Answers
Answer:
B
Step-by-step explanation:
Hope this Helped! Please tell me if I'm wrong!
Answer:A
Step-by-step explanation:
Related Questions
PLEASE HELP! GIVING POINTS!
Answers
a diagnostic test for a disease is such that it (correctly) detects the disease in 90% of the individuals who actually have the disease. also, if a person does not have the disease, the test will report that he or she does not have it with probability 0.9. only 3% of the population has the disease in question. if a person is chosen at random from the population and the diagnostic test indicates that she has the disease, what is the conditional probability that she does, in fact, have the disease? (round your answer to four decimal places.) are you surprised by the answer? would you call this diagnostic test reliable? this answer has not been graded yet.
Answers
The conditional probability that a person actually has the disease given a positive test result is approximately 0.0826 (rounded to four decimal places). This probability suggests that the test is not highly reliable.
To determine the conditional probability, we can use Bayes' theorem. Let's denote D as the event that a person has the disease and T as the event that the test result is positive. We are interested in finding P(D|T), the probability that a person has the disease given a positive test result.
According to the problem statement, P(D) = 0.03, which represents the probability that a person chosen at random from the population has the disease. The test has a sensitivity of 0.9, meaning that P(T|D) = 0.9, indicating that the test correctly detects the disease in 90% of individuals who actually have it.
Additionally, the test has a specificity of 0.9, implying that P(T|D') = 0.9, where D' represents the event that a person does not have the disease.
We can now apply Bayes' theorem:
P(D|T) = (P(D) * P(T|D)) / [P(D) * P(T|D) + P(D') * P(T|D')]
Substituting the known values:
P(D|T) = (0.03 * 0.9) / [(0.03 * 0.9) + (0.97 * 0.1)]
Calculating this expression yields P(D|T) ≈ 0.0826, or approximately 8.26%.
Given this result, it can be observed that the conditional probability of having the disease, given a positive test result, is relatively low. This suggests that the test is not highly reliable.
Although the test has a high accuracy in correctly identifying individuals without the disease, it has a significant false-positive rate when it comes to individuals who do have the disease. Therefore, it is important to consider other factors and confirmatory tests before reaching a conclusive diagnosis.
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Please awnser and make sure it’s to
Answers
Answer:
the third one
Step-by-step explanation:
I choose a random integer n between 1 and 10 inclusive. What is the probability that for the n I chose, there exist no real solutions to the equation x(x+5)=−n? Express your answer as a common fractio
Answers
The probability is 1/10.
The equation x(x+5) = -n can be rewritten as x^2 + 5x + n = 0. To find the solutions of this equation, we can use the quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a, where a = 1, b = 5, and c = n.
For there to be no real solutions, the discriminant (b^2 - 4ac) must be negative. The discriminant is 5^2 - 4(1)(n) = 25 - 4n. So for there to be no real solutions, 25 - 4n < 0, or n > 6.25.
Since the integer n is between 1 and 10 inclusive, the only value that would not have a real solution is n = 7. Therefore, the probability that for the randomly chosen n there exist no real solutions is 1/10.
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The greatest common divisor (GCD) of two integers is the largest integer that will evenly divide both integers. The GCD algorithm involves integer division in a loop, described by the following C++ code:int GCD(int x, int y)
{
x = abs(x); // absolute value
y = abs(y);
do {
int n = x % y;
x = y;
y = n;
} while (y > 0);
return x;
} Implement this function in assembly language and write a test program that calls the function several times, passing it different values. Display all results on the screen.
Answers
The given C++ code implements the Greatest Common Divisor (GCD) algorithm using integer division in a loop. To implement this algorithm in assembly language, we can use the same approach of dividing the larger number by the smaller number repeatedly until we get a remainder of zero.
The resulting quotient will be the GCD. A test program can be written in assembly language to call this function several times with different values and display the results on the screen. The assembly language implementation of the GCD algorithm can be done using the same basic approach as the C++ code. We start by taking the absolute values of the input integers, as the GCD is defined for positive integers. We then use a loop that repeatedly divides the larger integer by the smaller integer until the remainder becomes zero. At each iteration, we store the remainder in a temporary variable and swap the values of the two integers. We continue the loop until the smaller integer becomes zero. The last non-zero value of the larger integer will be the GCD. We can use the DIV instruction to perform the integer division, which takes the dividend in the DX:AX register pair and the divisor in a separate register. The quotient is stored in the AX register and the remainder in the DX register.
