Answer:
$4.90
Step-by-step explanation:
He already has $13.70 (7.40+6.30) saved up so you have to subtract that from 18.60 to find the total Ace needs to save up.
18.60-13.70=4.90
To check your answer, you can add 7.40, 6.30, and 4.90 and see if you get a total of 18.60.
Check: 7.40+6.30+4.90=18.60
Olivia used 9 blueberries for every 3 strawberries (x) in her smoothie. Which direct variation equation represents this relationship
Find each sum:
56 + (– 56)
(– 240) + 370
(– 5.7) – (– 4.2)
Answer:
56 + (- 56) = 0
(- 240) + 370 = 130
(- 5.7) - (- 4.2) = - 1.5
Step-by-step explanation:
56 + (- 56)
56 - 56
0
(- 240) + 370
- 240 + 370
370 - 240
130
(- 5.7) - (- 4.2)
- 5.7 + 4.2
4.2 - 5.7
- 1.5
Answer:
0, 130, -1.5
Step-by-step explanation:
Lets go over a few things that will help answer the questions:
A + and - make a - sign
A - and a - make a + sign
Ok, now lets sum our first expression:
56+(-56)
Remembering above that a + and - make a - sign:
56-(56)
=
0
Next:
(-240)+370
This is just a postive adding to a negative. So its:
-240+370=130
Finally we have:
(-5.7)-(-4.2)
This may look a bit confusing, so lets clean it up a bit:
The parethese around the -5.7 dont matter, and can be removed:
-5.7-(-4.2)
And remembering that a - and - make a +:
-5.7+4.2
Now adding the postive to the negative value:
-1.5
It is still a negative because the postive value being added to to -5.7 was smaller, so it still was negative, just a smaller negative number.
Hope this helps!
Write the equation of the line that is parallel to the line 5x- 4y = 4 and passes through one point (-8, 2).
Answer:
y = 5/4x - 8
Step-by-step explanation:
first you convert the equation to y = mx + b
then you add the the -8 into the x and the 2 into the y and solve for b
b = -8 and since it is parallel same slope.
hope this helps :)
Z varies directly as x^3 and inversely as y^3. If z=167 when x = 3 and y=10, find z if X=4 and y=6
Answer is 1832.7
step by step
z=kx^3 / y^3
167=27k/1000
k=16700/27
k=6185.2, then
z=6185.2×4^3/6^3
z=6185.2×64/216
z=1832.7
Q1 ? Help Robert is 7 ½ years old. How many months old is he?
Answer:
Step-by-step explanation:
If Robert is 7 1/2 months old you need to multiply 7 1/2 by 12 because there are 12 months in a year.
7x12=84
1/2x12=6
6+84=90
Translate and solve: 72 greater than r is less than -432,
Answer:
r < -504
Step-by-step explanation:
The problem says;
72 + r < -432
Inverse operations;
72 + r < -432
-72 -72
r < - 504
Which expression is equivalent to 250 + 150 ?
Answer:
if 25c + 15d = 0, then d = -25/15c
Step-by-step explan
just yes, that
Wite a numerical expression for the below problems. Simplify the expressions.
Multiply six times three then divide by lwo
The quotient of twelve and two subiracled from thirty-six
Answer:
1) 9
2) 34
Step-by-step explanation:
For the first one, it would be
= (6×3)/2
= 18/2
= 9
The second one is,
= 36- (12/6)
= 36 - 2
= 34
can someone help mepleace
Answer:Click on the file below
Step-by-step explanation:
Please help, I will give brain list.
Answer:
12.25
Step-by-step explanation:
3.5*3.5=12.25
Answer:
12.25m^2
Step-by-step explanation:
3 1/2 × 3 1/2
3 1/2 is equivalent to 7/2
7/2 × 7/2= 49/4
this simplifies to 12.25
answer: 12.25 m^2
Match the following equations with their direction field. Clicking on each picture will give you an enlarged view. While you can probably solve this problem by guessing, it is useful to try to predict characteristics of the direction field and then match them to the picture. Here are some handy characteristics to start with -- you will develop more as you practice.
A. Setyequal to zero and look at how the derivative behaves along thex-axis.
B. Do the same for they-axis by settingxequal to0
C. Consider the curve in the plane defined by settingy'=0-- this should correspond to the points in the picture where the slope is zero.
