200 grams of iron (III) chloride reacts with ammonium carbonate [(NH4)2CO3] in the following equation.

FeCl3 + (NH4)2CO3 ---------> NH4Cl + Fe2(CO3)3



The number of grams of ammonium chloride (NH4Cl) that will be produced is ___ grams.


a
395
b
181
c
198
d
339

Answer:

When conducting a chemistry lab experiment using chalk (calcium carbonate) in vinegar (acetic acid), there are several limitations and precautions to be aware of:

Limitations of chalk in vinegar chemistry experiment:

Reaction rate: The reaction between chalk and vinegar is relatively slow, which may require a longer observation period or higher concentration of vinegar to observe significant changes within a reasonable time frame.

Solubility: Chalk may not dissolve completely in vinegar, resulting in incomplete reaction or difficulty in obtaining accurate results.

Product formation: The reaction between chalk and vinegar produces carbon dioxide gas, water, and calcium acetate. The carbon dioxide gas may escape into the atmosphere, leading to loss of product and inaccurate measurements.

pH: Chalk is a basic substance, and the reaction with vinegar, which is acidic, may result in neutralization, leading to a decrease in the overall acidity of the reaction mixture.

Precautions to take in chalk in vinegar chemistry experiment:

Ventilation: The reaction between chalk and vinegar produces carbon dioxide gas, which can displace air and potentially cause asphyxiation in a closed or poorly ventilated area. Conduct the experiment in a well-ventilated area or under a fume hood to ensure adequate air circulation.

Eye and skin protection: Vinegar is an acid and can cause skin and eye irritation. Wear appropriate personal protective equipment (PPE), such as gloves and goggles, to protect yourself from contact with vinegar or any other chemicals used in the experiment.

Chemical handling: Handle the chemicals, including chalk and vinegar, with care, following proper lab safety protocols. Avoid ingestion, inhalation, or direct contact with the chemicals, and dispose of them properly according to local regulations.

Accuracy in measurements: Use calibrated and accurate measuring tools, such as graduated cylinders or burettes, to measure the amount of chalk, vinegar, and other reagents accurately. This will ensure the reliability and accuracy of the experimental results.

Observations: Make careful and detailed observations during the experiment, noting any changes in appearance, gas evolution, or other relevant observations. Take measurements at appropriate intervals and record the data accurately for analysis and interpretation.

It is important to follow good laboratory practices, including proper chemical handling, accurate measurements, and cautious observations, to ensure safe and reliable results in a chalk in vinegar chemistry lab experiment. Consult with a qualified instructor or supervisor for specific guidelines and precautions related to your experiment.

The mass of CaCl2 used was 114.2 g and the mass of water used was 280.1 g.

We are given that the mixture is 29.0% calcium chloride by mass, which means that 29.0 g of calcium chloride is present in 100 g of the mixture. This can be written as:

29.0 g CaCl2 / 100 g mixture

We are also given that the total mass of the mixture is 394.3 g. Therefore, the mass of calcium chloride present in the mixture is:

mass of CaCl2 = 29.0 g CaCl2 / 100 g mixture x 394.3 g mixture = 114.2 g

To find the mass of water in the mixture, we can subtract the mass of calcium chloride from the total mass of the mixture:

mass of water = total mass of mixture - mass of CaCl2

mass of water = 394.3 g - 114.2 g = 280.1 g

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Answer:

0.509 (to 3dp)

Explanation:

The formula for moles is:

moles = mass ÷ molar mass

The molar mass of NaCl can be calculated by adding the relative atomic masses of each element in the compound, which you can find in a periodic table:

molar mass = 23.0 + 35.5 = 58.5

Now, we can find the number of moles of NaCl in 29.8g:

moles = 29.8 ÷ 58.5 = 0.509 (to 3dp)

Answer:

Explanation:

A conversion factor is a number used to change one set of units to another, by multiplying or dividing. When a conversion is necessary, the appropriate conversion factor to an equal value must be used. For example, to convert inches to feet, the appropriate conversion value is 12 inches equal 1 foot. I am so sorry if i am wrong I am new at this

Answer: To create a conversion factor from this equality, write the quantity on one side of the equal sign in the numerator of a fraction, and write the other quantity in the denominator. Note that a second conversion factor could be developed by interchanging where each quantity is written, relative to the fraction bar.

