3/(2x-1)+4=6x/(2x-1)
X=?

The top angle is right (90 degrees, kinda looks like a bent elbow).

The 2nd is acute (smaller than 90, kind of 'cute' bc it's small).

The 3rd is obtuse (greater than 90, I have nothing corny to say, sorry).

4th is acute.

5th is straight because it's a straight line.

6th is also obtuse.

Have a good day :)

The remainder of the polynomial division \(\frac{\left(y^4-y^3+2y^2+y-1\right)}{\left(y^3+1\right)}\) is 2y²

From the question, we have the following parameters that can be used in our computation:

\(\frac{\left(y^4-y^3+2y^2+y-1\right)}{\left(y^3+1\right)}\)

When the numerator is expanded, we have

\(\frac{\left(y^4-y^3+2y^2+y-1\right)}{\left(y^3+1\right)} = \frac{(y - 1)(y^3 + 1) + 2y^2}{y^3 + 1}\)

Split the expanded expression

\(\frac{\left(y^4-y^3+2y^2+y-1\right)}{\left(y^3+1\right)} = \frac{(y - 1)(y^3 + 1)}{y^3 + 1} + \frac{2y^2}{y^3 + 1}\)

Evaluate

\(\frac{\left(y^4-y^3+2y^2+y-1\right)}{\left(y^3+1\right)} = y - 1 + \frac{2y^2}{y^3 + 1}\)

From the above, we have

Quotient = y - 1

Remainder = 2y²

Hence, the remainder of the polynomial division is 2y²

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Answer:

coefficient

5

constant

-10

Step-by-step explanation:

5x-10

The coefficient is the number in front of the variable

5

The constant is the number alone

-10

Answer:

6 m

Step-by-step explanation:

The diagrammatic illustration of the problem. Is attached

The diaabcw between Aaron and Jessica can be obtained using Pythagoras :

d = √(10² - 8²)

d = √100 - 64

d = √36

d = 6

After considering the given data we conclude that the clockwise rotational path of the line segment is a rotation of -59.04 degrees about the point (-6, -1).

We have to evaluate the center and angle of rotation to explain the clockwise rotation of the line segment.

So in the first step, we can evaluate the midpoint of the line segment JK and the midpoint of the line segment J'K'. we can calculate the vector connecting the midpoint of JK to the midpoint of J'K'. This vector is (4-1, 1-(-4) = (3,5)

The center of rotation is the point that is equidistant from the midpoints of JK and J'K'. We can evaluate this point by finding the perpendicular bisector of the line segment connecting the midpoints.

The slope of this line is the negative reciprocal of the slope of the vector we just found, which is -3/5. We can apply the midpoint formula and the point-slope formula to evaluate the equation of the perpendicular bisector:

Midpoint of JK: (1, -4)

Midpoint of J'K': (4, 1)

The slope of the vector: 3/5

(x₁ + x₂)/2, (y₁ + y₂) /2

Point-slope formula: y - y₁ = m(x - x₁)

Perpendicular bisector: y - (-4) = (- 3/5)(x - 1)

Applying simplification , we get: y = (- 3/5)x - 1.2

To evaluate the center of rotation, we need to find the intersection point of the perpendicular bisector and the line passing through the midpoints of JK and J'K'. This line has slope ( 3 - (4)) /(4 - 1) = 7/3 and passes through the point (4, 1). Applying the point-slope formula, we can evaluate its equation:

y - 1 = (7/3)( x - 4)

Apply simplification , we get: y = (7/3)x - 17/3

To evaluate the intersection point, we can solve the system of equations:

y =(- 3/5)x - 1.2 = (7/3)x - 17/3

Evaluating for x and y, we get x = -6 and y = -1.

Therefore, the center of rotation is (-6, -1).

√( 4 - 1)² + ( 1 - ( - 4))²) = 5√(2)

Distance between image points and center of rotation

√( ( 6 - (-6))² + ( 3 - (-1))² = 13

The ratio of these distances gives us the scale factor of the transformation, which is 13/√2).

The angle of rotation is negative as the image moves clockwise direction. We can apply the inverse tangent function to find the angle of the vector connecting the midpoint of JK to the midpoint of J'K':

Angle of vector: arctan(5/3) = 59.04 degrees

Therefore, the clockwise rotational path of the line segment is a rotation of -59.04 degrees about the point (-6, -1).

