3. Write an equation that would change the value of the 4 in 34 to 4 hundredths.

Answer:

z=1

Step-by-step explanation:

2.2(z+3)-1.93=6.87

2.2z+6.6-1.93=6.87

2.2z+4.67=6.87

       -4.67. -4.67

2.2z=2.2

/2.2. /2.2

z=1

Hopes this helps please mark brainliest

Answer:

z = 1

Step-by-step explanation:

2.2(z + 3) − 1.93 = 6.87

1. Distribute

2.2z + 6.6 - 1.93 = 6.87

2. Combine Like Terms

2.2z + 4.67 = 6.87

3. Subtract 4.67 on both sides

2.2z + 4.67 = 6.87

        - 4.67  - 4.67

2.2z = 2.2

4. Divide both sides by 2.2

\(\frac{2.2z}{2.2} = \frac{2.2}{2.2}\)

z = 1

The formula for the sum of a finite geometric series, when the common ratio is not equal to 1, is given by\(S = a(1 - r^n)/(1 - r)\), where S is the sum of the series, a is the first term, r is the common ratio, and n is the number of terms in the series.

To derive the formula for the sum of a finite geometric series, let's consider a series with a first term 'a' and a common ratio 'r'. The series can be represented as \(a + ar + ar^2 + ar^3 + ... + ar^(n-1)\), where n is the number of terms in the series.

Now, if we multiply the series by the common ratio 'r', we get\(ar + ar^2 + ar^3 + ... + ar^(n-1) + ar^n.\)

Subtracting the original series from this, we have: \((ar + ar^2 + ar^3 + ... + ar^(n-1) + ar^n) - (a + ar + ar^2 + ar^3 + ... + ar^(n-1)) = ar^n - a.\)

We can observe that most terms in the series cancel out, leaving only \(ar^n\) and -a. Now, if we factor out 'a' from the right side, we get: \(ar^n - a = a(r^n - 1).\)

Dividing both sides by (r - 1), we obtain the formula for the sum of the geometric series: S = \(a(1 - r^n)/(1 - r)\).

By using this formula, we can easily find the sum of a geometric series with a given first term, common ratio, and number of terms.

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Answer:

x-axis = (18, 0)

y-axis = (0, 12)

Quadrant I = (4.5, 10.6)

Quadrant II = (-15, 21)

Quadrant III = (-3/4, -4 1/9)

Quadrant IV = (3, -7)

Step-by-step explanation:

Hope this is helpful.

Answer:

It is B which in this case is 1 because "The fisherman plopped the giant sea bass onto the "scale" and smiled when he realized it was his biggest catch ever. So the only defintion that makes sense is B or 1.  

Step-by-step explanation:

Please can I have brainliest

To prove that (secθ+1)(secθ-1)=\tan²θ is an identity, we can start by expanding the left-hand side of the equation using the identity \sec²θ = 1 + \tan²θ.

Let's break down the steps:

1. Start with (secθ+1)(secθ-1).
2. Use the difference of squares formula to expand (secθ+1)(secθ-1) as sec²θ - 1².
3. Substitute sec²θ with 1 + \tan²θ using the identity \sec²θ = 1 + \tan²θ.
4. Simplify the expression to get (1 + \tan²θ) - 1.
5. Combine like terms by subtracting 1 from 1 + \tan²θ, which gives \tan²θ.

Therefore, we have shown that (secθ+1)(secθ-1)=\tan²θ is an identity.

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Answer:

D. Because even if you put the negative sign where the line separating the numerator and denominator the numerator is negative.

Answer:

if the graph of a proportional relationship passes through the point (1 , R) then r equals the slope and the unit rate , which is $4.75 per min

Step-by-step explanation:

The volume common to two spheres, each with radius r, if the distance between their centres is r/2 is V = (11/12)×π×r³.

The attached diagram shows 2 circumferences with radius r and separated centres by r/2.

