1. Which has more kinetic energy, a 40 kg cheetah running at 25 m/s or a 4,000 kg elephant moving at 2 m/s? How much more energy does it have?

2. At what speed would the animal with less KE have to travel to have the same kinetic energy as the animal with more KE?

3. Discuss the kinetic and potential energy of the ball on the end of a pendulum as it swings from point A to point B. Explain the kinetic energy and potential energy of the ball at each point and what happens to energy as the ball moves from point A to point B. In your discussion, answer the following questions: When is the kinetic energy of the ball zero and when is it at its highest? When is its potential energy at its lowest and at its highest? What happens to the kinetic energy and potential energy between point A and point B?

Joe's resulting velocity of mass 65 kg is 0.125 m/s.

Velocity is the rate of change of displacement.

To calculate Joe's resulting velocity, we use the formula below

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the velocity is 0.125 m/s.

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Answer:

The momentum, ΔP, and therefore, kinetic energy given to the ball in a serve is the result of the product of the tension force, 'F', in the string and the time of contact, Δt, between the ball and the string

ΔP = F × Δt

Explanation:

The impulse, ΔP, is the produce of the force, 'F', applied to a body for a given period of time, Δt', that gives motion to the body, and it is equal to the change of momentum of the body

ΔP = F × Δt

The momentum, 'P', of a body is the product of the mass, 'm', of the body and its velocity, 'v'

P = m × v

Tension is the axial pulling force of a string

T = Axial Force, F\(_{axial}\)

The tension used in Tennis Racket strings is between 40 to 65 lbs.

When high tension is used in the string, the string is taut, and the contact duration between the Racket string and the ball is minimal, and the player needs to use more force to obtain a high momentum, and therefore, energy in the ball, which reduces control, and increase stress, as force is more emphasized

When low tension is used in the string, the Tennis Racket strings are more elastic. During a serve, the ball pushes the strings further back into the racket, such that the ball spends more time in contact with the string, (Δt is larger), and therefore, the impulse, F·Δt = ΔP, given to the ball is larger, therefore, the ball has a larger change in momentum, and therefore more energy in the intended direction.

However, a very slackened string will increase the increase area and time (large Δt) of contact of the ball and the racket such that the force given to the ball, F = ΔP/(large Δt) is reduced and therefore reduce the likelihood of gaining points from a serve against an opponent with a much forceful return of a serve.

Hi there!

We can begin by finding the angular velocity using dimensional analysis:

\(\frac{1 rev}{0.56 s} * \frac{2\pi rad}{1 rev} = 11.22 rad/sec\)

(A)

Find the flea's velocity using the following relationship:

v = ωr

v = (11.22)(0.20) = 2.24 m/s

(B)

Centripetal acceleration is given by:

a = ω²r

a = (11.22²)(0.20) = 25.18 m/s²

Answer:

B

Explanation:

One positive charger and one negative charger

Answer: Wrong

Explanation:

The statement that accurately describes  the relationship between bond strength and the melting and boiling points of a substance is; "substances held together by ionic bonding have higher melting  and boiling points than those held together by hydrogen bonding."

Intermolecular forces refers to forces of attraction that holds molecules together in a particular state of matter. The nature and magnitude of intermolecular forces impacts on the magnitude of the melting and boiling points of substances.

Substances held together by ionic bonding have higher melting  and boiling points than those held together by hydrogen bonding. The bonds between ionic substances can only be broken at very high temperature.

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If a black hole has the mass of the Sun approximately, the radius of the event horizon is 2.95 kilometers. If a black hole has the mass of the Earth approximately, the radius of the event horizon is 8.87 millimeters.

We can use the formula provided to calculate the radius of the event horizon for both black holes. The formula is:   Rsch = 2GM/c²

(a) For a black hole with the mass of the Sun:
M = 1 solar mass = 1.989 x 10^30 kg (mass of the Sun)

Now, plug the values into the formula:
Rsch = (2 x 6.67 x 10^-11 m^3/kg.s² x 1.989 x 10^30 kg) / (3 x 10^8 m/s)²

Rsch = 2.95 x 10^3 meters = 2.95 kilometers

(b) For a black hole with the mass of the Earth:
M = 5.972 x 10^24 kg (mass of the Earth)

Now, plug the values into the formula:
Rsch = (2 x 6.67 x 10^-11 m^3/kg.s² x 5.972 x 10^24 kg) / (3 x 10^8 m/s)²

Rsch ≈ 8.87 x 10^-3 meters = 8.87 millimeters

So, for a black hole with the mass of the Sun, the radius of the event horizon is approximately 2.95 kilometers. For a black hole with the mass of the Earth, the radius of the event horizon is approximately 8.87 millimeters.

