, it becomes possible to identify the presence of water vapor or carbon dioxide and determine their respective concentrations.

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Answer:

the day where the daylight and night are equal in the Spring

Answer:

The recessive allele tends to be masked when it's in the presence of the dominant allele.

Explanation:

Many of our traits are affected by our genes. From each of our parents, we receive one copy of every gene. These copies are called alleles.

There are different types of relationships that can occur between alleles. One of them is called dominance. This occurs when one allele masks the other, not allowing its effect to be expressed. The allele that masks the other is called the dominant allele (A), and the masked one is called the recessive allele (a). This means that an individual needs to have only one dominant allele in order for its effect to be expressed (AA or Aa). The effect of the recessive allele will be expressed only when an individual has both recessive alleles (aa).

Answer: Earthquakes are usually caused when underground rock suddenly breaks and there is rapid motion along a fault. This sudden release of energy causes the seismic waves that make the ground shake.

Answer: This would cause an earthquake

Explanation:

Answer:

A. 2Fe + 3Cl2 --> 2FeCl3

B. 2Fe + 3O2 --> 2Fe2O3

C. C4H10O + 4O2 --> 4CO2 + 5H2O

D. C7H16 + 11O2 --> 7CO2 + 8H2O

Explanation:

Carbon shares four pairs of electrons to complete its valence shell (option C).

Based on the electron configuration, the carbon atom has 4 valence electrons or 4 electrons in its outermost shell. It is the presence of these valence electrons that play an important role in forming chemical bonds. Every atom is capable of forming a stable, including the carbon atom.

To achieve stability, this atom needs another 4 electrons by forming covalent bonds. Only the carbon atom is capable of forming 4 covalent bonds to reach the octet state.

The carbon atom (C ) has a unique characteristic with an atomic number of 6 electron configurations, namely the ability to form long C chains. Atom C has 4 valence electrons, which can be covalently bonded with similar atoms or other atoms.

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