D. Settingy'equal to a constant other than zero gives the curve of points where the slope is that constant. These are called isoclines, and can be used to construct the direction field picture by hand.
1.y'= e^{-x} + 2y
2.y'= 2\sin(x) + 1 + y
3.\displaystyle y'= -\frac{(2x+y)}{(2y)}
4.y'= y + 2
sps3-Q-stmarys-ca-Q-edu-1991-sethw4-7pro sps3-Q-stmarys-ca-Q-edu-1991-sethw4-7pro
A B
sps3-Q-stmarys-ca-Q-edu-1991-sethw4-7pro sps3-Q-stmarys-ca-Q-edu-1991-sethw4-7pro
C D
My answers are correct I just need someone to show me the work on how to get there
The option (b) set y equal to a constant other than zero to get the curve of points where the slope is that constant.
A slope field is a visual representation of the slopes of a function's derivative at different points on the xy-plane. The slope at a particular point in the xy-plane is given by the derivative of the function at that point.
To match the given equations with their corresponding slope fields, you need to analyze the behavior of the slopes and isoclines. An isocline is a curve in the plane along which the slope of a function is constant. Isoclines are useful in constructing slope fields by hand, as they help in determining the slope at different points.
To start with, set y equal to zero and observe how the derivative behaves along the x-axis. Similarly, set x equal to zero and observe the behavior of the derivative along the y-axis. These observations will give you an idea of the direction and magnitude of the slope at different points in the xy-plane.
Next, consider the curve in the plane defined by setting y' = 0. This curve represents the points in the picture where the slope is zero. These points are known as critical points or equilibrium points. They are essential in analyzing the stability and behavior of a system.
These curves are called isoclines and can be used to construct the slope field picture by hand.
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Complete Question:
Match the following equations with their slope field. Clicking on each picture will give you an enlarged view. While you can probably sove this problem by guessing, it is useful to try to predict characteristics of the slope field and then match them to the picture Here are some handy characteristics to start with- you will develop more as you practice. Set y equal to zero and look at how the derivatiwe behaves along the x axis. Do the same for the y axis by setting x equal to 0. Consider the curve in the plane defined by setting y' = 0-this should correspond to the points in the picture where the slope is zero. Setting y equal to a constant other than zero gives the curve of points where the slepe is that constant. These are called isoclines, and can be used to construct the slope field picture by hand.
Is AB a tangent? Why or Why not? (Hint: use Pythagorean Theorem)
Answer:
AB is not a tangent. The lengths 4, 12, and 13 do not form a right triangle.
√(4^2 + 12^2) = √160, which is not equal to 13.
Answer:
No
Step-by-step explanation:
if AB is a tangent the the angle BAC = 90°
using Pythagoras' theorem
then square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
BC² = 13² = 169
AB² + AC² = 12² + 4² = 144 + 16 = 160
since BC²≠ AB² + AC²
then Δ ABC is not a right triangle so AB is not a tangent
Question 4 O Mark this question Megan was conducting a study to determine if there was a relationship between eating a whole foods diet and general overall health. For her study Megan's null hypothesis was that a whole foods diet would not have any impact on general health. Megan's alternate hypothesis was that eating a whole foods diet would cause improvements in health. If Megan completed her study, which of the following statements would indicate a Type I error? Megan's results show that a whole foods
Type I error is "Megan's results show significant improvements in health associated with a whole foods diet."
A Type I error occurs when the null hypothesis is rejected, even though it is true.
In this case, the null hypothesis states that a whole foods diet would not have any impact on general health.
Therefore, a Type I error would occur if Megan's results show significant improvements in health associated with a whole foods diet.
This means that Megan would reject the null hypothesis and conclude that a whole foods diet does have an impact on general health, even though it is not true.
So, the statement that would indicate a Type I error is "Megan's results show significant improvements in health associated with a whole foods diet."
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Find the area and the circumference of a circle with radius 7 m.
Use the value 3.14 for π, and do not round your answers.
Area=?
Circumference=?
Answer:
\(Area = 153.938040026m^2\)
\(Circumference= 43.9822971503m\)
Step-by-step explanation:
Area
\(Area = \pi r^2\\Area = \pi *7^2\\Area = 49\pi\\Area = 153.938040026\)
Circumference
\(C = 2\pi r\\C = 2\pi*7\\C= 14\pi\\C=43.9822971503\)
Need a problem showing how to to divide beach toys into equal groups. Solve it too.
