1. Write down the first 5 letters of your name that have a corresponding amino acid. For instance, if your name is Albert, write down A, L, E, R, T (notice the letter B was not written down because there is no corresponding amino acid). Move onto your last name if your first name doesn't produce 5 amino acids. 2. Draw your peptide at a pH of 2.0. Make sure you have drawn the peptide bonds in the correct orientations (i.e. cis or trans) and refer to the pKa values provided in the lecture notes to assist with drawing each amino acid in the correct ionization state. 3. Label the N - and C - teini in the pentapeptide above. 4. What is the net charge of your pentapeptide at pH1.0,pH7.4, and pH14 ?

Answer: b. Propane is typically used as a fuel gas in oxyfuel cutting process.

Oxyfuel cutting is a thermal cutting process that uses a fuel gas and oxygen to generate a high-temperature flame to melt and sever metals. The process involves heating a metal to its ignition temperature by focusing a flame on it, and then introducing a stream of high-pressure oxygen to the heated area, which reacts with the metal and oxidizes it. The oxidized metal is then blown away by the force of the oxygen stream, resulting in a clean cut.

The fuel gas used in oxyfuel cutting is typically a hydrocarbon such as propane, acetylene, or natural gas. These gases are used as the fuel source for the process and are mixed with oxygen in the cutting torch to create a high-temperature flame. Propane is a common choice for fuel gas in oxyfuel cutting due to its high energy content, clean-burning properties, and ease of use.

Other gases, such as nitrogen and argon, are not typically used as fuel gases in oxyfuel cutting. Nitrogen is an inert gas that is often used as a shielding gas in welding applications to prevent oxidation of the weld, but it does not have the energy content or reactivity needed for oxyfuel cutting. Argon is another inert gas that is used in welding applications for shielding, but it is not typically used in oxyfuel cutting due to its low reactivity and inability to sustain a high-temperature flame.

Wrapping a hot potato in aluminum foil significantly reduces the rate at which it cools primarily by reducing heat loss through conduction. The aluminum foil acts as a barrier that slows down the transfer of heat from the potato to its surroundings, keeping it warm for a longer period.

Wrapping a hot potato in aluminum foil significantly reduces the rate at which it cools by reducing the process of conduction. Conduction is the transfer of heat between two objects that are in contact with each other. When a hot potato is left in open air, it transfers heat to the surrounding air molecules through conduction, resulting in a rapid decrease in temperature. However, wrapping the potato in aluminum foil prevents direct contact with the air, which decreases the rate of conduction and keeps the potato hotter for a longer period. Therefore, the correct answer is D. conduction.
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Answer:

length/width

Explanation:

Answer:

Length/Width

Explanation:

I did the module 10 exam so I know it is length/width

The statements correctly describe resonance structures is The actual molecule is an average of the Lewis structure. Therefore, option B is correct.

The representations known as Lewis structures, often referred to as Lewis dot formulas, Lewis dot structures, electron dot structures, or Lewis electron dot structures, depict the interactions between the atoms in a molecule as well as any lone pairs of electrons that may be present.

The electronic bonding of a single polyatomic species, including fractional bonds and fractional charges, is described by resonance structures, which are a collection of two or more Lewis structures.

In comparison to separate resonance structures, the resonance hybrid is more stable. The movement of a charge between two or more atoms is frequently represented by resonance structures. These atoms have a more evenly distributed charge, which makes it more stable.

Thus, option B is correct.

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Answer:

See explanation

Explanation:

Sr(s) + 2HCl(aq) -----> SrCl2(aq) + H2(g)

Ionically;

Sr(s) + 2Cl^-(aq) ----> SrCl2(aq)

If we look at the reaction above, strontium atom was dissolved in hydrochloric acid. The strontium atom is now oxidized by the acid to give Sr^2+ ion according to the equation shown above.

D because that’s the only one that makes sense

Pure substances typically only include one type of atom or molecule and are homogeneous in nature. The majority of these chemicals have a consistent or homogeneous makeup. Thus, option C is correct.

Elements are pure compounds that cannot be chemically broken down into less complex ones. Iron, gold, sulfur, oxygen, and oxygen are some well-known elements.

Because it cannot be converted into a more basic substance, an element is an example of a pure substance. Examples of pure substances include water, neon, and sodium chloride (NaCl) (table salt).

One element or a few related compounds make up pure substances. A kind of matter with a predictable chemical composition and physical properties is referred to as a chemical substance.

Homogeneous mixes are made up of two or more components or compounds that cannot be seen separately from one another.

