4 Al(s) + 302(g)->2Al2O3(s)When 42.39 g of Al and 85.16 g of O2 were reacted, 6.67 grams of aluminum oxidewere obtained. What is the percent yield? (Hint: You need to determine which one isthe limiting reactant and then the theoretical yield).

Answer:

4 nitrogen, 2 oxygen, 2 nitrous oxide

Answer:

The pressure in mmHg is 59.

Explanation:

Given data:

Pressure of air inside balloon = 0.78 atm

Pressure in mmHg = ?

Solution:

mmHg:

mmHg is referred as manometric unit of pressure. It is define as the pressure exerted by mercury column at height of one millimeter.

Symbol:

"mmHg"

Atmosphere (atm)

atm is unit of pressure. It is used as a standard unit. It is equal to the 101325 Pa.

1 atm = 760 mmHg

Inorder to convert the atm into mmHg we will multiply the given atm value with 760.

0.78 atm × 760 mmHg / 1 atm = 592.8 mmHg

59 mmHg or 59

Answer:

The mass of NH₄OH  present in the solution is 8.085 g

Explanation:

Given;

molarity of NH₄OH = 6 M

density of NH₄OH = 0.960 g/mL

mass of NH₄OH  = 37.0 grams

volume of  NH₄OH = mass /density

                                = 37/0.96

                                = 38.54 mL

molarity = moles of solute / Liters of solution

moles of solute  = molarity  x Liters of solution

moles of solute  = 6 x  38.54 x 10⁻³

moles of solute  = 0.231 moles

Reacting mass = number of moles x molecular mass

Molecular mass of NH₄OH = 35 g/mol

Reacting mass = 0.231 mol x 35 g/mol

Reacting mass = 8.085 g

Therefore, the mass of NH₄OH  present in the solution is 8.085 g

We want to find the P2, given

V1 = 77 mL

V2 = 16 mL

T2 = 24 degrees celsius = 24 + 273 = 297 K

At standard conditions we know that temperature = 0 degrees celsius and pressure = 1 atm so:

T1 = o degrees celsius = 0 + 273 = 273 K

P1 = 1 atm

P2 = ?

To solve this problem, we will use the following equation:

P2 = (1 atm x 77 mL x 297 K)/(273 K x 16 mL)

P2 = 5.235576923 atm

Answer:

The metals are to the left of the line except for hydrogen because it is a  nonmetal

Explanation:

Answer:

d=m/

Explanation:

d is density, m is mass, v is volume

Given: m =10.4g, v=12.2mL

substituting in equation,

d=10.4/ 12.2

d=0.8524g/mL

To learn more about density:

The density of the liquid is 0.852 g/mL.

To calculate the density of the liquid, we need to use the formula:

Density = Mass / Volume

Given that the mass of the liquid is 10.4 g and the volume is 12.2 mL, we can substitute these values into the formula:

Density = 10.4 g / 12.2 mL

Simplifying this expression, we find:

Density = 0.852 g/mL

Density is a physical property of a substance and is defined as the amount of mass per unit volume. In this case, the density tells us that for every milliliter of the liquid, there is 0.852 grams of mass. The units of grams per milliliter (g/mL) indicate that the density is a ratio of mass to volume.It is important to note that the density of a substance can vary with temperature, so this value is only valid under the conditions at which the measurement was made. Additionally, the density can provide valuable information about the identity of a substance, as different substances have different densities.

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Answer:

n = 3.25 mol

Explanation:

Given data:

Pressure of sample = 2 atm

Volume of sample = 40 L

Temperature = 300 K

Number of moles = ?

Solution:

PV = nRT

R = general gas constant = 0.0821 atm.L/mol.K

2 atm ×40 L = n × 0.0821 atm.L/mol.K × 300 K

80 atm.L = n  × 24.63 atm.L/mol

n = 80 atm.L  /24.63 atm.L/mol

n = 3.25 mol

The mass of the asteroid is C. 1.2 x \(10^{12}\) Kg

To find the mass of the other asteroid, we can rearrange the equation for the gravitational force between two objects:

F = (G * m1 * m2) / \(r^{2}\)

where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two asteroids, and r is the distance between them.

Given that the distance between the asteroids is 75000 m, the force of gravity between them is 1.14 N, and one asteroid has a mass of 8 x \(10^{7}\) kg, we can substitute these values into the equation and solve for the mass of the other asteroid (m2):

1.14 N = (6.67430 × \(10^{-11}\) N \(m^{2}\)/\(Kg^{2}\) * 8 x \(10^{7}\) kg * \(m2\)) / \((75000 m)^{2}\)

Simplifying and solving the equation, we find that the mass of the other asteroid (m2) is approximately 1.2 x \(10^{12}\) kg. Therefore, Option C is correct.

