2(3x - 6) + 5x = -x-4(7-1x)
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Answer:

5

Step-by-step explanation:

not you deleting it

(a) The domain closed and bounded.

(b) The domain bounded.

(c) The domain closed.

(d) The domain bounded.

(e) The domain closed and bounded.

(f) The domain closed and bounded.

In this question, we have been given some domains.

We need to check which domains are closed and which are bounded.

A domain of function is said to be closed if the region R contains all boundary points.

A bounded domain is nothing but a domain which is a bounded set.

(a) {(x,y)∈R2:x^2+y^2≤1}

The domain of x^2+y^2≤1 contains set of all points (x, y) ∈R2

so, the domain closed and bounded.

(b) {(x,y)∈R2:x2+y2<1}

The domain of x^2+y^2 < 1 contains set of all points (x, y) ∈R2

so, the domain is bounded.

(c) {(x,y)∈R2: x ≥ 0}

The domain of x ≥ 0 is R2 - {x < 0}

So, the domain is closed.

(d) {(x, y) ∈ R2 : x > 0,y > 0}

The domain is R2 - {(x, y) ≥ 0}

So, the domain is bounded.

(e) {(x, y) ∈ R2 : 1 ≤ x ≤ 4, 5 ≤ y ≤ 10}

The domain is closed and bounded.

(f) {(x,y)∈R2:x>0,x^2+y^2≤10}

The domain is closed and bounded.

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Firslty, we need to find the function, whcih we can do by substituting one into the other:

Now, for the domain we have more complicated approach.

We first have to find the domain for both f(x) and g(x).

The domain of f(x) is all real number, because it is a quadratic polynomial.

The domain of g(x) is all the real numbers except the x values that makes the square root interior negative, so all real numbers so that:

Now, the domain of the composite function f(g(x)) is the set of all the values of x in the domain of g(x) such that the corresponding g(x) is in the domain of f(x).

Since the domain of f(x) is all real numbers and g(x) is a real number function, all the values of g(x) will be in the domain of f(x), so we just need to check the values of x that are in the domain of g(x).

The domain of g(x), as we saw, is:

And any value of x will give a g(x) that will be in the domain of f(x) so, the domain of f(g(x)) is:

So, the correct alternative is:

Answer:

Part A: Sally paid less money per pound than Fred did

Part B: John paid $3.58 for 5.5 pounds of apples at the Grocery Mart

Part C: y = 0.65x

Step-by-step explanation:

Part A:

Sally: 1.5/2.5 = x/1

cross multiply: 2.5x = 1.5*1

simplify: 2.5x = 1.5

divide both sides by 2.5: x = 0.6

Fred: 1.95/3 = x/1

cross multiply: 3x = 1.95*1

simplify: 3x = 1.95

divide both sides by 3: x = 0.65

Fred paid 65¢/pound while Sally paid 60¢/pound

Part B:

price/pound*amount John bought: 0.65/1 = x/5.5

cross multiply: 1x = 0.65*5.5

simplify: x = 3.575

Part C:

y = 0.65x

Answer:

Between 85 and 100

Step-by-step explanation:

Getting this will get the average between the required numbers since the average of 83 and 87 is 85, getting 85 will keep the answer at 85 and getting 100 will get the average at 90.

Answer:

5

Step-by-step explanation:

I believe that this is correct because 220 is divisible by 5, which means it has completed the pattern 44 times (220 divided by 5 is 44). So 221 means that it has completed it 44 times, and then starts it one more time with only the first number.

We can find the eigenvalues of \($A$\) using the characteristic equation:

\($$\det(A-\lambda I) = \begin{vmatrix} a-\lambda & b \\ c & d-\lambda \end{vmatrix} = (a-\lambda)(d-\lambda) - bc = \lambda^2 - (a+d)\lambda + (ad-bc)$$\)

The discriminant of this quadratic equation is:

\($$(a+d)^2 - 4(ad-bc) = (a-d)^2 + 4bc$$\)

Therefore, \($A$\) is diagonalizable if and only if \($(a-d)^2 + 4bc > 0$\).

If \($(a-d)^2 + 4bc > 0$\), then the discriminant is positive, and the characteristic equation has two distinct real eigenvalues. Since \($A$\) has two linearly independent eigenvectors, it is diagonalizable.