Therefore, a single element or compound show properties of pure substance.

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Asbestos, a fire-resistant material, is no longer used due to its carcinogenicity.

Asbestos, a fire-resistant material that was widely used in building insulation and fireproofing, has been linked to various types of cancer and respiratory diseases. Due to its carcinogenicity and health hazards, it is no longer used in construction. Asbestos fibers are easily inhaled and can cause lung cancer, mesothelioma, and asbestosis, a lung disease that causes shortness of breath and other symptoms.

These health hazards associated with asbestos exposure led to its prohibition in many countries. The United States banned the production and use of asbestos in 1989, while the European Union banned it in 2005. Despite the ban, asbestos is still found in some older buildings and products, which requires safe handling and removal protocols to prevent asbestos exposure and ensure public health and safety.

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Show the chocolate's altered phase, The freedom of motion of the molecules can alter when energy is transferred to or from a substance.

The stimulants found in chocolate, such as caffeine, theobromine, and the amphetamine-like substance phenylethylamine, are probably to blame for the fact that so many of us eat it just out of a sensation of yearning. Another component of chocolate is the cannabinoid anandamide, which is supposed to help with cravings.

Three aldehydes, 1-methylpropanal, 2-methylbutanal, and 3-methylbutanal, are responsible for the characteristic aroma of chocolate [48]. They are created from amino acids, which also help to define their structure, during the roasting of cocoa beans.

In conclusion, black chocolate has 4.01 x 10²² sugar molecules, 7.7 x 10²² sugar molecules in white chocolate, and 7.4 x 1022 sugar molecules in milk chocolate.

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Answer:

The velocity of the bb when it reaches a height of 203 m can be determined using the laws of projectile motion. Since the bb is moving vertically upwards, its velocity at that height will be zero.

brainlest?

Answer: v = 83.96 m/s

Assuming the acceleration due to gravity is approximately 9.8 m/s^2, we can use the principles of projectile motion and energy conservation.

Using the equation for the vertical displacement of an object in free fall:

Δy = (v₀² - v²) / (2g)

Δy = vertical displacement (203m)

v₀ = initial velocity (105 m/s)

v = final velocity (not known yet)

g = accerlation due to gravity (9.8 m/s^2)

Lets rearrange the equation to solve for the final velocity:

v = v = √(v₀² - 2gΔy)

Substituting the given values:

v = √(105² - 2 * 9.8 * 203)

v ≈ √(11025 - 3979.6)

v ≈ √(7054.4)

v ≈ 83.96 m/s

Therefore, when the BB pellet is at the height of 203m, its velocity will be approximately 83.96 m/s.

The new kinetic energy per molecule at a temperature of 22 °C is approximately 6.56 x 10^-21 J.

Kave = (3/2) kT

To solve this problem, we can first convert the given temperature of 11 °C to Kelvin:

T1 = 11 °C + 273.15 = 284.15 K

Kave1 = (3/2) kT1

Next, we can calculate the new kinetic energy per molecule at a temperature of 22 °C:

T2 = 22 °C + 273.15 = 295.15 K

Kave2 = (3/2) kT2

Kave2 = (3/2) kT2 = (3/2) (1.38 x 10^-23 J/K) (295.15 K) ≈ 6.56 x 10^-21 J

A molecule is the smallest particle of a substance that retains its chemical and physical properties. It is formed by the combination of two or more atoms, which are held together by chemical bonds. Molecules can be made up of atoms of the same element or different elements, and their properties depend on the type and arrangement of atoms within the molecule.

Chemical reactions involve the breaking and forming of chemical bonds between molecules, and the study of molecules is essential in understanding chemical reactions and the behavior of matter. Molecules can be classified based on their shape, size, and chemical properties, and this classification helps in predicting their behavior under different conditions. Molecules are the building blocks of all matter, and their interactions with other molecules determine the properties and behavior of matter at the macroscopic level.

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Complete Question:

At 11 °C, the kinetic energy per molecule in a room is Kave.

A) If the temperature rises to 22 °C, what will the new kinetic energy per molecule be?

