2.
Which mixture could be a useful buffer in a solution?

acetic acid (CH3CO2H) and hydrochloric acid (HCl)
sodium hydroxide (NaOH) and elemental sodium (Na)
ammonia (NH3) and ammonium chloride (NH4Cl)
acetic acid (CH3CO2H) and ammonia (NH3)


Pls answer quickly

Answer:

D) SrCO3(s) + 2 HNO2(aq) → Sr(NO2)2 + H2O + CO2(g)

Explanation:

When an acid react with carbonate, it produces nitrate, carbon-dioxide gas and water molecule. When nitrous acid react with Strontium carbonate, three products are formed i. e. Strontium nitrate, carbon-dioxide gas and water. In the reaction, both nitrous acid and Strontium carbonate exchange their partners with each other and forming a different products.

Answer:

Option E is correct.

The net ionic equation is given as

SrCO₃(s) + 2H⁺ → Sr²⁺ + H₂O + CO₂(g)

Explanation:

When acids react with carbonate compounds, it leads to the liberation of CO₂, hence, when an aqueous solution of HNO₂ is poured onto a solid pile of SrCO₃, the balanced overall equation is given as

SrCO₃(s) + 2HNO₂(aq) → Sr(NO₂)₂ + H₂O + CO₂(g)

But for the net ionic reaction, it is obtained by eliminating ions that occur on both sides of the overall reaction. Note that ions exist onlubone the aqueous compounds.

Hence, the two aqueous compounds that exist in the balanced overall equation are

2HNO₂(aq) on the left hand side and Sr(NO₂)₂ on the right hand side

In their ionic form, 2HNO₂ ⇌ 2H⁺ + 2NO₂⁻

And Sr(NO₂)₂ ⇌ Sr²⁺ + 2NO₂⁻

And it is evident that the ion that occurs on both sides and needs to be deleted is NO₂⁻,

Hence, the net ionic equation is

SrCO₃(s) + 2H⁺ → Sr²⁺ + H₂O + CO₂(g)

Hope this Helps!!!

Bonds 2: Diene has a double bond; in the final product, it will become a single bond.

Our deciding factor will be the dinophile's single bond, which is one of five and determines how these two react as a product.

With the chemical formula COCH 3 and the structural formula C(=O)CH 3, acetyl is a functional group in organic chemistry. When referring to it, the letter A is sometimes used (not to be confused with the element actinium). Despite its infrequent use, acetyl is referred to as ethanoyl in IUPAC nomenclature.

The functional groups carboxyl, which is present in carboxylic acids, hydroxyl, which is present in alcohols and phenols, and carbonyl are frequently encountered.

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In order to test for ammonia, a moist red litmus paper should be held over the test tube containing the ammonia.  Option 3.

Ammonia is a substance that is alkaline in nature. All alkaline substances are able to turn red litmus paper to blue. This is in opposition to acidic substances that turn blue litmus paper to red.

Thus, the first test that can be used to determine if a substance is ammonia would be to hold a moist red litmus paper over the test tube containing the suspected substance.

Since ammonia is gas at room temperature, the substance suspected to be ammonia will diffuse from the test tube to turn the moist red litmus paper to blue.

Other methods to test for ammonia include passing a test tube containing hydrochloric acid over the test tube containing the substance. A white fume of ammonium chloride will confirm the presence of ammonia.

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Answer:

3N of sulfuric acid.

Explanation:

Remember that normality is a measure of concentration equal to the gram equivalent weight per liter of solution.

First, let's see the equation of normality:

And let's see that sulfuric acid (H2SO4) is a diprotic acid because it contains 2 protons in its structure (2H+), so we're going to use this value to calculate the equivalent mass of solute.

Now, let's replace the given data: molarity is 1.5 M, the molecular mass of solute is the molecular mass of H2SO4 which is 98 g/mol (you can calculate the molecular mass of a compound using the periodic table) and the equivalent mass of solute is the division between molecular mass and the number of protons, in this case, 2:

The normality of this solution would be 3N.

A container with a volume of nitrogen gas is filled to 1.50 atm of pressure and 23°C of temperature. Compute the amount of gas in moles led with as at 2.91 moles is 18.87 liters.

The three gas laws that make up the combined gas law, also known as a general gas equation, are Charle's law, Boyle's law, and Gay-Lussac law. The law shows the link between temperature, volume, and pressure for a given amount of gas.

PR/T=V

V= 2.91×150/23

V=18.87liters

According to Boyle's Law, gas volume increases as pressure lowers. Charles' Law states that a gas expands as its temperature rises. Also, according to Avogadro's Law, a gas's volume increases as its concentration does.

Either the total amount of gaseous substance or the number of gas moles.