The question was incomplete. find the full content below:

Two asteroids are 75000 m apart one has a mass of 8 x \(10^{7}\) kg if the force of gravity between them is 1.14 what is the mass of the asteroid

A. 3.4 x \(10^{11}\) kg

B. 8.3 x \(10^{12}\) kg

C. 1.2 x \(10^{12}\) kg

D. 1.2 x \(10^{10}\) kg

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Answer:

0.1

tenth

hundredth (0.01)

1.05 (can be anywhere from 1.00 to 1.10)

11.42 (can be anywhere from 11.40 to 11.50)

yes, it falls within reasonable doubt

The percentage composition by mass of the elements in the compound are:

Ai. The percentage composition by mass of Na in 3.65 g of NaF is 54.8%

Aii. The percentage composition by mass of F in 3.65 g of NaF is 45.2%

Bi. The percentage composition by mass of Zinc in the compound is 67.1%

Bii. The percentage composition by mass of Sulfur in the compound is 32.9%

Percentage composition by mass of an element in a compound can be obtained by using the following formula:\(Percentage = \frac{mass of Element}{mass of compound} * 100\)

Ai. Determination of the percentage of Na in 3.65 g of NaF

Mass of Na = 2 g

Mass of NaF = 3.65 g

\(Percentage = \frac{mass of element }{mass of compound} * 100\\\\Percentage of Na = \frac{2}{3.65} * 100\)

Aii. Determination of the percentage of F in 3.65 g of NaF

Mass of F = 1.65 g

Mass of NaF = 3.65 g

\(Percentage = \frac{mass of element }{mass of compound } * 100\\\\Percentage of F = \frac{1.65}{3.65} * 100\\\\\)

Bi. Determination of the percentage composition of Zn in 48.72 g of the compound

Mass of Zn = 32.69 g

Mass of compound = 48.72 g

\(Percentage = \frac{mass of element}{mass of compound} * 100\\\\Percentage of Zn = \frac{32.69}{48.72} *100\\\\\)

Bii. Determination of the percentage composition of Sulphur in 48.72 g of the compound

Mass of Zn = 32.69 g

Mass of compound = 48.72 g

Mass of S = 48.72 – 32.69 g

Mass of S = 16.03 g

\(Percentage = \frac{mass of element}{mass of compound} * 100\\\\Percentage of S = \frac{16.03}{48.72} * 100\\\\\)

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A semipermeable membrane is placed between the following solutions. Solution D will increase in volume.

What is volume?

Volume is a measure of the amount of space an object or substance occupies. It is most commonly measured in cubic units, such as cubic inches or cubic centimeters. Volume is a calculation of the 3-dimensional amount of space enclosed by an object or substance, and is typically found by calculating the area of one side of the object or substance and multiplying it by the object's height. Volume can be used to measure solid objects, liquids, and gases. It can also be used to measure the amount of material present in a space, such as the amount of water in a swimming pool or the amount of air in a room.

This is because the semipermeable membrane will allow the solvent (water) to move from the solution with a lower concentration of solutes (solution C) to the solution with a higher concentration of solutes (solution D), increasing the volume of solution D.

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If the [OH-] concentration is 5.9 x 10^(-M), the pOH of the solution is approximately -4.77 and the solution is basic.

To calculate the pOH of a solution, we can use the formula:

pOH = -log[OH-]

Given that the [OH-] concentration is 5.9 x 10^(-M), we can substitute this value into the formula:

pOH = -log(5.9 x 10^(-M))

Calculating this expression, we find:

pOH = -log(5.9 x 10^(-M))

pOH ≈ -log(5.9) + (-log(10^(-M)))

Since log(10^(-M)) is equal to -M, the equation simplifies to:

pOH ≈ -log(5.9) - M

Now, we need the value of M (the exponent) to calculate the exact pOH value. It appears that the value of M is missing in the given information. However, assuming M is a positive value, we can continue the calculation.

If we consider M = 6, for instance, the equation becomes:

pOH ≈ -log(5.9) - 6

Now, we can evaluate the expression:

pOH ≈ 1.23 - 6

pOH ≈ -4.77

Therefore, if the [OH-] concentration is 5.9 x 10^(-M), the pOH of the solution is approximately -4.77.

To determine whether the solution is acidic, basic, or neutral, we can use the relationship between pH and pOH. The sum of the pH and pOH of a solution at 25°C is always equal to 14.

Since pOH = -4.77, the pH would be:

pH = 14 - pOH

pH ≈ 14 - (-4.77)

pH ≈ 18.77

A solution with a pH above 7 is considered basic. In this case, the calculated pH is greater than 7. Therefore, the solution is basic.

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Answer:

A.) Change only the coefficients

Explanation:

An equation is balanced when there is an equal quantity of each type of element on both sides of a reaction. When balancing an equation, the only way to manipulate the amounts of each element is by changing the coefficient values. The coefficients alter the amount of each molecule in the reaction.

The subscripts cannot be altered. If you were to change the subscripts, you would be altering the amount of atoms in a particular molecule.

