Under normal circumstances, the reaction enthalpy for the reaction 2ch3oh (l) 3o2 => 2co2 (g) 4h2o is -1273 Kj/mol. The internal energy of a system determines its enthalpy.
along with the sum of its pressure and volume. For processes with constant pressure, the change in enthalpy equals the heat received or emitted. In the International System of Units (SI), the joule serves as the unit of measurement for enthalpy. Many chemical, biological, and physical measurements at constant pressure employ the preferred expression of system energy change, change in enthalpy (H), since it makes the description of energy transfer easier. H = U + pV is the formula for the enthalpy. H stands for the system's enthalpy. U is the system's internal energy.
enthalpy of a reaction = 4*(-241.181464) + 2(−393.5052)+3*(0) +(2*-239.03192)
enthalpy of a reaction = -1273 Kj/mol
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How would I balance this?
The balance chemical reaction is as below:
4Fe (s) + 3O₂ (g) ⇒ 2Fe₂O₃ (s)
What is balance chemical reaction ?The term balanced chemical equation is defined when the number of the atoms involved in the reactants side is exactly equal to the number of atoms in the products side.
The most important thing about balancing chemical equations is to satisfy the law of conservation of mass, This states that “the total mass of the products is exactly equal to the total mass of all the reactants”
Thus, The balance chemical reaction is as below:
4Fe (s) + 3O₂ (g) ⇒ 2Fe₂O₃ (s)
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The solubility of KNO3 is 32g/100g of water at 20oC and 62g/100g of water at 40oC. What will you observe if a saturated solution of KNO3 at 400C is cooled to 20oC.
Answer:
Explanation:
Solubility of KNO₃ at 20° C = 32 g / 100g of water
that means , per 100 g of water maximum of 32 g of KNO₃ can be dissolved at 20° C .
Solubility of KNO₃ at 40° C = 62 g / 100g of water
that means , per 100 g of water maximum of 62 g of KNO₃ can be dissolved
40° C.
So when a saturated solution in which maximum KNO₃ has been dissolved is cooled from 40° C to 20° C , due to decrease in solubility at lower temperature some KNO₃ will come out of the solution . Per 100 gram of saturated solution , 62 - 32 = 30 g of KNO₃ will precipitate out or come out of water . They can be filtered out .
Which explanations did you include in your response? Check all that apply. The oxidation number of carbon changes from -1 to +4. The oxidation number of oxygen changes from 0 to -2. Carbon is oxidized. Oxygen is reduced. Electrons are transferred from carbon to oxygen.
Answer:
B, E
Explanation:
Edge
Which of the following statements concerning mixtures is correct?
a. The composition of a homogeneous mixture cannot vary.
b. A homogeneous mixture can have components present in two physical states.
c. A heterogeneous mixture containing only one phase is an impossibility
d. More than one correct response..
The correct option from the given statements concerning mixtures is (d) more than one correct response.
The statement (a) "The composition of a homogeneous mixture cannot vary" is incorrect as the composition of a homogeneous mixture can vary. For example, a mixture of salt and water is homogeneous and its composition can vary depending on the amount of salt and water mixed in it.
The statement (b) "A homogeneous mixture can have components present in two physical states" is correct. Homogeneous mixtures are mixtures that are uniform throughout their composition, meaning that there is no visible difference between the components of the mixture. For example, a mixture of ethanol and water is homogeneous and its components are present in two physical states (liquid and liquid).
The statement (c) "A heterogeneous mixture containing only one phase is an impossibility" is incorrect. A heterogeneous mixture is a mixture where the components are not evenly distributed and the mixture has different visible regions or phases. However, it is possible for a heterogeneous mixture to contain only one phase. For example, a mixture of oil and water is heterogeneous but can have only one phase.
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Calculate the normal boiling point of chloroform given that the standard enthalpy of vaporization of chloroform is 31. 4 kj/mol and the standard entropy of chloroform is 93. 7 j/mol·k.
Chloroform's normal boiling point is 335 K given that the standard enthalpy of vaporization of chloroform is 31. 4 kj/mol and the standard entropy of chloroform is 93. 7 j/mol·k.
What function does chloroform serve?
