[28-(-3)+6]×(-3) please show your work ​

Answer: B. Brianna’s age is 5 less than 3 times Molly age.

Step-by-step explanation:

We are informed that the expression below represents Brianna’s age in

terms of m, Molly’s age.

3m − 5.

This shows that 3m simply means that 3 times of Molly's age while the -5 represent less than 5. This will now be:

Brianna’s age is 5 less than 3 times Molly age.

The slope of the line that passes through the points (-9, 0) and (−17,4) is -2

The slope-intercept form of an equation is used whenever the equation of a line is expressed in the form y = mx + b. M represents the line's slope. B is the b in the location where the y-intercept is located (0, b). For instance, the slope and y-intercept of the equation y = 3x - 7 are 3 and 0, respectively.

The formula to calculate slope is -

m = x2 - x1 / y2 - y1

(-9, 0) and (−17,4)

m = -17 + 9 / 4 - 0

m = -8/4

m = -2

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The opportunity cost of 1 lunch box is 3 sandwich containers. This means workers are giving up the opportunity to produce 3 sandwich containers

The opportunity cost represents the value of the next best alternative forgone when making a choice. In this case, the workers at Shadowland have the option to produce either lunch boxes or sandwich containers.

Given that they can produce 6 lunch boxes or 18 sandwich containers per hour, we can calculate the opportunity cost.

To find the opportunity cost of 1 lunch box, we compare the number of sandwich containers that could have been produced in the same amount of time.

Since they can produce 18 sandwich containers per hour, the opportunity cost of 1 lunch box is the number of sandwich containers that could have been produced instead, which is 18/6 = 3.

Therefore, the opportunity cost of 1 lunch box is 3 sandwich containers. This means that for every lunch box produced, the workers are giving up the opportunity to produce 3 sandwich containers, which represents the trade-off in their production choices.

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Answer; Now let's write expressions for the amount of cement contained in each bag:

(20)(0.25) = # lbs. of input 25% cement

(x)(1.00) = # lbs of input pure (100%) cement

(20 + x)(0.40) = # lbs. of output 40% cement

Next, we'll write an equation to express the mixing our two input bags to produce our output bag and solve that equation for our unknown (x):

(20)(0.25) + (x)(1.00) = (20 + x)(0.40)

5 + x = (20)(0.40) + 0.4x

5 + x = 8 + 0.4x

x - 0.4x = 8 - 5

0.6x = 3

x = 3/0.6

x = 5 lbs. of input pure (100%) cement

Step-by-step explanation:

The measure of angle m∠BFC, obtained using vertical and angle addition postulate is; m∠BFC = 62°

Vertical angles are angles that are formed by two intersecting lines, that are located on opposite sides to each other on the lines.

The specified parameters are;

m∠EFD = 28°

Line AD is perpendicular to line GC (Perpendicular line symbol at F)

m∠AFG = 90° (Definition of perpendicular lines)

∠AFG and ∠AFC are linear pair angles (Angles that together form a straight line GC)

m∠AFG + m∠AFC = 180° (linear pair angles are supplementary)

90° + m∠AFC = 180° (supplement angles have a sum of 180°)

m∠AFC = 180° - 90° = 90°

m∠AFC = 90°

∠AFC = ∠AFB + ∠BFC (Angle addition property)

∠EFD and ∠AFB are vertical angles

∠EFD ≅ ∠AFB (vertical angles are congruent)

∠EFD = ∠AFB (definition of congruency)

∠EFD = 28°

28° = ∠AFB (substitution property)

∠AFB = 28° (symmetric property)

90° = 28° + m∠BFC

m∠BFC = 90° - 28° = 62°

m∠BFC = 62°

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Answer:

The difference in areas:

Percent increase:

The equation of the line having slope = -1 and passing through a point (-3, 5) is y = -x + 2 and graph is given below.

The general equation of a line is y = m × x + c, where m is the slope and c is the y-intercept of the line.

Given slope is equal to -1.

Therefore the equation of the required line is y = (-1) × x + c.

Given that this line passes through the point (-3, 5).

Therefore we have 5 = (-1) × (-3) + c

⇒ 5 = 3 + c

⇒ 5 - 3 = c

⇒ 2 = c

⇒ c = 2

Therefore the y-intercept of the required line in cartesian coordinate form is (0, 2).

Therefore the required equation of the line is y = (-1) × x + 2

⇒ y = -x + 2.

Refer to the attached image for the graph of this line.

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Disclaimer: The question is not incomplete.

Assuming the following as the complete question.

Find the equation of the line having slope = -1, through point (-3,5) and also draw the graph of the line.

The solutions of the equation x^2 + 14x - 10 = 5, from smallest to largest, are x = -7 - 3√6 and x = -7 + 3√6. To solve the equation x^2 + 14x - 10 = 5, we will complete the square.

a. The coefficient of x^2 is 1, so we have a quadratic equation in the form x^2 + bx = c.

b. To complete the square, we take half of the coefficient of x (which is b/2) and square it. In this case, b = 14, so (14/2)^2 = 49.

c. Adding 49 to both sides of the equation gives us x^2 + 14x + 49 = 5 + 49, which simplifies to x^2 + 14x + 49 = 54.

d. To factor the left side of the equation, we can write it as a perfect square: (x + 7)^2 = 54.

e. Taking the square root of both sides gives us x + 7 = ±√54.

f. Simplifying the right side, we have x + 7 = ±3√6.

g. Subtracting 7 from both sides gives us x = -7 ± 3√6.

Therefore, the solutions of the equation x^2 + 14x - 10 = 5, from smallest to largest, are x = -7 - 3√6 and x = -7 + 3√6.

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To calculate the annual payment required to pay off a five-year, $25,000 loan at an interest rate of 3.50 percent EAR, we can use the formula for calculating the equal annual payment for an amortizing loan.

The formula is: A = (P * r) / (1 - (1 + r)^(-n))

Where: A is the annual payment,

P is the loan principal ($25,000 in this case),

r is the annual interest rate in decimal form (0.035),

n is the number of years (5 in this case).

Substituting the given values into the formula, we have:

A = (25,000 * 0.035) / (1 - (1 + 0.035)^(-5))

Simplifying the equation, we can calculate the annual payment:

A = 6,208.61

Therefore, the annual payment required to pay off the five-year, $25,000 loan at an interest rate of 3.50 percent EAR is $6,208.61.

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Answer:

Amount invested that yielded interest of 5% is $15000 and amount invested that yielded interest of 8% is $5000

Step-by-step explanation:

Johnny invested $20,000

We are told that it consisted of 2 portions because one returned an interest of 5% and the other one 8%

Now, Let x be the amount invested that earned 5% and y be the amount invested that earned 8%

Thus:

x + y = 20000 - - - (eq 1)

The total interest earned on the investment was $1150

Thus;

5%x + 8%y = 1150

This can be rewritten as;

0.05x + 0.08y = 1150 - - -(eq 2)

From eq 1, let's make x the subject.

x = 20000 - y

Putting 20000 - y for x in eq 2 gives;

0.05(20000 - y) + 0.08y = 1150

1000 - 0.05y + 0.08y = 1150

Rearranging, we have;

0.03y = 1150 - 1000

0.03y = 150

y = 150/0.03

y = 5000

Thus,

x = 20000 - 5000

x = 15000

Thus,

Amount invested that yielded 5% is $15000 and amount invested that yielded 8% is $5000

Answer:-10

Step-by-step explanation: solve by using pemdas and u get -10

Answer:

6.003*10^5

Step-by-step explanation:

Answer:

hope this helps :)

Step-by-step explanation:

The probability that student chosen at random is 16 years is 0.28.

The table shows the distribution of student by age in a high school with 1500 students. Therefore, the probability that randomly chosen student is  16 years can be found as follows:

Therefore,

probability = number of favourable outcome to age / total number of possible outcome

Hence,

probability that student chosen at random is 16 years =  420 / 150

probability that student chosen at random is 16 years = 0.28

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Answer:

drawing a blue marble is a harder then the yellow but not as hard as the red.

Explanation:- When they had asked, Round 468986 to the nearest thousand, You should know that :-

Th H T O

4 6 8 9 8 6

So, Here In Thousand place we have 8.

Then see the all numbers after 8 That is :-

8986

So 8986 is nearest to 9000

Therefore, answer will be 469000.

the answer is 469000 hope it help's

We have determined that the mean of the discrete random variable x is 2, and the variance is 5. This was achieved by solving the equations representing the mean and variance using the probabilities p(x) and the given expected values.

The mean of a discrete random variable x is given by the formula:

\(E(X) = \mu = \sum{x \cdot p(x)}.\)

Both E(X) and \(\mu\) represent the mean of the variable.

The probability p(x) represents the likelihood of x taking the value x. In this case, the expected value for E(X) is 2, so we can express it as:

\(2 = \sum{x \cdot p(x)}\) (1)

Similarly, the variance is defined as:

\(\Var(X) = E(X^2) - [E(X)]^2\).

Here, \(E(X^{2})\) represents the expected value of\(X^{2}\), and E(X) represents the mean of X.

The given expected value for \(E(X^{2})\) is 9, so we can write:

\(9 = \sum{x^2 \cdot p(x)}\)(2)

Now, we have two equations (1) and (2) with two unknowns, p(x and x, which we can solve.

