1. When asteroids collided some of the broken materials fall into Earth's orbit. What do
astronomers call the debris when it hits planet Earth?

Answer: A

Explanation: We know that f=p*n

f=50*300=15000 Hz = 15kHz.

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If the number of revolutions is 300 and the paired poles are 50 , then the frequency would be 15 kHz, therefore the correct answer is option A.

It can be defined as the number of cycles completed per second. It is represented in hertz and inversely proportional to the wavelength.

The frequency of a pendulum is the reciprocal of the time period can be given by the following relation,

F = 1 / T

As given in the problem, we have to calculate frequency if the number of revolutions is 300 and the paired poles are 50.

F = 300 × 50

  = 1500 kHz

Thus, If the number of revolutions is 300 and the paired poles are 50, then the frequency would be 15 kHz, therefore the correct answer is option A.

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Answer:

A

Explanation: Car A is the fastest

Hence, the time required is approximately equal to 4 minutes and 39 seconds.

Given, Power, P = 300 W= 300J/s

Power= Energy per second

Mass, m= 0.25 kg

Initial Temperature= 20.0°C

Final Temperature= 100.0°C

Temperature difference, T =( 100-20)°C= 80.0°C

Specific heat of water, S= 4184 J/kg°C

Energy can be represented as

E=mST

where E is the energy, m is the mass, S is the specific heat of water and T is the temperature difference.

As Energy can be written as the product of time and power, E=Pt

Pt=mST

So,

t=(msT)/P

t=(0.25×4184×80)/300

Time, t = 278.934 seconds= 4 minutes and 39 seconds.

Hence, 4 minutes and 39 seconds will be required for a 300.0 W immersion heater to heat 0.25 kg of water from 20.0°C to 100.0°C.

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Answer:

D

Explanation:

Answer:

Material's density

Explanation:

Seismic waves travel at different rates of speed based on a material's density. Hopefully, you understand that the Earth has three main layers: the crust, mantle, and core. Earthquake waves move faster through solids.

Our muscles need more oxygen to make energy (in the form of ATP) while we workout.

When the respiratory rate picks up to fulfill this need, more oxygen can enter the body and more carbon dioxide can be exhaled.

Student 3 is breathing more forcefully than usual in this situation because of the high temperature and physical activity.

The respiratory system is the organ system engaged in this process.

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# complete question:

A group of students were playing basketball together during recess. The temperature outside was 30.5 oC (87 oF) and the sun was out. The students ran, shot baskets, and dribbled the ball for 30 minutes. When they finished their game some of the students made the following comments:

Student 1: Wow! I am so hot and sweaty! I need some water to cool down.

Student 2: My cheeks are really red.

Student 3: I am breathing so hard, I can barely catch my breath!

Explain what is happening to the students and how their bodies are trying to maintain homeostasis. Be sure to include any of the organ systems involved with each student.

Older adults have greater freedom to pursue interests, to use time, to think, and to reflect is not positive aspects of aging.

Early adulthood is the beginning of a long, ongoing process of natural change called aging. Many body processes start to gradually deteriorate in the early middle years. At no particular age do people become old or elderly. Old age has traditionally been defined as commencing at age 65.

Oxidative stress, glycation, telomere shortening, adverse responses, mutations, and protein aggregation are a few of the factors that contribute to aging.

Positive aspects of aging except older adults have greater freedom to pursue interests, to use time, to think, and to reflect.

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The magnitude of the tension in the rope of this two-block system is:

\(T=73.56\: N\)

We have here an equilibrium system, which means that all forces acting are equal to zero.

We can analyze the hanging block. We just two forces acting in this block, the tension upwards (T) direction and the weight downward (W) direction.

\(T-W_{2}=0\)

\(T=W_{2}\)

\(T=m_{2}g\)

\(T=m_{2}g\)

The mass of the second mass is 7.5 kg and g = 9.81 m/s².

\(T=7.5*9.81\)

\(T=73.56\: N\)

Therefore, the tension will be 73.56 N.

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Answer:

-700

formula is heat gained - work done

The change in internal energy if A system gains 1500J of heat and 2200J of work is done by the system on its surroundings, is 700 joules.

Energy is the ability to perform work in physics. It could exist in several different forms, such as potential, kinetic, thermal, electrical, chemical, radioactive, etc.

Additionally, there is heat and work, which is energy being transferred from one body to another. Energy is always assigned based on its nature once it has been transmitted. Thus, heat transmitted may manifest as thermal energy while work performed may result in mechanical energy.

Given:

A system gains 1500J of heat and 2200J of work is done by the system on its surroundings,

Calculate the change in internal energy as shown below,

The change in internal energy = heat gained - work done

The change in internal energy = 1500 - 2200

The change in internal energy = -700 J

Thus, the change in internal energy is 700 joules.