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The magnitude of the magnetic field at point P, which is at the center of the semicircle, is given by the formula mu_0 i/2R, where mu_0 is the magnetic constant, i is the current flowing through the semicircle, and R is the radius of the semicircle.

This formula is derived from the Biot-Savart law, which states that the magnetic field at a point is proportional to the current flowing through a wire and the distance from the wire to the point.

The given options are slightly different from the correct formula, but the correct answer is mu_0 i/2R. The other options involve either pi or R^2 in the denominator, which is not consistent with the formula. The correct formula only has 2R in the denominator.

To calculate the magnetic field at point P, you would need to know the current flowing through the semicircle and the radius of the semicircle. Once you have these values, you can plug them into the formula mu_0 i/2R to find the magnetic field at point P. It is important to note that the direction of the magnetic field is perpendicular to the plane of the semicircle and follows the right-hand rule.

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The statement "Stars have their own light" is the true statement of the following.

The answer is Option (C).

Stars are one of the most important celestial bodies in the universe. At the base of any existing system, there exists a star, providing heat, and light and holding many bodies together with their immense gravity.

Millions of stars are born every minute, and many of them die in explosions, which are extremely beautiful.

Now, by looking at the statements given, we can understand a few properties of stars.

Our Sun, which is very huge in size compared to the planet we live in, is in reality very small compared to the other stars in the universe. As a fact, the largest star is about 5 billion times larger than our Sun.

All the stars which we see in our night sky are actually not so nearby. Some of them are millions of light-years away but emit light bright enough to be visible at such a great distance.

Stars do have their own light, emitted due to the continuous fusion reactions in the stars. They provide a seemingly endless source of energy, which runs them for billions of years.

Thus, the statement in option (C) is correct.

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The true statement about stars is that stars have their own light.

stars are massive celestial bodies made up of hot gases, primarily hydrogen and helium. They emit light and heat energy through the process of nuclear fusion occurring in their cores. Stars vary in size, temperature, and brightness.

The statement 'stars have their own light' is true. Stars generate their own light through the process of nuclear fusion. The intense heat and pressure in their cores cause hydrogen atoms to fuse together, forming helium and releasing a tremendous amount of energy in the form of light and heat. This process is what makes stars shine.

On the other hand, the statement 'Stars are so close to Earth' is false. While stars may appear close to each other in the night sky, they are actually incredibly far away from Earth. The distances between stars are measured in light-years, which is the distance light travels in one year.

Therefore, the correct answer is 'C. Stars have their own light.'

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At the summit of Mount Shasta,

Atmospheric pressure, Patm = 58.5 kPa

                                             = 58500Pa

Let h be the height that water will reach when siphoned at the summit.

58500 Pa = h x 1000 kg/m^3 X 9.8 m/s^2

h = 58500 Pa/1000 kg/m^3 X 9.8 m/s^2

h = 5.97 m

Therefore, at the summit the water will rise to a height of 5.97 m, which is less than 8.5 m.

Hence, the student will not be successful in her attempt.

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The summit the water will rise to a height of 5.97 m, which is less than 5.97 m.

Atmospheric pressure is the pressure of the air or gas surrounding the Earth. It is caused by the weight of the air pushing down on the Earth's surface. Atmospheric pressure is usually measured in millibars (mb). The average atmospheric pressure at sea level is 1013.25 mb. This value can change due to differences in weather and altitude. Low atmospheric pressure is associated with storms and high atmospheric pressure is associated with fair weather. Atmospheric pressure is important to the functioning of many everyday items, such as aircraft, car engines, and weather instruments. Additionally, atmospheric pressure changes are used in weather forecasting and to predict the movement of air masses, fronts, and storms.

