3/4 - 1/2 PLEASE HELP

Answer:

We have slope of EF : \(\mathbf{\frac{-4}{5}}\) and slope of GH: \(\mathbf{\frac{-4}{5}}\)

Both have same slope, so EF is parallel to GH i.e. EF || GH

Step-by-step explanation:

We need to find Is EF and GH parallel.

If EF and GH are parallel, they have same slopes.

So, we will find slopes of EF and GH

The formula used is: \(Slope=\frac{y_2-y_1}{x_2-x_1}\)

Slope of EF

We have: E(2,5) and F(7,1)

So, \(x_1=2, y_1=5, x_2=7, y_2=1\)

Putting values in formula and finding slope

\(Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{1-5}{7-2}\\Slope=\frac{-4}{5}\\\)

So, slope of EF is \(\mathbf{\frac{-4}{5}}\)

Slope of GH

We have: G(2,-3) and F(-3,5)

So, \(x_1=2, y_1=-3, x_2=-3, y_2=5\)

Putting values in formula and finding slope

\(Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{5-(-3)}{-8-2}\\Slope=\frac{5+3}{-10}\\Slope=\frac{8}{-10}\\Slope=\frac{-4}{5}\)

So, slope of GH is \(\mathbf{\frac{-4}{5}}\)

We have slope of EF : \(\mathbf{\frac{-4}{5}}\) and slope of GH: \(\mathbf{\frac{-4}{5}}\)

Both have same slope, so EF is parallel to GH i.e. EF || GH

Answer:

1. 2

2. 7

3. 17

4. 18

5. 83

6. 79

7. 7

8. 7

9. 19

10. 54

11. 26

12. 16

13. 9

14. 4

15. 3

16. 7

17. 5

18. 5

19. 30

20. 14

21. 20

22. 27

Step-by-step explanation:

Hope this helps!

The area of the part of the plane 2x+y+2z=4 in the first octant is S= \(\int_{0}^{2}\int_{0}^{-2x+4}\frac{3}{2}dydx\).

In the given question we have to check which of the following integrals represents the area of the part of the plane in the first octant.

The given plane is 2x+y+2z=4 that lies in the first octant.

In the first octant the all variables are positive.

First we need to find the equation of hypotenuse in the linethat intersects xy plane means z=0. So:

2x+y=4

y=4-2x

Now find the surface area. We need the function in the form of z=f(x,y). So:

2x+y+2z=4

2z=4-2x-y

z=(4-2x-y)/2

On taking the partial derivative we get

f(x) = -1 and f(y) = -1/2

Now the defining the limits will be;

0≤x≤2 and 0≤y≤ (-2x+4)

So the area will be;

S= \(\int \int _{D}\sqrt{f(x)^{2}+f(y)^{2}+1}dydx\)

S= \(\int_{0}^{2}\int_{0}^{-2x+4}\sqrt{(-1)^{2}+(-1/2)^{2}+1}dydx\)

S= \(\int_{0}^{2}\int_{0}^{-2x+4}\sqrt{1+1/4+1}dydx\)

S= \(\int_{0}^{2}\int_{0}^{-2x+4}\sqrt{(4+1+4)/4}dydx\)

S= \(\int_{0}^{2}\int_{0}^{-2x+4}\sqrt{9/4}dydx\)

S= \(\int_{0}^{2}\int_{0}^{-2x+4}\frac{3}{2}dydx\)

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It is given that:

1) f(g(x)) will be:

2)The domain will be all real numbers except x=-4.

3)g(f(x)) will be:

4) The domain of g(f(x)) is:

5) f(f(x)) is given by:

6)The domain of f(f(x)) is:

7) g(g(x)) is calculated as:

8)The domain of g(g(x)) is:

Answer:

586

Step-by-step explanation:

It would not be in decimal form because the number don't have a decimal so it would be a whole number

Answer: The answer is 586, so there is no decimal form

The profit function at each vertex are: P = 0.0128 at (8, 1)

P = 0.02016 at (3, 6)P = 0.0156 at (5, 10).

The given profit function is:

P = 0.04x * 0.05y * 0.06(16 – x – y)

The vertices of the triangle are (8, 1), (3, 6), and (5, 10).The profit function at each vertex are:

P = 0.04(8) * 0.05(1) * 0.06(16 – 8 – 1)P

= 0.0128P

= 0.04(3) * 0.05(6) * 0.06(16 – 3 – 6)P

= 0.02016P

= 0.04(5) * 0.05(10) * 0.06(16 – 5 – 10)P

= 0.0156

Hence, the profit function at each vertex are:

P = 0.0128 at (8, 1)

P = 0.02016 at (3, 6)

P = 0.0156 at (5, 10).