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Answer:

The needed force is 35,000 N.

Explanation:

By the second Newton's law, we know that:

F = M*a

Force equals mass times acceleration.

If we know that the mass of the car is 1750kg, then M = 1750kg, and the acceleration is 20 m/s^2, then a = 20m/s^2

We can replace these values in the original equation to find the value of F.

F =  1750kg*20 m/s^2 = 35,000 N

Answer:

Explanation:

A cargo spacecraft was orbiting the earth. It is equipped with rocket and has an initial mass of 30 metric ton. It wants to catch up with the international space station to deliver the cargo. So its rocket engine was fired for 1 minute. The engine ejects mass at a rate of 30 kg/s with an exhaust velocity of 3.1 km/s. The pressure at the nozzle exit is 5 kPa and the diameter of exit area is 94.4 cm. What is the thrust of the eng

The linear speed will be the insect be 0.5759 meter/second carried collision with the near stationary photograph.

Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.

Given that an insect lands 0.1m from the center of the turn table.

Rotational speed of the turn table = 55 rev/min

= (55×2π/60) rad/second

= 5.759 rad/second.

Hence, the speed of the insect be = Rotational speed × length

= 5.759 rad/second × 0.1 M.

= 0.5759 meter/second.

Therefore, the speed of the insect be 0.5759 meter/second.

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ANSWER AND EXPLAINATION:
To calculate the impulse imparted on the baseball, we can use the impulse-momentum principle, which states that the impulse experienced by an object is equal to the change in momentum of the object. Mathematically, it can be expressed as:

Impulse = Change in momentum

The momentum of an object is given by the product of its mass and velocity:

Momentum = mass × velocity

In this case, the baseball has an initial mass of 0.14 kg and an initial velocity of 32 m/s. After being struck by the bat, it travels in the opposite direction at a velocity of 49 m/s.

Therefore, the change in momentum is given by:

Change in momentum = (mass × final velocity) - (mass × initial velocity)

Change in momentum = mass × (final velocity - initial velocity)

Change in momentum = 0.14 kg × (49 m/s - (-32 m/s))

Change in momentum = 0.14 kg × (49 m/s + 32 m/s)

Change in momentum = 0.14 kg × 81 m/s

Change in momentum = 11.34 kg·m/s

So, the impulse imparted on the baseball is 11.34 kg·m/s.

The bag would move in the direction of the applied force.

What is the direction?

Recall that work is done when the force applied moves a distance in the direction of the force. In this case, we can see that the force was applied from the right. Do not also forget that the force applied must make the object to move in a given direction. The direction in which the acceleration is imparted must also be in the direction of the force.

The understanding of the impact of force on motion could be seen from the Newtons law. We know from the Newton’s law that an object would remain at rest or in  a state of uniform motion unless it I acted upon by an external force. This external force makes the object to move in the direction of the force.

Looking at the question, we are told that a 20 newtons is applied from the right hence, the bag would move in the direction of the applied force.

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Answer:

Explanation:

We can use the kinematic equation for vertical motion to find the value of the initial vertical velocity, v0y:

v0y = v0 * sin(θ)

Next, we can use the equation for vertical motion with constant acceleration (g = 9.8 m/s^2 is the acceleration due to gravity) to find the time it takes for the ball to reach the target:

v0y * t - 0.5 * g * t^2 = h

Solving for t:

t = sqrt(2 * h / g)

Finally, we can use the kinematic equation for horizontal motion (no acceleration in the horizontal direction) to find the horizontal velocity:

v0x = v0 * cos(θ)

So,

v0x = 10.84 * cos(θ) = 10.84 * cos(θ)

v0x = 10.84 * cos(θ) = 10.84 * cos(θ)

We do not have the value of θ, so we cannot determine the exact value of v0x.

A VfL (Vertical Field LED) backlighting system is commonly used in LCD (Liquid Crystal Display) televisions.

LCD TVs rely on a backlight to illuminate the liquid crystal layer, which controls the passage of light to create the visual image. The VfL technology is a specific type of LED backlighting arrangement used in certain LCD TV models. In a VfL backlighting system, the LEDs (Light-Emitting Diodes) are positioned vertically along the edges of the LCD panel.

The light emitted by these LEDs is directed across the panel using light guides or optical films, illuminating the liquid crystal layer uniformly. One advantage of VfL backlighting is its ability to provide consistent illumination across the LCD panel, reducing any potential inconsistencies in brightness or color uniformity. The vertical orientation of the LEDs allows for more precise control over light distribution, improving overall image quality.