If \($(a-d)^2 + 4bc < 0$\), then the discriminant is negative, and the characteristic equation has two complex conjugate eigenvalues. In this case, \($A$\) does not have two linearly independent eigenvectors, and so it is not diagonalizable.

(b) If \($(a-d)^2 + 4bc = 0$\), then the discriminant of the characteristic equation is zero, and the eigenvalues are equal. We can find two examples to demonstrate that \($A$\) may or may not be diagonalizable in this case.

Example 1: Consider the matrix \($A = \begin{bmatrix} 1 & 2 \\ 2 & 4 \end{bmatrix}$\). We have \($(a-d)^2 + 4bc = (1-4)^2 + 4(2)(2) = 0$\), so the eigenvalues of \($A$\) are both \($\lambda = 2$\). The eigenvectors are \($\begin{bmatrix} 1 \\ 1 \end{bmatrix}$\) and \($\begin{bmatrix} -2 \\ 1 \end{bmatrix}$\), respectively. Since these eigenvectors are linearly independent, \($A$\) is diagonalizable.

Example 2: Consider the matrix \($A = \begin{bmatrix} 1 & 1 \\ -1 & -1 \end{bmatrix}$\). We have \($(a-d)^2 + 4bc = (1+1)^2 + 4(-1)(-1) = 0$\), so the eigenvalues of\($A$\) are both \($\lambda = 0$\). The eigenvector is\($\begin{bmatrix} 1 \\ -1 \end{bmatrix}$\), which is the only eigenvector of \(A$. Since $A$\) has only one linearly independent eigenvector, it is not diagonalizable.

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Answer:

c) 3.78

Step-by-step explanation:

Atmosphere and temperatures of 273 Kelvin and 298 Kelvin, along with a pressure of 1 kilopascal and a temperature of 273 Kelvin.


Standard conditions refer to a specific set of conditions, usually including a pressure of 1 atmosphere and a temperature of 0 degrees Kelvin, that are used to measure enthalpy changes. Under these conditions, the enthalpy change of a given reaction is known as the standard enthalpy of reaction (ΔH°). Other standard conditions used to measure enthalpy changes include a pressure of 1 atmosphere and temperatures of 273 Kelvin and 298 Kelvin, along with a pressure of 1 kilopascal and a temperature of 273 Kelvin.

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Step-by-step explanation:

everything can be found in the picture

We can use trigonometric ratio to find the value of x

From the question,

θ=22 opposite = x hypotenuse = 15

substitute the values into the formula and evaluate

cross-multiply

Therefore, the closest value is 5.6

Answer:

B- hope this helps:)

Step-by-step explanation:

The total cost to paint 864.5 square feet of wall is $2,048.87.

It is given that the cost to paint one square foot of wall is $2.37.

We are asked to find the total cost to paint 864.5 square feet of wall.

If we have a number that has a decimal point then we have two parts.

The whole number part and the fractional part.

After the decimal point, we will count the place value as tenths, hundredths, thousandths, and so on.

You can also see the given figure below.

We know that,

One square foot = $2.37.

Remember that Feet is the plural form of the foot.

We can write,

864.5 square feet = 864.5 x  one square foot

Because in 864.5 square feet we have 864.5 one square foot.

And since one square foot cost $2.37.

864.5 square feet will cost 864.5 x 2.37 dollars.

Now,

864.5 x 2.37 = $2048.865.

Rounding to the nearest hundredth.

6 is in the hundredth place so we will round 86 to 87 since the number in the thousandth place is greater than 4.

Thus the total cost to paint a wall of 864.5 square feet is $2,048.87.

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Answer:

A: 42

Step-by-step explanation: 10.5x4=42

Answer:

your answer is A 42

Step-by-step explanation:

make me brainliest

Answer:

amount = £1415.57  

Step-by-step explanation:

given data

computer buy = £1600

depreciates rate = 4% per year

time = 3 year

solution  

we get here amount that is express here as

amount = P × \((1-r)^{t}\)    ...................................1                                    

here r is rate and t is time put here value

amount will  be              

amount = 1600 × \((1-0.04)^{3}\)  

solve it we get

amount = £1415.57  

Answer:

267.45 sq units

Step-by-step explanation:

Area of shaded region = Area of Square minus Area of Circle

the sides of the square are twice the radius of 9, therefore 18

A(square) = 18² = 324

A(circle) = π9² = 81π ≈ 56.55

324 - 56.55 = 267.45

The solution to each of the arithmetic sequence are:

1) a₁₀ = 56

2) a₁₀ = 87

3) missing term is 13

4) missing term is 14

The formula for the nth term of an arithmetic sequence is:

aₙ = a + (n - 1)d

where:

a is first term

n is nth term

d is common difference

1) a = 2

d = 6

a₁₀ = 2 + (10 - 1)6

a₁₀ = 2 + 54

a₁₀ = 56

2) a = 15

d = 8

a₁₀ = 15 + (10 - 1)8

a₁₀ = 87

3) The missing term will be gotten by finding the common difference.

d = (22 - 4)/2

d = 18/2

d = 9

missing term = 4 + 9 = 13

4) The missing term will be gotten by finding the common difference.

d = (53 - 25)/2

d = 28/2

d = 14

missing term = 4 + 9 = 14

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The top right graph could show the arrow's height above the ground over time.

The initial and the final height are both at eye level, which is the reference height, that is, a height of zero.

This means that the beginning and at the end of the graph, it is touching the x-axis, hence either the top right or bottom left graphs are correct.

The trajectory of the arrow is in the format of a concave down parabola, hitting it's maximum height and then coming back down to eye leve.

Hence the top right graph could show the arrow's height above the ground over time.

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the area of the dartboard is approximately 254.34 square inches.

The area of a dartboard can be calculated using the formula for the area of a circle, which is given by:

Area = π * \(radius^2\)

Given that the radius of the dartboard is 9 inches, we can substitute this value into the formula:

Area = π * \(9^2\)

Area = π * 81

To calculate the area, we need to use the value of π (pi). Pi is an irrational number and is commonly approximated as 3.14. Using this approximation, we can calculate the area:

Area ≈ 3.14 * 81

Area ≈ 254.34 square inches

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The expressions formed are,

Formation of expressions in 1, 2 and 3:

In 1, twelve times f is, 12f

Taking away 5, it becomes (12f-5)

In 2, sum of k and 6 is, (k+6)

One-half of the above quantity is, (k+6)/2

In 3, sum of 5 with x is, (x+5)

Now, x squared minus the above expression indicates (x²-x+5)

Formation of expressions in 4 and 5:

In 4, product of a and b, is ab and 3 times c is 3c

Sum of the expressions evaluated in the previous statement = ab+3c

In 5, 24 times the product of x and y is, 24xy

Adding, g in the above computed expression, we get, 24xy+g

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The solution for A'0 is as follows:

A'0 = (βR^(-1/γ) / (1 - R^(-1/γ)))^(1/γ)

We start with the equation (A0 - A0')^(-γ) = βR(RA0')^(-γ). To solve for A'0, we isolate it on one side of the equation.

First, we raise both sides to the power of -1/γ, which gives us (A0 - A0') = (βR(RA0'))^(1/γ).

Next, we rearrange the equation to isolate A'0 by subtracting A0 from both sides, resulting in -A0' = (βR(RA0'))^(1/γ) - A0.

Finally, we multiply both sides by -1, giving us A'0 = -((βR(RA0'))^(1/γ) - A0).

Simplifying further, we get A'0 = (βR^(-1/γ) / (1 - R^(-1/γ)))^(1/γ).

Complete question - Solve for A'0, given the equation (A0 - A0')^(-γ) = βR(RA0')^(-γ),

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A baseball bat strikes a ball with an average force of 2.0 x 104 Newtons. if the bat stays in contact with the ball for a distance of 5.0 x 10-3 meter, kinetic energy will be 2.0 x 102 J.

Bat remains in touch for 5.0 X 10³ and the speed of the ball is 2.0 X 10 to the power 4

kinetic energy of an object is the energy that it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes.

In classical mechanics, the kinetic energy of a non-rotating object of mass m traveling at a speed v is 1/2 mv²

Favg= -1/2 MV2

Favg = -1 2 ( 5.0 x 10-3)^2

Favg = - 1/2 ×25 × 10 ^-6

Favg = 2× 10^2 J

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Answer:

(5,15)

Step-by-step explanation:

we know that c=12 is 5 so your answer is 5,15

The true statements for all invertible n×n matrices A and B are: B. A+A⁻¹ is invertible, C. (In+A)(In+A⁻¹)=2In+A+A⁻¹, F. AB=BA.