Let´s call circumferences  1 and 2; by symmetry, rotating area A will produce a volume V₁ identical to a V₂, Obtained by rotating area B ( both around the x-axis), then the whole volume V will be:

V = 2× V₁

V₁ = ∫π×y²×dx         (1)

Now

( x - r/2)²  +  y² = r²       the equation of circumference 1

y² = r² - ( x - r/2)²

Plugging this value in equation (1)

V₁ = ∫π×[  r² - ( x - r/2)²]×dx        with integrations limits    0 ≤ x ≤ r/2

V₁ = π×∫ ( r² - x² + (r/2)² - r×x )×dx

V₁ = π× [  r²×x - x³/3 + (r/2)²×x - (1/2) × r × x²]    evaluate between 0 and r/2

V₁ = π× [(5/4)×r²×x - x³/3 - (1/2) × r × x²]

V₁ =  π× [(5/4)×r² × ( r/2 - 0 ) - (1/3)×(r/2)³ -  (1/2) × r × (r/2)²]

V₁ =  π× [ (5/8)×r³ - r³/24 - r³/8]

V₁ =  π× (11/24)×r³

Then

V = 2× V₁

V = 2×π×11/24)×r³

V = (11/12)×π×r³

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The derivative of the function f(x) = 390 by using the rules of differentiation is f'(x) = 0.

To find the derivative of the function f(x) = 390, we can apply the rules of differentiation.

In this case, the function f(x) = 390 is a constant function, which means it does not depend on the variable x. The derivative of a constant function is always zero.

Therefore, the derivative f'(x) of the function f(x) = 390 is:

f'(x) = 0

The derivative of a constant function is zero because a constant value does not change with respect to the variable x. So regardless of the value of x, the rate of change of the function is always zero.

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Answer:

Step-by-step explanation:

500

Answer:

9cm

Step-by-step explanation:

4.5+4.5=9

a) U is subspace of R^3.

b) The set {(3, -2, 0), (0, 1/2, 1)} is a basis for U.

c) 2.

a) To show that U is a subspace of R^3, we need to verify the following three conditions:

i) The zero vector (0, 0, 0) is in U.

ii) U is closed under addition.

iii) U is closed under scalar multiplication.

i) The zero vector is in U since 0 + 2(0) - 3(0) = 0.

ii) Let (x1, y1, z1) and (x2, y2, z2) be two vectors in U. Then we have:

x1 + 2y1 - 3z1 = 0 (by definition of U)

x2 + 2y2 - 3z2 = 0 (by definition of U)

Adding these two equations, we get:

(x1 + x2) + 2(y1 + y2) - 3(z1 + z2) = 0

which shows that the sum (x1 + x2, y1 + y2, z1 + z2) is also in U. Therefore, U is closed under addition.

iii) Let (x, y, z) be a vector in U, and let c be a scalar. Then we have:

x + 2y - 3z = 0 (by definition of U)

Multiplying both sides of this equation by c, we get:

cx + 2cy - 3cz = 0

which shows that the vector (cx, cy, cz) is also in U. Therefore, U is closed under scalar multiplication.

Since U satisfies all three conditions, it is a subspace of R^3.

b) To find a basis for U, we can start by setting z = t (where t is an arbitrary parameter), and then solving for x and y in terms of t. From the equation x + 2y - 3z = 0, we have:

x = 3z - 2y

y = (x - 3z)/2

Substituting z = t into these equations, we get:

x = 3t - 2y

y = (x - 3t)/2

Now, we can express any vector in U as a linear combination of two vectors of the form (3, -2, 0) and (0, 1/2, 1), since:

(x, y, z) = x(3, -2, 0) + y(0, 1/2, 1) = (3x, -2x + (1/2)y, y + z)

Therefore, the set {(3, -2, 0), (0, 1/2, 1)} is a basis for U.

c) Since the basis for U has two elements, the dimension of U is 2.

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The calculated area of the kite is 1340.1 square units

Given that

BE = 21

BC = 32

Start by calculating EC using pythagoras theorem

So, we have

EC^2 = 32^2 - 21^2

EC^2 = 583

So, we have

EC = 24.15

Calculate ED using

tan(35) = 24.15/ED

So, we have

ED = 24.15/tan(35)

Evaluate

ED = 34.49

The area of the kite is then calculated as

Area = BD * EC

So, we have

Area = (21 + 34.49) * 24.15

Evaluate

Area = 1340.1

Hence, the area is 1340.1

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The angular velocity of link CD when angle BAD = 60° is 21.16 rad/s.