Let's start with equation (1):

\(2 = \sum{x \cdot p(x)}\)

\(= 1 \cdot p_1 + 2 \cdot p_2 + 3 \cdot p_3 + \dots + 6 \cdot p_6\)

\(= p_1 + 2p_2 + 3p_3 + \dots + 6p_6 (3)\)

Next, let's consider equation (2):

\(9 = \sum{x^2 \cdot p(x)}\)

\(= 1^2 \cdot p_1 + 2^2 \cdot p_2 + 3^2 \cdot p_3 + \dots + 6^2 \cdot p_6\)

\(= p_1 + 4p_2 + 9p_3 + \dots + 36p_6\) (4)

We have equations (3) and (4) with two unknowns, p(x) and x.

We can solve them using simultaneous equations.

From equation (3), we have:

\(2 = p_1 + 2p_2 + 3p_3 + 4p_4 + 5p_5 + 6p_6\)

We can express \(p_1\) in terms of\(p_2\) as follows:

\(p_1 = 2 - 2p_2 - 3p_3 - 4p_4 - 5p_5 - 6p_6\)

Substituting this in equation (4), we get:

\(9 = (2 - 2p_2 - 3p_3 - 4p_4 - 5p_5 - 6p_6) + 4p_2 + 9p_3 + 16p_4 + 25p_5 + 36p_6\)

\(= 2 - 2p_2 + 6p_3 + 12p_4 + 20p_5 + 30p_6\)

\(= 7 - 2p_2 + 6p_3 + 12p_4 + 20p_5 + 30p_6\)

We can express \(p_2\) in terms of \(p_3\) as follows:

\(p_2 = \frac{7 - 6p_3 - 12p_4 - 20p_5 - 30p_6}{-2}\)

\(p_2 = -\frac{7}{2} + 3p_3 + 6p_4 + 10p_5 + 15p_6\)

Now, we substitute this value of \(p_2\)in equation (3) to get:

\(2 = p_1 + 2(-\frac{7}{2} + 3p_3 + 6p_4 + 10p_5 + 15p_6) + 3p_3 + 4p_4 + 5p_5 + 6p_6\)

\(= -7 + 8p_3 + 16p_4 + 27p_5 + 45p_6\)

Therefore, we obtain the values of the probabilities as follows:

\(p_3 = \frac{5}{18}$, $p_4 = \frac{1}{6}$, $p_5 = \frac{2}{9}$, $p_6 = \frac{1}{6}$, $p_2 = \frac{1}{9}$, and $p_1 = \frac{1}{18}.\)

Substituting these values into equation (3), we find:

\(2 = \frac{1}{18} + \frac{1}{9} + \frac{5}{18} + \frac{1}{6} + \frac{2}{9} + \frac{1}{6}\)

2 = 2

Thus, the mean of the discrete random variable x is indeed 2.

In the next step, let's calculate the variance of the discrete random variable x. Substituting the values of p(x) in the variance formula, we have:

\(\Var(X) = E(X^{2}) - [E(X)]^{2}\)

\(= 9 - 2^{2}\)

= 5

Therefore, the variance of the discrete random variable x is 5.

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The total length of the wall that the individuals have to paint is 69 3/13 m.

The first step is to add the fractions of the wall painted by the three people together. Addition is the mathematical operation that is used to determine the sum of two or more numbers.

Sum of the fractions:

\(\frac{1}{4} + \frac{1}{3} + \frac{1}{5}\)

\(\frac{15 + 20 + 12}{60}\) = \(\frac{47}{60}\)

The fraction of the wall that has not been painted = 1 - \(\frac{47}{60}\) = \(\frac{13}{60}\)

13/60 of the wall = 15m

13/60 x w = 15

w = 15 ÷ 13/60

w = 15 x 60 /13 = 69 3/13 m

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Answer:

13 :V

Step-by-step explanation:

Answer: 13

Step-by-step explanation:

13 because 13+2=15 which would be the answer.

Answer:

B) \(\$8395.80\)

Step-by-step explanation:

\(A=P(1+rt)\\A=7996(1+0.06\cdot\frac{10}{12})\\A=7996(1+0.05)\\A=7996(1.05)\\A=\$8395.80\)

This is all assuming that r=6% is an annual rate, making t=10/12 years

Input data

Pocket: 8255

Iphone: 9000

Procedure

Total = Pocket - Iphone

Total = 8255 - 9000

Total = -745

Cindy would owe a total of USD 745

Answer:

x, greater than sign with a line under it, 14

Step-by-step explanation:

The tangent line to the graph of the function g(t) = (4sin(t) + 4cos(t))^3 at t = π/2 is y = 24. The normal line to the graph at the same point is y = -1/24.

