10. many amusement parks have rides that make vertical loops like the one shown below. for safety, the cars are attached to the rails in such a way that they cannot fall off. if the car goes over the top at just the right speed, gravity alone will supply the centripetal force. what other force acts and what is its direction if:

Answer:

      ρ = 20.4 kg / m³

Explanation:

For this exercise we use Archimedes' principle, the thrust on a submerged body is equal to the weight of the released liquid

           B = ρ g V_liquid           (1)

let's write the equilibrium equation

           F -W + B = 0

           B = W -F

let's calculate

           B = 0.900 9.8 - 2.94

            B = 5.88 N

From equation 1

            V_{liquid} =  \(\frac{B}{\rho_{Hg} g}\)

            V_{liquid} = \(\frac{5.88}{13.6 \ 10^3 \ 9.8}\)

            V_{liquid} = 4.41176 10⁻⁵ m³

in this case it is indicated that the body is completely submerged

           V_body = V_liquid = V

     the definition of density is

           ρ = m / V

           ρ = \(\frac{0.900 \ 10^{-3}}{ 4.41176 \ 10^{-5} }\)

           ρ = 2.04 10¹ kg / m³

           ρ = 20.4 kg / m³

a) The motion of the object between 15 s to 30 s is increasing velocity, to a constant velocity and finally a decreasing velocity.

(b) The average velocity of the object between 0 and 15 seconds is 0.167 m/s.

(c) The position of the object at 5.0 seconds is 0.5 m.

(d) Between 30 and 40 seconds, the velocity of the object is decreasing and the object is decelerating.

(a) The motion of the object between 15 s to 30 s can be described as increasing velocity, to a constant velocity and finally a decreasing velocity.

(b) The average velocity of the object between 0 and 15 seconds is calculated as;

average velocity = total displacement / total time

average velocity = (2.5 m - 0 m ) / ( 15 s - 0 s ) = 0.167 m/s

(c) The position of the object at 5.0 seconds is calculated as follows;

at 5.0 seconds, the position of the object is traced from the graph as 0.5 m.

(d) The motion of the object between 30 and 40 seconds is calculated as;

velocity = ( 0 m - 4 m ) / ( 40 s - 30 s ) = - 0.4 m/s

Between 30 and 40 seconds, the velocity of the object is decreasing and the object is decelerating.

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In conclusion, the light source in a fluorescence microscope is ultraviolet (UV) light, which is used to excite fluorophores and capture emitted light for imaging.

The light source in a fluorescence microscope is ultraviolet (UV) light. In this type of microscope, UV light is used to excite fluorophores, which are molecules that emit light of a different color when excited.
1. Fluorescence microscopes use UV light because it has a shorter wavelength than visible light, allowing for higher resolution imaging.
2. The UV light source emits a specific wavelength that matches the absorption properties of the fluorophores used in the sample.
3. When the UV light interacts with the fluorophores, they absorb the energy and enter an excited state.
4. The excited fluorophores then release the excess energy as light of a longer wavelength, typically in the visible range.
5. This emitted light is then captured by the microscope's objective lens and detected, producing an image.
In conclusion, the light source in a fluorescence microscope is ultraviolet (UV) light, which is used to excite fluorophores and capture emitted light for imaging.

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answer:

change in momentum = 37,500kg.m/s in the opposite direction

time it takes = 12.5s

working:

u=25m/s

v=0m/s

F=ma

-3000=(1500)(a)

-3000÷1500=a

a= -2m/s^2

Change in momentum=mv-mu

(1500)(0)-(1500)(25)

= -37,500kg.m/s

relax the( - ) represents direction

v=u-at

0=25-2t

2t=25

t= 12.5s

Answer:

a hypothesis is a explanation made on the basis of limited evidence

Explanation:

Answer:

an hypothesis is an educated guess  based on what you already know

Explanation:

hope this helps

Answer:

the electric magnitic is not a field to have an violen not elictric because a pandmic

sana maka toulong

The distance to the star, in parsecs, is 30 pc.

The distance to the star, in light years, can be calculated using the conversion factor of 3.26 light years per parsec. Therefore, the distance to the star in light years is approximately 97.8 light years.

The distance to a star can be determined using its measured parallax angle. Parallax is the apparent shift in the position of an object when viewed from two different points. It is measured in units of arc seconds.

The formula to calculate the distance to a star in parsecs is:

Distance (in pc) = 1 / Parallax (in arc sec)

Given that the measured parallax is 1/30 of an arc second, we can substitute this value into the formula:

Distance (in pc) = 1 / (1/30) = 30 pc

This gives us the distance to the star in parsecs.