Explanation:

Answer:

Higher temperature = more bouncing.

So, the correct answer is that there will be less bouncing at 39 degrees F. (Lower at 39 F)

Let me know if this helps!

Answer:

New temperature T2 = -124.7 °C

Explanation:

Given:

Old volume V1 = 135 cm³

New volume V2 = 140 cm³3

Old temperature T1 = 143 K

Find:

New temperature T2

Computation:

V1 / T1 = V2 / T2

135 / 143 = 140 / T2

New temperature T2 = 148.3 K

New temperature T2 = 148.3 - 273

New temperature T2 = -124.7 °C

B. It will be slow because you will have to wait for natural processes to affect each area.

What is Ocean?

An ocean is a vast body of saltwater that covers more than 70% of the Earth's surface. Oceans are the largest bodies of water on our planet and are essential for supporting life on Earth. Oceans play a crucial role in regulating the Earth's climate, absorbing heat and carbon dioxide, and generating oxygen.

The impact of human activities on ocean shores zones, such as coastal development, pollution, and overfishing, can have long-lasting and sometimes irreversible effects on these ecosystems. Restoring or mitigating the impacts of human activities on ocean shores zones requires time and effort, as natural processes need to take place to restore the affected areas.

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IUPAC (International Union of Pure and Applied Chemistry) naming is also known as systematic naming.

It is a set of rules and guidelines used to name chemical compounds systematically. It provides a standardized method for naming organic and inorganic compounds based on their molecular structure and composition.

The longest continuous carbon chain in the compound is identified as the parent chain.

The IUPAC name of the given compounds are:

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Job/Situation 1: Chemical laboratory technician, where the importance is ,in a chemical laboratory, precise measurement of chemicals and substances is crucial for conducting experiments, formulating accurate solutions, and bad things are are not accurate or balanced in a chemical laboratory. Another is financial analyst,they deal with managing financial data, analyzing investments, bad thing is inaccuracy. Another is Chef where the cooking skill must be good. Risk is fire etc.

As a chef bad thing is ,it can lead to improperly seasoned dishes, inconsistent flavors, undercooked or overcooked food, and dissatisfied customers. It can harm the reputation of the restaurant, lead to negative reviews, and impact customer satisfaction and loyalty. , misinformed investment decisions, and financial losses are the bad of financial analyst etc.

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Answer:

it is the one below that. NO, because it debt net the octet rule

The term that identifies the amount of heat needed to raise the temperature of 1 gram of a substance by 1 degree Celsius is Specific heat capacity.

Specific heat capacity is the quantity of heat needed to raise the temperature of 1 gram of a substance by 1 degree Celsius. The unit of specific heat capacity is joule per gram per degree Celsius (J/g⁰C).

Specific heat capacity is heat required to raise the temperature of a unit mass of a substance while heat capacity is the quantity of heat required to raise the temperature an entire mass of a substance.

Heat capacity is measure in Joules (J) while specific heat capacity is measured in joule per gram per degree Celsius (J/g⁰C).

Thus, the term that identifies the amount of heat needed to raise the temperature of 1 gram of a substance by 1 degree Celsius is Specific heat capacity.

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The term that identifies the amount of heat needed to raise the temperature of one gram of a substance by one degree Celsius is : ( A ) Specific heat

Specific heat also known specific heat is the amount of heat that is added to 1 unit ( gram ) of a substance in order to raise its temperature by one ( 1 ) degree Celsius of temperature.

Hence we can conclude that The term that identifies the amount of heat needed to raise the temperature of one gram of a substance by one degree Celsius is Specific heat

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Answer:

Option d) 3 only is the right answer

After the reaction is complete, no nitrogen and no hydrogen molecules remain, and 8.00 x 1014 molecules of NH3 are produced.