Additionally, VfL backlighting offers potential advantages in terms of power efficiency. By selectively dimming or turning off specific zones of LEDs, local dimming techniques can be employed to enhance contrast and black levels, resulting in improved picture quality while conserving energy. It's important to note that VfL backlighting is just one of several backlighting technologies available for LCD TVs.

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Answer:

  \(\frac{T}{T_o} = ( 1 + \frac{1}{n} )^2\)

Explanation:

This is a string resonance exercise, the wavelengths in a string held at the ends is

          λ = 2L₀ / n

where n is an integer

the speed of the wave is

           v = λ f

            f = v /λ

the speed of the wave is given by the characteristics of the medium (string)

           v = \(\sqrt{\frac{T}{\mu } }\)

we substitute  

            f = \(\frac{n}{2L_o} \ \sqrt{\frac{T}{\mu } }\)

to obtain the following harmonic we change n → n + 1

            f’ =  \(\frac{n+1}{2L_o} \ \sqrt{\frac{T_o}{\mu } }\)

In this case, it tells us to change the tension to obtain the same frequency.

            f ’= \frac{n}{2L_o} \  \sqrt{\frac{T}{\mu } }

how the two frequencies are equal

         \(\frac{n+1}{2L_o} \sqrt{\frac{T_o}{ \mu } } = \frac{n}{2L_o} \sqrt{\frac{T}{\mu } }\)

           (n + 1) \(\sqrt{T_o}\) = n \(\sqrt{T}\)

             \(\frac{T}{T_o} = ( \frac{n+1}{n} )^2\)

             \(\frac{T}{T_o} = ( 1 + \frac{1}{n} )^2\)

this is the relationship of the voltages to obtain the following harmonic,

Answer:

1) 6 seconds

2) 60 m/s

Explanation:

Given:

Δy = 180 m

v₀ = 0 m/s

a = 10 m/s²

1) Find t.

Δy = v₀ t + ½ at²

180 m = (0 m/s) t + ½ (10 m/s²) t²

t = 6 s

2) Find v.

v² = v₀² + 2aΔy

v² = (0 m/s)² + 2 (10 m/s²) (180 m)

v = 60 m/s

Answer:

D) Thermal energy will move from the water bottle to the ice.

Explanation:

Overtime, what happens is that thermal energy will move from the water bottle to the ice.

The water bottle is at a higher temperature compared to the ice. So, thermal energy will move from a place at higher temperature to one with lower temperature.

The term "internal energy" describes the combined potential and kinetic energy of a system or substance. It is the potential energy held inside the bonds between those particles as well as the energy that results from the motion and interactions of the molecules and atoms within a substance.

The chaotic, random motion of molecules is known as a system's internal energy; a system's total (internal) energy is made up of both potential and kinetic energy.

The sum of the random internal kinetic energies of the atoms and the total internal potential is known as a system's internal energy.energies due to the bonds between atoms. Internal energy is not a new concept or form of energy. On the other hand, heat is a new concept that is central to thermodynamics.

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Answer:

Δx = 2*d

Explanation:

        \(k*\Delta x = m*g (1)\)

       \(F = k_{eff} * \Delta x_{eff} = m*g (2)\)

       \(\Delta x_{1} = \frac{F}{\ k_{1} } (3)\)

       \(\Delta x_{} = \frac{F}{\ k_{1} } + \frac{F}{\ k_{2} } (4)\)

       \(\frac{F}{k_{eff} } = \frac{F}{\ k_{1} } + \frac{F}{\ k_{2} } (5)\)

      Since k₁ = k₂ = k, we can find keff, as follows:

      \(k_{eff} = \frac{k^{2} }{2*k} = \frac{k}{2} (6)\)

     \(F = \frac{k}{2} * \Delta x_{eff} = k*\Delta x = m*g (7)\)

       \(\Delta x_{eff} = \frac{2*k*\Delta x}{k} = 2* \Delta x = 2*d (8)\)

The option that represents what the magnetic field look like above the North pole is an arrow that decreases as we go up and points up (E)

The magnetic field lines of a magnet point away from the north pole and towards the south pole. The field lines are strongest at the poles and weaken as you move away from the poles.

So, the arrow that represents the magnetic field above the north pole will be pointing up, but it will become smaller and smaller as you go up.

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The answers are:

a.) The translational kinetic energy of its center of gravity:  638.144J  

b.)The rotational kinetic energy about its center of gravity 319.072 J

c.) Its total kinetic energy 957.216 J

Given:

M = 11.8 kg cylinder

V = speed of center of gravity = 10.2m/s

(a) Translational kinetic energy = 1/2mv²

1/2x 11.8kg x 10.2²

= 11.8x108.16/2

= 1276.288/2

= 638.144 J

This is the translational energy

(b) Rotational energy =1/2Iw²

I = mv²/2

w = v/r

When we substitute

1/2[mv²/2][v/r]²

= 1/4mv²

= 1/4 x 11.8 x 10.2²

= 1276.288/4

= 319.072

This is the rotational energy

(c) Total kinetic energy:

We add the values of A and B above to get this.