Answer:
ok
Step-by-step explanation:
The residual plot shows the residuals for the day of the month and the amount in Kali’s checking account. Which statement best assesses the linearity of the relationship between the day of the month and account balance if the scatterplot appears to be reasonably linear?
A) Because the residual plot has an obvious pattern, and the scatterplot appears linear, it is appropriate to use the line of best fit to predict the account balance based on the day of the month.
B) Because the residual plot has an obvious pattern, and the scatterplot appears linear, it is not appropriate to use the line of best fit to predict the account balance based on the day of the month.
C) Because the residual plot has no obvious pattern, and the scatterplot appears linear, it is appropriate to use the line of best fit to predict the account balance based on the day of the month.
D) Because the residual plot has no obvious pattern, and the scatterplot appears linear, it is not appropriate to use the line of best fit to predict the account balance based on the day of the month.
The best assessment of the linearity of the relationship between the day of the month and account balance would be "Because the residual plot has no obvious pattern, and the scatterplot appears linear, it is appropriate to use the line of best fit to predict the account balance based on the day of the month."The correct answer is option C.
When assessing linearity, it is important to examine both the scatterplot and the residual plot. The scatterplot is used to visualize the relationship between the variables, while the residual plot helps us assess the appropriateness of a linear model by examining the pattern of the residuals (the differences between observed and predicted values).
If the scatterplot appears reasonably linear, it suggests that there is a linear relationship between the variables. In this case, since the scatterplot appears linear, it supports the use of a linear model to predict the account balance based on the day of the month.
Furthermore, the residual plot is used to check for any patterns or systematic deviations from the line of best fit. If the residual plot exhibits no obvious pattern and the residuals appear randomly distributed around zero, it indicates that the linear model captures the relationship adequately.
Therefore, if the residual plot shows no obvious pattern, it provides further evidence in favor of using the line of best fit to predict the account balance based on the day of the month.
In conclusion, when the scatterplot appears linear and the residual plot shows no obvious pattern, it is appropriate to use the line of best fit to predict the account balance based on the day of the month.
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Answer:
person above
Step-by-step explanation:
the obvious
HELP, QUICKLY! Which equation shows the quadratic formula used correctly to solve 7x2 = 9 + x for x? (for Edg2020)
Answer
D
Step-by-step explanation:
Edge 2020
What grade levels are covered in Brainly? If I am homeschooling a Kindergartener, a 3rd grader, and a 6th grader, will there be help for all of them?
Answer:
6th grade all the way up to colledge
Step-by-step explanation:
Answer:
Not really ideal as this is just fact finder and not crunch home schooling, This is because as the real teachings for 3rd grader and 6th grader start with worksheets and end with tests and such prep for such is exactly worksheets and tests, then mock past papers and predicted past papers and finally learning the specification ie) formula need to be at front of answers to guarantee higehr points as one of the specs of good exam efforts.
Thus saying; For 3rd yr and 6th graders
Maths worksheets that would help both units are
Fractions both converting, adding (HCF for denominator) , dividing (Flipping and subtracting), multiplying various ways.
Graphs Showing all equations
Linear is y to find points = mx+c format
Linear is equation of the line is y - y1 = y1 (x-x1)
Perpendicular is if m1 , m2 are perpendicular lines then then m1= -1/m2 which basically means divide your gradient by -1.
For year 6 build up to partial fractions A / ( x+ a) +B/ (x+a)^2 = C/(x+b)
Being special case of the recognised formula (x)^2 (a+b) sort of question.
Faster Theorem = f(a)
Then x-a is a factor of f(x)
inequalities true method is negating flips
< flips to > and vice verca
when rearranging etc.
Index Laws
a^n x a ^m = a^ n+m
a^n = 1 as n always means 1 and 1x 1 = 1
Here their are 6 formats for index laws
Log Laws
In 1 = 0 is year 7
Here there is 6 In as Log law examples to find in Log type question formats.
ie) In xy = In x + Iny
and
Inx/y = In x-Iny
In 1/x = negative - In x
as it turns negative from moving from divide to the side of the = sign.
This is why worksheets are so important.
As reflecting y = x even can be tough to recognise sometimes.
Midpoint formula is x^1 +x^2 / 2 see if they know this.
