14895 decreased by 3%

Answers:  585,  587, and 593

Basically everything except 599

==============================================================

Why?

Those answers in bold are closer to 590 than they are to 580 or 600. When rounding to the nearest ten (not tenth) we look at the units digit. If it is 5 or larger, then we bump the tens digit up by 1 and replace the units digit with a 0.

This explains why 585 and 587 round to 590

The number 599 rounds to 600 for similar reasoning, but we cross it off the list since we want 590.

The number 593 rounds to 590 because the 3 in the units digit isn't 5 or larger. So we just replace the 3 with 0 and keep everything else as is.

Answer:

........................

Answer:

\(144ft^{2}\) (144ft^2)

Step-by-step explanation:

Since the living room is 6 inches by 6 inches, the formula of the living room can be seen as: \(6in^{2}\). And since each inch is equal to 2 feet, (6*2=12) we can turn the equation into: \(12ft^{2}\). 12 times 12 is 144, so the answer is \(144ft^{2}\)

N = 4.2m

Sorry for my bad writing but this is the explanation and answer.

Answer:

2x^2+9x-35

Step-by-step explanation:

(2x-5)(x+7)

=2xx + 2x  x 7 + (-5)x + (-5) x 7

=2xx + 2 x 7x - 5x - 5 x 7

=2x^2+9x-35

False. A rectangle is conventionally used in a process flowchart to represent a storage area or queue. Triangles are typically used in flowcharts to represent decision points, where a choice must be made between two or more alternatives.

Rectangles are used to represent activities or operations, while arrows connecting the shapes indicate the flow or direction of the process. The use of standardized shapes in flowcharts helps to make them easily understandable and accessible to a wide range of individuals, regardless of their background or experience with the specific process being depicted.

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Answer:

11.3

Step-by-step explanation:

To find mean: All values added together divided by amount of values:

X: 11+12+13+14 = 50

50 / 4 (amount of values) = 12.5 (mean of x)

F: 8+3+17+12 = 40

40/4 (amount of values) = 10 (mean of f)

To find mean of x and f combined:

10 + 12.5 = 22.5

22.5 / 2 (amount of values) = 11.25 (mean of x and f combined)

To 1 dec pl.

= 11.3

Hope that makes sense

When a group of individuals selects a particular consumer-submitted entry, it is called a "winner." However, if the selection process is part of a marketing promotion, it could be classified as a sample, premium, contest, or sweepstake depending on the specific rules and regulations.  The correct option is A.

Generally speaking, a sample refers to a small portion of a product or service that is given away for free, a premium is a bonus item or incentive offered with a purchase, a contest involves a skill-based competition with a predetermined set of rules and criteria, and a sweepstake is a random drawing with no purchase necessary. A contest is an event where a group of individuals selects a particular consumer-submitted entry as the winner. This often involves participants submitting entries that showcase their skills, creativity, or other qualities.

The entries are then judged by a panel or group, who choose the winning submission based on predetermined criteria. In contrast, a sweepstake is a promotional event where winners are chosen randomly from all eligible entries, rather than being judged on the merits of their submission. A sample, on the other hand, typically refers to a small portion of a product provided for free to potential customers. Lastly, a premium is a reward offered to customers for making a purchase or participating in a promotion.

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The approximate solution using the three-point formula with step size h = 1/2 is y(t) = 0 for all t.

The boundary value problem given is y′′ − y = 0 with boundary conditions y(0) = 0 and y(2) = e2 − e−2.

(a) To find the exact solution y(t), we can use the characteristic equation r^2 - 1 = 0. This gives us r = 1 and r = -1. The general solution is therefore y(t) = c1e^t + c2e^-t.

Using the boundary conditions, we can find the constants c1 and c2.

For y(0) = 0, we have 0 = c1 + c2, which gives us c2 = -c1.

For y(2) = e2 − e−2, we have e2 − e−2 = c1e^2 + c2e^-2. Substituting c2 = -c1, we get e2 − e−2 = c1e^2 - c1e^-2.

Solving for c1, we get c1 = (e2 − e−2)/(e^2 - e^-2) = 1/2. Therefore, c2 = -1/2.

The exact solution is y(t) = (1/2)e^t - (1/2)e^-t.

(b) To use the three-point formula with step size h = 1/2, we can set up a table with tn and yn values.

tn | yn
---|---
0  | 0
1/2| y1
1  | y2
3/2| y3
2  | e2 - e-2

The three-point formula is yn+1 = yn-1 + 2h(y′n). We can use this formula to find the values of y1, y2, and y3.