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The midsegment determines a smaller triangle that is similar to the larger triangle. If two triangles are similar, then their side lengths are at the same ratio, so that:

From this expression, you can determine the value of x:

-First. multiply both sides by 45:

-Second, divide both sides by 5 to determine the value of x:

The value of x is equal to 5

Answer:

D

Step-by-step explanation:

7/10 + 2/5 + 3/4

Convert to common denominator

14/20 + 8/20 + 15/20 = 37/20

Convert to mixed number

1 17/20

The standard matrix of a linear transformation T can be found by using the formula A = [T(e1) T(e2) ... T(en)], where A is the standard matrix, e1, e2, ..., en are the columns of the identity matrix, and T(e1), T(e2), ..., T(en) are the images of the identity matrix columns under the transformation T.

1. For the first transformation, the standard matrix of T can be found by using the formula A = [T(e1) T(e2)] = [(3,1,3,1) (-5,2,0,0)] = [[3 -5] [1 2] [3 0] [1 0]]. Therefore, the standard matrix of T is [[3 -5] [1 2] [3 0] [1 0]].

2. For the second transformation, the standard matrix of T can be found by using the formula A = [T(e1) T(e2) T(e3)] = [(1,3) (4,-7) (-5,4)] = [[1 4 -5] [3 -7 4]]. Therefore, the standard matrix of T is [[1 4 -5] [3 -7 4]].

3. For the third transformation, the standard matrix of T can be found by using the formula A = [T(e1) T(e2)] = [cos(31/2) -sin(31/2) sin(31/2) cos(31/2)], where cos(31/2) and sin(31/2) are the cosine and sine of 31/2 radians, respectively. Therefore, the standard matrix of T is [cos(31/2) -sin(31/2) sin(31/2) cos(31/2)].

4. For the fourth transformation, the standard matrix of T can be found by using the formula A = [T(e1) T(e2)] = [cos(-1/4) -sin(-1/4) sin(-1/4) cos(-1/4)], where cos(-1/4) and sin(-1/4) are the cosine and sine of -1/4 radians, respectively. Therefore, the standard matrix of T is [cos(-1/4) -sin(-1/4) sin(-1/4) cos(-1/4)].

5. For the fifth transformation, the standard matrix of T can be found by using the formula A = [T(e1) T(e2)] = [(1,0) (2,1)] = [[1 2] [0 1]]. Therefore, the standard matrix of T is [[1 2] [0 1]].

6. For the sixth transformation, the standard matrix of T can be found by using the formula A = [T(e1) T(e2)] = [(1,0) (3,1)] = [[1 3] [0 1]]. Therefore, the standard matrix of T is [[1 3] [0 1]].

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Answer:

Step-by-step explanation:

Options B, C and D will satisfy the given inequality by putting the values in the given inequality.

let's first try to understand what are inequalities.

An inequality in algebra is a mathematical statement that employs the inequality symbol to show how two expressions relate to one another. The phrases on either side of an inequality symbol are not equal. The phrase on the left should be larger or smaller than the expression on the right, or vice versa, according to this symbol. Relationships between two algebraic expressions that are represented by inequality symbols are referred to as literal inequalities.

If the symbols ">,"< ">=," "<=,"  are used to connect two real numbers or algebraic expressions, that relationship is referred to as an inequality.

We put Given values in inequality and then see whether inequality is true or not.

Inequality is 3x+y < = 6

first x = 4 y =3

3x+y <= 6

3*4 + 3 <= 6

15 <= 6 this is not true because 15 is greater than 6.

second x = -2 y =4

3x+y <= 6

3*-2 + 4 <= 6

-2 <= 6 this is true because -2 is less than 6.

third x = -5, y =-3

3x+y <= 6

3*-5 + -3 <= 6

-15 <= 6 this is true because -15 is less than 6.

fourth x = 3, y = -3

3x+y <= 6

3*3 - 3 <= 6

6 <= 6 this is true because 6 is equal to  6.

Given Question is incomplete Complete the Question here:

How do you determine ordered pairs are part of the solution set of inequalities ex: #3x+y<=6#

for A(4,3), B(-2,4), C(-5,-3), D(3,-3)?