Find x <-> y do they know they would need to rearrange
Reciprocal graphs
find y = k/x find the graph
Reciprocal graphs
find y = -k/x find the graph (its opposite diagonals reciprocal to the one above
Reciprocal graphs
find y = k/x^1 (it shows a symmetrical (upside down V above the x axis)
Reciprocal graph
find k/x-1 it shows a symmetrical V below x axis so they reflect with the reciprocal above, one above.
Get them to draw it and make a game of it.
This sort of thing will help your kindergarten sit at table and draw and remember formula as its just y = k/x etc.
Other functions such as Domain = input x and Range = input y can be drawn out for the kindergarten child and cut out x and y's help him play games.
Nth route needs N
Such formula is a^n = 1
^ this is a square so cna be shown smaller number raised to n
like n² so you cna also cut these out and make them interactive for your kindergarten child along with fractions and Surds for year 6.
The Units in books are around 200 - 235 for year 3-6
I would most certainly get at least 1/4 of these in worksheets and attempt 2 easy and 2 hard questions on each, then learn formulas and then do past papers and mock exams that show the answer to re correct and try again.
Such maths websites include fun mock exam tests answer given etc..
Copy and paste the formulas so you can help them.
IF you need more just ask me below and post request and i can try sending whole list for you. But you would have to do another question if the list is full where you can remind me here when I've responded same time
Take care.
Hope this helps.
25,000 gallons of my pool needs to be completely drained for maintenance purposes your pump and principal at a rate of 30 gallons a minute let it represent the number of hours the pool has been raining right now equation that can be used to determine the number of hours it will take to complete the drain the pool supposed start raining the pool Monday, May 7 at 8 AM would it be safe to schedule maintenance to begin on Tuesday, May 8 at noon
Answer:
c
Step-by-step explanation:
Solve for x: 12x= 36
Please show all the steps that were given above that you must take to solve for x.
Step-by-step explanation:
x=36/12
x=2
I hope it's helpful for you12x = 36
x = 36÷12
x = 3
Hope it helps......
sequence three missing terms to comple 7444> →→19-
To complete the sequence "7444> →→19-", we need to find the missing terms that fit the pattern established by the given numbers. Let's analyze the sequence and identify any discernible pattern or rule.
Looking at the sequence, we can observe that each number is decreasing by a certain value. In this case, the first number is 7444, and the second number is 19, indicating a decrease of 7425. Now, we need to continue this pattern.
To find the third missing term, we subtract 7425 from 19, resulting in -7406. Therefore, the third missing term is -7406
To find the fourth missing term, we subtract 7425 from -7406, resulting in -14831. Therefore, the fourth missing term is -14831.
To find the fifth missing term, we subtract 7425 from -14831, resulting in -22256. Therefore, the fifth missing term is -22256.
Therefore, the completed sequence is:
7444> →→19- → -7406 → -14831 → -22256
Each term in the sequence is obtained by subtracting 7425 from the previous term.
It's important to note that this solution assumes a linear pattern in which the same subtraction value is applied to each term. However, without additional context or information about the sequence, there could be alternative patterns or interpretations.
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if a clock shows it is 3 o'clock, how could you describe the smaller angle made my the two hands of the clock? solve this problem any way you choose
The smaller angle made by the two hands of the clock at 3 o'clock is 90 degrees.
What is an angle?A figure known as an angle is created by two rays or line segments that meet at a place known as the vertex of the angle. The sides or legs of the angle are other names for the rays or line segments.
According to question:To determine the smaller angle made by the two hands of a clock when it is 3 o'clock, we can use the following formula:
angle = |(11/2) * m - 30h|
where:
m is the number of minutes past the hour (in this case, since it is 3 o'clock, m = 0)
h is the hour (in this case, h = 3)
By using this formula, we get:
angle = |(11/2) * 0 - 30(3)| = |0 - 90| = 90
Therefore, the smaller angle made by the two hands of the clock at 3 o'clock is 90 degrees.
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Evaluate this exponential expression 7 • (6+2)^2 - 3^2=
Answer: 441
Step-by-step explanation:
\(7*(6+2)^2-3^2\)
\(7*8^2-3^2\)
\(7*64-9\)
\(448-9\)
441
Solve this inequality 15n<8n-21
The solution of the inequality 15n>8n-21 is given by, n<-3.
Inequality is a relation between two or more mathematical expression or quantities via unequal signs i.e. greater, less, greater or equal, less or equal, not equal.