A test program can be written in assembly language to call the GCD function several times with different values and display the results on the screen. The program can use the INT 21H interrupt to display the output on the console. The input values can be read from the user using the INT 21H interrupt as well. The program can use a loop to repeatedly call the GCD function and display the results until the user decides to exit. Overall, implementing the GCD algorithm in assembly language is straightforward and can be done using simple arithmetic and looping constructs.
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How to find the volume of a trapezoidal prism calculator?.
Answers
13. Jennifer has $900 in a savings account at the beginning of the summer. She wants to have at least $250 in the account by the end of November. She withdraws $35 each week for food and shopping. If w represents the number of weeks, which of the following inequalities could be used to solve for the amount of money she may have by the end of summer?
Answers
Answer:
455
Step-by-step explanation:
900-(35×13)=455
The first week of January, there are 49 dogs and 28 cats in an animal shelter. Throughout the month, the ratio of dogs to cats remains the same. The last week of January, there are 20 cats in the same shelter. How many dogs are there?
Answers
Answer:
35 dogs
Step-by-step explanation:
DOG:CAT = DOG:CAT
49:28 = x:20
7:4 = x:20
x = 35
if rx y= 0.83, then we can conclude that x and y have a relatively
Answers
If rxy = 0.83, we can conclude that x and y have a relatively strong positive linear relationship or correlation.
The correlation coefficient (r) measures the strength and direction of the linear relationship between two variables, in this case, x and y. The value of r ranges between -1 and 1. A positive value indicates a positive relationship, meaning that as one variable increases, the other variable tends to increase as well.
In this case, with rxy = 0.83, the correlation coefficient is close to 1, suggesting a strong positive linear relationship. This means that when x increases, y also tends to increase, and vice versa. The closer the value of r is to 1, the stronger the linear relationship between x and y.
It is important to note that correlation does not imply causation. While a high correlation coefficient indicates a strong linear relationship, it does not provide information about the underlying cause or direction of the relationship between the variables. Other factors and variables may influence the relationship, and further analysis may be required to understand the nature of the relationship between x and y.
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Do the following lengths form a right triangle? Show your work.
12
5
13
Please answer quick
Answers
Answer:
yes
Step-by-step explanation:
side 5 and side 12 where the angle is you can form a square in the corner
mia has a certain amount of money. if she buys $4$ pens and $1$ pencil, she will have $\$5$ left over. if she buys $2$ pens and $2$ pencils, she will have $\$3$ left over. if edward arrives with the same amount of money as mia, together they can buy $7$ pens and $4$ pencils and spend all their money. if $a$ is the cost of one pen and $b$ is the cost of one pencil, compute the ordered pair $(a,b)$.
Answers
If 2 is the cost of one pen and 6 is the cost of one pencil, compute the ordered pair (2,6)
When Mia buys 4 pens and 1 pencil, she has $5 left; the number of dollars she starts with is 4a+b+5.
When she buys 2 pens and 2 pencils, she has $3 left; the number of dollars she starts with is 2a+2b+3.
Since those two expressions represent the same number, set them equal to each other and simplify to get an equation in a and b.
4a+b+5=2a+2b+3
2a-b=-2 [1]
They can purchase 7 pens and 4 pencils with their entire budget if Edward shows up with the same amount of money that Mia did.
The two of them have twice as much money as Mia did in the beginning, and they can buy 7 pens and 4 pencils with the money they have left over. To get a second equation in a and b, write an equation that says that and simplify it.
7a+4b = 8a+2b+10
a-2b=-10 [2]
solving both the equations 1 and 2:
2a-b = -2 - [1]
a-2b = -10 -[2]
a = 2 , b= 6
if 2 is the cost of one pen and 6 is the cost of one pencil, compute the ordered pair (2,6)
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Starting with an initial value of P(0)=30, the population of a prairie dog community grows at a rate of P′(t)=20− t/2 (in units of prairie dogs/month), for 0 ≤ t ≤ 40. a. What is the population 11 months later? b. Find the population P(t) for 0≤ t ≤40.
a. After 11 months, the population is enter your response prairie dogs.
Answers
(a) After 11 months, the population is approximately 35 prairie dogs.
(b) The population P(t) for 0 ≤ t ≤ 40 can be found by integrating the growth rate function P′(t). The integral of P′(t) is given by P(t) = 20t - (t^2)/4 + C, where C is the constant of integration determined by the initial population value.