For y1, we have y1 = 0 + 2(1/2)(y′0) = y′0. Since y′0 = y′(0) = (1/2)e^0 - (1/2)e^0 = 0, we have y1 = 0.

For y2, we have y2 = y0 + 2(1/2)(y′1) = 0 + 2(1/2)(0) = 0.

For y3, we have y3 = y1 + 2(1/2)(y′2) = 0 + 2(1/2)(0) = 0.

Therefore, the approximate solution using the three-point formula with step size h = 1/2 is y(t) = 0 for all t.

It is important to note that the three-point formula is not accurate for this particular boundary value problem due to the size of the step and the nature of the differential equation. A smaller step size or a different numerical method may yield a more accurate approximation.

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The value of a of the given right angle triangle using trigonometric ratios is: a = 9

The three main trigonometric ratios in right angle triangles are expressed as:

sin x = opposite/hypotenuse

cos x = adjacent/hypotenuse

tan x = opposite/adjacent

Looking at the given right angle triangle, we can say that:

a/9√2 = sin 45

a = 9√2 * 1/√2

a = 9

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Type - I error states that the training program actually raised the score but statistically, it is not.

Type-II error states that the training program does not actually raise the score but statistically, it raised the scores.

Given statement is

"A random sample of test-takers who had completed the training showed a mean increase smaller than 30 points."

Hypothesis is,

Null hypothesis H0 :μ ≥ 30 (claim)

Alternate hypothesis H1 :μ < 30  (actual result)

in the null hypothesis, we have to consider the claim and the other in the alternate hypothesis.

In the given context of the problem, the Type-1 error will be stated below

" If in reality, the training program raises the SAT score by more than or equal to 30 points and statistically the claim is rejected".

The training program actually raised the score but statistically, it is not.

Type-II error

" If in reality, the training program does not raise the SAT score by more than or equal to 30 points and statistically the claim is failed to reject".

The training program does not actually raise the score but statistically, it raised the scores.

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Answer:

8

Step-by-step explanation:

Hope that helps :)

.....

The answer to this question requires the use of the Poisson distribution and the cumulative distribution function.

(a) We are asked to find the probability that the fourth person weighed is the first person to be overweight. Since 63% of Americans are overweight, this means that the probability of a randomly selected American being overweight is 0.63. The probability of the first overweight person being the fourth person weighed is given by P(X=3) where X is the number of overweight people in the first 4 people weighed. Using the binomial distribution formula, we have:

\(P(X=3) = (4 choose 3) * (0.63)^3 * (0.37)^1\\\\ = 4 * (0.63)^3 * (0.37)\)

(b) We are asked to find the probability that it takes more than 4 people to observe the first overweight person. This is equivalent to finding the probability that none of the first 4 people weighed are overweight. Using the complement rule, we have:

\(P(X=0) = 1 - P(X > 0)\\\\ = 1 - [P(X=1) + P(X=2) + P(X=3) + P(X=4)]\\\\ = 1 - [ (4 choose 1) * (0.63)^1 * (0.37)^3 + (4 choose 2) * (0.63)^2 * (0.37)^2 + P(X=3) ]\)

(c)  The expected value (mean) of a binomial distribution is given by μ = np, where n is the number of trials and p is the probability of success in each trial. In this case, n=4 and p=0.63. Thus, the mean number of overweight people in 4 trials is 4 * 0.63 = 2.52. The variance of a binomial distribution is given by σ^2 = np(1-p), so in this case the variance is 4 * 0.63 * 0.37 = 1.41. The standard deviation is the square root of the variance, so the standard deviation is approximately \(\sqrt{(1.41) } = 1.19\). This means that the number of overweight people in 4 trials is expected to be around 2.52, with a standard deviation of 1.19.

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Answer:

-x^6/125-y^3/64

Step-by-step explanation:

that's what it Got

Answer:

70 cars

Step-by-step explanation:

if the ferry took the same number of cars each hour, then you would just do 350/5 = 70

The expression which has product of two binomials is (5-n)(n+7).

An expression is combination of variables, numbers and operators.

Binomials are expressions containing the sum (or difference) of two terms.

The expression (x + 3)(x + 2) is the product of two binomials.

(pq)(qp), (5-n)(n+7), 3x(2x+5), 6x-2y

(pq)(qp) is not the product of binomials because pq and qp are products.

3x(2x+5) is not the product of binomials because 3x is not a sum or difference.

6x-2y is also not because it is one binomial, not two multiplied together.