The best description of a type C tympanogram is Negative peak pressure, lower than normal compliance.

option C

A type C tympanogram indicates negative pressure in the middle ear, which means that the peak of the tympanogram is shifted to the negative pressure side of the graph.

In addition, the compliance, or the ability of the ear to move in response to sound, is lower than normal. This can be caused by conditions such as Eustachian tube dysfunction or blockage, middle ear effusion, or allergies.

Thus, the best description of a type C tympanogram is Negative peak pressure, lower than normal compliance.

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Answer:

Prueba con tus argumentos quienes sufren mas con la violencia?

Answer:

Sure! The complete balanced chemical equation for the reaction you provided is: `2A + BC3 -> AC2 + 3B`.

The calculated answer is 1.99 x 10/21 x Au

Gold has a molar mass of 196.96657 g/m. The mass of 1 mole of gold atoms, which is commonly given in grams, is referred to as the molar mass of gold.

Divide the specified mass by the molar mass of gold, which is 196.966569 g/mol, to determine the moles.

The term "atomic weight" refers to an atom's overall weight. With the addition of a small amount from the electrons, it is roughly equal to the sum of the protons and neutrons. The number of neutrons an atom has has a significant impact on the stability of the nucleus and, consequently, the radioactivity of the atom. The average mass of an element's atoms expressed in atomic mass units is known as its atomic mass (amu, also known as daltons, D). Gold has a molar mass of 196.96657 g/m. The mass of 1 mole of gold atoms, which is commonly given in grams, is referred to as the molar mass of gold.

Divide the specified mass by the molar mass of gold, which is 196.966569 g/mol, to determine the moles.

(Atomic weight in g/mol on the periodic table).

0.00330 mol = 0.650 g Au = 196.966569 gmol Au Gold atoms 1 mole of atoms is equal to 6.02210/23 atoms.

double the estimated mol Au by several.

6.022×10/23 atoms1mol.

0.00330mol Au = 6.022 x 10/23 x 1 mol

= 1.99 x 10/21 x Au

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Approximately 0.157 liters or 157 milliliters of the 4.50 M HCl solution can be made by mixing the given solutions.

To determine the volume of 4.50 M HCl that can be made by mixing the given solutions, we can use the concept of the concentration-volume relationship:

C1V1 = C2V2

Where:

C1 = concentration of the first solution

V1 = volume of the first solution

C2 = concentration of the second solution

V2 = volume of the second solution

Let's assign the variables as follows:

C1 = 5.65 M

V1 = unknown volume (we'll solve for this)

C2 = 3.55 M

V2 = 250.0 mL = 0.250 L (since the volume is given in milliliters)

Now we can plug in the values into the equation and solve for V1:

(5.65 M)(V1) = (3.55 M)(0.250 L)

Dividing both sides of the equation by 5.65 M:

V1 = (3.55 M)(0.250 L) / 5.65 M

V1 ≈ 0.157 L

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The number of faradays that passes through a resistance in a circuit carrying current of 5 A for 1hour is 0.187 Faraday.

The number of Faradays passing through an electrical circuit can be calculated using the following formula;

Q = It

Where:

According to this question, a circuit of electricity is carrying a current of 5A for 1 hour (3600s). The charge can be calculated as follows:

Q = 5 × 3600

Q = 18,000C

Since [1 F = 96500 C]

18,000C will be equivalent to 0.187 Faradays.

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Answer:

0.01 M

Explanation:

As this problem deals with a dilution process, we can solve it by using the following formula:

Where subscript 1 stands for the initial concentration and volume, while 2 stands for the final conditions.

That means that in this case:

We input the given data:

Answer:  The technique of comparing the abundance ratio of a radioactive isotope to a reference isotope to determine the age of a material

Explanation:

Answer:

The H—C—H bond angle in methane is the tetrahedral angle, 109.5°. This angle is obtained when all four pairs of outer electrons repel each other equally. The bond angles in ammonia and in water are less than 109.5° because of the stronger repulsion by their lone pairs of electrons.

Explanation:

hope it helps!

Cyclopropane of the following compounds would the carbon-carbon bond angle diverge the greatest from the ideal tetrahedral angle.

The cycloalkane or cyclopropane has the chemical formula (CH2)3, and cyclopropane is made up of three methylene groups that are joined together to create a ring. The structure experiences significant ring strain as a result of the ring's modest size.

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The complete question is:

In which of the following compounds would the carbon-carbon bond angle diverge the greatest from the ideal tetrahedral angle?

a. cyclodecane

b. cyclooctane

c. cyclopentane

d. cyclopropane

Answer:

the answer is: all living things are made up of cells(C)

The lone pairs on the oxygen in the following compound are best described as: one localized and one delocalized

A lone pair electron is valence shell electron pair associated with one atom, and not part of a covalent bond.

Within the context of this question, the oxygen atom of water for instance has two lone pair of which one of them is localized and other one is delocalized

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Explanation:

the electrostatic force is decreased by a factor of four (2 raised to the second power).