To convert the distance to light years, we use the conversion factor of 3.26 light years per parsec. Multiplying the distance in parsecs by this conversion factor gives us the distance in light years:

Distance (in light years) = 30 pc × 3.26 light years/pc = 97.8 light years

Therefore, the distance to the star is approximately 30 parsecs or 97.8 light years.

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Gravitational force between two masses m, and m, is represented as F = Gm₂ m₂ / r^2 where r = xi+yj + zkG, m, m₂ are nonzero constants and let's assume that I = 0

a) Calculation:For F = Gm₂ m₂ / r^2.

Using r = xi+yj + zk and let r^2 = x^2 + y^2 + z^2∴ F = Gm₂ m₂ / (x^2 + y^2 + z^2), Where G, m, m₂ are nonzero constants. Divergence of F = ∇ · F= 1/r^2(d/dx(r^2Fx) + d/dy(r^2Fy) + d/dz(r^2Fz))= 1/r^2(d/dx(r^2Gm₂ m₂ x/(x^2+y^2+z^2)^(3/2)) + d/dy(r^2Gm₂ m₂ y/(x^2+y^2+z^2)^(3/2)) + d/dz(r^2Gm₂ m₂ z/(x^2+y^2+z^2)^(3/2)))= 1/r^2(d/dx(r^2Gm₂ m₂ x/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2) + d/dy(r^2Gm₂ m₂ y/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2) + d/dz(r^2Gm₂ m₂ z/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2))= 1/r^2(Gm₂ m₂ [2x(x^2+y^2+z^2)-3x^2]/(x^2+y^2+z^2)^(5/2) + Gm₂ m₂ [2y(x^2+y^2+z^2)-3y^2]/(x^2+y^2+z^2)^(5/2) + Gm₂ m₂ [2z(x^2+y^2+z^2)-3z^2]/(x^2+y^2+z^2)^(5/2))= 1/r^2(Gm₂ m₂ [(2x^2+2y^2+2z^2-3x^2)/(x^2+y^2+z^2)^(3/2)] + [2x^2+2y^2+2z^2-3y^2]/(x^2+y^2+z^2)^(3/2)] + [2x^2+2y^2+2z^2-3z^2]/(x^2+y^2+z^2)^(3/2)])= 1/r^2(Gm₂ m₂ [x^2+y^2+z^2]/(x^2+y^2+z^2)^(3/2))= 0.

Curl of F = ∇ × F= i(d/dy(Fz) - d/dz(Fy)) - j(d/dx(Fz) - d/dz(Fx)) + k(d/dx(Fy) - d/dy(Fx))= i(d/dy(Gm₂ m₂ z/(x^2+y^2+z^2)) - d/dz(Gm₂ m₂ y/(x^2+y^2+z^2))) - j(d/dx(Gm₂ m₂ z/(x^2+y^2+z^2)) - d/dz(Gm₂ m₂ x/(x^2+y^2+z^2))) + k(d/dx(Gm₂ m₂ y/(x^2+y^2+z^2)) - d/dy(Gm₂ m₂ x/(x^2+y^2+z^2)))= i(Gm₂ m₂ [-2xz]/(x^2+y^2+z^2)^(5/2)) - j(Gm₂ m₂ [-2yz]/(x^2+y^2+z^2)^(5/2)) + k(Gm₂ m₂ [(x^2+y^2-2z^2)]/(x^2+y^2+z^2)^(5/2))

b) Calculation:The line integral of F along a curve C can be evaluated by the following formula∫C F.dr = ∫∫ ( ∇ x F) ds, Where r is the position vector of the curve, s is the scalar parameter representing the curve, and the integral is evaluated from the initial point to the final point.

Using the curl of F obtained in part a) and for the surface with ∂S as C∫C F.dr = ∫∫ ( ∇ x F) ds= ∫∫ curl(F) ds= ∫∫ (-2xz i -2yz j + (x^2+y^2-2z^2)k) ds...[1]

Let's consider the surface S as a plane perpendicular to the z-axis of the form ax+by+c=0 and the curve C as the intersection of the plane and the cylinder x^2 + y^2 = a^2.

Let's choose the unit normal to the surface S as k (along the z-axis).

The curl of F is a vector field perpendicular to the plane and along the direction of k.

Thus the integral can be written as∫C F.dr = ∫∫ ( ∇ x F) . k ds= ∫∫ (x^2+y^2-2z^2) ds...[2]

Now let's evaluate the integral over the given plane ax+by+c=0. We can write x = t, y = (c-at)/b and z = 0, where t is the scalar parameter along the line of intersection of the plane and the cylinder (x^2 + y^2 = a^2).