(5-n)(n+7) is the product of two binomials.

Hence, (5-n)(n+7) is the expression which has product of two binomials.

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Answer:

\(y = \frac{5}{2} x^{2}\)

Step-by-step explanation:

When you scale a parabola vertically, you multiply the \(x^{2}\) by what you are scaling it vertically by.

For example, say you have  \(y = 8x^{2}\). That means that  \(y = x^{2}\) was scaled vertically by a factor of 8.

I hope this helps!

Answer: someone told me its 35 so...

Step-by-step explanation:

Answer:

Step-by-step explanation: Since there are 7 people who shake hands with everybody including the people who know each other, we can add 11+10+9+8+7+6+5, because each handshake counts once, but the other five can't be counted because they are the people who already know each other and if you add 11+10+9+8+7+6+5, you will also get 16*3 +8 which equals to 56.

The point (2,-4), (x,y), A, and B all lie on the line. An equation relating x and y is m(x-2)=y+4.

The points (2, -4), (x, y) are lie on the line.

The slope formula is the vertical change in y divided by the horizontal change in x, sometimes called rise over run. The slope formula uses two points, (x1, y1) and (x2, y2), to calculate the change in y over the change in x. Slope is a ratio that includes how y changes for every unit increase of x.

The slope formula,

m\((x_{2}-x_{1})= y_{2}-y_{1}\)

Here, \(x_{1} = 2, x_{2}= x, y_{1}= -4\) and \(y_{2}= y\)

Now, we have to substitute the values in the formula,

\(m=\frac{y-(-4)}{x-2}\)

\(m= \frac{y+4}{x-2}\)

m(x-2)= y+4

Therefore, the equation is m(x-2)=y+4.

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Assuming that x ≥ 0 and y ≥ 0, the situation is infeasible: True.

In Mathematics, these rules are generally used for writing and interpreting an inequality or system of inequalities that are plotted on a coordinate plane:

In this context, we can logically deduce that the given system of inequalities 5x+3y ≤ 15 and y ≥ 6 would not have a feasible solution set if they are subjected to x ≥ 0 and y ≥ 0:

Assuming the ordered pair (1, 2), we have:

y ≥ 6

2 ≥ 6 (False).

5x+3y ≤ 15

5(1) +3(2) ≤ 15

5 + 6 ≤ 15

11 ≤ 15 (True).

Therefore, it is not a feasible solution.

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

The correct answer is a) the probability of precipitation is 72%. and b)  the probability of precipitation is 2%.

The given formula to determine the probability of precipitation (PoP) is PoP = (C * A) * 100 percent where C represents the confidence that precipitation will occur somewhere in the forecasted area and A represents the percentage of the area that will receive measured precipitation if it occurs.

(a) If a forecaster expresses confidence that there is an 80% chance of precipitation in the forecasted area, and it is expected to produce measurable precipitation over 90% of the area, then the probability of precipitation is given as follows: PoP = (C * A) * 100 per cent C = 80%A = 90%PoP = (80% * 90%) * 100%

PoP = 72%.

Therefore, the probability of precipitation is 72%.

(b) If a forecaster expresses confidence that there is a 20% chance of precipitation in the forecasted area, and it is expected to produce measurable precipitation over 10% of the area, then the probability of precipitation is given as follows: PoP = (C * A) * 100 per cent C = 20%A = 10%PoP = (20% * 10%) * 100%PoP = 2%

Therefore, the probability of precipitation is 2%.

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Answer:

y=-3/2x

Step-by-step explanation:

y=mx + b

First find slope, here we take 2 points

(0,0) and (2, -3)

m = (-3-0)/(2-0)

m = -3/2

Find B which is 0 since it hits (0,0) which is a y intercept when x= 0

Therefore equation is:

y=-3/2 x

x3 would be the answer

The problem can be modeled as a linear programming problem. We need to minimize the total cost of shipping the boots, which can be represented as a linear combination of the shipment quantities.