In the equation, nitrogen and hydrogen react at a high temperature, in the presence of a catalyst, to produce ammonia, according to the balanced chemical equation:N2(g)+3H2(g)⟶2NH3(g)The coefficients of each molecule suggest that one molecule of nitrogen reacts with three molecules of hydrogen to create two molecules of ammonia.

So, to determine how many molecules of ammonia are produced when four nitrogen and nine hydrogen molecules are present, we must first determine which of the two reactants is the limiting reactant.

To find the limiting reactant, the number of moles of each reactant present in the equation must be determined.

Calculations:
Nitrogen (N2) molecules = 4Hence, the number of moles of N2 = 4/6.02 x 1023 mol-1 = 6.64 x 10-24 mol
Hydrogen (H2) molecules = 9Hence, the number of moles of H2 = 9/6.02 x 1023 mol-1 = 1.50 x 10-23 mol

Now we have to calculate the number of moles of NH3 produced when the number of moles of nitrogen and hydrogen are known, i.e., mole ratio of N2 and H2 is 1:3.

The mole ratio of N2 to NH3 is 1:2; thus, for every 1 mole of N2 consumed, 2 moles of NH3 are produced.
The mole ratio of H2 to NH3 is 3:2; thus, for every 3 moles of H2 consumed, 2 moles of NH3 are produced.
From these mole ratios, it can be observed that the limiting reactant is nitrogen.

Calculation for NH3 production:
Nitrogen (N2) moles = 6.64 x 10-24 moles
The mole ratio of N2 to NH3 is 1:2; therefore, moles of NH3 produced is 2 × 6.64 × 10−24 = 1.33 × 10−23 moles.

Now, to determine how many molecules of NH3 are produced, we need to convert moles to molecules.
1 mole = 6.02 x 1023 molecules
Thus, 1.33 x 10-23 moles of NH3 = 8.00 x 1014 molecules of NH3 produced.

To find the amount of each reactant remaining after the reaction is complete, we must first determine how many moles of nitrogen are consumed, then how many moles of hydrogen are consumed, and then subtract these from the initial number of moles of each reactant.

The moles of nitrogen consumed = 4 moles × 1 mole/1 mole N2 × 2 mole NH3/1 mole N2 = 8 moles NH3
The moles of hydrogen consumed = 9 moles × 2 mole NH3/3 mole H2 × 2 mole NH3/1 mole N2 = 4 moles NH3
Thus, the moles of nitrogen remaining = 6.64 × 10−24 mol – 8 × 2/3 × 6.02 × 10^23 mol-1 = 5.06 × 10−24 mol
The moles of hydrogen remaining = 1.50 × 10−23 mol – 4 × 2/3 × 6.02 × 10^23 mol-1 = 8.77 × 10−24 mol

Finally, the number of molecules of each reactant remaining can be calculated as follows:
Number of N2 molecules remaining = 5.06 × 10−24 mol × 6.02 × 10^23 molecules/mol = 3.05 × 10−1 molecules ≈ 0 molecules
Number of H2 molecules remaining = 8.77 × 10−24 mol × 6.02 × 10^23 molecules/mol = 5.28 × 10−1 molecules ≈ 0 molecules.

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Answer:

NH3 ------dipole - dipole forces

CH3OH ------ dipole - dipole forces

AlBr3 ------- ion - dipole forces

AlCl3 ------- ion - dipole forces

Explanation:

Let us recall that water is a polar molecule. This means that water has a positive as well as a negative end. NH3 also has a dipole. The interaction between solute and solvent dipoles leads to the dissolution of NH3 in water. Hence the strongest intermolecular force here is dipole - dipole forces.

Similarly, CH3OH  possesses a polar -O-H group which can interact with water via dipole - dipole interaction as its strongest intermolecular force.

As for AlBr3 and AlCl3, the two substances dissociate into ions in solution and these ions interact with the dipole in water via ion - dipole interaction as its strongest intermolecular interaction.