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Step-by-step explanation:

using y=mx+c (equation of a line)

equation of one point form

y-y1=m(x-x1)

where y1=8,x1=6,m=1

y-8=1(x-6)

y-8=x-6

y=x-6+8

y=x+2

intercept form=2

or

y=mx+c where y=8,x=6,m=1

8=1(6)+c

8=6+c

8-6=c

2=c

or c=2

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Answer:

(- ∞,1]

Step-by-step explanation:

Answer: In the fraction 80/16, 80 is the numerator and 16 is the denominator. When you ask "What is 80/16 simplified?", we assume you want to know how to simplify the numerator and denominator to their smallest values, while still keeping the same value of the fraction. We do this by first finding the greatest common factor of 80 and 16, which is 16.

HOPE THIS HELPS

Answer:

\(\log\left(\dfrac{\sqrt{x}\:z^2}{4y^2}\right)\)

Step-by-step explanation:

\(\dfrac12\log(x)-2\log(2y)+2\log(z)\)

\(\textsf{Apply log power rule}: \quad n \log(x)=log(x)^n\)

\(\implies \log(x)^{\frac12}-\log(2y)^2+\log(z)^2\)

\(\textsf{Apply exponent rule}: \quad(ab)^c=a^cb^c\)

\(\implies \log(\sqrt{x})-\log(4y^2)+\log(z^2)\)

\(\textsf{Apply log quotient rule}: \quad \log(x)-\log(y)=log(\frac{x}{y})\)

\(\implies \log\left(\dfrac{\sqrt{x}}{4y^2}\right)+\log(z^2)\)

\(\textsf{Apply log product rule}: \quad \log(x)+\log(y)=log(xy)\)

\(\implies \log\left(\dfrac{\sqrt{x}\:z^2}{4y^2}\right)\)

The required information is (B), (C), (D), and (I).

So,

A. Who paid for the survey? It is not required.

B. Who made up the population from which the sample was drawn? Needed.

We need to know if the sample is representative of the "college students" population, on which we are basing our conclusions.

C. What sampling strategy was used? Needed.

We want to know if the sample was chosen at random.

D. How large was the sample size? Needed.

This information is required to determine the accuracy of the results.

E. What are the colleges represented in the sample?

It's not necessary if we already know "B."

F. How many survey questions were there? It is not required.

G. How many people participated in the survey? It is not required.

H. What were the questions? It is not required.

I. Is the language in the questions clear, accurate, unbiased, and valid? Needed.

We want to know if the answer was unbiased and clear so that we can determine if the conclusions are also unbiased.

J. What day of the week was the survey held? It is not required.

Therefore, the required information is B, C, D, and I.

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The correct question is given below:

A survey indicates that the vast majority of college students own their own personal computers. What information would you want to know before you accepted the results of this​ survey? Select all that apply. A. Who funded the​ survey? B. What was the population from which the sample was​ selected? C. What sampling design was​ used? D. What was the sample​ size? E. What are the names of the colleges included in the​ sample? F. How many questions were asked in the​ survey? G. How many people conducted the​ survey? H. What questions were​ asked? I. Were the questions​ clear, accurate,​ unbiased, and​ valid? J. On what day of the week was the survey​ conducted? g

Answer:

Step-by-step explanation:

To solve for x, isolate it on one side of the equation.

Use a distributive property.

a(b+c)=ab+ac

a(b-c)=ab-ac

2(x-14)

2*x=2x

2*14=28

=2x-28

-5x>2x-28

Subtract by 2x from both sides.

-5x-2x>2x-28-2x

Solve.

-7x>-28

Multiply by -1 from both sides.

\(\sf{\left(-7x\right)\left(-1\right) < \left(-28\right)\left(-1\right)}\)

Solve.

-7x*-1=7x

-28*-1=28

7x<28

Divide by 7 from both sides.

7x/7<28/7

Solve.

Divide these numbers from left to right.

28/7=4

\(\Rightarrow \boxed{\sf{x < 4}}\)

Therefore, the final answer is b. x<4.

I hope this helps, let me know if you have any questions.

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{-5x > 2(x-14) } \end{gathered}$}}\)

Use distributive property to multiply 2 by x−14.

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{-5x > 2x-28 } \end{gathered}$}}\)

Subtract 2x on both sides.

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{-5x-2x > -28 } \end{gathered}$}}\)

Combine −5x and −2x to get −7x.

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{-7x > -28 } \end{gathered}$}}\)

Divide both sides by −7. Since −7 is <0, the direction of inequality is changed.

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{x < \dfrac{-28}{-7} } \end{gathered}$}}\)

Divide −28 between −7 to get 4.