Thus, the objective function to be minimized can be written as:

Minimize Z = 4x11 + 5x12 + 7x13 + 6

32 + y33 ≤ 40 (capacity limit at warehouse 3)

y41 + y42 + y43 ≤ 30 (capacity limit at warehouse 4)

y51 + y52 + y53 ≤ 45 (capacity limit at warehouse 5)

xij, yjk ≥ 0 (non-negativity constraint)

Thus, the complete linear programming problem can be formulated as:

Minimize Z = 4x11 + 5x12 + 7x13 + 6x21 + 4x22 + 5x23 + 4y11 + 3y12 + 6y13 + 5y21 + 5y22 + 4y23 + 6y31 + 7y32 + 5y33 + 4y41 + 6y42 + 5y43 + 5y51 + 4y52 + 6y53

Subject to:

x11 + x12 + x13 ≤ 60

x21 + x22 + x23 ≤ 90

x11 + x21 = y11 + y21 + y31 + y41 + y51

x12 + x22 = y12 + y22 + y32 + y42 + y52

x13 + x23 = y13 + y23 + y33 + y43 + y53

y11 + y12 + y13 ≤ 35

y21 + y22 + y23 ≤ 50

y31 + y32 + y33 ≤ 40

y41 + y42 + y43 ≤ 30

y51 + y52 + y53 ≤ 45

xij, yjk ≥ 0

Solving this linear programming problem using a suitable solver will provide us with the optimal values of xij and yjk, which will help us in determining the minimum cost required for shipping the boots while satisfying all the constraints.

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The mass of the pencil is approximately 5.49 ounces.

To find the mass of the pencil, we can integrate the density function over the length of the pencil.

The density function is given by rho(x) = 5/x oz/in.

We want to find the mass of the pencil, so we integrate the density function from x = 2 (the starting point of the pencil) to x = 6 (the endpoint of the pencil).

The integral is ∫[2, 6] (5/x) dx.

Evaluating the integral, we have:

∫[2, 6] (5/x) dx = 5 ln(x) ∣[2, 6] = 5 ln(6) - 5 ln(2) = 5 (ln(6) - ln(2)).

Using the property of logarithms, we can simplify this to:

5 ln(6/2) = 5 ln(3) ≈ 5 (1.098) ≈ 5.49 oz.

The mass of the pencil is approximately 5.49 ounces.

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Answer:

-3

Step-by-step explanation:

Based on his weekly salary and commission, we can calculate that Mr. Randall sold goods worth $1,800.

In the formula given, sales is represented as s. To find the total sales, you can solve the equation:

300 + 0.07s = 426

0.07s = 426 - 300

s = 126 / 0.07

= $1,800

In conclusion, Mr. Randall sold $1,800 worth of goods.

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The maximum combined loads for a residential building using the recommended AISC 7 expressions for LRFD is 434 kips.

The maximum combined loads for a residential building using the recommended AISC 7 expressions for LRFD,

where

D = 100k,

L = 140k, L < 100psf,

Lr = 40k,

W = +160k or −100k, and

E = +180k or −125k is given below:

Design load = 1.2D + 1.6(Lr or S or R) + 0.5(L + Lr or R) + (W or E)

Here, D is the weight of dead load, L is the weight of live load, Lr is the weight of the roof live load, W is the weight of wind load and E is the weight of earthquake load.

Therefore, for the given loads,

D = 100k

L = 140k

Lr = 40k

W = +160k or −100k

E = +180k or −125k

Max load = 1.2D + 1.6(Lr) + 0.5(L + Lr) + W

= 1.2 (100) + 1.6 (40) + 0.5 (140 + 40) + 160

= 120 + 64 + 90 + 160

= 434 kips

Therefore, the maximum combined loads for a residential building using the recommended AISC 7 expressions for LRFD is 434 kips.

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The distance the puck traveled from the wall to Pedro is determined as √(ab).

Let's call the distance from Meg to the wall "a" and the distance from Pedro to the wall "b".

Let's also call the distance the puck travels from the wall to Pedro "x".

Since the two triangles are similar, we can set up a proportion:

a / x = x / b

We can cross-multiply to get:

x² = ab

And then take the square root of both sides to get:

x = √(ab)

So the distance the puck traveled from the wall to Pedro is √(ab).

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About 3 full cones of water are needed to be added to the cylinder to completely fill it.

The radius of the right circular cone is 3cm and the slant height is 5 cm.

The height of the cone can be found as,

H = √(5)²- (3)²

H = 4cm

The volume of the cone is given by,

V = πR²H/3

R is the radius and H is the height of the cone,

Putting values,

v = π x 5 x 5 x 4/3

v = 104.71 cm³

Now, the height h of cylinder is given to be 6 cm and the radius r of the cylinder is 4cm.

The volume of the cylinder is given as,

V = πr²h

V = π x 4 x 4 x 6

V = 301.59

Let us assume that we have to add n full cones of water to completely fill the cylinder, so, we can write,

nv = V

Putting values,

n104.71 = 301.59

n = 2.85

So, we have to add roughly three full cones of water to completely fill the cylinder.

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