(a) To find the population 11 months later, we need to evaluate the population function P(t) at t = 11. We will use the growth rate function P′(t) = 20 - t/2 to integrate and find the population function. However, we first need to determine the constant of integration, C, using the initial population value P(0) = 30.
Integrating P′(t), we have P(t) = ∫(20 - t/2) dt = 20t - (t^2)/4 + C.
Substituting P(0) = 30, we get 30 = 20(0) - (0^2)/4 + C, which simplifies to C = 30.
Now we can evaluate P(t) at t = 11: P(11) = 20(11) - (11^2)/4 + 30. Evaluating this expression, we find that the population 11 months later is approximately 35 prairie dogs.
(b) To find the population function P(t) for 0 ≤ t ≤ 40, we use the growth rate function P′(t) = 20 - t/2 and integrate it as we did in part (a). The result is P(t) = 20t - (t^2)/4 + C, where C is the constant of integration determined by the initial population value.
Since the initial population is given as P(0) = 30, we substitute this value into the equation to find C. Thus, 30 = 20(0) - (0^2)/4 + C, which simplifies to C = 30.
Therefore, the population function for 0 ≤ t ≤ 40 is P(t) = 20t - (t^2)/4 + 30, which gives the population of the prairie dog community at any time t within that range.
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The measure of an exterior angle of a regular polygon is 45 degrees name then shape of the polygon
Answers
Given
Exterior angle of a regular polygon = 45 degree.
Find
Name of the shape of polygon
Explanation
As we know that sum of exterior angle of exterior angle is 360 degree.
given each angle = 45 degree
so,
number of sides of regular polygon =
\(\begin{gathered} \frac{360\degree}{45\degree} \\ \\ 8 \end{gathered}\)number of sides = 8
Final Answer
The shape of the regular polygon = octagon
Let y = sec(x).
dy
TT
What is the value of at =
?
dac 4
Choose 1 answer:
1
1
2
V2
Answers
Answer:
C. √2
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
Function NotationPre-Calculus
Unit CircleCalculus
Derivatives Derivative Notation Derivative of sec(x) = sec(x)tan(x)Step-by-step explanation:
Step 1: Define
y = sec(x)
x = π/4
Step 2: Differentiate
Differentiate: y' = sec(x)tan(x)Step 3: Evaluate
Substitute in x: y'(π/4) = sec(π/4)tan(π/4)Evaluate: y' = √2What is the circumference of this circle?
A.
81π
B.
(8
1π
⁄
4
)
C.
None of the above
D.
18π
E.
(4
1π
⁄
2
)
Answers
Answer:
A.
81π
Step-by-step explanation:
PLEASE MAKE IT BRAINLIEST
PLEASE FOLLOW....
After the SmartWool company had their website redesigned, an analyst wants to know if the proportion of website visits resulting in a sale has changed in any way. If the old site's proportion was 15%, what is the appropriate null hypothesis
Answers
The appropriate null hypothesis for this situation would be: H₀: The proportion of website visits resulting in a sale after the redesign is equal to 15% (P = 0.15).
This hypothesis assumes that there is no significant change in the proportion of website visits resulting in a sale after SmartWool's website has been redesigned.
A null hypothesis is a claim that there is no effect or difference in the population. It is usually denoted by H0.
A null hypothesis can be tested using a statistical test that compares the observed data with the expected data under the null hypothesis.
A null hypothesis can be rejected or not rejected based on the p-value of the test, which measures the probability of observing the data under the null hypothesis.
Think about what the proportion of website visits resulting in a sale means and how it can be compared to the old site’s proportion.
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A plane, initially traveling 150 mi./hr. 100 east of north, suddenly enters a region where the wind is blowing at 50 mi./hr. from the southwest.
What is the plane’s resultant direction?
Answers
Answer:
the Velocity of the plane is 100 mi/hr along the northeast direction
Step-by-step explanation:
According to the Question,
Given That, the Initial velocity of the plane is 150 mi/hr along the east north direction and the wind is blowing at 50 mi/hr along the southwest directionsince the velocity of wind and plane is exactly opposite
the relative velocity of the plane with respect to the wind is given by\(V_{r} = V_{p} -V_{w}\) , where \(V_{p}\) is the velocity of plane = 150mi/hr and \(V_{w}\) = velocity of wind = 50 mi/hr
Therefore, Relative Velocity = 150-50 ⇒ 100mi/hr along northeast directionThus, the velocity of the plane is 100 mi/hr along the northeast direction
can anyone answer this i need real help..
the answer for 18. is 11/4(as fraction), but how did they get that? from 2 3/4..