\(\boxed{\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{x < 4 } \end{gathered}$}}}\)

Answer:

A. you won't have enough

   1/8 x 6 = 6/8 of a teaspoon

   you have 2/3 teaspoon of black pepper set it equal and get a common denominator

6/8 = 2/3 --------------->  18/24 = 16/24 so you dont have enough

Using the combination, 1716 are 7 digit phone numbers in which the digits are non-increasing and every digit is less than or equal to the previous one.

In the given question,

We have to find how many 7 digit phone numbers are there in which the digits are non-increasing and that is, every digit is less than or equal to the previous one.

We have to write 7 digit phone number.

Let the 7 digit are

A, B, C, D, E, F, G

Every digit is less than or equal to the previous one.

A ≥ B ≥ C ≥ D ≥ E ≥ F ≥ G

The sum of these number is 7.

So |A| + |B| + |C| + |D| + |E| + |F| + |G| = 10

We always have precisely one non-increasing digit for any given set of seven digits. Therefore, the solution to our problem is to make it simpler to calculate the total number of combinations where 7 digits must be chosen from a set of 7 digits where each digit is repeatable.

So the solution should be

= \(^{7+7-1}C_{7}\)

= \(^{13}C_{7}\)

We know that \(^nC_{r}=\frac{n!}{r!(n-r)!}\)

= \(\frac{13!}{7!(13-7)!}\)

= \(\frac{13!}{7!6!}\)

Simplifying

= \(\frac{13\times12\times11\times10\times9\times8\times7!}{7!\times6\times5\times4\times3\times2\times1}\)

Simplifying

= 13×11×2×3×2

= 1716

Hence, 1716 are 7 digit phone numbers in which the digits are non-increasing and every digit is less than or equal to the previous one.

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Answer:

l = 40 m

Step-by-step explanation:

The formula for area of a rectangle is

A = lw, where

Step 1:  Since we're given the area and width, we plug in these two values for A and w and to solve for l (length):

360 = 9l

Step 2:  Divide both sides by 9 to solve for l

(360 = 9l) / 9

40 m = l

Optional Step 3:  We can check our answers by checking that the product of 40 and 9 is 360

40 * 9 = 360

360 = 360

Yes it is a function because there are not any repeating x values ( first number in each set of parentheses)

Answer:

78

Step-by-step explanation:

102+x=180

x=180-102

x=78

If f(x) = |x|, then g(x) is f(x) shifted to the right 3 units.

g(x) = |x - 3|

Hope this helps!

The maximum height of the ball is 2.437 meters.

What we have to change if the maximum height of the ball is more than 2.4 meters is the initial value of time.

We are given the quadratic function that represents the path of the ball kicked as; h(t) = -4.9t² + 6t + 0.6

Where;

t is the time in seconds and h is the height in meters above the ground.

This polynomial is a second degree polynomial that has a negative leading coefficient . Thus, this tells us that it is a downward parabola which gives the maximum value at vertex.

If the parabola is defined as;

f(x) = ax² + bx + c

Then the vertex of the parabola is;

(-b/2a, f(-b/2a))

x-coordinate of vertex = -6/(2 * - 4.9) = 0.612

y-coordinate of vertex = f(0.612) = 2.437

This tells us that the vertex is (0.612, 2.437) and the maximum height of the ball is 2.437 meters.

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Note that the proof that ΔABC ≅ ΔEDC is given as follows:

According to the ASA rule, if any two angles and sides included between the angles of one triangle are comparable to the corresponding two angles and sides included between the angles of the second triangle, the two triangles are said to be congruent.

Thus, given the above statements, it is clear that ΔABC ≅ ΔEDC

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Full Question:

Angle BAC is congruent to Angle DEC: Given

C is the midpoint of AE: Given

Prove triangle ABC is congruent to triangle EDC

What are the statements and reasons for this proof?

Answer:

Step-by-step explanation:

brain is 4 bradon is 8  billy 16 i do not know but that is my answer

Answer:

x = 2x = 2x+2

Step-by-step explanation:

Brian = x

Brandon = 2x

Billy = 2x+2

Answer:

It would be the first equation that has a higher initial start. (d = -50t + 70)

Step-by-step explanation:

This is because 70 is greater than 65. Assuming that the 65 is the distance, we can say that the first equation has a higher initial start, that of 70 miles from destination, while the second equation starts from 65 miles from destination.

The negative for the 50 and 60 is counting down the amount of miles until the destination is reached.

Answer:

√134

---------

4

Step-by-step explanation:

√3²-5÷8

√9-5÷8

√9-0.625

√8.375

√67 / 8

√67 / √8

√67 / 2√2

√67×√2 / 2√2×√2

√134 / 2×2

√134 / 4