Since the curve C is on the cylinder of radius a, we have x^2+y^2 = a^2 ⇒ t^2+(c-at)^2/b^2 = a^2On solving for t, we have t = (bc±ab √(a^2-b^2-c^2))/[a^2+b^2].

Substituting t in x and y, we get the curve C in the x-y plane as a function of the scalar parameter s asx = (bc±ab √(a^2-b^2-c^2))/[a^2+b^2]y = (c-at)/b= (c-(bc±ab √(a^2-b^2-c^2))/[a^2+b^2])/b.

Now we can evaluate the integral over the curve C, which is along the intersection of the plane and the cylinder.

Integral over C (x^2+y^2-2z^2) ds= ∫t₁^t₂ [(t^2 + [(c-at)^2]/b^2 - 2(0)^2)^(1/2)] dt= ∫t₁^t₂ [(a^2-b^2-c^2)t^2+2bc(c-at)+b^2c^2-a^2b^2]^(1/2) dt.

Now we can choose the value of t₁ and t₂ such that the square root in the integrand is minimized (so that the integral is path-independent).

This can be done by choosing the value of t that gives the minimum value of (a^2-b^2-c^2)t^2+2bc(c-at)+b^2c^2-a^2b^2 over the range of t from t₁ to t₂.

On differentiation with respect to t and equating to 0, we get the value of t = bc/(a^2+b^2).

Substituting this value of t in the integrand, we get the minimum value of the square root in the integrand to be |c| √(a^2+b^2)/|b|.

Thus the integral over C is given by∫C F.dr = ∫∫ (-2xz i -2yz j + (x^2+y^2-2z^2)k) ds= ∫∫ (x^2+y^2-2z^2) ds= ∫t₁^t₂ |c| √(a^2+b^2)/|b| dt= |c| √(a^2+b^2)/|b| (t₂-t₁).

Now we can see that the integral is path-independent as it depends only on the end points t₁ and t₂ and not on the path taken to reach them.

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Answer:

I think its D.....

The difference between adhesive and cohesive is that adhesive refers to the attraction between different substances, while cohesive refers to the attraction between similar substances.

Adhesive and cohesive are terms used to describe the behavior of liquids and the forces between their molecules.

Adhesive refers to the attraction between different substances. Adhesive forces between liquids and solids, for example, result in the wetting of the solid surface by the liquid. Adhesive forces can be strong or weak, depending on the properties of the substances involved. For example, water is a highly adhesive liquid and has a strong attraction to many surfaces.

Cohesive refers to the attraction between similar substances. Cohesive forces between liquids, for example, result in surface tension. Cohesive forces can also be strong or weak, depending on the properties of the liquid. For example, water has a relatively high level of surface tension due to its cohesive forces.

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Answer:

A

Explanation:

because the water carRies but also compacts

Answer:

White Lake was contaminated with the Chemical Complany dispersing their waste in the lake. Eventually, they were forced to stop dumping it into the lake

To find the spherical convex mirror radius, learn the focal length and magnitude.

What is focal length?

The focal length of a thin lens in air is measured from the lens's center to its primary foci, also known as focal points. The focal length of a converging lens, such as a convex lens, is positive and determines how far a collimated light beam must travel to focus on a single point.

What is magnitude?

Magnitude typically refers to size or distance. By comparing the size and motion speed of the object, we can relate magnitude to movement. The object's or quantity's size determines its magnitude.

R=0.123m

Focal length E= R/2

E= - 0.0615m.

Therefore, the focal length is 0.0615m.

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Answer:

Explanation:

hope this helps

The maximum speed of the bucket can experience before the rope snaps if A 3.4-kg bucket of water is attached to a 1.0-m rope. The bucket is swung in a circle at a speed of 10.0-m/s is 10.85 m / s.

Force is the influence of either pull or pushes in the body. Basically, gravitation forces, nuclear forces, and friction forces are the types of forces. For e.g. when the wall is hit by a hand then a force is exerted by the hand on the wall as well as the wall also exerts a force on the hand. There are different laws given to Newton to understand force.

Newton is a unit of force used by physicists that is part of the International System (SI). The force required to move a body weighing one kilogram one meter per second is known as a newton.