Answers
Step-by-step explanation:
ok multiply the denominator by the whole number to get 8 and add it to the numerator to get 11. the denominator stays the same so you get 11/4
There are 40 students in a class and 95% of these students passed their Chemistry text. What number of these students passed their test? Round you answer to the nearest whole number if necessary.
(Please answer, I will mark brainliest!)
Answers
Answer: 38 students
Step-by-step explanation:
To answer this question we will find 95% of 40. Keep in mind that a percent divided by 100 becomes a decimal.
95% / 100 = 0.95
0.95 * 40 = 38
38 students passed their test.
ganas 9.65 por hora a la semana ganaste 173.70 escribe y resuelve una ecuación para hallar el número de horas trabajadas esta semana
ayudaaa
you earn 9.65 per hour week you earned 173.70 write and solve an equation to find the number of hours worked this week
help
Answers
Hope this will help
Write the equation of the line in Point-Slope Form given the information below. Use Point One. point 1=(-1,-1) Point 2-(0,4)
Answers
Answer:
\(\bold{y+1=5(x+1)}\)
Step-by-step explanation:
\(m=\dfrac{y_2-y_1}{x_2-x_1}\\\\(-1,\,-1)\ \implies\ x_1=-1\,,\ y_1=-1\\(0,\,4)\ \implies\ x_2=0\,,\ y_2=4\\\\m=\dfrac{4-(-1)}{0-(-1)}=\dfrac{5}{1}=5\)
\(y-y_1=m(x-x_1)\) - point-slope form of Equation of the Line
\(x_1=-1\,,\ y_1=-1\,,\ m=5\\\\equation:\\{}\qquad\qquad y-(-1)=5\big(x-(-1)\big)\\\\{}\qquad\qquad y+1=5\big(x+1\big)\)
Solomon is planning to recover a lampshade. How much fabric does he need?
a.912 cm^2
b.1,056 cm^2
c.768 cm^2
d.2,304 cm^2
Answers
Area of fabric needed to cover the lampshade is 768 \(cm^2\)
What is Fabric?
Fabric can be either a cloth made by weaving or knitting, or it can be the framework of a construction. Some individuals use twisting, felting, or braiding to create fabrics. When I remark that termites are "gradually eating away at the fabric of the building," I'm referring to either the floor or the walls.
The phrase may also be used to refer to the fundamental framework or organization of society. For instance, "the fabric of society" refers to its fundamental structure, which includes all of its practices and beliefs.
I'm referring to the body of the car when I remark, "I heard clanking noises in the fabric of the car." This phrase can also be used to describe the body of an aircraft.
Length= 16 cm
Breath= 12 cm
Area= 4(16*12) \(cm^2\)
Area=768 \(cm^2\)
Hence, Fabric needed is 768 \(cm^2\)
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(2) Mai walked 1/8 of a 30-mile walking trail. How many miles did Mai walk? Explain or show your reasoning. *
Answers
Answer: 3.75 miles
Step-by-step explanation:
Divide 30 by 8. 30/8= 3.75. If she walked 1/8 then she walked 3.75 miles
Mia crosses a river when she drives from her house to the beach. The function d(t)=40|t-1. 25| shows Mia's distance from the river, d, in miles after t hours. The domain of the function is 0
Answers
The domain of the function is given as 0<t<3, which means that the time elapsed is between 0 and 3 hours. Mia's distance from the river after 2 hours of driving is 30 miles.
The given function is:
d(t) = 40|t-1.25|
Here, t represents the time elapsed in hours and d represents the distance from the river in miles.
To find Mia's distance from the river, we need to plug in values of t into the function.
For example, if t=2, then:
d(2) = 40|2-1.25|
d(2) = 40|0.75|
d(2) = 30
So Mia's distance from the river after 2 hours of driving is 30 miles.
Similarly, we can find Mia's distance from the river at other points in time.
To graph the function, we can plot points by choosing different values of t and finding the corresponding values of d. We can then connect these points to get a graph of the function.
Graph of the function d(t) = 40|t-1.25|
The graph shows that Mia starts at a distance of 40 miles from the river and then approaches it until she reaches the other side of the river, where her distance from the river is again 40 miles. The graph is symmetric about t=1.25, which means that Mia spends the same amount of time on either side of the river.