Answer:

Ammonia \(NH_3\)

Aluminium Chloride \(AlCl\)

Methanol \(CH_3OH\)

Aluminium bromide \(AlBr_3\)

Explanation:

Because water is not in ionic form it can only forms dipole forces which are strongest. Methanol, Ammonia and AlCl are also dipoles not ions . Thus dipole dipole forces exist.

On the other hand, aluminium bromide are ionic and it can forms ion dipole bonds with water.

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Answer:

C.) Sodium

Explanation:

Sodium is an "Alkali Metal"

The ideal gas law equation is: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.

To determine the mass of NaCl that reacted with F2 at 290 K and 1.5 atm, we can rearrange the equation as follows: n = PV/RT. Substituting in the values for P, V, R, and T, we get: n = (1.5 atm)(18.0 L)/(0.0821 atm*L/mol*K)(290 K) = 0.835 mol NaCl.

To determine the mass of sodium chloride that can react with the same volume of fluorine gas at STP (standard temperature and pressure), we would use the same equation but with the values for P, V, R, and T corresponding to STP. At STP, P = 0.987 atm, V = 18 L, R = 0.0821 atm*L/mol*K, and T = 273 K. Therefore, n = (0.987 atm)(18 L)/(0.0821 atm*L/mol*K)(273 K) = 0.792 mol NaCl.

What is Sodium chloride?

Sodium chloride, also known as table salt, is an ionic compound composed of sodium and chloride ions in equal proportions. It is a mineral found naturally in most bodies of water, including sea water, and is widely used as a seasoning and preservative in food.

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Answer:

The ideal gas law equation is: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.

To determine the mass of NaCl that reacted with F2 at 290 K and 1.5 atm, we can rearrange the equation as follows: n = PV/RT. Substituting in the values for P, V, R, and T, we get: n = (1.5 atm)(18.0 L)/(0.0821 atm*L/mol*K)(290 K) = 0.835 mol NaCl.

To determine the mass of sodium chloride that can react with the same volume of fluorine gas at STP (standard temperature and pressure), we would use the same equation but with the values for P, V, R, and T corresponding to STP. At STP, P = 0.987 atm, V = 18 L, R = 0.0821 atm*L/mol*K, and T = 273 K. Therefore, n = (0.987 atm)(18 L)/(0.0821 atm*L/mol*K)(273 K) = 0.792 mol NaCl.

Explanation:

Answer:

4 or 3 atoms; leaning towards 4 more

Explanation:

Answer:

3 atoms

Explanation:

The molarity of the NiSO₄ solution made by dissolving 38.81 grams of nickel (ii) sulfate, NiSO₄, in enough water to make 0.467 liters of solution is 0.535 M

First, we shall obtain the mole of 38.81 grams of nickel (ii) sulfate, NiSO₄. Details below:

Mole of NiSO₄ = mass / molar mass

= 38.81 / 154.75

= 0.25 mole

Now, we shall determine the molarity of the solution. Details below:

Molarity of solution = mole / volume

= 0.25 / 0.467

= 0.535 M

Thus, the molarity of the solution is 0.535 M

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Answer:

Explanation:

Water is capable of dissolving a variety of different substances, which is why it is such a good solvent. And, water is called the "universal solvent" because it dissolves more substances than any other liquid. This allows the water molecule to become attracted to many other different types of molecules.

Answer:

A.) 1.88 L

Explanation:

To find the volume of HCl , you need to (1) convert grams to moles (using the molar mass) and then (2) calculate the volume (using the molarity ratio).

(Step 1)

Molar Mass (HCl): 36.46 g/mol

303 grams HCl               1 mole
-------------------------  x  ----------------------  =  8.31 moles HCl
                                    36.46 grams

(Step 2)

Molarity = 4.4 M

Moles = 8.31 moles

Molarity = moles / volume (L)                       <----- Molarity ratio

4.4 M = 8.31 moles / volume                        <----- Insert values

(4.4 M)  x volume = 8.31 moles                    <----- Multiply both sides by volume

volume = 1.88                                              <----- Divide both sides by 4.4

The answer is A. verb- My research paper on osmosis was to record or make a note with scientific sources from around the world.