To find the equation of the tangent line, we need to find the derivative of the function g(t) and evaluate it at t = π/2. The derivative of g(t) can be found using the chain rule and simplifying the expression:

g'(t) = 3(4sin(t) + 4cos(t))^2 * (4cos(t) - 4sin(t)).

Evaluating g'(t) at t = π/2 gives:

g'(π/2) = 3(4sin(π/2) + 4cos(π/2))^2 * (4cos(π/2) - 4sin(π/2)) = 3(4(1) + 4(0))^2 * (4(0) - 4(1)) = 3(4)^2 * (-4) = -192.

Using the point-slope form of a line, the equation of the tangent line is given by:

y - g(π/2) = g'(π/2) * (t - π/2).

Plugging in the values, we get:

y - g(π/2) = -192 * (t - π/2).

y - 24 = -192t + 96π.

y = -192t + 96π + 24.

For the normal line, we can use the fact that the slope of the normal line is the negative reciprocal of the slope of the tangent line. The slope of the normal line is given by -1/g'(π/2). Plugging in the value, we have:

slope of normal line = -1/(-192) = 1/192.

Using the point-slope form again, we get:

y - g(π/2) = (1/192) * (t - π/2).

y - 24 = (1/192)t - π/384.

y = (1/192)t - π/384 + 24.

Simplifying further, we have:

y = (1/192)t - π/384 + 9216/384.

y = (1/192)t + (9216 - π)/384.

y = (1/192)t + (9216 - 3.14)/384.

y = (1/192)t + 8885.86/384.

y = (1/192)t - 23.16.

Therefore, the equations of the tangent and normal lines to the graph of the function g(t) at t = π/2 are y = -192t + 96π + 24 and y = (1/192)t - 23.16, respectively.

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Answer:

Hello. You did not enter the answer options, but if two parallel lines are cut by a transversal, it is impossible to see a scenario with adjacent angles.

Step-by-step explanation:

When two parallel lines are cut by a transverse line, the result will always be a scenario where congruent alternating angles are created, whether internal or external.

This type of activity will never give rise to adjacent angles, regardless of how the lines are cut.

Answer:

25 quarters, 5 half dollars

Step-by-step explanation:

let a = the number of half dollars in the jar

and b = the number of quarters

a + b = 30

0.5a + 0.25b = 8.75

multiply the second equation by -2 to get

-a - 0.5b = -17.5

Now add the new equation and the first to eliminate h

a + b = 30

-a - 0.5b = -17.5

----------------------------

0.5b = 12.5

b = 25

There are 25 quarters, so there must be 5 half dollars

Answer:

Step-by-step explanation:

Let half dollars be d and quarters be q

d + q = 30 thus, q = 30 - d

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

0.5d + 0.25q = 8.75 substitute for q:

0.5d + 0.25(30 - d) = 8.75

0.5d + 7.5 - 0.25d = 8.75

0.25d = 1.25

d = 5 so there are 5 half dollars in the jar

Therefore, there are 30 - 5 = 25 quarters in the jar

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Check:

25 x 0.25 = 6.25

5 x 0.5 = 2.5

-----------------

Total . . 8.75 Correct

Answer:

(7, -1)

Step-by-step explanation:

Look at vertex R. The x is 7. Q has the same x value as R and same Y value as P.

The position value, r(t) is equals to the (t³/6)k + 2j and velocity value, v(t) is equals to ( t²/2 )k + 4i , for a(t) = tk, v(0) = 4i, r(0) = 2j.

Acceleration is defined as the rate of change of the velocity of an object with respect to time. Accelerations are vector quanty.

a = dv/dt

We have the following informations are available,

Initial velocity, v(0) = 4i

Initial position, r(0) = 2j

Acceleration at any time "t",

a(t) = tk

we have to determine the value of v(t) and r(t).

As we know, a(t) = dv(t)/dt = tk

integrating the above equation ,

v(t) = ∫tk dt = ( t²/2 )k + c

at t = 0 , v(0) = 0 + c = 4i ( since, v(0) = 4i

=> c = 4i

So, v(t) = ( t²/2 )k + 4i

Also, velocity is calculated by derivative of postion (r) with respect to time.

=> v(t) = dr(t) /dt

=> r(t) = ∫ v(t) dt

=> r(t) = ∫ ( t²/2 )k dt

integrating value of the right hand side,

r(t) = ( t³/2×3 )k +d

= (t³/6)k + d

At t = 0, r(0) = (0/6)k + d

=> r(0) = d = 2j

so, r(t) = (t³/6)k + 2j

Hence, the required position and velocity are

(t³/6)k + 2j and ( t²/2 )k + 4i.

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