638.144 J + 319.072 J

= 957.216J

Complete question: A 11.8-kg cylinder rolls without slipping on a rough surface. At an instant when its center of gravity has a speed of 10.2 m/s, determine the following. (a) the translational kinetic energy of its center of gravity (b) the rotational kinetic energy about its center of gravity (c) its total kinetic energy.

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Answer:

2.66 cm

Explanation:

Apparent depth ( d1 ) = 2.0 cm

d2 = ?

Determine how far below top surface the medallion would appear

lets express The two scenarios

Case 1 : apparent depth as d1 = dactual (Nair/ nplastic) . ( eyes in the air )

Case 2 : Apparent depth as d2 = dactual (Nwater / nplastic) ( eyes in water )

Final How far below top surface will the medallion appear

d2 = d1 * Nwater / Nair

    = ( 2 * 1.33) / 1  = 2.66 cm

note :  Nwater = 1.33,  , Nair = 1 ( missing values in your question )

Answer:

0.00000408

Explanation:

Answer:

Vi = 32 [m/s]

Explanation:

In order to solve this problem we must use the following the two following kinematics equations.

\(v_{f} =v_{i} - (a*t)\\\)

The negative sign of the second term of the equation means that the velocity decreases, as indicated in the problem.

where:

Vf = final velocity = 8[m/s]

Vi = initial velocity [m/s]

a = acceleration = [m/s^2]

t = time = 5 [s]

Now replacing:

8 = Vi - 5*a

Vi = (8 + 5*a)

As we can see we have two unknowns the initial velocity and the acceleration, so we must use a second kinematics equation.

\(v_{f}^{2} = v_{i}^{2} - (2*a*d)\)

where:

d = distance = 100[m]

(8^2) = (8 + 5*a)^2 - (2*a*100)

64 = (64 + 80*a + 25*a^2) - 200*a

0 = 80*a - 200*a + 25*a^2

0 = - 120*a + 25*a^2

0 = 25*a(a - 4.8)

therefore:

a = 0 or a = 4.8 [m/s^2]

We choose the value of 4.8 as the acceleration value, since the zero value would not apply.

Returning to the first equation:

8 = Vi - (4.8*5)

Vi = 32 [m/s]

Given data:

* The force applied on the bookshelf towards the direction of motion by George is,

* The force applied on the bookshelf towards the direction of motion by the friend of George is,

* The force of friction opposite to the direction of motion is,

Solution:

Thus, the net force acting on the bookshelf is,

Here, the negative sign before the friction force indicates the direction of friction force is oppoiste to the direction of motion,

Substituting the known values,

Here, the positive value of net force indicates the net force is acting in the direction of motion of the bookshelf.

Thus, the bookshelf will move to the right with a force of 4 N.

Hence, 4th option is the correct answer.

The frequency of f3 is approximately 716 Hz.

The frequency of a repeated event is its number of instances per unit of time. Hertz (Hz), which stands for the number of cycles per second, is a popular unit of measurement.

a. Given two frequencies, f1 and f2, the frequency ratio is as follows:

frequency ratio= \(\frac{f2}{f1}\)

Inputting the values provided yields:

frequency ratio = \(\frac{576}{320Hz}\) =1.8.

As a result, the difference in frequency between f1 = 320 Hz and f2 = 576 Hz is 1.8.

b. Since there are 12 half-steps in an octave and a fourth is a distance of 5 half-steps, going down a fourth requires dividing the frequency by \(2^{(4/12)}\). Hence, once a fourth is subtracted, the frequency ratio between f and f1 is:

frequency ratio= \(\frac{f}{ (f1 /f2 ) }\)=  \(\frac{f}{ (f1 / 1.3348) }\)

By dividing the numerator and denominator by 1.3348, we may make this more straightforward:

frequency ratio= (f × 1.33348)/f1

As a result, (f × 1.3348) / f1 is the frequency ratio between f and f1 after descending a fourth.

c. (c) To find the frequency of f3, we need to know the interval between f1 and f3. Let's assume that f3 is a fifth above f2. The frequency ratio for a fifth is given by: \(2^{(7/12)}\) = 1.49831

Therefore, the frequency of f3 is:

f3 = f1 × (\(2^{(7/12)}\)) × (\(2^{(7/12)}\)) = 320 Hz × 1.49831 ×1.49831 = 716 Hz

Therefore, the frequency of f3 is approximately 716 Hz.

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because he is carrying more mass and as the ground is muddy his feet goes in due to the pull of gravity

Answer:

i don't know but my father i think he can't answer this