A chemical known as a solvent, or one that facilitates the dissolving of other substances, is formaldehyde. Along with being used in the building, paper, and board industries, it is also used in the production of insecticides and films.
Given, 31.4 kJ/mol is the vaporisation enthalpy.
The standard entropy is 93. 7 j/mol k.
At equilibrium (when the liquid is boiling), according to the Gibbs free energy equation,
G = H - T (S), therefore
T (S) = H
S = H / T
93.8 = (31400 J/mol.) / T
T = 334.7 = 335K.
Chloroform has a 335K boiling point as a result.
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Of the following, which are not polyprotic acids?
hi
hno3
hcl
h2so4
Answer:
HI
H2SO4
Explanation:
H2SO4-diprotic acid
You check the air pressure in your car tires on Monday morning and the pressure
reads 765 mmHg. A cold front drops the temperature considerably overnight. You
check your tire pressure Tuesday morning and the pressure reads 740 mmHg.
Using what you've learned about the properties of gases, what causes this change
in pressure?
Calculate the number of hydrogen atoms in180 grams of glucose
Answer:
Explanation:
Calculating the number of hydrogen atoms in 180 grams of glucose involves using the molecular formula of glucose (C6H12O6) and the Avogadro constant (6.022 x 10^23).
First, calculate the molar mass of glucose by adding the atomic masses of its elements:
C6H12O6 = (6 x 12.01) + (12 x 1.01) + (6 x 16.00) = 180.18 g/mol
Next, use the molar mass to find the number of moles of glucose in 180 grams:
180 g / 180.18 g/mol = 0.999 moles
Finally, multiply the number of moles by Avogadro's constant to find the number of hydrogen atoms:
0.999 mol x 6.022 x 10^23 atoms/mol = 6.02 x 10^23 hydrogen atoms
Premium brands positioned at the high end of the market use the positioning approach in which ______.
Premium brands positioned at the high end of the market usually use the price-quality-based approach to positioning.
By essentially charging more for a commodity, the price-quality-based positioning strategy aims to give buyers the impression that the product is of higher quality than the competition.
Actually, it's a strategy that is highly effective in today's modern world as we often come across brands in all sectors whose pricing is way higher when compared to their fellow competitors. These brands create a placebo in the minds of the consumer that the product they offer is of the best possible quality that can exist in the market and due to which people purchase it.
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how many moles are 2.54 x 10^29 molecues of H2O
Answer:
\(\boxed {\boxed {\sf 421,786.7818 \ mol \ H_2O}}\)
Explanation:
We are asked to convert from molecules of water to moles.
1. Avogadro's Number1 mole of any substance contains the same number of particles (atoms, molecules, formula units, etc). This is Avogadro's Number: 6.022*10²³. In this problem, the particles are molecules of water.
2. Convert Molecules to MolesUse Avogadro's Number to make a ratio.
\(\frac {6.022 *10^{23} \ molecules \ H_2O}{1 \ mol \ H_2O}\)
Multiply by the number of molecules given: 2.54 *10²⁹
\(2.54 *10^{29} \ molecules \ H_2O \times \frac {6.022 *10^{23} \ molecules \ H_2O}{1 \ mol \ H_2O}\)
Flip the ratio so the units of molecules of water cancel.
\(2.54 *10^{29} \ molecules \ H_2O \times \frac {1 \ mol \ H_2O}{6.022 *10^{23} \ molecules \ H_2O}\)
\(2.54 *10^{29} \times \frac {1 \ mol \ H_2O}{6.022 *10^{23} }\)
Condense the problem into 1 fraction.
\(\frac {2.54 *10^{29} }{6.022 *10^{23} }\ mol \ H_2O\)
\(421786.7818 \ mol \ H_2O\)
2.54 *10²⁹ molecules of water are 421, 786.7818 moles of water.
What pillar of sustainability is broken by recycling
electronics in India? Should the US make a law that electronics can
only be recycled in the US?
The pillar of sustainability broken by recycling electronics in India is environmental sustainability. Implementing a law that restricts electronics recycling to the US would not necessarily be the most effective solution, as it overlooks the complex global dynamics of electronic waste management.
Recycling electronics in India often involves improper disposal methods, such as burning or dismantling without proper safety measures. This leads to environmental pollution, including the release of hazardous substances into the air, soil, and water, thus violating the principle of environmental sustainability.