Given that the inequality is 15n<8n-21
Solving the inequality we have,
15n<8n-21
15n-8n<8n-21-8n, subtracting from both sides
7n<-21
n<-3, dividing 7 from both sides
So the solution of the given inequality is, n<-3.
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A fair die is rolled in a board game to determine how many spaces a player can move on their turn. It has one of the numbers 1,2,3,4,5, or 6 on each of its faces.
Let event A be rolling an even number and event B be rolling an odd number.
Identify the numbers of each of the following:
Provide your answer below:
A. There are_______ outcomes in the sample space.
B. There are_______ outcomes in event A.
C. P(A) =_________ is the probability that you choose an even number.
Answer:
(a)6 (b)3 (c)0.5
Step-by-step explanation:
Given a fair die with the numbers 1,2,3,4,5, or 6 on each of its faces.
Event A is the event of rolling an even numberEvent B is the event of rolling an odd number.(a)The sample space for the outcomes in this experiment is {1,2,3,4,5,6}
There are 6 outcomes in the sample space.
n(S)=6
(b)
Event A is the event of rolling an even number
Sample space of A = {2,4,6}
There are 3 outcomes in event A.
n(A)=3
(c)The probability of event A
\(P(A)=\dfrac{n(A)}{n(S)} =\dfrac{3}{6} =0.5\)
P(A) =0.5 is the probability that you choose an even number.
Eduardo buys a sandwich and a drink.
Use mental math to find the amount of
change he gets from $10.00
Answer:
Eduardo will get $4.03
Step-by-step explanation:
To solve this problem, first add 4.99 and 0.98 together, remember to line up the decimals
4.99
+ 0.98
-------------
5.97
Now take 5.97 from 10.00
first you can't take 7 from 0 so you take 1 from the tens place making 10.00 into 9.9 10, now you can take 7 from 10 which equals 3. Into the tenths place you can take 9 from 9 which is a 0. Lastly 9 - 5 is 4, adding the decimal back you get
10.00
- 05.97
--------------
$ 4.03
A fast-food restaurant operates both a drive through facility and a walk-in facility. On a randomly selected day, let X and Y, respectively, be the proportions of the time that the drive-through and walk-in facilities are in use, and suppose that the joint density function of these random variables is,
f (x, y) ={2/3(x+2y) 0 ≤ x ≤ 1 , 0 ≤ y ≤ 1
(a) Find the marginal density of X.
(b) Find the marginal density of Y .
(c) Find the probability that the drive-through facility is busy less than one-half of the time.
Answer:
\((a)\ g(x) = \frac{2}{3}(x+1)\)
\((b)\ h(y) = \frac{1}{3}[1 + 4y]\)
\((c)\) \(P(x>0.5) =\frac{5}{12}\)
Step-by-step explanation:
Given
\(f(x,y) = \left \{ {{\frac{2}{3}(x+2y)\ \ 0\le x \le 1,\ 0\le y\le 1} \right.\)
Solving (a): The marginal density of X
This is calculated as:
\(g(x) = \int\limits^{\infty}_{-\infty} {f(x,y)} \, dy\)
\(g(x) = \int\limits^{1}_{0} {\frac{2}{3}(x + 2y)} \, dy\)
\(g(x) = \frac{2}{3}\int\limits^{1}_{0} {(x + 2y)} \, dy\)
Integrate
\(g(x) = \frac{2}{3}(xy+y^2)|\limits^{1}_{0}\)
Substitute 1 and 0 for y
\(g(x) = \frac{2}{3}[(x*1+1^2) - (x*0 + 0^2)}\)
\(g(x) = \frac{2}{3}[(x+1)}\)
Solving (b): The marginal density of Y
This is calculated as:
\(h(y) = \int\limits^{\infty}_{-\infty} {f(x,y)} \, dx\)
\(h(y) = \int\limits^{1}_{0} {\frac{2}{3}(x + 2y)} \, dx\)
\(h(y) = \frac{2}{3}\int\limits^{1}_{0} {(x + 2y)} \, dx\)
Integrate
\(h(y) = \frac{2}{3}(\frac{x^2}{2} + 2xy)|\limits^{1}_{0}\)
Substitute 1 and 0 for x
\(h(y) = \frac{2}{3}[(\frac{1^2}{2} + 2y*1) - (\frac{0^2}{2} + 2y*0) ]\)
\(h(y) = \frac{2}{3}[(\frac{1}{2} + 2y)]\)
\(h(y) = \frac{1}{3}[1 + 4y]\)
Solving (c): The probability that the drive-through facility is busy less than one-half of the time.