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Answer:

24:
6 of 4
or

8 of 3

Step-by-step explanation:

6x4=24
8x3=24

Answer:

The solution

\(Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3 t}\)

Step-by-step explanation:

Explanation:-

Consider the initial value problem y′+3 y=9 t,y(0)=7

Step(i):-

Given differential problem

                           y′+3 y=9 t

Take the Laplace transform of both sides of the differential equation

                L( y′+3 y) = L(9 t)

 Using Formula Transform of derivatives

                L(y¹(t)) = s y⁻(s)-y(0)

   By using Laplace transform formula

              \(L(t) = \frac{1}{S^{2} }\)

Step(ii):-

Given

             L( y′(t)) + 3 L (y(t)) = 9 L( t)

            \(s y^{-} (s) - y(0) + 3y^{-}(s) = \frac{9}{s^{2} }\)

            \(s y^{-} (s) - 7 + 3y^{-}(s) = \frac{9}{s^{2} }\)

Taking common y⁻(s) and simplification, we get

             \(( s + 3)y^{-}(s) = \frac{9}{s^{2} }+7\)

             \(y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}\)

Step(iii):-

By using partial fractions , we get

\(\frac{9}{s^{2} (s+3} = \frac{A}{s} + \frac{B}{s^{2} } + \frac{C}{s+3}\)

  \(\frac{9}{s^{2} (s+3} = \frac{As(s+3)+B(s+3)+Cs^{2} }{s^{2} (s+3)}\)

 On simplification we get

  9 = A s(s+3) +B(s+3) +C(s²) ...(i)

 Put s =0 in equation(i)

   9 = B(0+3)

   B = 9/3 = 3

  Put s = -3 in equation(i)

  9 = C(-3)²

  C = 1

 Given Equation  9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Comparing 'S²' coefficient on both sides, we get

  9 = A s²+3 A s +B(s)+3 B +C(s²)

  0 = A + C

put C=1 , becomes A = -1

\(\frac{9}{s^{2} (s+3} = \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}\)

Step(iv):-

\(y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}\)

\(y^{-}(s) =9( \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}) + \frac{7}{s+3}\)

Applying inverse Laplace transform on both sides

\(L^{-1} (y^{-}(s) ) =L^{-1} (9( \frac{-1}{s}) + L^{-1} (\frac{3}{s^{2} }) + L^{-1} (\frac{1}{s+3}) )+ L^{-1} (\frac{7}{s+3})\)

By using inverse Laplace transform

\(L^{-1} (\frac{1}{s} ) =1\)

\(L^{-1} (\frac{1}{s^{2} } ) = \frac{t}{1!}\)

\(L^{-1} (\frac{1}{s+a} ) =e^{-at}\)

Final answer:-

Now the solution , we get

\(Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3t}\)

Answer:

2(15p+1)

Step-by-step explanation:

hope this helps

Answer: D.rotation 270 counterclockwise about the origin

Step-by-step explanation:

hello

the answer to the question is:

y = a cot(bx – c) + d

a = 1, b = 1/2, c = 0

the midline is y = d, so y = 0

the vertical stretch is 1, so label the y-axis so the inflection point of the curve is 1 above the midline, and the other inflection point is 1 below the midline

the period is:

T = π/b ----> T = 2π

the phase shift is:

PS = c/b ----> PS = 0

and also, there's no amplitude for tangent and cotangent, there is only the vertical stretch that takes the place of an amplitude

Answer:

amplitude does not exist. period = 2π (360°)

Step-by-step explanation:

there is no amplitude for tan θ or cot θ, since there is no limit up or down (positive/negative infinity).

period for cot θ is π (180°)

period for cot 1/2 θ is 2π (360°)

Answer:

its wrong answer and question

The required perimeter of the scale drawing is given as 18 inches.

Given that,
The rectangular floor of a classroom is 30 feet in length and 24 feet in width. A scale drawing of the floor has a length of 5 inches. The perimeter, in inches, of the floor in the scale drawing, is to be determined.

Perimeter is the measure of the figure on its circumference.