However, simply mandating that electronics can only be recycled in the US may not be the most optimal solution. Electronic waste is a global issue, and restricting recycling to a single country disregards the fact that electronic products are manufactured and consumed worldwide. A more comprehensive approach to addressing electronic waste would involve international cooperation, strict regulations, and monitoring of recycling practices to ensure they meet environmental standards.
Efforts should focus on improving recycling practices globally, including promoting responsible electronic waste management, developing sustainable recycling infrastructure in multiple countries, and encouraging the adoption of safe and environmentally friendly recycling practices. This approach would foster global sustainability and address the challenges associated with electronic waste disposal more effectively than a geographically limited restriction.
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Convert 48 g O2 to moles of O2
Answer:
1.5 moles
Explanation:
O mole weight = 15.999
O2 mole weight = 2 * 15.999 = 31.998 gm
48 / 31. 998 = ~ 1.5 moles
The optimum temperature for sucrase activity is 37 °C. The hydrolysis of sucrose is slowest at which temperature in the choices below? a) 45 °C b) 20 °C c) 25 °C d) 10 °C e) 0 °C
The optimum temperature for sucrase activity is 37 °C. The hydrolysis of sucrose is slowest at 0 °C.
The optimum temperature for sucrase activity is 37 °C, which means that the enzyme functions most efficiently at this temperature. As the temperature deviates from the optimum, the enzyme activity decreases. Therefore, the hydrolysis of sucrose would be slowest at a temperature that is significantly lower or higher than 37 °C.
Among the given choices, the temperature that is significantly lower than 37 °C is 0 °C (choice e). Enzyme activity is typically greatly reduced or completely halted at very low temperatures, as the enzyme molecules become less active or may even denature. Therefore, the hydrolysis of sucrose would be slowest at 0 °C.
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Identify the product(s) in the following reaction:
Zn+2HCl → ZnCl₂ + H₂
Answer:
ZnCl2 + H2
Zinc (II) Chloride + Hydrogen gas
The interstitial fluid is generally poor, while the plasma is generally rich in ---------. A. Protein B. Sodium and chloride ions C. Hydrogen ions D. Carbohydrates
Answer:
B Hydrogen Ions is answer
Prepare 1.0 l of 0.1 m citrate buffer, ph = 4.95, from crystalline citric acid (fw = 210) and 1.0 m naoh.
To make 1 L of citrate buffer (pH 3.0 to 6.2), follow these instructions
A. 800 mL of distilled water should be ready in a convenient container.
B. Add the solution with 25.703 g of sodium citrate dihydrate.
C. Add 2.421 g of citric acid in the mixture.
D. Use HCl or NaOH to adjust the solution's pH to the appropriate level.
E. Add distilled water until there is 1 L in the container.
What is a buffer?
Buffer solution refers to a solution whose pH is not significantly changed by the addition of modest amounts of either an acid or a basic. The solution of reserve acidity or alkalinity that resists pH change upon the addition of a modest amount of acid or alkali is known as a buffer.
Use these directions to create 1 L of citrate buffer (pH 3.0 to 6.2).
A handy container with 800 mL of distilled water should be prepared.
B. Include the sodium citrate dihydrate solution, which contains 25.703 g.
C. Include the mixture with 2.421 g of citric acid.
D. To bring the pH of the solution to the proper range, use HCl or NaOH.
E. Fill the container with distilled water until it measures 1 L.
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In the Lewis dot structure for H2CCH2, how many bonds are between the carbon atoms?
3
4
1
2
Answer:
2
Explanation:
The compound H2CCH2 has the condensed formula C2H4. The name of the compound is ethene. The compound is unsaturated, that is, it contains multiple bonds. The compound has a formula which fits into the general molecular formulae of alkenes (olefins) which his CnH2n.
Olefins have a double bonds between the carbon atoms. That is , the two carbon atoms in Olefins are connected via a double covalent bond. This now implies that the two carbon atoms in ethene (C2H4) are connected by two covalent bonds in the lewis structure of the molecule as is common for Olefins.
In the Lewis dot structure for \(\rm H_2CCH_2\), there is one covalent bond present between the carbon atoms. The correct answer is option c.
A dot structure is a method of depicting an atom's valence electrons by placing dots around the atomic symbol. One valence electron is represented by each dot.
In the Lewis dot structure of \(\rm H_2CCH_2\), there is one bond between the carbon atoms. This is because each carbon atom has two electrons in its valence shell, and each hydrogen atom has one electron in its valence shell.
The two carbon atoms share two electrons to form one covalent bond, and each carbon atom also shares one electron with a hydrogen atom to form two additional covalent bonds.
Therefore, the correct answer is option c. There is one bond (covalent bond) between the carbon atoms in the Lewis dot structure for \(\rm H_2CCH_2\).
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a sample of gas weighs 3.33 g and occupies a volume of 1.365 l at 95 °c and 790 torr. identify the gas sample.A. Cl₂ (molar mass-70.90 g/mol)B. NH (molar mass- 17.03 g/mol)C. N₂0 molar mass-44.02 g/mol)D. CHC, (molar mass-119.4 g/mol)E. SO₂ (molar mass - 64.07 g/mol)
The sample of gas that will be in the container is CL2(chlorine)(molar mass= 70.90g/mol).
what is the ideal gas law?The phrase "ideal gas" refers to a fictitious gas made up of molecules that abide by a few guidelines: Perfect gas particles do not contact or repel one another. The sole interaction between molecules of an ideal gas would be an elasticity collision when they collided or an elasticity collision with the container walls.
Briefing:
By ideal gas law, PV=nRT,
where p= pressure of the gas
V= volume occupied by the gas,
R= gas constant
T= temperature of the gas
n= no.of moles of gas
given, the mass of gas=3.33 g
the volume of gas= 1.365ltr
temp of gas= 95 c = 95+273.15 =368.15 k
pressure= 790 torr= 790/760= 1.03 atm
R= 0.0820 l atm k^-1 mol ^-1
n=PV/RT
by solving, n=0.04699
MOLAR MASS= GIVEN MASS/n
so, the molar mass will come out to 70.90 g/ mol
so gas will CI2.
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when the volume of a gas is changed from 3.6 L to 15.5 L, the temperature will change from ___°C to 87°C.
Answer:
- 387.39 oC
See below for degrees Kelvin
Explanation:
Change the 87oC to degrees Kelvin.
87 + 273 = 360
V1 = 3.6 L
V2 = 15.5 L
T1 = ?
T2 = 360
V1/T1 = V2/T2
3.6 / T1 = 15.5 / 360 Cross multiply
3.6 * 360 = 15.5 * T1
1296= 15.5 * T1 Divide by 15.5
1296/15.5 = T1
T1 = 83.61 The answer is in oKelvin
t1 = 83.62 - 273 = -387 oC
2. As NH4OH is added to an HCl solution, the pH of the solution
A) increases as the OH- concentration decreases
B ) increases as the OH- concentration increases
C ) decreases as the OH- concentration decreases
D ) decreases as the OH- ion concentration increases
Answer:
c
Explanation:
Nh4OH + HCL ---> NH4Cl + H3O
so ph decreases as H3O increases
and OH also decreases
When NH4OH is added to a solution with HCI, the pH of the solution B ) increases as the OH- concentration increases.
Why would the solution increase?NH₄OH is a strong base as a result of the presence of the OH compound which is a base as well. Bases have high pH and acids have low pH.
This means that as the OH- concentration increases, the solution is being made to be more basic which would lead to the pH rising.
In conclusion, option B is correct.
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The reaction below is at equilibrium. What would happen if more carbon were
added?
C(s) + O₂(g) CO₂(g)
Explanation:
\(C_{(s)} + O_{2(g)} \rightleftharpoons CO_{2(g)}\)
According to le ch-atelier's principle when a chemical reaction at equilibrium subjected to any stress, then the equilibrium shifts in that direction in which effect of stress is reduced.
When we would add more number of carbon in above reaction then rate of forward reaction will increase to attain the equilibrium again.
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An allylic carbocation is an example of a(n) _____ system. (select all that apply.)
An allylic carbocation is an example of a system that is:
delocalizedconjugated.What is allylic carbocation?An allylic carbocation is a resonance-stabilized carbocation with a formal charge of +1 on an allylic carbon in each of the two resonance forms.
Thus, it is correct to state that:
An allylic carbocation is an example of a system that is:
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Full Question:
An allylic carbocation is an example of a(n) _______ system. (Select all that apply.)
- localized
- isolated
- delocalized
- conjugated
Ge
Express your answer in complete form in the order of orbital as a string without blank space between orbitals.
The complete string representing the order of orbital filling without blank spaces is: \(1s^22s^22p^63s^23p^64s^23d^1{0}4p^65s^24d^105p^66s^24f^145d^{10}6p^67s^25f^146d^{10}7p^6\)
To express the order of orbital filling as a string without blank spaces, we follow the Aufbau principle, which states that electrons fill orbitals starting from the lowest energy level and move upward. The order of orbital filling is as follows:\(1s^22s^22p^63s^23p^64s^23d^1{0}4p^65s^24d^105p^66s^24f^145d^{10}6p^67s^25f^146d^{10}7p^6\)
Let's break it down step by step:
1s^2: The 1s orbital can hold up to 2 electrons.
2s^2: The 2s orbital can also hold up to 2 electrons.
2p^6: The 2p orbitals can hold up to 6 electrons.
3s^2: The 3s orbital can hold up to 2 electrons.
3p^6: The 3p orbitals can hold up to 6 electrons.
4s^2: The 4s orbital can hold up to 2 electrons.
3d^10: The 3d orbitals can hold up to 10 electrons.
4p^6: The 4p orbitals can hold up to 6 electrons.
5s^2: The 5s orbital can hold up to 2 electrons.
4d^10: The 4d orbitals can hold up to 10 electrons.
5p^6: The 5p orbitals can hold up to 6 electrons.
6s^2: The 6s orbital can hold up to 2 electrons.4f^14:
The 4f orbitals can hold up to 14 electrons.
5d^10: The 5d orbitals can hold up to 10 electrons.
6p^6: The 6p orbitals can hold up to 6 electrons.
7s^2: The 7s orbital can hold up to 2 electrons.
5f^14: The 5f orbitals can hold up to 14 electrons.
6d^10: The 6d orbitals can hold up to 10 electrons.
7p^6: The 7p orbitals can hold up to 6 electrons.
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a wet gas well is out of methane. what does it contain that will likely still be of value? a wet gas well is out of methane. what does it contain that will likely still be of value? propane polyethylene polystyrene polypropylene
A wet gas well that is out of methane may still contain other valuable components such as propane. Option A is correct.
Propane is a hydrocarbon gas that is commonly used as a fuel for heating and cooking, and as a feedstock for the production of petrochemicals.
Polyethylene, polystyrene, and polypropylene, on the other hand, are not typically found in natural gas wells. These are thermoplastic polymers that are produced through chemical processes using feedstocks derived from crude oil or natural gas.
Therefore, if a wet gas well is out of methane, it is more likely that the remaining valuable components would be other hydrocarbons such as propane, butane, or natural gas liquids (NGLs) rather than polymer materials like polyethylene, polystyrene, or polypropylene.
Hence, A. is the correct option.
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--The given question is incomplete, the complete question is
"A wet gas well is out of methane. what does it contain that will likely still be of value? A) propane B) polyethylene C) polystyrene D) polypropylene."--
Logan demonstrates to the class how mass must be conserved in every chemical reaction.
He measures the mass of hydrochloric acid and a magnesium strip separately. He then places the magnesium strip into the acid and bubbles form as the magnesium
seems to disappear. The combined mass afterward is less than the original.
Hydrochloric Acid + Magnesium
How could Logan explain this lower mass?
Answer:
Logan could explain the lower mass by explaining that the reaction between hydrochloric acid and magnesium produces hydrogen gas, which escapes and therefore is not included in the final combined mass measurement. The reaction is:HCl + Mg → MgCl2 + H2Since the hydrogen gas has mass, its escape from the reaction vessel explains the decrease in the combined mass of the reactants after the reaction.
Which object is at the center of the solar system in the heliocentric model?
A. The asteroid belt
B. The Sun
C. Earth
D. The Moon
In the heliocentric model, the object at the center of the solar system is the Sun. Therefore, the answer is B.
What is the heliocentric model?
The heliocentric model is a theory that places the Sun at the center of the solar system, with all the planets orbiting around it. This model was first proposed by the ancient Greek astronomer Aristarchus of Samos in the 3rd century BCE, but it was not widely accepted until the 16th century when the Polish astronomer Nicolaus Copernicus presented a detailed mathematical description of the heliocentric model.
The heliocentric model provided a more accurate description of the solar system, and it was later confirmed by the observations and calculations of other astronomers such as Johannes Kepler and Galileo Galilei. The heliocentric model is now widely accepted, and it forms the basis of modern astronomy.
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The complete question is: The Sun is at the center of the solar system in the heliocentric model.
How many calories (units of heat energy) per serving is an 18 pound deep fried turkey?
Answer:
245
Explanation:
BECAUSE THERE ENERGY THEY GIVES THE IMPRESSION OF THE TURKISH
1)
Create a new species of a plant and an animal that is well-suited
for living in the tundra ecosystem. Make a drawing of each, then
list and describe three characteristics that help each organism
thrive in its environment. Don't forget to name your plant and
animali
An organism that is well-suited for living in the tundra ecosystem should ideally be adapted to cold conditions. These organisms should take advantage of the growing season and survive in low humidity conditions.
What is a tundra ecosystem?Tundra is a special type of ecosystem characterized by low temperatures, a short growing season, and low humidity.
In consequence, any organism (either plant or animal) living in a tundra should exhibit adaptation to these climate conditions.
For example, plants in the tundra are able (i.e., they are adapted) to perform photosynthesis in extremely cold temperature conditions.
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1. At Time 1, a cool air mass is moving from Location 1 toward a stationary warm air mass at Location 2. After the cool air mass collides with the warm air mass at Time 2, clouds begin to appear over Location 2. The partial model below shows the two air masses at Time 1, but does not show their interaction at Time 2.
The warm and the cool air masses affects the formation of clouds and precipitation.
Does warm and cool air masses affect cloud formation?Warm and cool air masses can affect cloud formation. Clouds are formed when water vapor in the atmosphere rises and cools, condensing into tiny water droplets or ice crystals. The type and amount of clouds that form can be influenced by the temperature and moisture content of the air masses.
In general, the interaction between warm and cool air masses can result in cloud formation and precipitation.
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Decane (C10H22) is used in diesel. The combustion for decane follows the equation: 2 C10H22 + 31 O2 à 20 CO2 + 22 H2O. Calculate the amount, in grams, of water (H2O) produced by the combustion of 568 grams of decane (C10H22) with 2976 grams of oxygen gas (O2). 692 792 892 992
The mass of water produced is 792 grams by the combustion of 568 grams of decane.
Given:
Combustion of 568 grams of decane with 2979 grams of oxygen.
\(2 C_{10}H_{22 }+ 31 O_2 \rightarrow 20 CO_2 + 22 H_2O\)
To find:
The mass of water produced by combustion of 568 grams of decane.
Solution:
Mass of decane = 568 g
Moles of decane :
= \(\frac{568 g}{142 g/mol}=4 mol\)
Mass of oxygen gas = 2976 g
Moles of oxygen gas:
= \(\frac{2976 g}{32 g/mol}=93 mol\)
\(2 C_{10}H_{22 }+ 31 O_2 \rightarrow 20 CO_2 + 22 H_2O\)
According to reaction, 2 moles of decane reacts with 31 moles of oxygen, then 4 moles of decane will react with:
\(=\frac{31}{2}\times 4mol=62\text{ mol of}O_2\)
But according to the question, we have 93.0 moles of oxygen gas which is more than 62 moles of oxygen gas.
So, this means that oxygen gas is present in an excessive amount. Which simply means:
Oxygen gas is an excessive reagent.Decane is a limiting reagent.Decane being limiting reagent will be responsible for the amount of water produced after the reaction.According to reaction, 22 moles of water is produced from 2 moles of decane, then 4 moles of decane will produce:
\(=\frac{22}{2}\times 4mol=44\text{mol of }H_2O\)
Mass of 44 moles of water ;
\(=44mol\times 18g/mol=792g\)
792 grams of water is produced by the combustion of 568 grams of decane.
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