Answer:

3s^1 would be 3s^2

Explanation:

Answer:

start moving faster

Explanation:

i would guess because they slow down our freeze when they get cold

a) In contrast, CH2ClCH2CO2H lacks a double bond and cannot undergo resonance, making the conjugate base less stable and the acid weaker, b) In the pair M-ClC6H4CO2H and P-ClC6H4CO2H, P-ClC6H4CO2H would be expected to be stronger

a. In the pair CH2ClCH2CO2H and CH3CHCHCO2H, CH3CHCHCO2H would be expected to be stronger. This is because the presence of the double bond in CH3CHCHCO2H allows for delocalization of the negative charge in the conjugate base, making it more stable. The presence of the double bond facilitates resonance, which disperses the negative charge over a larger area, resulting in greater stability of the conjugate base. In contrast, CH2ClCH2CO2H lacks a double bond and cannot undergo resonance, making the conjugate base less stable and the acid weaker.

b. In the pair M-ClC6H4CO2H and P-ClC6H4CO2H, P-ClC6H4CO2H would be expected to be stronger. This is because the para position (P) is closer to the carboxylic acid group than the meta position (M), allowing for greater delocalization of the negative charge in the conjugate base. The closer proximity of the electron-withdrawing chlorine group to the carboxylic acid group enhances the acidity of P-ClC6H4CO2H compared to M-ClC6H4CO2H. The electron-withdrawing effect of the chlorine group stabilizes the conjugate base, making the acid stronger.

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Answer:

In 1889, Ernest Rutherford recognized and named two modes of radioactive decay, showing the occurrence of both processes in a decaying sample of natural uranium and its daughters. Rutherford named these types of radiation based on their penetrating power: heavier alpha and lighter beta radiation. Gamma rays, a third type of radiation, were discovered by P. Villard in 1900 but weren't recognized as electromagnetic radiation until 1914. Since gamma radiation is only the discharge of a high-energy photon from an over-excited nucleus, it does not change the identity of the atom from which it originates and therefore will not be discussed in depth here.

Because nuclear reactions involve the breaking of very powerful intra nuclear bonds, massive amounts of energy can be released. At such high energy levels, the matter can be converted directly to energy according to Einstein's famous Mass-Energy relationship E = mc2. The sum of mass and energy are conserved in nuclear decay. The free energy of any spontaneous reaction must be negative according to thermodynamics (ΔG < 0), and ΔG is essentially equal to the energy change ΔE of nuclear reactions because ΔE is so massive.

Explanation:

Hope it helps

The average atomic mass of the Mc in the sample, given the that the hypothetical mass spectrum of Mc, is 289.1 amu

First, we shall determine the atomic mass of each isotope as shown from the spectrum. Details below:

For 1st isotope

Atomic mass of 1st isotope = (Number of atom /total atom) × atomic mass

Atomic mass of 1st isotope = (3 / 10) × 288.2

Atomic mass of 1st isotope = 86.46 amu

For 2nd isotope

Atomic mass of 2nd isotope = (Number of atom /total atom) × atomic mass

Atomic mass of 2nd isotope = (5 / 10) × 289.2

Atomic mass of 2nd isotope = 144.6 amu

For 3rd isotope

Atomic mass of 3rd isotope = (Number of atom /total atom) × atomic mass

Atomic mass of 3rd isotope = (2 / 10) × 290.2

Atomic mass of 3rd isotope = 58.04 amu

Finally, we shall determine the average atomic mass of Mc. Details below:

Average atomic mass of Mc = sum atomic masses of isotopes

Average atomic mass of Mc = 86.46 + 144.6 + 58.04

Average atomic mass of Mc = 289.1 amu

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True. For example, the reference table of vibrational modes and their wavenumbers for several functional groups was published by the National Institute of Standards and Technology (NIST) in 1986.

This table provides information on the vibrational modes of different functional groups such as alcohols, amines, ketones, and carboxylic acids, as well as their wavenumbers. This is important for spectroscopy studies since the wavenumbers of different functional groups can be used to identify certain compounds and to study their structure.

The NIST also publishes an updated version of this table, which includes additional functional groups. This table can be used as an important reference for researchers in the field of spectroscopy.

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Answer: what question?

Explanation:

Answer:

theirs no question

Explanation:

no question or picture

No, the volume of water in a beaker is not an extensive property.

Extensive properties are those that depend on the amount or size of the substance being measured. In other words, they are properties that change with the quantity of the substance. Examples of extensive properties include mass, volume, and total energy.

In the given scenario, the volume of water in the beaker is 50 milliliters. This volume remains the same regardless of the quantity of water present. Whether it's 50 milliliters or 500 milliliters, the volume measurement does not change. Therefore, the volume of water in the beaker is an example of an intensive property.

Intensive properties are independent of the amount or size of the substance. They are characteristics that remain constant regardless of the quantity of the substance. Examples of intensive properties include temperature, density, and color.

It's important to note that the distinction between extensive and intensive properties depends on the specific property being considered. While volume is typically an extensive property for a bulk substance, in the case of a fixed volume of water in a beaker, it becomes an intensive property.