At the summit of Mount Shasta,

Atmospheric pressure, Patm = 58.5 kPa

                                            = 58500Pa

Let h be the height that water will reach when siphoned at the summit.

58500 Pa = h x 1000 kg/m^3 X 9.8 m/s^2

h = 58500 Pa/1000 kg/m^3 X 9.8 m/s^2

h = 5.97 m

Therefore, at the summit the water will rise to a height of 5.97 m, which is less than 5.97 m

Hence, the student will not be successful in her attempt.

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Explanation:

sink and fill in space..........

Answer:

here

Explanation:

see in picture! hereee

The total number of revolutions undergone by the tub during the entire time interval is 23.1 revolutions.

To determine the total number of revolutions, we need to calculate the angular displacement of the tub during the starting phase, the stopping phase, and the constant speed phase.

During the starting phase, the tub goes from rest to its maximum angular speed of 2.2 rev/s. We can use the equation of motion for angular acceleration:

ω = ω₀ + αt

Given that ω₀ = 0 (initial angular speed) and ω = 2.2 rev/s (final angular speed), and t = 6.8 s (time), we can solve for α (angular acceleration). Using this angular acceleration, we can calculate the angular displacement (θ) during the starting phase.

During the stopping phase, the tub decelerates and comes to a stop. The angular displacement during this phase can be calculated using the same equation of motion for angular acceleration, with ω = 0 (final angular speed), ω₀ = 2.2 rev/s (initial angular speed), and t = 14.5 s (time).

Finally, during the constant speed phase, the angular displacement is given by ωt, where ω is the constant angular speed of 2.2 rev/s and t is the time interval between the end of the starting phase and the beginning of the stopping phase.

Adding up the angular displacements from each phase will give us the total angular displacement, which can be converted to the total number of revolutions by dividing it by 2π.

Calculating these values will result in a total of 23.1 revolutions undergone by the tub during the entire time interval.

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The heat of reaction (ΔH) for the given reaction CH4 + 2O2 → CO2 + 2H2O is approximately -322 kJ/mol. (three significant figures)

Explanation:-

To calculate the heat of reaction (ΔH) for the given reaction, we need to determine the difference in bond energies between the bonds broken and the bonds formed.

The balanced equation is:

CH4 + 2O2 → CO2 + 2H2O

Let's calculate the bond energies for each bond broken and formed using the average bond dissociation energies (in kilojoules per mole):

Bond energies for bonds broken:

C-H bond (in CH4): 413 kJ/mol (1 bond)

O=O bond (in O2): 495 kJ/mol (2 bonds)

Bond energies for bonds formed:

C=O bond (in CO2): 799 kJ/mol (1 bond)

O-H bond (in H2O): 463 kJ/mol (4 bonds, 2 per water molecule)

Now, let's calculate the heat of reaction (ΔH) using the bond energies:

ΔH = (Energy of bonds broken) - (Energy of bonds formed)

ΔH = (413 kJ/mol) + (2 * 495 kJ/mol) - (799 kJ/mol) - (2 * 463 kJ/mol)

ΔH = 413 kJ/mol + 990 kJ/mol - 799 kJ/mol - 926 kJ/mol

ΔH = -322 kJ/mol

Therefore, the heat of reaction (ΔH) for the given reaction CH4 + 2O2 → CO2 + 2H2O is approximately -322 kJ/mol. (three significant figures).

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Answer:

Most pneumonia occurs when a breakdown in your body's natural defenses allows germs to invade and multiply within your lungs.

Explanation:

Answer:

As the temperature increases, the volume of the material also increases. This is known as thermal expansion. It can also be explained as the fractional change in the length or volume per unit change in the temperature.

The relation between alpha, beta, and gamma is given in the form of a ratio and the ratio is 1:2:3 and can be expressed as:

alpha=fracbeta2=fracgamma3

Following is the relation between the three:

L = L (1 + α.ΔT)

Where, α is the coefficient of linear expansion  

A = A (1 + β.ΔT)

Where, β is the coefficient of aerial expansion

V = V (1 + γ.ΔT)

Where, γ is the coefficient of cubical expansion  

V = V + γV.ΔT

V = V (1 + γ.ΔT)  

L3 = L3 (1 + α.ΔT)3

L3 = L3 (1 + 3α.ΔT + 3α2.ΔT2 + α3.ΔT3)

L3 = L3 (1 + 3α.ΔT)

Alpha, beta, and gamma are related to one another in the form of a ratio, and that ratio is 1:2:3, and yes they are universal constants.