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If a reaction has a negative ΔG and a positive ΔS, the reaction will be spontaneous at all temperatures.

If a reaction is spontaneous at all temperatures, it implies that the reaction will occur without the need for any external intervention, such as the addition of energy. For a reaction to be spontaneous, it must satisfy the criteria of thermodynamic favorability, which is determined by the change in Gibbs free energy (ΔG) associated with the reaction.

The relationship between ΔG, temperature (T), and the equilibrium constant (K) of a reaction is described by the equation ΔG = ΔH - TΔS, where ΔH is the change in enthalpy and ΔS is the change in entropy.

To ensure spontaneity at all temperatures, two conditions must be met:

ΔG must be negative: A negative ΔG indicates a thermodynamically favorable reaction, meaning the products have a lower Gibbs free energy than the reactants. If ΔG is negative, the reaction will proceed spontaneously in the forward direction.

ΔS must be positive: A positive ΔS signifies an increase in the overall entropy of the system. Higher entropy means more disorder, and spontaneous reactions often involve an increase in randomness. When ΔS is positive, it can compensate for the enthalpic term, ΔH, allowing the reaction to proceed spontaneously.

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Answer:

100cg-1g

Explanation:

This is because for:

10m=100dm

1ml = 0.001L

1000000cm3=1L

100cg=1g

The rate constant of the second-order reaction is 0.111 M^-1 min^-1.

The given data represents a second-order reaction where the rate of the reaction is proportional to the square of the concentration of A.

The integrated form of the second-order reaction is:

1/[A]t = kt + 1/[A]0

where [A]t and [A]0 are the concentrations of reactant A at time t and time zero, respectively, k is the rate constant.

We can use the given information to calculate the rate constant (k) of the reaction for the given half-life (t1/2) of 3.15 minutes:

t1/2 = (1 / k[A]0)

Using the percentage decrease in concentration and the given initial concentration, we can calculate the concentration of A at time t:

[A]t = [A]0 - 0.30[A]0 = 0.57126 M

Substituting the given values, we get:

3.15 min = (1 / k)(0.0818 M) / (0.0818 M - 0.57126 M)

Simplifying the equation above, we can solve for k:

k = 0.111 M^-1 min^-1

Therefore, the rate constant of the second-order reaction is 0.111 M^-1 min^-1.

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Answer:

b,a,b

Explanation:

The energy transfers and transformations that occur are kinetic energy is from the person's legs to the pedals and thermal energy due to friction when the wheels get warm.

The law of conservation of energy states that energy can neither be created nor destroyed but can be converted from one form to another.

The energy transfers and transformations that occur when a person rides a bicycle are:

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Answer:

Mean: 350

Median: 300

Range: 650

Mode: 300

Explanation:

Mean: 800+300+150+300+200= 1750, 1750 divided by 5 = 350

You add up all the numbers then you divide it by the TOTAL NUMBER of NUMBERS to find the mean.

Median: (150, 200, 300, 300, 800)

To find Median put the numbers in order from greatest to least then you choose the middle number.

Range: Range is the distance from the smallest number to the largest the way to solve this is (Highest number) - (lowest number). In your case its 800-150 which equals 650

Mode: The mode is the value that appears most frequently in a data set.

Brainliest?

\(\\ \sf\longmapsto 2C_6H_6+15O_2\longrightarrow 6H_2O+12CO_2\)

On reactant side

On products side

Hence balanced

Answer:

Percent yield of reaction is 150%.

Explanation:

Given data:

Percent yield = ?

Actual yield of SO₃ = 586.0 g

Mass of SO₂ = 705.0 g

Mass of O₂ = 80.0 g

Solution:

Chemical equation:

2SO₂ + O₂      →     2SO₃

Number of moles of SO₂:

Number of moles = mass/ molar mass

Number of moles = 586.0 g/ 64.1 g/mol

Number of moles = 9.1 mol

Number of moles of O₂:

Number of moles = mass/ molar mass

Number of moles = 80.0 g/ 32g/mol

Number of moles = 2.5 mol

Now we will compare the mole of SO₃ with O₂ and SO₂.

                      SO₂          :          SO₃

                        2             :            2

                     9.1              :           9.1

                       O₂            :          SO₃

                        1              :            2

                     2.5             :           2×2.5 = 5

The number of moles of SO₃ produced by oxygen are less it will limiting reactant.

Theoretical yield of SO₃:

Mass = number of moles × molar mass

Mass = 5 mol × 80.1 g/mol

Mass = 400.5 g

Percent yield of reaction:

Percent yield = actual yield / theoretical yield  × 100

Percent yield = 586.0 g/ 400.5 g× 100

Percent yield = 1.5× 100

Percent yield = 150%

Answer:.