Osmosis is the diffusion of water molecules across a semi-permeable membrane. This process is driven by the difference in osmotic pressure across the membrane and results in a net movement of water molecules from an area of higher water potential (lower osmotic pressure) to an area of lower water potential (higher osmotic pressure). As a result, the particles become more evenly distributed across the membrane and the water molecules build up on the side with the lower water potential, which in turn causes an increase in pressure.

A semi-permeable membrane is a thin barrier that allows some molecules or ions to pass through but not others. This type of membrane is selectively permeable, meaning that it is designed to be permeable to certain molecules while blocking others. Semi-permeable membranes are commonly used in biological systems as cell walls, allowing the cells to regulate what they let in or out. They also have applications in water filtration, artificial kidneys, and various other scientific fields.

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Answer:primary consumer

Explanation:

i got it right

Approximately 70.57 mL of 1.00 M NaOH should be added to 250 mL of 0.50 M CH3CO₂H to produce a buffer with a pH of 4.50.

To determine the volume of 1.00 M NaOH required to produce a buffer with a pH of 4.50 when added to 250 mL of 0.50 M CH3CO₂H, we need to consider the Henderson-Hasselbalch equation and the stoichiometry of the reaction.

The Henderson-Hasselbalch equation for a buffer solution is given as:

pH = pKa + log([A-]/[HA])

In this case, CH3CO₂H (acetic acid) acts as the weak acid (HA) and CH3COO- (acetate ion) acts as its conjugate base (A-). We are given that the desired pH is 4.50, and we can determine the pKa value for acetic acid from reference sources, which is approximately 4.75.

Using the Henderson-Hasselbalch equation, we can rearrange it to solve for the ratio [A-]/[HA]:

[A-]/[HA] = 10^(pH - pKa)

[A-]/[HA] = 10^(4.50 - 4.75) = 10^(-0.25) = 0.5623

This means that the ratio of the acetate ion to acetic acid in the buffer solution should be approximately 0.5623.

To calculate the required volume of NaOH, we need to consider the stoichiometry of the reaction. Acetic acid reacts with hydroxide ions (OH-) to form acetate ions and water:

CH3CO₂H + OH- → CH3COO- + H2O

The stoichiometric ratio between acetic acid and hydroxide ions is 1:1. Therefore, the volume of 1.00 M NaOH needed can be calculated using the equation:

Volume (NaOH) × 1.00 M = Volume (CH3CO₂H) × 0.50 M × 0.5623

Volume (NaOH) = (Volume (CH3CO₂H) × 0.50 M × 0.5623) / 1.00 M

Volume (NaOH) = (250 mL × 0.50 M × 0.5623) / 1.00 M

Volume (NaOH) ≈ 70.57 mL

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Answer:

11690J

Explanation:

Use formula Q = mL

where:

Q = Energy (J)

m = Mass (g)

L = Latent heat of fusion for water (J/g) = 344J/g

Therefore:

Q = 35.0 x 344

Q = 11690J

Answer:

The correctly written thermochemical equation is:

C3H8 (g) + 5O2 (g) → 3CO2 (g) + 4H2O (l), ΔH = -2,220 kJ/mol

This equation represents the combustion of propane (C3H8) in the presence of oxygen (O2) to produce carbon dioxide (CO2) and water (H2O), with a heat release of -2,220 kJ/mol. The state symbols (g) for gases and (l) for liquids indicate the physical state of each substance at standard conditions.

Explanation:

ABOVE

The  name of the organic compound with structural formula of nine carbons and sixteen hydrogens  depends on different factors

The nomenclature of the organic molecule comprising nine carbons and sixteen hydrogens is determined by the arrangement of its atoms as well as the nature of the chemical bonds linking them together. Cyclononane is a circular formation of nine carbon atoms.

An organic substance belongs to a group of chemicals that have carbon atoms linked to each other and other atoms through covalent bonds, and are present in the biological cells. Organic compounds contain usual elements such as carbon, as well as hydrogen, oxygen, and nitrogen.

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Answer:

3:372-88U:771-772828