A substance's volume expands while its mass stays constant. Heating is typically the cause of expansion. When a substance is heated, the molecular bonds separating its particles weaken, the particles move more quickly, and the substance expands as a result.

Determine the relation as shown below,

L = L (1 + α × Δ T)

here, α is the coefficient of linear expansion  

A = A (1 + β × Δ T)

here, β is the coefficient of aerial expansion

V = V (1 + γ × Δ T)

here, γ is the coefficient of cubical expansion  

V = V + γ × V × Δ T

V = V (1 + γ × ΔT)  

L3 = L3 (1 + α × Δ T)3

L3 = L3 (1 + 3α × ΔT + 3α2 × ΔT2 + α3 × ΔT3)

L3 = L3 (1 + 3α × Δ T)

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Answer:

B. An echo

Explanation:

An echo is the sound heard after the reflection of sound waves from a hard surface. It has both advantages and disadvantages with respect to its applications.

Some of it applications include;

i. it can be used to determine the depth of the sea

ii. it can be used in crude oil exploration

iii. it can be used to determine the speed of sound in air

An echo is different to reverberation of sound.

Answer: Newton

Explanation:

Isaac Newton is viewed as one of history's most persuasive researchers. During his lifetime, Newton created the hypothesis of gravity, the laws of movement (which turned into the establishment of material science), another strategy for arithmetic known as analytics, and leap forwards in optics like the reflecting telescope.

The image height on the detector will change by a factor of 2 if you change from a 50-mm-focal-length lens to a 100-mm-focal-length lens and refocus.

The magnification of a lens is given by the ratio of the image height to the object height. Since the object height remains the same, the change in magnification is solely determined by the change in focal length.

The magnification of a lens is given by the formula:

Magnification = - (image distance / object distance).

Since we are only interested in the ratio of image heights, we can ignore the negative sign.

For the 50-mm lens, the magnification is:

Magnification1 = 50 mm / object distance.

For the 100-mm lens, the magnification is:

Magnification2 = 100 mm / object distance.

Taking the ratio of the two magnifications:

Magnification2 / Magnification1 = (100 mm / object distance) / (50 mm / object distance) = 100 mm / 50 mm = 2.

Therefore, the image height on the detector changes by a factor of 2 when switching from a 50-mm-focal-length lens to a 100-mm-focal-length lens and refocusing.

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If the temperature becomes double, the total radiant energy becomes 16 times of the initial value

stefan Boltzman's law. state that According to the Stefan-Boltzmann law, the total radiant heat power emitted by a surface is proportional to the fourth power of its absolute temperature

the total radiant Object energy emitted by is directly Propotional to the fourth Power of its temperature. the

The Stefan-Boltzmann law expresses the power radiated by a black body as a function of temperature. The Stefan-Boltzmann law states that the total energy radiated per unit surface area of a black body across all wavelengths per unit time jstar (also known as the black-body radiant emittance) is directly proportional to the fourth power of the thermodynamic temperature T of the black body.

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The magnitude of the angular velocity of the wheel after the block has descended 3.80 m is 5.23 rad/s.

Explanation :

We can use conservation of energy to solve this problem. Initially, the system is at rest and has a total energy of zero. As the block descends, its potential energy is converted into kinetic energy and work done by friction. We can express this as:

\(mgh = (1/2)mv^2 + W_{friction} + (1/2)Iw^2\)

where m is the mass of the block, g is the acceleration due to gravity, h is the height the block descends (3.80 m), v is the velocity of the block at the bottom, W_friction is the work done by friction (−8.50 J), I is the moment of inertia of the wheel, and ω is the angular velocity of the wheel.