Explanation: Matter must have Mass and Volume to be considered matter!

The number of moles of gas produced from the reaction of 2.00g of potassium with an excess amount of water is 0.025 moles.

The reaction of potassium with an excess amount of water is:

2K + 2H\(_2\)O \(\rightarrow\) 2KOH + H\(_2\)

To calculate the moles of hydrogen gas first we need to calculate moles of potassium in 2.00g

No. of moles = (mass) / (molecular mass)

The mass given is 2.00 g and the Molecular mass is 39.09 units

∴ No. of moles = (2) / (39.09) = 0.05

From the above reaction, we get that 2 moles of potassium give 1 mole of hydrogen gas. Thus, 0.05 moles of potassium gives 0.025 moles of hydrogen gas.

Therefore, the no. of moles of hydrogen gas produced is 0.025 moles.

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Answer:

See explanation

Explanation:

The reaction with \(OsO_4\) and \(NaHSO_3\)  will add two "OH" groups to the molecule. In the reaction (figure 1) we can see the different structures for the alkenes. In the Z alkene (cis) we have the 2 methyl groups on the same side. In the E alkene (trans) the 2 methyl groups are placed on opposite sides. In the products, all the "OH" groups are placed at the top. This indicates that the addition of the hydroxyl groups is "syn". In the syn reactions, all the groups are bonded on the same side therefore we will have a stereospecific reaction.

I hope it helps!

Answer:

Explanation:

The density of a substance can be found by using the formula

\(density = \frac{mass}{volume} \\\)

From the question

mass = 4.05 g

volume = 28 mL

We have

\(density = \frac{4.05}{28} \\ = 0.1446428571...\)

We have the final answer as

Hope this helps you

The equilibrium constant Keq is the ratio of product of concentration of products in a reaction to that reactants. In the given reaction the equilibrium constant is 1.05 × 10²⁴.

The equilibrium constant in a reaction is the ratio of product of molar concentrations of products to the product of molar concentration of the reactants in the reaction.

In the given reaction, the product is PCl₅ and reactants are Cl₂ and PCl₃. Thus the expression for Keq is written as:

\(Keq = \frac{[PCl_{5}]}{[PCl_{3}][Cl_{2}]}\)

Apply the number of moles and volume of all the reactants and products in this expression.

Keq = (2.01 × 10²¹molecules /1 L ) [(0.12/1L) (0.15/ 1L)]

      = 1.05 × 10²⁴

Hence, the equilibrium constant Keq is 1.05 × 10²⁴.

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Explanation:

From the image given;

Number of Protons = 1

Number of Electrons = 1

Number of Neutrons = 0

Positive Charge (From the protons) = + 1

Negative charge (From the electrons) = -1

Atomic mass = Mass of Proton + Mass of Neutron = 1.00727647 amu + 0.000549 amu = 1.00784 amu

Overall Charge = Positive charge + Neutral charge = 1 -1 = 0 (Neutral atom)

The rate is reduced by a factor of 3/4, or 0.75, when the concentration of A is tripled and the concentration of B is reduced by a factor of 4.

To determine the factor by which the rate changes when the concentrations of reactants are altered, we need to examine the reaction's rate law. However, since the rate law is not provided, we'll assume a simplified scenario where the reaction rate is directly proportional to the concentrations of A and B.

Let's assume the initial rate of the reaction is R₀, and the concentrations of A and B are [A]₀ and [B]₀, respectively. According to the assumed rate law, the rate can be expressed as:

Rate = k[A][B]

Now, let's consider the changes in concentrations and calculate the new rate.

If the concentration of A is tripled, the new concentration becomes 3[A]₀, while the concentration of B is reduced by a factor of 4, resulting in [B] = (1/4)[B]₀.

The new rate (R) can be calculated as follows:

R = k[3[A]₀][(1/4)[B]₀]

= (3/4)k[A]₀[B]₀

= (3/4)R₀

Therefore, the rate is reduced by a factor of 3/4, or 0.75, when the concentration of A is tripled and the concentration of B is reduced by a factor of 4.

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Answer:

A

Explanation:

the enzyme is substrate specifix coz of this trait

Answer:

1.E25 it is the answer the answer to mass of 1×10^25 molecules of water​

Explanation:

this is just EXPLINATION find your answer using this

first divide the number of molecules by Avogadro's number 6.022*10^25

you will

l get no. of Moles of water

multiply the no. of Moles with mass of 1 Mole of water 18g per mole

if get answer you comment

you should try on your own you will understand better

Because a greater proportion of the Y2Y2 molecules will have the required energy to break through the activation energy barrier, line B will shift to the left.

Any group of atoms joined together by chemical bonds is referred to as a molecule. A molecule is created from any two atoms together. A compound is an organic molecule composed of atoms from several elements. Not all molecules are compounds, yet all molecules are compounds.

A substance like table salt (NaCl), which is formed of two different types of elements (sodium and chlorine), is a compound, but it is not a molecule since the connection that binds NaCl together is an ionic bond.

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Why do diamonds have these properties ​?

A carbon atom can form four covalent bonds. This lets the carbon atom form many organic compounds (e.g. Diamond).

Diamond has a covalent structure in which:

1) Each carbon atom is joined to four other carbon atoms by covalent bonds.

2) The carbon atoms have a regular lattice arrangement.

3) It doesn't have free electrons

The strong structure, held together by strong covalent bonds, makes diamond very hard.

The process decomposes dinitrogen pentoxide into nitrogen dioxide and oxygen. The reaction has a rate constant of 5.8103/s (5.8 10 3 / s).

According to the process described below, the thermal breakdown of N₂O₅ follows first order kinetics: N₂O₅→2NO₂+12O₂. Find the rate constant of the reaction if the starting pressure of N₂O₅   is 100 mm and the pressure created after 10 minutes is 130 mm.

The breakdown of N₂O₅  according to the equation: 2N₂O₅ (g)4NO₂(g)+O₂(g) is a first-order reaction. After 30 minutes of decomposition in a closed vessel, the total pressure created is 284.5 mm of Hg, and after full decomposition, the total pressure is 584.5 mm of Hg.

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Answer:

D. Potential

Explanation:

Answer:

Potential

Explanation:

Gravitational potential is the energy the object has of it's position of the earth's surface. When the object is lifted, work is done.  When work is done in raising the height of an object, energy is transferred as a gain in the gravitational potential energy of the object.

Answer:

expressed in moles

a)0.1 moles

b)2.99 moles

c)0.5 moles

molarmass of the substances

a)26g/mol

b)14g/mol

c)17g/mol

Explanation:

remember

1mole=6.02×10^23molecules

The expressions in moles are:

The molar masses of the substances are:

In more detail, the number of particles in a substance can be expressed in terms of moles. A mole is defined as the number of particles in a substance that contains Avogadro's number of particles, which is 6.02 x 10²³. To convert the number of particles in a substance to moles, we divide the number of particles by Avogadro's number.

The molar mass of a substance is the mass of one mole of the substance, expressed in grams. The molar mass of a substance can be calculated by summing up the atomic masses of all the atoms in the substance.

A) 6.02 x 10²² C₂H₂ molecules:

1 mole = 6.02 x 10²² particles

0.1 moles = (6.02 x 10²² particles) / (6.02 x 10²³ particles/mole) = 6.02 x 10²² particles / 6.02 x 10²³ particles/mole = 1 mole / 6.02 x 10²³ = 0.1 moles

B) 1.80 x 10¯¹⁰²⁴ nitrogen atoms:

1 mole = 6.02 x 10²³ particles

2.99 moles = 1.80 x 10¯¹⁰²⁴ particles / (6.02 x 10²³ particles/mole) = 1.80 x 10¯¹⁰²⁴ particles / 6.02 x 10²³ particles/mole = 2.99 moles

c) 3.01 x 10²³ NH3 molecules

1 mole = 6.02 x 10²³ particles

0.5 moles = 3.01 x 10²³ particles / (6.02 x 10²³ particles/mole) = 3.01 x 10²³ particles / 6.02 x 10²³ particles/mole = 0.5 moles

The molar mass of C₂H₂ is calculated by summing up the atomic masses of carbon (12 g/mol) and hydrogen (1 g/mol) in the molecule.

The molar mass of nitrogen is calculated based on the atomic mass of nitrogen (14 g/mol).

The molar mass of NH3 is calculated by summing up the atomic masses of nitrogen (14 g/mol), and hydrogen (1 g/mol) in the molecule.

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Answer:

The human cheek cell is a good example of a typical animal cell. It has a prominent nucleus and a flexible cell membrane which gives the cell its irregular, soft-looking shape.

The mass of P-32 remaining after 27 days, if the initial mass is 40g is 10.5 g.

The half-life of a radioactive isotope is the amount of time it takes for one-half of the radioactive isotope to decay.

The half-life of a specific radioactive isotope is constant; it is unaffected by conditions and is independent of the initial amount of that isotope.

The number of half lives in 27 days;

n = 27 days/14 days

n = 1.929

The mass of P-32 remaining after 27 days, if the initial mass is 40g;

mass remaining = 40 g / (2^1.929)

mass remaining = 40 g / 3.808

mass remaining = 10.5 g

Thus, the mass of P-32 remaining after 27 days, if the initial mass is 40g is 10.5 g.

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