Here,
According to the question,

L = 30 feet, W = 24 feet,
for Scaled drawing
l = 5 inch, w = x
Now,
30/5 = 24 / x
6 = 24 / x
x = 24 {1/6}
x = 4,
So the width of the scale drawing is 4 inches,
perimeter of the scaled drawing  = 2[l + w]
                                                       = 2 [5 + 4] = 18 inches

Thus, the required perimeter of the scale drawing is given as 18 inches.

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Answer:

what do you need help with

Step-by-step explanation:

All have ax included so add the numbers together.

5ax + 8ax + 6ax = 19ax

The time Jack left Santa Clara is 1 : 55 pm

A word problem in math is a math question written as one sentence or more. These statements are interpreted into mathematical equation or expression.

The time for Jack to walk to lose Altos is 25 min and he uses another 25mins to work to Palo alto.

Therefore, the total time he spent is

25mins + 25 mins = 50 mins

He arrived Palo at 2 :45 pm, therefore the time he left Santa Clare will be ;

2:45 pm = 14 :45

= 14:45 - 50mins

= 13:55

= 1 : 55pm

Therefore he left at 1:55 pm

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Answer:

None of the choices are correct

Stefofp-by-step explanation:

Simplify the following:

(-6 x^3 y^4 + 9 x^8 y^2)/(3 x y)

Factor 3 x^3 y^2 out of -6 x^3 y^4 + 9 x^8 y^2:

(3 x^3 y^2 (-2 y^2 + 3 x^5))/(3 x y)

(3 x^3 y^2 (-2 y^2 + 3 x^5))/(3 x y) = 3/3×(x^3 y^2 (-2 y^2 + 3 x^5))/(x y) = (x^3 y^2 (-2 y^2 + 3 x^5))/(x y):

(x^3 y^2 (-2 y^2 + 3 x^5))/(x y)

Combine powers. (x^3 y^2 (-2 y^2 + 3 x^5))/(x y) = x^(3 - 1) y^(2 - 1) (-2 y^2 + 3 x^5):

x^(3 - 1) y^(2 - 1) (-2 y^2 + 3 x^5)

3 - 1 = 2:

x^2 y^(2 - 1) (-2 y^2 + 3 x^5)

2 - 1 = 1:

Answer:  x^2 y (-2 y^2 + 3 x^5)

Answer:

0.758

explaination

using poisson distribution

0.08208+0.2052+0.2565+0.2138

0 .758

Answer:

i think it’s 260 too^^

Step-by-step explanation:

The total Amount Spent by the volleyball team spend on shirts from the given piecewise function is; $260

From the given piecewise function, we see that;

y = {13n, 0 < n ≤ 20

y = {11n, 20 < n ≤ 50

y = {9n, n > 50

We are told that the volleyball team purchased 20 shirts.

From the first piecewise function, we can deduce that;

Amount Spent = 13n = 13 * 20

Amount Spent = $260

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Answer:

I believe the thirds length could be 17 cm

Step-by-step explanation:

Answer:

17

Step-by-step explanation:

8² + 15² = y²

64 + 225 = y²

y² = 289

√y² = √289

y = 17

Answer:

x=20

Step-by-step explanation:

120=6x

120/6=6x/6

20=x

The factorized form of \(x^3 - (y - z)^3\ is \ (x - y + z)(x^2 - xy + 2xz + yz - 2z^2).\)

The Factorization is derived from the application of a mathematical identity. As an AI language model, the information provided is generated based on existing knowledge and formulas.

The given expression is \(x^3 - (y - z)^3.\)To factorize it,  the difference of cubes, which states that a^3 - b^3 can be factorized as\((a - b)(a^2 + ab + b^2).\)

Applying this identity to our expression, we have:

\(x^3 - (y - z)^3 = (x - (y - z))((x - (y - z))^2 + (x - (y - z))(y - z) + (y - z)^2)\)

Simplifying further, we get:

\(= (x - y + z)(x^2 - 2xy + 2xz - y^2 + 2yz - z^2 + xy - y^2 + yz - z^2 + y^2 - 2yz + z^2)\\= (x - y + z)(x^2 - 2xy + xy + 2xz + yz - 2yz - y^2 + y^2 - y^2 + 2yz - 2z^2 + y^2 - z^2 + z^2)\\= (x - y + z)(x^2 - xy + 2xz + yz - 2z^2)\)

So, the factorized form of \(x^3 - (y - z)^3 \ is\ (x - y + z)(x^2 - xy + 2xz + yz - 2z^2).\)

the above factorization is derived from the application of a mathematical identity.