The given values are:

AD = 150 mm

AB = 40 mm

CD = 80 mm

The crank AB rotates at 120 r.p.m. clockwise.

BC and AD are of equal length.

To find:

The angular velocity of link CD when angle BAD = 60°.

From the given data, we have to first find the value of angle BCD.

Angle BCD can be calculated as follows:

AB = 40 mm

BC = AD

= 150 mm

In ΔABC,

By using Cosine rule;

AC² = AB² + BC² - 2 × AB × BC × Cos ∠ABC∴ AC² = (40)² + (150)² - 2 × 40 × 150 × Cos 180°

∴ AC = 160.6 mm

In ΔBCD,

By using Cosine rule;

BD² = BC² + CD² - 2 × BC × CD × Cos ∠BCD

∴ BD² = (150)² + (80)² - 2 × 150 × 80 × Cos ∠BCD

In ΔABD,By using Cosine rule;

BD² = AB² + AD² - 2 × AB × AD × Cos ∠BAD

∴ BD² = (40)² + (150)² - 2 × 40 × 150 × Cos 60°

∴ BD = 184.06 mm

In ΔABD,By using Sine rule;

AB / Sin ∠BAD = BD / Sin ∠ABD

∴ Sin ∠ABD = BD × Sin ∠BAD / AB

∴ ∠ABD = Sin⁻¹ [BD × Sin ∠BAD / AB]

∴ ∠ABD = Sin⁻¹ [184.06 × Sin 60° / 40]

∴ ∠ABD = 87.2°∠ACD = ∠ABD - ∠ACB

∴ ∠ACD = 87.2° - 180°

∴ ∠ACD = - 92.8°∠BCD

= 180° - ∠ACD

∴ ∠BCD = 180° - (- 92.8°)

∴ ∠BCD = 272.8°

As we know that for four-bar mechanism, we have a formula for finding the angular velocity of link CD.

ωCD / Sin ∠BCD = ωAB / Sin ∠BADωCD / Sin 272.8°

= ωAB / Sin 60°

Substituting the values, ωCD / Sin 272.8° = ωAB / Sin 60°ωCD

= ωAB × Sin 272.8° / Sin 60°

But, ωAB = 2 × π × N / 60

= 2 × π × 120 / 60

= 4 × π rad/s

∴ ωCD = 4 × π × Sin 272.8° / Sin 60°ωCD

= 21.16 rad/s

Therefore, the angular velocity of link CD when angle BAD = 60° is 21.16 rad/s.

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Answer:

Step-by-step explanation:

-5 = n - 3

- 5 + 3 = n

-2 = n

--------------

check

-5 = -2 - 3

-5 = -5

the answer is good

Answer:

746.4

Step-by-step explanation:

The measure, x, which is of one of the base angles of the isosceles triangle in the question is 71°

The value of x is 71°

An isosceles triangle is a triangle that has congruent base angles

The description of the specified triangle mare as follows;

The length of the sides are;

21 and 21

Therefore;

The triangle is an isosceles triangle

The base angles of an isosceles triangle are congruent, therefore;

The measure of the  angle adjacent the angle x is also m∠x

Which indicates;

38° + x° + x° = 180° (Angle sum property of a triangle)

38° + 2·x°  = 180°

2·x° = 180° - 38° =  142°

x = 142° ÷ 2 = 71°

x = 71°

The measure of the angle x is 71°

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The  probability of event A is P(A) = 1/4 or 0.25.

The formula to find P(A) for a series of simple events is:

P(A) = (number of outcomes that satisfy the event A) / (total number of possible outcomes)

For example, if you are tossing a coin and selecting a number at the same time, and event A is defined as getting a head and an even number, then:

- The number of outcomes that satisfy event A is 1 (getting a head and an even number, i.e., H2)
- The total number of possible outcomes is 4 (H1, H2, T1, T2)
- Therefore, the probability of event A is P(A) = 1/4 or 0.25.

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Step-by-step explanation:

15+10z=105

10z=105-15

10z=90

z=9

Answer:

$92.5

Step-by-step explanation:

1,8500x.05=92.5

Answer:

1850 / 5% = 36000

Step-by-step explanation:

The measures of angles 4 and 5 are:

∠5 = 104°

∠4 =76°

On the image we can see that angles 1 and 2 are next to eachother, that means that the sum of their measures must be a plane angle, that is an angle of 180°.