In summary, the volume of water in a beaker is not an extensive property but rather an intensive property because it does not change with the quantity of the substance.

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Answer:

The Sunlight

Oxegyn

Heat in soi

Explanation:

Answer:

sun, air, and heat.

Explanation:

hope this helps!

A column at high temperature can reduce the retention time.

The components do not have interaction with the desk bound segment as strongly leading to negative separation of components within the column and occasional retention instances. A excessive drift price can gradually lessen the retention time.

Temperature is the measure of hotness or coldness expressed in terms of any of numerous scales, such as Fahrenheit and Celsius. Temperature shows the route in which heat energy will spontaneously float—i.e., from a warmer frame (one at a higher temperature) to a colder frame (one at a decrease temperature).

Temperature plays a crucial function in medical care (each human beings and animals), food, drinks, and agriculture. Our universal fitness is frequently reliant upon temperature in many approaches as nicely. keeping proper temperature ranges in medical cold garage regions is important.

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Answer:

Metals

Explanation:

When acids react with metals h2 gas is produced and a salt is formed

eg. Na + HCL ---------- NaCl + H2

Answer:

active metals

Explanation:

The radiocarbon age of the deeper layer of sediment in the cave is approximately 4160 years.

This age is determined by measuring the ratio of Carbon-14 (14C) to Carbon-12 (12C). Charcoal is often used for this purpose because it is preserved for long periods of time.

The ratio of 14C to 12C is typically used to calculate the age of a sample. This is because the amount of 14C in a sample decreases over time due to radioactive decay, meaning a sample with a lower ratio of 14C to 12C has been around longer than one with a higher ratio.

In the case of the cave sample, the ratio of 14C to 12C was found to be only 15% of that of the charcoal sample from a higher level with a known age of 2540 years.

To calculate the age of the deeper layer, we need to take the known age of 2540 years and divide it by 0.15 (the ratio of the cave sample to the higher level sample). This gives us a radiocarbon age of 4160 years for the deeper layer of sediment.

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Answer:

It is important to collect all data first, or else your guesses could purely be the opposite of the right answer. If you make inferences of what might happen, your guesses may be purely fictional, and totally off-topic. During experiments, this step is important.

A good opening statement in passive voice would be 3 ounces of potassium cyanide were added to 1/2 cup of skim milk.

The passive voice is used in scientific writing to emphasize the object or the experiment being studied, rather than the subject performing the experiment. This allows the reader to focus on the experiment itself, rather than the person performing the experiment.

In writing experiments, passive voice statements are used to describe the process that was followed to conduct the experiment, the results that were obtained, and the conclusions that were drawn.

For example, a passive voice statement might read: "The experiment was conducted using a specific methodology," rather than "I conducted the experiment using a specific methodology."

The use of the passive voice in scientific writing also allows the writer to remain unbiased and objective. By not referring to the subject performing the experiment, the writer is able to focus on the experiment itself.

This can help to ensure that the results and conclusions are based solely on the data that was collected, rather than any preconceived notions or biases that the writer might have.

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Answer:

⇒ n = 2.4088 × 10²⁴

- So, the no of atoms in 4 moles of helium is 2.4088 × 10²⁴.

Explanation:

Therefore, the net ionic equation for the reaction is Copper(2+) (aq) + 2 chlorine- (aq) → Copper(II) chloride (aq).

Ammonium sulphate and Copper hydroxide precipitate are the first products of the reaction between copper sulphate and ammonium hydroxide.

Mixing copper(II) sulphate and ammonium chloride results in the following observations:

Conventional: When copper ions (Copper2+) from Copper(II) sulfate are present, a blue solution develops. The colour of Ammonium Chloride doesn't seem to have changed at all.

Ionic total: While Ammonium Chloride dissociates into Ammonium and Chlorine- ions in solution, Copper(II) sulfate dissociates into Copper2+ and Sulfate 2- ions.

Copper(II) sulfate (aq) + 2 Ammonium Chloride (aq) → Copper(II) Chloride (aq) + 2 Ammonium (aq) + Sulfate 2- (aq)

Net Ionic: The net ionic equation shows only the species involved in the reaction. In this case, the Copper2+ and the Cl- ions combine to form Copper(II) chloride.

Copper2+ (aq) + 2 Chlorine- (aq) → Copper(II) chloride (aq)

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Answer:

Chemical energy.

Explanation:

This is biology btw, not chemistry

\(\\ \sf\longmapsto C_3H_8+O_2\longrightarrow 4H_2O+3CO_2\)