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Two groups of hikers take two different routes from Camp A to Camp B. The first group leaves Camp A at 9:00 AM and takes a route that is 30 miles longer than the second group's route. The second group leaves Camp A at 1:00 PM. Their hiking speed is 2 mph slower than the first group's speed. Both groups reach Camp B at 4:00 PM. How fast does each group hike?
Answers
Answer: first groups hiking was 6mph, second groups was 4mph.
Step-by-step explanation:
Speed of first group = 6 mph
Speed of second group = 4 mph
We are told that first group leaves Camp A at 9:00 AM.If the normal distance between camp A and camp B is x, then the total distance this first group covers will be;
(x + 30) miles
This first group reached camp B at 4pm. This is 7 hours from when they left camp A.Thus, their speed is;
v1 = (x + 30)/7 mph
We are told that;Second group left by 1pm and got to camp B by 4pm. This is 3 hours.
We are also told that their speed was 2mph slower than the first group.Thus;
v2 = ((x + 30)/7) - 2 mph
Since normal distance from camp A to camp B is x. Then this second group will have;x = ((x + 30)/7) - 2) × 3
Since;
distance = speed × time
Divide both sides by 3 to get;
x/3 = ((x + 30)/7) - 2)
Multiply through by 21 to get;
7x = 3(x + 30) - 42
7x = 3x + 90 - 42
7x - 3x = 48
4x = 48
x = 48/4
x = 12 miles
Thus, putting 12 for x in V1 equation gives;
v1 = (12 + 30)/7
v1 = 42/7
v1 = 6 mph
Similarly;
v2 = ((12 + 30)/7) - 2
v2 = (42/7) - 2
v2 = 6 - 2
v2 = 4 mph
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In May, Jim’s lunch account has a balance of $58.19. If lunch costs $2.74 per day, how many days will Jim be able to buy lunch before his account runs out of money?
Answers
Answer:
21 days.
Step-by-step explanation:
To solve this, divide the cost of lunch from the initial amount in his account. Therefore:
58.19 = 2.74x ('x' being the number of days)
Divide both sides by 2.74:
\(\frac{58.19}{2.74} = \frac{2.74x}{2.74}\)
x ≈21.24, or 21 days.
***Since you use whole numbers when counting days, round down to determine the amount of days he can buy lunch. Thus, he can buy lunch for 21 days.
Consider the function f given by f(n) = 4n-9.
Evaluate the value
f(8) = ???
Answers
Answer:
i am so confused 12345
Step-by-step explanation:
In Exercises 8-10, sketch the figure described.
8. plane A and line c intersecting at all points on line c
9. GM and GH
10. line CD and plane X not intersecting
Answers
The sketch answers to question 8, 9 and 10 is given in the image attached.
What is an intersecting lines?A link is known to be intersecting if two or more lines are said to have cross one another in a given plane.
Note that the intersecting lines are known to be one that often share a common point, and it is one that can be seen on all the intersecting lines, and it is known to be the point of intersection.
Looking at the image attached, you can see how plane A and line c intersecting at all points on line c and also GM and GH and line CD and plane X as they are not intersecting
Therefore, The sketch answers to question 8, 9 and 10 is given in the image attached.
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1). -8x^2
2). 6x
3). -40x^2
4). -2x
Answers
Answer:
6x
Step-by-step explanation:
I guess it is but i don't know exact answer
Answer:
-8x^2
Step-by-step explanation:
This works like multiplying numbers "by hand." The partial product in the bottom row comes from two multiplications: (-4x)(-1) = +4x, shown in red in the attached image. The second multiplication is (-4x)(2x) = -8x, shown in blue.
a tank contains 1000 l of pure water. brine that contains 0.05 kg of salt per liter of water enters the tank at a rate of 5 lymin. brine that contains 0.04 kg of salt per liter of water enters the tank at a rate of 10 lymin. the solution is kept thoroughly mixed and drains from the tank at a rate of 15 lymin. how much salt is in the tank (a) after t minutes and (b) after one hour?
Answers
According to the information we can infer that the rate of salt in the water is: 0.65 Kg/min.
How to find the rate of salt in the water?To find the rate of salt in the water we must perform the following mathematical operation:
Rate in = 0.05lg/L * 5 L/min + 0.04 kg/L * 10 L/minRate in = 0.25 kg/min + 0.4 kg/minRate in = 0.65 kg/minAccording to the above, to find the amount of salt that is draining from the tank per minute we must multiply the value of 0.65kg/min. For example, in the case of being an hour (60 minutes).
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