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Answer:

Step-by-step explanation:

1/2 , 2/3 , 5/6

There are 20 students who do not study any language.

To determine the number of students who do not study any language, we need to subtract the total number of students who study at least one language from the total number of students in the group.

Given the information provided, we can use the principle of inclusion-exclusion to calculate the number of students who study at least one language.

Using the inclusion-exclusion principle, we can calculate the number of students who study at least one language as follows:

Students studying at least one language = Students studying Spanish + Students studying German + Students studying French - Students studying Spanish and German - Students studying Spanish and French - Students studying German and French + Students studying all three languages

Substituting the given values from the question:

Students studying at least one language = 28 + 30 + 42 - 8 - 10 - 5 + 3

Students studying at least one language = 80

Now, we can calculate the number of students who do not study any language:

Students not studying any language = Total number of students - Students studying at least one language

Students not studying any language = 100 - 80

Students not studying any language = 20

20 students do not study any languages, as a result.

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Answer:

10

Step-by-step explanation:

Answer:

The answer is 10

Step-by-step explanation:

The volume of the container is approximately 12.9516 cubic meters when rounded to the nearest hundredth.

To find the volume of the container, we need to multiply its length, width, and height. Let's convert the given measurements to meters to ensure consistent units.

The length of the container is 2.76 meters.

The width of the container is 23.5 decimeters, which is equal to 2.35 meters (since 1 decimeter = 0.1 meters).

The height of the container is 196 centimeters, which is equal to 1.96 meters (since 1 meter = 100 centimeters).

Now we can calculate the volume of the container:

Volume = Length × Width × Height

Volume = 2.76 meters × 2.35 meters × 1.96 meters

Volume ≈ 12.9516 cubic meters (rounded to four decimal places)

Therefore, the volume of the container is approximately 12.9516 cubic meters when rounded to the nearest hundredth.

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Answer:

20

Step-by-step explanation:

Answer: h - 5

Step-by-step explanation:

h decreased by 5

h - 5

I'm sorry TnT I don't really know how to explain this but I'm 100% sure my answer is correct. Hope it helped!

Answer:

see explanation

Step-by-step explanation:

h is decreased by 5

5-h

The percentage improvement in reliability when test length is doubled is 15%

R(n) = 0.25n / (0.75 + 0.25n)

substitute n = 1 into the equation :

R(n) = 0.25n / (0.75 + 0.25n)

R(1) = 0.25(1) / (0.75 + 0.25(1))

R(1) = 0.25 / 1

R(1) = 0.25

when test length is doubled , n = 2

substitute n = 1 into the equation :

R(n) = 0.25n / (0.75 + 0.25n)

R(2) = 0.25(2) / (0.75 + 0.25(2))

R(2) = 0.5 / 1.25

R(2) = 0.4

Percentage improvement can be calculated thus ;

R(2)-R(1)/R(1) × 100%

(0.4-0.25)/0.25 × 100%

0.15 × 100%

=15%

Therefore, percentage improvement in reliability is 15%

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The distance between Basti and Cian is approximately 138.2 ft. Option D

To find the distance between Basti and Cian, we can use the Law of Sines, which relates the lengths of sides to the sines of their opposite angles in a triangle.

Let's label the points: A, B, and C. Ali is at point A, Basti is at point B, and Cian is at point C.

Given:

Angle ABC = 50 degrees (angle opposite side AC)

Angle BAC = 60 degrees (angle opposite side BC)

Ali is 150 ft away from Basti (side AB)

We want to find the distance between Basti and Cian, which is side BC.

Using the Law of Sines, we have:

BC/sin(50) = AB/sin(60)

Substituting the known values:

BC/sin(50) = 150/sin(60)

To find BC, we can rearrange the equation:

BC = (150/sin(60)) * sin(50)

Using a calculator to evaluate the expression:

BC ≈ 138.2 ft

Option D is correct.

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