Since the wire is wrapped around the rim of the wheel, the distance the block descends (3.80 m) is also the distance the rim of the wheel moves. Therefore, the work done by friction can be expressed as:

\(W_{friction} = -F_{friction} * d = -\)τΘ

where F_friction is the force of friction at the axle, τ is the torque exerted by friction, d is the distance the rim moves, and θ is the angle through which the wheel rotates. Since the wheel rotates through an angle of θ = h/r = 3.80 m/0.190 m = 20.0 rad, we have:

τ = W_friction / θ = -8.50 J / 20.0 rad = -0.425 N*m

Substituting the given values into the energy conservation equation and solving for ω, we get:

\((0.350 kg)(9.81 m/s^2)(3.80 m) = (1/2)(0.350 kg)v^2 - 0.425 N*m + (1/2)(0.470 kgm^2)w^2\)

Simplifying and solving for ω, we get:

ω = √[(2mgh + 2τ)/I]

\(w =\sqrt{[(2)(0.350 kg)(9.81 m/s^2)(3.80 m) + 2(-0.425 Nm)] / 0.470 kgm^2}\)

ω = 5.23 rad/s

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A negative slope's graph slopes downhill from left to right. When viewing a graph on a xy coordinate plane, the slope is negative because as x rises, y falls.

The line is sloped downhill from left to right when there is a negative slope. Here, the inverse link between the two variables depicted along the x- and y-axes of the negative slope graph applies. The other variable decreases when the first variable goes up.

Negative values are below the origin on the y-axis and to the left of the origin on the x-axis. If the x-value is negative, begin at the origin and go to the left. In the event that the y-coordinate is negative, descend.

A line that slopes positively ascends from left to right. Remember that a line with a negative slope descends from left to right.

Therefore, Graph below the x axis and in the negative downward slope direction.

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Recall, Newton's gravitational law states that any particle of matter in the universe attracts any other particle with a force varying directly as the product of their masses and inversely as the square of the distance between them. It is expressed as

F = Gm1m2/r^2

where

F is the force in Newton

G is gravitational constant = 6.673 x 10^-11 Nm^2/kg^2

m1 and m2 are the masses in kg

r is the distance in meters

From the information given,

r = 1.5

acceleration = 2cm^2/s

Recall, 100 cm = 1m

2 cm = 2/100 = 0.02m

Thus,

acceleration = 0.02m/s^2

Since the masses are identical, then m1 = m2

Each of them is accelerating at 0.02m/s^2

Recall,

Force = mass x acceleration

Force = m1 x 0.02 = 0.02m1 N

By substituting the given values into the formula, we have

0.02m1 = (6.673 x 10^-11 x m1 x m1)/1.5^2

m1 on the left cancels out one m1 on the right. It becomes

0.02 = (6.673 x 10^-11 x m1)/1.5^2

By crossmultiplying,

0.02 x 1.5^2 = 6.673 x 10^-11 x m1

0.045 = 6.673 x 10^-11 x m1

m1 = 0.045/6.673 x 10^-11

m1 = 6.74 x 10^8 kg

The mass of each ball is 6.74 x 10^8 kg

A house is designed to have passive solar energy features, Brickwork is to be incorporated into the interior of the house to act as a heat absorber. Each brick weighs approximately 1.8 kg. The specific heat of the brick is 0.85 j/g-K. How many bricks must be incorporated into the interior of the hose to provide the same total heat capacity as 1.0 103 gal of water.

The heat capacity of the water can be calculated using the specific heat capacity formula as follows:Q = m * C * ΔTWhere Q is the amount of heat energy, m is the mass of water, C is the specific heat of water, and ΔT is the change in temperature.To find the mass of water, we need to convert the volume from gallons to kilograms.1 gal of water = 3.78541 kg of waterTherefore, 1.0 x 103 gal of water = 3.78541 x 1.0 x 103 = 3.78541 x 103 kg of waterNow, let us calculate the heat capacity of water.Qwater = m * C * ΔTQwater = 3.78541 x 103 * 4.18 * (20 - 10)Qwater = 1.58 x 105 J/KNow, let us calculate the heat capacity of one brick.Qbrick = m * C * ΔTWe are looking for the number of bricks required to have the same heat capacity as 1.0 x 103 gal of water.