Given:

The mass of the bucket, m = 3.4 kg,

The length of the rope, r = 1 m,

The speed of the bucket, v = 10 m / s,

The force of the rope, F = 400 N,

Calculate the maximum speed by the formula given below,

\(F_c = mv^2 / r\)

400 = 3.4 v² / 1

v² = 400 / 3.4

v² = 117.6

v = 10.85 m / s

Therefore, the maximum speed of the bucket can experience before the rope snaps if A 3.4-kg bucket of water is attached to a 1.0-m rope. The bucket is swung in a circle at a speed of 10.0-m/s is 10.85 m / s.

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The conduction of current on the postsynaptic neuron in an electrical synapse occurs through direct flow of ions between the presynaptic and postsynaptic neurons.

In electrical synapses, the conduction of current on the postsynaptic neuron occurs through direct flow of ions between the presynaptic and postsynaptic neurons. These synapses are formed by specialized structures called gap junctions, which create channels between the cells, allowing ions to pass through. The channels are formed by connexin proteins that span the plasma membranes of adjacent neurons.

When an action potential reaches the presynaptic neuron, it depolarizes the cell membrane and triggers the opening of voltage-gated ion channels. This results in the influx of positively charged ions, such as sodium (Na+), into the presynaptic neuron. As a result, the electrical potential of the presynaptic neuron becomes more positive.

Due to the direct connection provided by the gap junctions, these positive ions can flow through the channels into the postsynaptic neuron. This movement of ions generates an electrical current that spreads across the postsynaptic neuron. The current causes depolarization of the postsynaptic membrane, leading to the initiation of an action potential in the postsynaptic neuron.

The strength of the electrical synapse is determined by the size of the gap junctions and the number of connexin proteins present. The larger the gap junctions and the more connexin proteins, the more ions can pass through, resulting in a stronger electrical coupling between the neurons.

at electrical synapses, the conduction of current on the postsynaptic neuron occurs through the direct flow of ions between the presynaptic and postsynaptic neurons via specialized gap junctions. This direct electrical coupling allows for rapid and synchronized transmission of signals. Electrical synapses are particularly important in neural circuits that require fast and coordinated communication, such as in reflex arcs or the synchronization of cardiac muscle cells.

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The key function of the hormonal secretions that accompany an emotion is to prepare the body for the appropriate response is stimulation of defecation.

When an individual experiences an emotion, such as fear or anxiety, the body prepares for the fight or flight response. This response involves an increase in heart rate, respiration, and blood pressure. In addition, hormones such as adrenaline and cortisol are released to help prepare the body for the appropriate response. Adrenaline increases blood flow to the muscles and increases the breakdown of glycogen to provide energy for the body. Cortisol increases blood glucose levels and decreases inflammation.

In some cases, emotions may also stimulate defecation. This is because the body wants to eliminate any unnecessary weight or distractions so that it can focus on the situation at hand. This is why individuals may experience "butterflies in their stomach" or have the urge to go to the bathroom when they are nervous or anxious.

In summary, the key function of hormonal secretions that accompany an emotion is to prepare the body for the appropriate response. This includes an increase in heart rate, respiration, and blood pressure, as well as the release of hormones such as adrenaline and cortisol. In some cases, emotions may also stimulate defecation to eliminate unnecessary distractions.

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To determine the speed at which the baseball player threw the ball and the height it reached, we can use the equations for motion with constant acceleration. So hence  t is the time it took for the ball to return to the player's hand.

Since the ball was thrown vertically upward and we know the time it took for it to return to the player's hand, we can use the following equation to determine the initial velocity (vₒ) of the ball: vₒ = gt . where g is the acceleration due to gravity (approximately 9.8 m/s²) and t is the time it took for the ball to return to the player's hand (3.0 s).

Plugging in the known values, we get:

vₒ = 9.8 m/s² x 3.0 s = 29.4 m/s

To determine the height the ball reached, we can use the following equation: h = vₒt + (1/2)gt²

where h is the height, vₒ is the initial velocity, t is the time it took for the ball to return to the player's hand, and g is the acceleration due to gravity.

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Answer:

asteroid belt

Explanation:

The asteroid belt is a torus-shaped region in the Solar System, located roughly between the orbits of the planets Jupiter and Mars, that is occupied by a great many solid, irregularly shaped bodies, of many sizes but much smaller than planets, called asteroids or minor planets.

Answer:

5m North

Explanation:

Displacement is the distance between an object's current vs starting position.

If we consider the starting position to be (0,0), we subtract 1 from the y-component to go south and add 6 to go north. We get a position of (0,5), or 5m north.

Answer:current

Explanation:water flows down a river. Current flows down a wire (in the drude model, at least)

Answer:

electricity

Explanation:

Among the reasons for the frequent use of composite measures is that they give a more comprehensive and accurate indication of a given variable. Besides, the researcher is seldom able to develop in advance single indicators of complex concepts. A single data item might not have enough categories to provide a range of variation. And lastly, they are efficient data reduction devices.

So, the correct answer is option (e) all of these choices.

Composite measures are used to combine several variables or scores into a single measurement or index. In other words, they are multidimensional measurement tools. It is useful to make this kind of index because it is possible to calculate the reliability and validity of composite measures, which are statistical measures that indicate whether or not the measurements were conducted accurately or are otherwise legitimate.

For example, if a researcher wants to assess the economic development of a country, he/she could create a composite measure by combining data on GDP per capita, literacy rates, and poverty rates. In this case, each of the three variables reflects a different aspect of economic development.

So, the correct answer is E.

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Answer:

current must flow and chemical energy must take place

When the electric field is pointing towards you and its magnitude is increasing the induced magnetic field will be clockwise and when the electric field is pointing away from you and its magnitude is decreasing the induced magnetic field will be clockwise.

According to Faraday's law of electromagnetic induction, a changing electric field induces a magnetic field. The direction of the induced magnetic field can be determined using Lenz's law, which states that the direction of the induced magnetic field is such that it opposes the change that produced it.

In summary, when an electric field is changing, the direction of the induced magnetic field is such that it opposes the change that produced it, regardless of the direction of the electric field.

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Given:

The mass of the automobile is

To find:

The weight of the car in N and its mass in kg

Explanation:

We know,

So, the mass of the automobile is

1. Frequency

2. Reflected

3. Absorbed

4. Black

Answer:

pls mark as brainliest

Explanation:

Velocity and speed is constant

Answer:

hahaha thank you for the points

The slopes that are formed by angular, ragged stones are more stable because they have the largest angle of repose.

1. In physics, the angle formed by the plane de contact between both bodies and the horizontal so when upper body is just about to slide: the angle whose tangent represents the frictional resistance of the two bodies.

One aspect of inter particulate friction, or the resistance to particle movement, is angle of repose. The USP describes it as the consistent, three-dimensional angle (relative to the horizontal base) acquired by a cone-shaped pile of material created using any of a number of different techniques.

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Answer:

Burning fossil fuels contributes to climate change.

Fossil fuels are nonrenewable.

Explanation:

Fossil fuels are fuels formed from the remains of dead organic matters that have long been buried under the ground while hydrogen fuel cells are formed from electrochemical reactions.

Fossil fuel burning creates pollution in the environment and some of the pollutants generated contribute to global warming and associated climate change. This is as opposed to fuel cells that generate power through electrochemical reactions and whose products can be converted for other uses.

Also, fossil fuel deposits are finite and non-renewable. Once their deposits become exhausted, there is no way to artificially regenerate them unlike fuel cells.

Answer:

i hope this helps

Explanation:

1.24% percentage of parts will not meet the weight specs amd the sample means will fall between 25.046 and 25.354 ounces.

a. To determine the percentage of parts that will not meet the weight specifications, we need to calculate the probability of a part weighing less than 24.7 ounces or more than 25.7 ounces. First, we need to calculate the z-scores for these values using the formula:

z = (x - μ) / σ

where x is the value, μ is the mean, and σ is the standard deviation. For 24.7 ounces:

z1 = (24.7 - 25.2) / 0.20 = -2.50

For 25.7 ounces:

z2 = (25.7 - 25.2) / 0.20 = 2.50

Using Table-A (Z-score table), we can find the area under the standard normal curve corresponding to these z-values. From the table, the area to the left of -2.50 is 0.0062, and the area to the right of 2.50 is also 0.0062. Therefore, the total probability of a part not meeting the weight specs is:

P(z < -2.50 or z > 2.50) = P(z < -2.50) + P(z > 2.50) = 0.0062 + 0.0062 = 0.0124

So, the percentage of parts that will not meet the weight specs is .

b. To determine the values within which 99.74% of the sample means will fall, we need to calculate the margin of error for a sample mean. The margin of error is given by the formula:

E = z * (σ / sqrt(n))

where E is the margin of error, z is the z-score corresponding to the desired level of confidence (in this case, 99.74% corresponds to a z-score of 2.75), σ is the standard deviation, and n is the sample size.

Plugging in the values:

E = 2.75 * (0.20 / sqrt(10)) ≈ 0.154

The range of sample means will be within ±E of the population mean. Therefore, the values within which 99.74% of the sample means will fall are:

25.2 ± 0.154 = (25.046, 25.354)

So, for samples of size 10, 99.74% of the sample means will fall between 25.046 and 25.354 ounces.

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