This is represented as:
\(P(x>0.5)\)
The solution is as follows:
\(P(x>0.5) = P(0\le x\le 0.5,0\le y\le 1)\)
Represent as an integral
\(P(x>0.5) =\int\limits^1_0 \int\limits^{0.5}_0 {\frac{2}{3}(x + 2y)} \, dx dy\)
\(P(x>0.5) =\frac{2}{3}\int\limits^1_0 \int\limits^{0.5}_0 {(x + 2y)} \, dx dy\)
Integrate w.r.t. x
\(P(x>0.5) =\frac{2}{3}\int\limits^1_0 (\frac{x^2}{2} + 2xy) |^{0.5}_0\, dy\)
\(P(x>0.5) =\frac{2}{3}\int\limits^1_0 [(\frac{0.5^2}{2} + 2*0.5y) -(\frac{0^2}{2} + 2*0y)], dy\)
\(P(x>0.5) =\frac{2}{3}\int\limits^1_0 (0.125 + y), dy\)
\(P(x>0.5) =\frac{2}{3}(0.125y + \frac{y^2}{2})|^{1}_{0}\)
\(P(x>0.5) =\frac{2}{3}[(0.125*1 + \frac{1^2}{2}) - (0.125*0 + \frac{0^2}{2})]\)
\(P(x>0.5) =\frac{2}{3}[(0.125 + \frac{1}{2})]\)
\(P(x>0.5) =\frac{2}{3}[(0.125 + 0.5]\)
\(P(x>0.5) =\frac{2}{3} * 0.625\)
\(P(x>0.5) =\frac{2 * 0.625}{3}\)
\(P(x>0.5) =\frac{1.25}{3}\)
Express as a fraction, properly
\(P(x>0.5) =\frac{1.25*4}{3*4}\)
\(P(x>0.5) =\frac{5}{12}\)
Find the dimensions of the rectangular garden of greatest area that can be fenced off (all four sides) with 300 meters of fencing.
The dimensions of the rectangular garden to maximize the area is length = width = 75 meters.
Let l be the length and w be the width of the rectangular garden.
We need to find the dimensions of the rectangular garden of greatest area that can be fenced off (all four sides) with 300 meters of fencing.
The perimeter of the rectangular garden = 300 meters
We know that the perimeter of the rectangle =2(length + width)
300 = 2(l + w)
l + w = 150 .......(1)
Now, the maximum area of a rectangular garden is when Length = width
So, for equation 1
l + l = 150
l = 75 meters
So, w = 75 meters
And the area of the rectangular garden = length * width
= 75 * 75
= 5625 m²
So the maximum area of the rectangular garden is 5625 m²
Therefore, the dimensions of the garden to maximize the area is length = width = 75 meters and maximum area is 5625 m²
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Please help will mark Brainly
Answer:
f(x) = - 2x + 4
Step-by-step explanation:
Since we are only trying to move the graph up 3 units, the slope does not change. So, it would be -2.
We also know that the 1 in f(x)= -2x + 1 is the y-intercept (y=mx+b). But again, we are moving the graph 3 units up, so we have to add 3. That makes it 4 (3+1=4).
So, the new equation would be f(x) = -2x + 4
Step-by-step explanation:
it simply means that g(x) is f(x) just shifted 3 units upwards.
that means nothing else changes, only whatever y result f(x) produces is increased by 3.
so,
g(x) = f(x) + 3 = -2x + 1 + 3 = -2x + 4
therefore, as domain and range were the whole set of real numbers, the addition of 3 does not make any difference in relation to infinity. so, they remain unchanged.
the slope stays the same (g(x) is simply a parallel line to f(x)).
the y-intercept (the y-value when x = 0) also increases by 3, and is 4.
the x-intercept (the x-value when y = 0) changes :
0 = -2x + 4
2x = 4
x = 2
the x-intercept is 2.
of the 400 employes 5% of them are manegers
Answer:
20%
Step-by-step explanation:
To answer this question we have to 5% of 400, this will give us the number of managers!
1) 5% of 400
To find 5% of 400 we have to do 5 × 400...5 × 400 = 2000Then 2000 ÷ 100...2000 ÷ 100 = 20%This gives us the answer!
Have a lovely day :)