Thus, we can equate the two heat capacities as follows:Qbrick = QwaterTherefore,mbrick * Cbrick * ΔT = mwater * Cwater * ΔTmbrick * Cbrick = mwater * Cwatermbrick = (mwater * Cwater) / CbrickSubstituting the values,mbrick = (3.78541 x 103 x 4.18) / (0.85 x 1000)Note that we have converted the specific heat of the brick from J/g-K to J/kg-K. This is because the mass of the brick is given in kilograms.Thus,mbrick = 19.03Therefore, 19 bricks must be incorporated into the interior of the house to provide the same total heat capacity as 1.0 x 103 gal of water.Explanation:The mass of water is calculated as:1 gal of water = 3.78541 kg of waterTherefore, 1.0 x 103 gal of water = 3.78541 x 1.0 x 103 = 3.78541 x 103 kg of waterHeat capacity of water is calculated as:Qwater = m * C * ΔTQwater = 3.78541 x 103 * 4.18 * (20 - 10)Qwater = 1.58 x 105 J/KThe heat capacity of one brick is calculated as:Qbrick = m * C * ΔTWe equate the two heat capacities to find the mass of the bricks.mbrick * Cbrick * ΔT = mwater * Cwater * ΔTmbrick * Cbrick = mwater * Cwatermbrick = (mwater * Cwater) / CbrickThe specific heat of the brick is given as 0.85 j/g-K, so we need to convert this to J/kg-K because the mass of the brick is given in kg. Thus,mbrick = (3.78541 x 103 x 4.18) / (0.85 x 1000)Note that mbrick is rounded to two decimal places.Therefore, 19 bricks must be incorporated into the interior of the house to provide the same total heat capacity as 1.0 x 103 gal of water.

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Answer:

25

Explanation:

hinli ako sure yan jok mali

The source of nutrition that Andrew should consume prior to the match to get the boost of energy he desires is carbohydrate.

Nutrition refers to the organic process by which an organism assimilates food and uses it for growth and maintenance.

There are 6 major classes of nutrients and they are as follows:

Among these classes of nutrients, carbohydrates provide the fastest source of energy in the body and hence, can be recommended for an athlete like Andrew who is preparing for a weight lifting endeavor.

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Ignoring a defect in the exhaust system increases the risk of carbon monoxide poisoning, engine damage, decreased fuel efficiency, and potential safety hazards on the road.

Carbon monoxide is a toxic gas that can be deadly if inhaled in high concentrations, and a faulty exhaust system can lead to increased levels of this gas inside the vehicle. Engine damage can occur if the system is not functioning properly, leading to costly repairs or even engine failure.

Additionally, a malfunctioning exhaust system can decrease fuel efficiency and increase emissions, contributing to air pollution. Finally, ignoring defects in the exhaust system can pose a safety risk on the road, as a sudden failure of the system can cause the vehicle to stall or emit excessive smoke.

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Answer:it c

Explanation: I took the test

The mass of the second snowball is 0.280 kg.

The mass of the second snowball can be calculated using the conservation of momentum. The conservation of momentum applies that the total momentum before the collision is equal to the total momentum after the collision. The law of conservation of momentum is derived from Newton's laws of motion, where Newton's third law states that "For every action, there is an equal and opposite reaction."

Calculate the total momentum before collision using the following formula,

Total momentum before collision = Momentum of first snowball + Momentum of second snowball

Total momentum before collision = mass of first snowball x velocity of first snowball + mass of second snowball x velocity of second snowball

Total momentum before collision = 0.450 x 15.4 + m₂(-13.5)

Total momentum before collision = 6.93 - 13.5m₂

where m₂ is the mass of the second ball.

Calculate the total momentum after the collision using the following formula,

Total momentum after collision = Total mass of the two snowballs x Velocity of both snowballs

Total momentum after collision = (mass of first snowball + mass of second snowball) x 3.5 m/s

Total momentum after collision = (0.450 + m₂) x 3.5

Total momentum after collision = 1.575 + 3.5m₂

Equating equation (1) and (2),

6.93 - 13.5m₂ = 1.575 + 3.5m₂

Solving for m₂, we get,

m₂ = 0.280 kg

Hence, the second ball has a mass of 0.280 kg.

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