The resolving power of a microscope is a function of both the magnifying power of the lenses and the numerical aperture of the lenses. The correct answer is option (d) - both (a) and (b) are correct.
The magnifying power of the lenses determines the degree of enlargement, while the numerical aperture affects the ability of the microscope to distinguish between closely spaced objects. The wavelength of light (option c) also plays a role in resolving power, but it is not the only factor.
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What is vi for an object dropped from a raised position?
Answer:
Option C. vi = 0
Explanation:
An object held at a particular height above the ground is considered to be at rest. If the object is release from that height, the initial velocity (vi) is considered to be zero since the object is at rest or at a stand still position.
Thus,
Initial velocity (vi) = 0
The four tires of an automobile are inflated to an absolute pressure of 2.0 x 105
Pa. Each tire has an area of 0.024 m? in contact with the ground. Determine the weight (Fg) of the automobile.
The four tires of an automobile are inflated to an absolute pressure of 2.0 x 10⁵ Pa. A total of 0.024 m2 of each tire is in touch with the ground. Then the weight (Fg) of the automobile is 19.2 × 10³ N.
The definition of pressure is "force per unit area." P = F/A, for example, yields the force on a unit area. Its Pascal (Pa) SI unit is equivalent to N/m2. is a scalar quantity. its dimensions are [M¹ L⁻¹ T⁻²]. Mass times the gravitational acceleration equals weight.
Pressure is P = F/A
Force on each tire,
F' = PA = 2.0 x 10⁵ Pa × 0.024 m²
F' = 4.8 × 10³ N
For on for tires,
F = F'×4
F = 4.8 × 10³ N × 4
F = 4.8 × 10³ N × 4
F = 19.2 × 10³ N
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how do advancements in technology help to advance scientific knowledge
Technology and science support one another's advancement. New technologies are developed using scientific knowledge. New technology frequently enable scientists to examine nature in novel ways and generate novel findings.
How might a shift in technology impact scientific understanding?By introducing a new area of scientific inquiry, a change in technology can have an impact on our understanding of science. For instance, the development of the microscope allowed biologists to study species that were invisible to the eye, resulting in the development of the field of microbiology.
How are scientific knowledge and technology related?Building new technologies with the use of scientific information frequently leads to new observations being made about the world, which in turn leads to the development of even more scientific knowledge.
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An object of mass 5kg moves round a circle of radius 600cm with a constant speed of 10.0ms calculate the angular velocity.
If an object moves around a circle, of radius 6 m, with constant velocity, the angular velocity of the object is 1.67 1.67 radians per second.
The angular velocity of an object moving in a circular path can be calculated using the formula:
ω = v / r
Where ω is the angular velocity, v is the constant speed, and r is the radius of the circle.
In this case, we are given the constant speed (v) as 10.0 m/s and the radius (r) as 600 cm. We need to convert the radius to meters in order to use the formula correctly:
r = 600cm * (1m / 100cm) = 6m
Now we can plug in the values and solve for the angular velocity:
ω = v / r
ω = 10.0 m/s / 6 m
ω = 1.67 radians per second
Therefore, the angular velocity of the object is 1.67 radians per second.
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A baseball is thrown at a speed of 25 m/s and travels a distance of 100 m. How
far did it go?
You just said that it "... travels a distance of 100 m".
What is a valid frame of reference for observing motion if you
are riding on a bus with a friend?
a the bus driver at the front of the bus
b the wastebasket on the bus
c your friend sitting next to you
d objects like trees and houses outside the windows
Answer: D
Explanation:
A 2kg rock is dropped from a height of 10m and hits the ground going 11m/s. How much work was done by air resistance as it fell?
Answer: 0.24 kg/m
Explanation: use k = ρ * A * C / 2 as the formulaYour high school quarterback has thrown a football horizontally down the football field. He needs to increase the time the ball is in the air to give the receiver an opportunity to get in the right position to catch the ball. Which factor will increase the flight time of the football?
A. Increasing the horizontal velocity of the ball
B. Decreasing the horizontal velocity of the ball
C. Increasing the vertical height from which the ball is thrown
D. Decreasing the vertical height from which the ball is thrown
self note *11
Answer:
C. Increasing the vertical height from which the ball is thrown.
Explanation:
In this case, we understand that ball experiments a parabolical motion, which is the combination of horizontal uniform motion and vertical uniform accelerated motion, due to gravity. Equations of motion for the ball are described below:
\(x = x_{o}+v_{o,x}\cdot t\) (Eq. 1)
\(y = y_{o} + v_{o,y}\cdot t +\frac{1}{2}\cdot g\cdot t^{2}\) (Eq. 2)
Where:
\(x_{o}\), \(x\) - Initial and final horizontal positions, measured in meters.
\(y_{o}\), \(y\) - Initial and final vertical positions, measured in meters.
\(v_{o,x}\), \(v_{o,y}\) - Initial horizontal and vertical velocities, measured in meters per second.
\(g\) - Gravitational acceleration, measured in meters per second.
\(t\) - Time, measured in seconds.
Now we get (Eq. 2) and solve the expression for the time:
\(\frac{1}{2}\cdot g\cdot t^{2}+v_{o,y}\cdot t + (y_{o}-y) = 0\)
\(t = \frac{-v_{o,y}\pm\sqrt{v_{o,y}^{2}-2\cdot g \cdot (y_{o}-y)}}{g}\)
If \(v_{o,y} > 0\), \(g < 0\) and \(y_{o} -y < 0\), then maximum time occurs when:
\(t = \frac{-v_{o,y}+ \sqrt{v_{o,y}^{2}-2\cdot g \cdot (y_{o}-y)}}{g}\)
And,
\(v_{o,y}^{2}-2\cdot g\cdot (y_{o}-y)\geq 0\).
If \(y_{o}\) is increased, then \(y_{o} - y\) goes closer to zero and \(v_{o,y}^{2}-2\cdot g\cdot (y_{o}-y)\) becomes greater and time increased. Hence, we conclude that correct answer is C.
A resistor and an inductor are connected in parallel. If the voltage across the resistor is 120 volts, the voltage across the inductor is 120 volts.
True
True, A resistor and an inductor are connected in parallel. If the voltage across the resistor is 120 volts, the voltage across the inductor is 120 volts.
A resistor is a passive two-terminal electrical issue that implements electrical resistance as a circuit element. In digital circuits, resistors are used to reduce contemporary drift, regulate signal ranges, divide voltages, bias energetic elements, and terminate transmission strains, amongst different makes use of.
Resistors are used for many functions. A few examples include proscribing electric-powered modern, voltage division, warmness technology, matching, and loading circuits, gain control, and placing time constants.
A resistor is a two-terminal electrical issue that provides electric resistance. In digital circuits, resistors are predominantly used to lower the waft of modern, divide voltages, block transmission alerts, and bias active factors.
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Pete is driving down 7th street. He drives 550 meters in 8 seconds. Assuming he does not
speed up or slow down, what is his speed in meters per second
Answer:
Speed = 68.75m/s
Explanation:
Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.
Mathematically, speed is given by the equation;
\(Speed = \frac{distance}{time}\)
\(S = \frac{d}{t}\)
Given the following data;
Distance = 550m
Time = 8secs
Substituting into the above equation;
\(S = \frac{550}{8}\)
Speed, S = 68.75m/s
The __________ theory claims that emotions are innate reactions to stimuli in one’s surrounding environment. A.evolutionaryB.two-factorC.James-LangeD.Cannon-Bard
Answer:
A. evolutionary
Explanation:
i took one for the team
The temperature at which a liquid will turn into a gas, or vapor, is its ________.
Answer:
Evaporation
Hope this helps :)
WHICH TYPES OF ENERGY IS HAPPENING
Answer:
kinetic energy turned potential energy
Explanation:
it moves up the hill and stops so the movement is kinetic energy and the stop is potential energy
Manu took a pebble and a sheet of paper both weigh one gram. His friend told that if we drop both at the same time, the pebble will fall straight to the floor, while the paper will slowly drift to the ground. Do you think friction have any role in this case? How can we relate that to the topic which we are learning today?
Answer: friction has no role to play in this case. because friction usually occurs between to parts which come in contacts. examples (a)our joints in the human body (b)two mechanical parts (shafts).
Explanation:
However what this topic relates to is gravity. The pebble and paper both weigh one gram, but have different density this is the sole reason why if both are drop from same height the pebble would reach the ground faster than the paper because it is more denser. unlike the paper with a lesser density which would take a longer time to reach the ground.
which of the following are features of the nucleus of an atom
finding evidence to support or dispove is how science advanes
What is a stationary front?
A. When a cold air mass and a warm air mass meet and don't move
B. When a cold air mass remains in place
C. When two cold air masses meet and don't move
D. When a warm air mass doesn't move
Arocket mass 1500kg if the engines provide a force 2000N, what would its accelerations..
Please
Answer:
Force=mass × acceleration
or, acceleration=Force/mass
=2000/1500
:. Acceleration=1.33 m/s²
*mark me brainliest
a. Looking at the diagram above, what is the net force in the horizontal direction?
b. What is the net force in the vertical direction?
Answer:
A) Net force in the horizontal direction is 19.641 N
B) Net force in the vertical direction is 20 N
Explanation:
The normal force (20 N) and the weight force (20 N) cancel out.
Next lets find the horizontal and vertical components on the right side of the diagram.
We are given the angle and the hypotenuse.
First lets find the opposite side (vertical component).
\(sin(x)\frac{O}{H}\)
\(O=Hsin(x)\)
\(O=40sin(30)\)
\(O=20\)
Now lets find the adjacent side (horizontal component).
\(cos(x)=\frac{A}{H}\)
\(A=Hcos(x)\)
\(A=40cos(30)\)
\(A=34.641\)
Now we can ignore the 40 N force.
We are left with 1 force in the vertical direction.
So the net force in the vertical direction is 20 N
We are left with 2 forces in the horizontal direction.
We have 1 force of 15 Newtons moving in the left direction.
We also another force of 34.641 Newtons moving to the right.
So the net force in the horizontal direction is 19.641 N.
Can we get less ads please i don’t like this
WILL GIVE BRAINLIST a HELP PLEASE
pleaseeee
Answer:
Concave mirror
Explanation:
Because as we move the object far away from the mirror, the image gets inverted.
Answer:
Concave mirror
Explanation:
scientific thinking usually starts with what?
Answer:
Ask a question.
Explanation:
Your question is the basis of any theory.
Assume that a satellite with a mass of 500kg orbits Earth 225km above its surface. Given that the mass of Earth is 5.97 x 10^24 kg and the radius of Earth is 6.38 x 10^6 m. (A)
What is the force of gravity that acts on the satellite? (B) What is the speed of the Satellites orbit
With the use of formulas, the force of gravity on the satellite is 4563.8 N and the speed of the Satellites is 7764.5 m/s
What is Newton's Law of Gravitation ?It states that the force of attraction between two object is proportional to the product of the masses and inversely proportional to the square of the distance between them.
Assume that a satellite with a mass of 500kg orbits Earth 225km above its surface. Given that the mass of Earth is 5.97 x 10^24 kg and the radius of Earth is 6.38 x 10^6 m.
(A) The force of gravity that acts on the satellite will be
F = GMm/r²
Where
G = 6.67 × 10^-11 Nm²/kg²M = 5.97 x 10^24 kgm = 500kgr = 6.38 x 10^6 m + 225 000 m = 6605000 mF = ?Substitute all the parameters
F = (6.67 × 10^-11 × 5.97 x 10^24 × 500)/6605000²
F = 4563.8 N
(B) The speed of the Satellites orbit will be
v = √GM/r
v = √(6.67 × 10^-11 × 5.97 x 10^24 )/6605000
v = √60287509.5
v = 7764.5 m/s
Therefore, the force of gravity that acts on the satellite is 4563.8 N and the speed of the Satellites orbit is 7764.5 m/s
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What are some things to be wary of with hemoconcentrators?
By being wary of these factors and following the recommended guidelines, you can ensure the safe and effective use of hemoconcentrators in medical procedures.
When using hemoconcentrators, it's essential to be cautious and consider a few factors to ensure their safe and effective use. Some things to be wary of with hemoconcentrators include:
1. Compatibility: Make sure the hemoconcentrator is compatible with your specific application and equipment to avoid any malfunctions or complications during the procedure.
2. Clotting risks: Hemoconcentrators can sometimes lead to increased blood clotting risks. Ensure appropriate anticoagulation measures are in place during the procedure to minimize this risk.
3. Flow rate: Be mindful of the blood flow rate through the hemoconcentrator. Exceeding the recommended flow rate could lead to hemolysis or other complications.
4. Sterility: Maintain a sterile environment and follow proper handling procedures to prevent contamination, which could potentially lead to infection.
5. Monitoring: Closely monitor the patient's vital signs, blood pressure, and fluid balance during the procedure to promptly identify and address any adverse reactions or complications.
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pls pls pls help i need to know the correct answer and why it’s correct, thanks in advance
What is the relationship between power, work, and time?
A
As the amount of time increases,
power and work both increase.
B
As the amount of time increases,
power and work both decrease.
С
As the amount of time increases,
power increases and work is not affected. D. As the amount of time increases power decreases and work is not affected.
Answer:
it's ans is D because all three are wrong
A string of density 0.01 kg/m is stretched with a tension of 5N and fixed at both ends. The length of the string is 0.1m. What is the first four resonance frequencies in the string?
Answer:
The first four resonance frequency in the string are;
1) 50·√50 Hz
2) 100·√50 Hz
3)150·√50 Hz
4) 200·√50 Hz
Explanation:
The given parameters of the string are;
The density of the string, ρ = 0.01 kg/m
The tension force on the string, T = 5 N
The length of the string, l = 0.1 m
Therefore the mass of the string, m = Length of string × Density of the string
∴ m = 0.01 kg/m × 0.1 m = 0.001 kg
The formula for the fundamental frequency, f₁, is given as follows;
\(f_1 = \dfrac{\sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{\sqrt{\dfrac{T}{\rho} } }{2 \cdot L}\)
Where;
f₁ = The fundamental frequency in the string
T = The tension in the string = 5 N
m = The mass of the string = 0.001 kg
L = The length of the string = 0.1 m
ρ = The density of the string = 0.01 kg/m
By plugging in the values of the variables, we have;
\(f_1 = \dfrac{\sqrt{\dfrac{5}{0.01} } }{2 \times 0.1} = 50 \cdot \sqrt{5}\)
The first four harmonics are;
f₁, 2·f₁, 3·f₁, 4·f₁
Therefore, we have the first four resonance frequency of the string are as follows;
1 × 50·√50 Hz = 50·√50 Hz
2 × 50·√50 Hz = 100·√50 Hz
3 × 50·√50 Hz = 150·√50 Hz
4 × 50·√50 Hz = 200·√50 Hz
TWO QUESTIONS
A runner exerting a running force of 305 N to the right is met with an air resistance force of 35 N to the left. What is the net force of the runner?
305 N
280 N
270 N
205 N
A pushing force of 3 N to the right is applied to a book on a table. A frictional force of 7 N is applied in the opposite direction (left). In which direction will the book move?
to the right
to the left
stay at rest
Answer to the first question-
Ans- The net force of the runner will be 280 N
Data obtained from the question-
A running force to the right - 305 NAir resistance force to the left - 35 NNet force?The net force of the runner could be obtained by -
Net force = Exerting force - resistance force
Net force = 305 - 35
Net force = 280 N
So we can conclude that the runner's net force is 280 N
Answer to the second question-
Ans- The book will stay at rest
Explanation-
As we can see that the pushing force applied to the book is 3 N and the frictional force applied by the table is 7 N, so due to the overpowering frictional force in the opposite direction of the pushing force, the book will remain on its place until and unless a pushing force more significant than 7 N is applied on the book, in that case, the book will start moving in the right direction or in the direction of the pushing force.
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A conducting bar moves to the left in a constant magnetic field what is the direction of the current. Clockwise or counterclockwise
Answer:
Clockwise
Explanation:
To determine the direction of the current induced in the conducting bar moving in a constant magnetic field, you can apply the "right-hand rule." Here's how:
1. Place your right hand in the same direction as the magnetic field with your fingers extended.
2. Your thumb points in the direction of the bar's motion (in this case, to the left).
3. Your palm faces the direction of the current flow.
Given that the magnetic field direction is not provided, I’ll assume it's pointing out of the plane of the screen/page (towards you). In this case, as you follow the right-hand rule:
1. Point your fingers towards yourself, representing the magnetic field.
2. Place your thumb pointing to the left, representing the direction of the bar's motion.
3. Your palm should be facing down, which means the current direction is counterclockwise.
So, in this case, the direction of the induced current would be counterclockwise. If the magnetic field direction is reversed (into the plane), then the induced current would be clockwise.
Need this ASAP please because it's for a homework!
Make a time line where you organize the events since the Big Bang in sequence.
After the universe's 13.7 billion year old Big Bang, it has gone through numerous phases or epochs.
What is Big bang theory?It may have experienced more activity and change in the first second than in all the billions of years since because of the harsh environment and violence of its very early beginnings.
We can construct a rough timeline as follows using our current understanding of how the Big Bang might have developed, taking into account notions about inflation, the Grand Unification, etc.
The Planck Epoch (or Planck Era), which spans from 0 to around 10-43 seconds (1 Planck Time), is the closest that modern physics can come to the beginning of time itself.
Therefore, After the universe's 13.7 billion year old Big Bang, it has gone through numerous phases or epochs.
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Answer asap! No links or weird answers pls. Thank you
An object with a mass of 5.4 kg has a force of 20.0 Newton’s applied to it. What is the resulting acceleration?
Answer:
Mass (m) = 5.4 kg
Force (f) = 20 N
Acceleration (a) = ?
Acceleration= m × a
\(m \times a \\ = 5.4 \times 20 \\ = 108 \: ms ^{ - 2} \)
=> The resulting acceleration of the object is 108 m/s².
if you double your driving speed what happens to your stopping distance (the distance it takes to stop the car)?
If you double your driving speed, then the stopping distance will be four times the original.
What is the equation of motion?Equations of motion are equations that describe a physical system's behavior in terms of its motion as a function of time. Equations of motion, The three equations of the motion are,
v - u = atS = ut + 0.5(at²)v² - u² = 2aswhere
S is the distance,
u is the initial velocity,
v is the final velocity,
t is the time,
a is the acceleration.
Given that the car is traveling at a speed and is needed to be stopped, therefore, the car will deaccelerate. Also, the final velocity of the car will become 0. Therefore, we can write,
v² - u² = 2as
Substitute the values,
Final velocity, v = 0Initial velocity, u = uDistance covered, s = s₁Acceleration, a = -aTherefore, we can write,
v² - u² = 2as₁
(0)² - u² = 2(-a)s₁
-u² = -2as₁
u² = 2as₁
s₁ = u² / 2a
Now, if you double your driving speed. Therefore, we can write,
v² - u² = 2as
Substitute the values,
Final velocity, v = 0Initial velocity, u = 2uDistance covered, s = s₂Acceleration, a = -aTherefore, we can write,
v² - u² = 2as₂
(0)² - (2u)² = 2(-a)s₂
-4u² = -2as₂
4u² = 2as₂
s₂ = 4u² / 2a
Since u²/2a is equal to s₁, therefore, we can write,
s₂ = 4(u² / 2a)
s₂ = 4(s₁)
Hence, if you double your driving speed, then the stopping distance will be four times the original.
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