Then we can write the sum:

∠1 + ∠2 = 180°

(3x + 5) + (2x + 10) = 180

5x + 15 = 180

5x = 180 - 15

x = 165/5 = 33

the measure of angle 5 is the same one of angle 1 then:

∠5 = (3*33 + 5)° = 104°

And angle 4 is supplementary of angle 1, then:

∠4 + 104° = 180°

∠4 = 180 - 104= 76°

These are the measures

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The equation to represent the total cost as a function of the number of packages delivered is C(p) = 12.50 + 0.25p.

The revenue as a function of the number of packages delivered. is R(p) = 4.25p

a. i. The equation to represent the total cost, C, as a function of the number, p, of packages delivered is C(p) = 12.50 + 0.25p

ii. The revenue, R, as a function of the number, p, of packages delivered. is R(p) = 4.25p

b. The algebraic model for the profit function P(p) = R(p) - C(p) = 4.25p - (12.50 + 0.25p) = 4.00p - 12.50

c. i. C(p) has domain of all non-negative integers (p ≥ 0) and range of all real numbers greater than or equal to $12.50 (C(p) ≥ $12.50)

ii. R(p) has domain of all non-negative integers (p ≥ 0) and range of all real numbers greater than or equal to $0 (R(p) ≥ $0)

iii. P(p) has domain of all non-negative integers (p ≥ 0) and range of all real numbers (P(p) can be any real number)

Note: The domain of p is limited to 27 in this case as the maximum packages that can be delivered is 27.

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The total length of craft wire used by Samantha is 10x + 9

What is the scale factor?

A scale factor is defined as the ratio between the scale of a given original object and a new object, which is its representation but of a different size (bigger or smaller).

Let's call the length of the smaller quadrilateral's 6-centimeter side "x".

Then the length of the corresponding side in the larger quadrilateral would be 6+3=9 centimeters, since the scale factor is 3.

To find the total length of craft wire used, we need to add up the lengths of all the sides in both quadrilaterals.

The smaller quadrilateral has four sides, each with a length of x.

The larger quadrilateral also has four sides, but only one of them has a different length (9 cm), while the other three sides are simply 3 times longer than the corresponding sides in the smaller quadrilateral.

So the total length of craft wire used by Samantha is:

4x + 9 + 3x + 3x + 3x

Simplifying this expression, we get:

10x + 9

Hence,  the total length of craft wire used by Samantha is:

10x + 9

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Answer:

Ah Here We Go Again :) After Five Years

Answer:

120

Step-by-step explanation:

3 feet in a yard

36÷3=12

12×10=120

Answer:

h = 440.94 feet

Step-by-step explanation:

It is given that,

An architect is standing 370 feet from the base of a building, x = 370 feet

The angle of elevation is 50°.

We need to find the approximate height of the building. let it is h. It can be calculated using trigonometry as follows :

\(\tan\theta=\dfrac{P}{B}\\\\\tan\theta=\dfrac{h}{x}\\\\h=x\tan\theta\\\\h=370\times \tan50\\\\h=440.94\ \text{feet}\)

So, the approximate height of the building is 440.94 feet

Answer:

37

Step-by-step explanation:

To find the average, you need to add all the numbers in the set and divide that value by the total amount of numbers there are,

We already know that the average of the set of temperatures is 40,

Since there are 5 different days with temperatures, multiply 40 by 5,

40 × 5

= 200

200 is what all the temperatures should equal once they are added up,

Now add 40, 39, 44, and 40 together,

40 + 39 + 44 + 40

= 163

Now subtract 163 from 200,

200 - 163

= 37

Therefore the temperature that was recorded on the fifth day was 37f.

Answer:

100x + 150y = 3050

x + y = 23

Step-by-step explanation:

the other answer had the right start and equations, and then did not give the result.

so, here the full picture :

x + y = 23

100x + 150y = 3050

so, the first equation gives us

x = -y + 23

which we can now use in the second equation

100(-y + 23) + 150y = 3050

-100y + 2300 + 150y = 3050

50y = 750

y = 15 (15 adults)

x = -y + 23 = -15 + 23 = 8 (8 minors)