A. (A+B)² = A² + AB + BA + B². This equation is only true for certain matrices, and not all invertible matrices.

B. This statement is true for all invertible matrices A. The sum of an invertible matrix and its inverse is always invertible.

C. This statement is true for all invertible matrices A. It is a special case of the Sherman-Morrison formula.

D. This statement is not true for all invertible matrices A. For example, the matrix A = 0 is invertible, but A⁶ is not invertible.

E. This statement is not true for all invertible matrices A. For example, the matrix A = -1 is invertible, but (A+A⁻¹)⁹ = 2⁹ - 2⁷+ 2⁵ - 2³+ 2 = 506.

F. This statement is true for all invertible matrices A and B. It is known as the commutativity property of invertible matrices.

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Complete Question : Select all statements below which are true for all invertible n×n matrices A and B

A. (A+B)^2=A^2+B^2+2AB

B. A+A^−1 is invertible

C. (In+A)(In+A^−1)=2In+A+A^−1

D. A^6 is invertible

E. (A+A^-1)^9=A^9+A^−9

F. AB=BA

Answer:

B. is your answer.

Step-by-step explanation:

Answer:

196 miles

Step-by-step explanation:

distance (D) is calculated as

D = S × T ( S is average speed and T is time in hours )

here T = 3 and a half hours = 3.5 hours and S = 56 , then

D = 56 × 3.5 = 196 miles

Answer: Monthly Repayment = $117.43

The area of the largest circle at the surface of the water over which light from the ring could escape is approximately 474.37 square meters.

To determine the area of the largest circle, we can use the concept of critical angle in optics. When light travels from a medium with a higher refractive index to a medium with a lower refractive index, there is a specific angle called the critical angle at which the light is totally internally reflected and does not escape.

In this case, the ring is assumed to be a point source of light. The critical angle can be calculated using the formula

sin(\(\theta\)) = n2/n1,

where n2 is the refractive index of air (approximately 1) and n1 is the refractive index of water (approximately 1.33).

Using this formula, we find that the critical angle is approximately 48.76 degrees. The circle at the surface of the water with this angle as the central angle will have the maximum area over which light from the ring could escape. The area of this circle can be calculated using the formula \(A = \pi * r^2\), where r is the radius of the circle.

Substituting the radius as the depth of the Rhine (12.3 meters), we find that the area of the largest circle is approximately 474.37 square meters.

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Explanation:

The two points (0,0) and (2,1) are on the line. Apply the slope formula to them to get the following

m = (y2-y1)/(x2-x1)

m = (1-0)/(2-0)

m = 1/2

This indicates that each time you go up 1 unit, you must move to the right 2 units.

Slope = rise/run = 1/2

rise = 1, run = 2

To solve such problems we need to know about the area of a rhombus.

\(\rm Area\ of\ rhombus &= \dfrac{(Diagonal_1 \times Diagonal_2)}{2}\)

As it is given that Each Rhombus will be 6 inches tall and 4 inches wide, therefore, the diagonals of the rhombus are 6 inches and 4 inches.

The paper needed for each rhombus =  Area of the rhombus

\(\begin{aligned}Area\ of\ rhombus &= \dfrac{(Diagonal_1 \times Diagonal_2)}{2}\\&=\dfrac{6 \times 4}{2}\\&= \dfrac{24}{2}\\&= 12\end{aligned}\)

Therefore, the paper needed for each rhombus is 12 square inches.

As it is we have got the area of the rhombus in. We need to change the wall length to the wall to inches.

1 foot = 12 inches

so,

11 feet = 11 x 12 = 132 in

As per the information given each rhombus is 4 inches wide, and we need to cover 132 in. to make the border of the wall. therefore,

\(\rm{Number\ of\ rhombus\ needed = \dfrac{Length\ of\ the\ wall}{Width\ of\ the\ rhombus}\)

                                             \(=\dfrac{132}{4}\\\\=33\)

Thus, a total of 33 rhombus are needed to cover the wall.

\(\rm{Total\ paper\ needed = Number\ of\ rhombus\ needed\ \times Area\ of\ rhombus\)

                              \(= 12 in.^2 \times 33\\= 396 in.^2\)

Therefore, the paper used by Juan is 396 square inches.

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Answer:12 396

Step-by-step explanation: