Answer:
The balanced chemical equation for the reaction of nitrogen gas (N2) with hydrogen gas (H2) to form ammonia gas (NH3) is:
N2 + 3H2 → 2NH3
According to the stoichiometry of the reaction, 1 mole of N2 reacts with 3 moles of H2 to produce 2 moles of NH3. Therefore, the ratio of N2 to NH3 is 1:2.
To find the amount of NH3 produced when 649 grams of N2 react completely, we need to use the mole ratio between N2 and NH3:
1 mol N2 → 2 mol NH3
First, we need to calculate the number of moles of N2 in 649 grams:
Number of moles of N2 = Mass of N2 / Molar mass of N2
= 649 g / 28.014 g/mol
= 23.173 mol N2
According to the stoichiometry of the reaction, 1 mole of N2 reacts to produce 2 moles of NH3. Therefore, the number of moles of NH3 produced can be calculated as:
Number of moles of NH3 = 2 x Number of moles of N2
= 2 x 23.173 mol
= 46.346 mol NH3
Finally, we can use the molar mass of NH3 to convert the number of moles to grams:
Mass of NH3 = Number of moles of NH3 x Molar mass of NH3
= 46.346 mol x 17.031 g/mol
= 789.5 g NH3
Therefore, 649 grams of N2 react completely to produce 789.5 grams of NH3.
C c Why did they work an average brightness for each length of graphite tested?
An average brightness was calculated for each length of graphite tested to get a better understanding of the relationship between the length of the graphite and the brightness of the line it produced.
What is the use of graphite?Graphite has many uses in various industries. Some of its uses include: Pencils, Lubricants, Refractories, Batteries, Electrodes, Nuclear reactors, Aerospace industry.
By calculating the average, it is possible to see if there is a trend in the data and if longer or shorter lengths of graphite produce brighter or duller lines. This information can be useful in determining the best length of graphite to use for a particular task or project.
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A filtration system continuously removes water from a swimming pool, passes the water through filters, and then returns it to the pool. Both pipes are located near the surface of the water. The flow rate is 15 gallons per minute. The water entering the pump is at 0 psig, and the water leaving the pump is at 10 psig.
A. The diameter of the pipe that leaves the pump is 1 inch. How much flow work is done by the water as it leaves the pump and enters the pipe?
B. The water returns to the pool through an opening that is 1.5 inches in diameter, located at the surface of the water, where the pressure is 1 atm. How much work is done by the water as it leaves the pipe and enters the pool?
C. "The system" consists of the water in the pump and in the pipes that transport water between the pump and the pool. Is the system at steady state, equilibrium, both, or neither?
Answer:
A . \(\mathbf{W = 7133.2 \dfrac{ft. lb_f}{min} }\)
B. \(\mathbf{W = 4245.24 \dfrac{ft. lb_f}{min} }\)
C. The system is at steady state but not at equilibrium
Explanation:
Given that:
The volumetric flow rate of the water = 15 gallons per minute
The diameter of the pipe that leaves the pump is 1 inch.
A. The objective here is to determine how much work flow is done by the water as it leaves the pump and enters the pipe
The work flow that is said to be done can be expressed by the relation :
W = P × V
where;
P = pressure
V = volume
Also the given outlet pressure is the gauge pressure
The pressure in the pump P is can now be expressed by the relation:
\(P_{absolute} = P_{guage} + P_{atmospheric}\)
\(P_{absolute}\) = 10 psig + 14.7 psig
\(P_{absolute}\) = 24.7 psig
W = P × V
W = 24.7 psig × 15 gal/min
\(W = (24.7 \ psig * \dfrac{\frac{lb_f}{in^2}}{psig}) * ( 15 \frac{gal}{min}* \dfrac{0.1337 \ ft^3}{1 \ gal }* \dfrac{144 \ in^2}{1 \ ft^2})\)
\(\mathbf{W = 7133.2 \dfrac{ft. lb_f}{min} }\)
Thus ; the rate of flow of work is said to be done by the water at \(\mathbf{W = 7133.2 \dfrac{ft. lb_f}{min} }\)
B.
Given that :
The water returns to the pool through an opening that is 1.5 inches in diameter.
where the pressure is 1 atm.
Then ; the rate of work done by the water as it leaves the pipe and enter the pool is as follows:
W = P × V
W = 1 atm × 15 gal/min
\(W = 1 \ atm * ( 15 \frac{gal}{min}* \dfrac{0.1337 \ ft^3}{1 \ gal }* \dfrac{144 \ in^2}{1 \ ft^2})\)
\(\mathbf{W = 4245.24 \dfrac{ft. lb_f}{min} }\)
Thus ; the rate of flow of work done by the water leaving the pipe and enters into the pool is at \(\mathbf{W = 4245.24 \dfrac{ft. lb_f}{min} }\)
C.
We can consider the system to be at steady state due to the fact that; the data given for the flow rate and pressure doesn't reflect upon the change in time in the space between the pump and the pool.
On the other-hand the integral factor why the system is not at equilibrium is that :
the pressure leaving the pipe is different from that of the water at the surface of the pool as stated in the question.
why does glass containing an iced beverage feel cold
Answer:
Molecules in the skin are moving faster than molecules in the glass.
Explanation:
Put it in your own words.
Answer:
The energy from the ice transferred to the glass.
Compare and contrast cations and anions and give an example of each.
Cations are positively charged particles while anions are negatively charged particles. They both have different forces therefore they are attract each other.
What is cation ?
Positively charged ions are known as cations. Negatively charged ions are referred to as anions. A charged atom or molecule is an ion. A balanced atom will become a positively charged cation if it loses one or more electrons.
An ion that has lost one or more electrons and now has a net positive charge is said to be a cation. The cation of an atom is smaller than the neutral atom because one or more electrons are taken out to produce a cation.
As an electron donor, the cathode has the potential to initiate reduction. Positive ions from the solution will be drawn to the negatively charged electrode by its charge. It can provide some of the extra electrons it has to these cations or other species in the electrolyzing liquid.
Thus, Cations and anions both have different forces therefore they are attract each other.
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What is the correct name for the compound FeF3?Iron (III) fluorineIron (III) fluorideIron fluorideIron (I) fluoride
Iron (III) fluoride
Explanations:Accoridng to the question, we are to name the compound FeF3. The compound consist of 3 flouride atoms and 1 iron atom.
When naming such compounds in the old ways, it is Iron triflouride or ferric flouride. The new way of naming the compound FeF3 is Iron (III) fluoride
In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide Al2O3 dissolved in molten cryolite Na3AlF6, resulting in the reduction of the Al2O3 to pure aluminum. Suppose a current of 100.A is passed through a Hall-Heroult cell for 41.0 seconds. Calculate the mass of pure aluminum produced. Round your answer to 3 significant digits. Also, be sure your answer contains a unit symbol.
Answer:
0.382g
Explanation:
Step 1: Write the reduction half-reaction
Al³⁺(aq) + 3 e⁻ ⇒ Al(s)
Step 2: Calculate the mass of Al produced when a current of 100. A passes through the cell for 41.0 s
We will use the following relationships.
1 A = 1 C/s1 mole of electrons has a charge of 96486 C (Faraday's constant)1 mole of Al is produced when 3 moles of electrons pass through the cell.The molar mass of Al is 26.98 g/mol.The mass of Al produced is:
\(41.0s \times \frac{100C}{s} \times \frac{1mole^{-} }{96486C} \times \frac{1molAl}{3mole^{-} } \times \frac{26.98gAl}{1molAl} = 0.382gAl\)
write the condensed (noble-gas) electron configuration of iodine. for multi-digit superscripts or coefficients, use each number in succession.
Iodine, its atomic number is 53. Its complete electron configuration is 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁵ or [Kr] 5s² 4d¹⁰ 5p⁵.
The electron configuration of an atom is the representation of the arrangement of electrons distributed among the orbital shells and subshells.
The four different types of orbitals, s,p,d, and f have different shapes, and one orbital can hold a maximum of two electrons.
The p, d, and f orbitals have different sublevels, thus can hold more electrons. As stated, the electron configuration of each element is unique to its position on the periodic table.
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What is the density of a piece of granite whose volume is 20 mL and mass is 53
grams?
3.05 g/mL
2.75 g/mL
4.0 g/mL
2.65 g/mL
2.65g/ml is the density of a piece of granite whose volume is 20 mL and mass is 53grams. Density is the mass of a specific material per unit volume.
What is density?Density is the mass of a specific material per unit volume. Density is defined as d = M/V, in which d represents density, M is weight, as well as V is volume. Density is generally expressed in grams every cubic centimetre. Water, for example, has a density of 1 gram per square centimeter, but Earth has a density of 5.51 kilograms per cubic centimetre.
Density is sometimes measured in kilos per cubic centimeter (in metre-kilogram-second or SI units). The density of air, for example, is 1.2 kilos per cubic metre.
density = mass / volume
=53/ 20
=2.65g/ml
Therefore, 2.65g/ml is the density of a piece of granite whose volume is 20 mL and mass is 53grams.
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1. A student dissolved 36.8 grams of KF into 1.2 L of water. What is molarity of the final solution?
The molarity of the final solution is 1.00 M.
The molarity of the final solution when a student dissolved 36.8 grams of KF into 1.2 L of water is 1.00 M.Molarity is a unit of concentration that measures the amount of a solute present in a solution. Molarity is defined as the number of moles of solute per liter of solution.
The formula for molarity is given as;Molarity (M) = moles of solute / liters of solution.The following steps should be followed to calculate the molarity of a solution:Convert the mass of the solute to moles using its molar mass.Divide the number of moles of solute by the volume of the solution in liters.
The volume of the solution in liters can be measured in any units (mL, L, etc.).
Example:A student dissolved 36.8 grams of KF into 1.2 L of water.
Mass of KF = 36.8 gMolar mass of KF = 58.1 g/mol
Number of moles of KF = mass / molar mass= 36.8 / 58.1= 0.632 M
Divide the number of moles of solute by the volume of the solution in liters= 0.632 M / 0.6 L= 1.00 M
Therefore, the molarity of the final solution is 1.00 M.
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Which equation shows an increase in entropy?
Hint: Look at the states of matter, g s l, of the chemicals in each equation. A C2H4(g) + H2(g) + C2H6(g) в Caco3(9) + Cao(s) - CO2(g) c Fe(s) + S (s) -+ FeS (s)
The equation C2H4(g) + H2(g) + C2H6(g) → Caco3(s) + Cao(s) + CO2(g) shows an increase in entropy due to the formation of a gas as a product. Option A
In this equation, the reactants on the left-hand side consist of gases (C2H4 and H2), while the products on the right-hand side include a solid (Caco3) and a gas (CO2).
When a reaction involves a change from gaseous to solid or liquid states, there is typically a decrease in entropy because the particles become more ordered and constrained in the solid or liquid phase.
Conversely, when a reaction involves the formation of gases, there is generally an increase in entropy because gases have higher degrees of molecular motion and greater freedom of movement compared to solids or liquids.
In the given equation, the reactants include three gaseous compounds (C2H4, H2, and C2H6), and one of the products is a gas (CO2). Therefore, the overall entropy of the system increases during this reaction.
The equation Fe(s) + S(s) → FeS(s) does not show an increase in entropy. Both the reactants (Fe and S) and the product (FeS) are solids. Since solids have lower entropy compared to gases or liquids, the entropy of the system does not increase in this reaction. Option A
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A cell is placed in a salt solution that has the same concentration as the inside of the cell. What will happen to the cell
A. The cell will contract
B. The cell will expand slightly
C. The cell will burst
D. The cell will remain the same size
By the way I had to ask again because I f forgot to put the answer choices
Answer:
B
Explanation:
If not B then its d
Answer:
D
Explanation:
This would be an isotonic solution. If a cell is placed in a solution of salt with the same concentration of salt in the cell, nothing will happen.
what is the difference between modernism and postmodernism in literature
In contrast to postmodernism, which makes explicit use of older styles and traditions, modernism is defined by a radical departure from the established forms of prose and verse.
The literary movement known as modernism rose to prominence around the start of the twentieth century. Moreover, historical occurrences like the World Wars, industrialization, and urbanisation had a significant impact on this literary form. People began to doubt the tenets of western culture and the course of humanity in the wake of these types of occurrences. As a result, writers who identified as modernists started to write about the downfall of society, the inner self, and awareness. Additionally, a sense of disappointment and disintegration may be seen in their art.
Modernist authors frequently employed the stream of consciousness approach to describe the many ideas and emotions that go through the mind. In addition, writers frequently employed irony, satire, and comparison to highlight the flaws in society.
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What is the coefficient of aluminum (Al)?
( I’m confused because I’m not sure whether it wants the Al from the reactants or products side )
Answer:
answer : a. 4
explanation:
if u look at the reactants, the coefficient of the Al is 4, while the product the coefficient is 2. By the way, if u look properly u can see that at the product side, the Al is written as Al2, which means that, the coefficient 2 is need to be multiply by 2 from the Al2.
Reactant = 4Al
Product = 2Al2, therefore the 2 at the Al2, should be multiply be the coefficient to make it 4.
What areas of the work force can science be applied to?
Select all that apply
Answer:
1. the study of the structure, properties, and interactions of materials and the changes they undergo
2. the study of matter and energy and how they interact
3. the systematic study and analysis of facts
4. a process to test a proposed solution to a problem
Click again to see term
Until the 1600s, people who investigated problems related to our understanding of the natural world were called _____.
Click ca
Explanation:
even one or two crystals of copper sulphate can make its solution in water coloured blue. why
How many moles of aluminum ions al3+ are present in 0.42 mol of al2so43
There are 0.84 moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3.
To determine the number of moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3, we need to consider the stoichiometry of the compound.
The formula of aluminum sulfate (Al2(SO4)3) indicates that for every 1 mole of the compound, there are 2 moles of aluminum ions (Al3+). This means that the mole ratio of Al3+ to Al2(SO4)3 is 2:1.
Given that we have 0.42 mol of Al2(SO4)3, we can calculate the moles of Al3+ as follows:
Moles of Al3+ = 0.42 mol Al2(SO4)3 x (2 mol Al3+ / 1 mol Al2(SO4)3)
Moles of Al3+ = 0.42 mol Al2(SO4)3 x 2
Moles of Al3+ = 0.84 mol Al3+
Therefore, there are 0.84 moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3.
It's important to note that the stoichiometry of the compound determines the mole ratio between the different species involved in the chemical formula. In this case, the 2:1 ratio of Al3+ to Al2(SO4)3 allows us to determine the number of moles of Al3+ based on the given amount of Al2(SO4)3.
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La
Nd
Pm
Sm
Tb
Но
Er
Tm
Yb
Lu
Ac
Np Pu Am Cm Bk
CH
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Fm Md No
100 g of acetic acid (CH, COOH) is dissolved in a 500.0 ml solution. What is the molarity? Report your answer with the
correct number of significant figures
Answer:
3.34 M
Explanation:
Step 1: Given data
Mass of acetic acid: 100 gVolume of solution (V): 500.0 mL (0.5000 L)Step 2: Calculate the moles of acetic acid
The molar mass of acetic acid is 60.05 g/mol.
100 g × 1 mol/60.05 g = 1.67 mol
Step 3: Calculate the molarity of acetic acid
The molarity is equal to the moles of solute divided by the liters of solution.
M = n/V
M = 1.67 mol/0.5000 L = 3.34 M
How does soil convert the organic matter back to co2
Acetaldehyde is a substance commonly used in chemical factories. It is often produced by
combining ethylene gas and oxygen gas.
Consider the following reaction:
12 molecules of ethylene (CH) react with 6 molecules of oxygen (O2) to produce some
amount of acetaldehyde (C,H,O).
Complete the table below.
Chemical element Number of atoms in the reaction
H
С
o
During this reaction, how many molecules of acetaldehyde (C2H,0) are produced?
There are 48 hydrogen atoms, 24 carbon atoms, and 12 oxygen atoms, also 12 molecules of acetaldehyde were produced in the reaction.
The equation of the reaction is;
12C2H4 + 6O2 ------> 12 CH3CHO
In order to approach this problem, the balanced reaction equation is the first step. There are 12 ethylene molecules and six oxygen molecules. These will combine as shown.
There number of atoms involved are as follows;
H = 48
C = 24
O = 12
There are 12 molecules of acetaldehyde produced in the reaction.
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Which amphibian organ has a high blood supply and many folds to increase surface area?
a. heart
b. stomach
c. lungs
d. brain
Answer:
lungs
Explanation:
An isotope with the combination of subatomic particles (69n,50p+,50e-) is?
Answer:
A typical atom consists of three subatomic particles: protons, neutrons, and electrons (as seen in the helium atom below). Other particles exist as well, such as alpha and beta particles (which are discussed below). The Bohr model shows the three basic subatomic particles in a simple manner. Most of an atom's mass is in the nucleus—a small, dense area at the center of every atom, composed of nucleons. Nucleons include protons and neutrons. All the positive charge of an atom is contained in the nucleus, and originates from the protons. Neutrons are neutrally-charged. Electrons, which are negatively-charged, are located outside of the nucleus.
Explanation:
A reaction A(aq)+B(aq)↽−−⇀C(aq) A ( aq ) + B ( aq ) ↽ − − ⇀ C ( aq ) has a standard free‑energy change of −3.06 kJ/mol − 3.06 kJ / mol at 25 °C. 25 °C. What are the concentrations of A, A , B, B , and C C at equilibrium if, at the beginning of the reaction, their concentrations are 0.30 M, 0.30 M, 0.40 M, 0.40 M, and 0 M, 0 M, respectively?
At equilibrium, A= 0.30 M, B= 0.40 M, and C = 0.402 M.
What is energy?Energy is a physical quality that makes things capable of performing work. To put it another way, it is the capacity to bring about change or carry out a task. There are various types of energy.
How do you determine it?The equilibrium constant (K) of the reaction and the standard free-energy change for the process are connected.
G=-RT ln K
where ln is the natural logarithm, T is the temperature in kelvin (298 K for 25°C), G° is the standard free-energy change, R is the gas constant (8.314 J/mol K), and R is the gas constant.
If we rewrite this equation, we obtain:
ln K = -ΔG°/RT
Inputting the values provided yields:
ln K = -(-3060 J/mol)/(8.314 J/mol K × 298 K) = 1.207
The result of taking the antilogarithm of both sides is:
K = e^1.207 = 3.35
The equilibrium constant will result in the following relationships between the concentrations of A, B, and C at equilibrium:
K = C/AB
where [A], [B], and [C] represent the equilibrium concentrations of A, B, and C, respectively.
This equation can be used to find [C]:
3.35 = C/(0.30 M × 0.40 M)
C = 3.35 × 0.30 M × 0.40 M = 0.402 M.
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20.1 cm3 of metal hydroxide (MOH) containing 4.8 g/dm3 react Completely with 23.0 cm3 of the HCL and Containing 3.8g/dm3. Identify the metal of M of MOH
Answer:
A metal M readily forms water-soluble sulphate MSO4, water-insoluble hydroxide M(OH)2 and oxide MO. The oxide and hydroxide are soluble in NaOH. The M is:
Which of the following is an example of climate?
A. The polar regions have long winters and short, cool summers.
B. Humidity levels are high today.
C. Canada experienced an unusually warm summer this year.
D. Tornados formed across Oklahoma yesterday.
Answer:
A. The polar regions have long winters and short, cool summers.
Explanation:
Climate is location based, however is over long periods of time, so Canada would not be considered because it is only 1 summer
Given the following electronic configuration of neutral atoms, identify the element and state the number of unpaired electrons in its ground state. Example: [He]2s1 Answer: Li, 1 (one space between the comma and the number):
[Ar]4s13d5
The electronic configuration [Ar]4s13d5 corresponds to the element Manganese (Mn) in its ground state.
To determine the number of unpaired electrons, we need to first fill the 4s and 3d orbitals according to the Aufbau principle and Hund's rule. The 4s orbital can hold up to 2 electrons, and the 3d orbital can hold up to 10 electrons. In the case of Mn, the [Ar] noble gas configuration represents the completely filled inner shells, so we start by adding 4s1 electron and then 5 more electrons to the 3d orbital. We have:
1s2 2s2 2p6 3s2 3p6 4s1 3d5
We can see that there are five unpaired electrons in the 3d orbital (in the d-subshell, there are five unpaired electrons in the five available d-orbitals), which makes manganese a transition metal. Therefore, the number of unpaired electrons in the ground state of manganese is 5.
So, the answer is: Mn, 5.
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In a science demonstration, a teacher mixed zinc (Zn) with hydrogen chloride (HCl) in a flask and quickly attached a balloon over the mouth of the flask. Bubbles formed in the solution and the balloon inflated.
What most likely occurred during this demonstration?
a.The Zn and HCl both retained their identity.
b.Either Zn or HCl, but not both, retained its identity.
c.Evaporation of one of the substances occurred.
d.One or more new substances formed.
Answer:
a. The Zn and HCl both retained their identity.
Use the drop-down menus to rank the boiling points of the following hydrocarbons. Use a "1" to indicate the compound with the lowest boiling point. A carbon chain with 5 central carbons, with C H 3 bonded to the first, second, and last carbons in the chain. 2 central carbons with C H 3 bonded to the outside, and C H 3 bonded to the leftmost inside carbon. 2 central carbons, each with C H 3 bonded to them. A central C has H bonded left, above, behind to the right, and in front to the right.
The ranking of boiling point is based on the molecular weight and intermolecular forces between molecules.
2 central carbons, each with CH3 bonded to them. A central C has H bonded left, above, behind to the right, and in front to the right. A carbon chain with 5 central carbons, with CH3 bonded to the first, second, and last carbons in the chain. 2 central carbons with CH3 bonded to the outside, and CH3 bonded to the leftmost inside carbon.
In this case, all compounds are hydrocarbons, meaning they are non-polar molecules and exhibit van der Waals forces. However, the length of the carbon chain and the arrangement of atoms in the molecule affect the magnitude of these forces.
The first compound has only two carbons and exhibits weak intermolecular forces, so it has the lowest boiling point. The second compound has three carbons and a more complex arrangement of atoms, resulting in slightly stronger van der Waals forces and a higher boiling point.
The third compound has a longer carbon chain, which increases the molecular weight and results in stronger intermolecular forces, giving it a higher boiling point than the previous two. The fourth compound has the longest carbon chain and has multiple branches, which increases the surface area of the molecule and the strength of the intermolecular forces, giving it the highest boiling point.
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Answer:
The answers are 4, 2, 3, 1
Explanation:
give the result of the following expression with the correct number of significant figures
\(84 \frac{m}{s} \times 32.533s\)
Complete the table below by deciding whether a precipitate forms when aqueous solutions A and B are mixed. If a precipitate will form, enter its empirical formula in the last column.
solution A solution B Does a precipitate form when A and B are mixed? empirical formula of precipitate
zinc nitrate iron(II) iodide
yes
no
potassium bromide lead(II) nitrate
yes
no
ammonium bromide sodium hydroxide
yes
no
Answer:
1) No, 2) Yes, 3) Yes
Explanation:
Refer to solubility rules to understand if a precipitate occurs between a mix of solutions.
Two solutions form a precipitate if they react to yield an insoluble product.
Let us now consider each of the reacting species one after the other.
In the first case;
Zn(NO3)2(aq) + FeI2(aq) ----> ZnI2(aq) + Fe(NO3)2(aq)
The two products of the reaction are soluble so no precipitate is formed.
In the second case;
2KBr(aq) + Pb(NO3)2(aq) ------> 2KNO3(aq) + PbBr2(s)
An insoluble product PbBr2 is formed hence a precipitate is formed.
In the third case;
NH4Br(aq) + NaOH(aq) -------> NH4OH(aq) + NaBr(aq)
No insoluble product is formed so the there is no precipitate.
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7.0 x 10 -3 mol of I2 in 100.00ml of solution