1. A wave has a wavelength of 5 m and a frequency of 2 Hz. At what speed/velocity does the
wave travel?

2. The speed/velocity of a wave on a guitar string is 100m/s and the frequency is 1,000 Hz. What
is the wavelength of the wave?

3. If the speed/velocity of a wave is 25 m/s and the wavelength is 5 m, what is the frequency of
this wave?

Answer:

The correct answer is - the Social Readjustment Rating Scale.

Explanation:

The social readjustment rating scale is developed by Richard Rahe and Thomas Holmes to measure the stress caused by this important and major life event. Stress helps in developing a psychological approach for the particular person.

It is an assessment tool to calculate the impact of the major life events in the time period of one year with the help of units of 0 to 100. 100 is extreme or highest stress caused by the event such as the death of the spouse.

Answer:

S = Vy t + 1/2 g t^2 = 1/2 g t^2    vertical speed with zero initial speed

t = (2 S / g)^1/2      with g = 32 ft/sec^2

t = (900 / 32)^1/2 = 5.30 sec    time to reach ground

V = a t = 32 ft/s^2 * 5.30 s = 170 ft/sec

170 ft/sec / (88 ft/sec / 60 mph) = 116 mph           since 88 ft/sec = 60 mph

Answer:

50kgm/2

Explanation:

Answer: 22.1 m/s

Explanation:

The velocity of Car traveling 30 m/s towards the north

In vector form it is

\(v_x=30\hat{j}\)

The velocity of car Y w.r.t X is

\(\Rightarrow v_{yx}=15[-\cos 45^{\circ}\hat{i}-\sin 45^{\circ}\hat{j}]\)

Solving this

\(\Rightarrow v_{yx}=v_y-v_x\\\Rightarrow v_y=v_{yx}+v_x\)

putting values

\(\Rightarrow v_y=15[-\cos 45^{\circ}\hat{i}-\sin 45^{\circ}\hat{j}]+30\hat{j}\)

\(\Rightarrow v_y=-10.606\hat{i}+19.39\hat{j}\)

absolute velocity relative to ground is

\(\left | v_y\right |=\sqrt{(-10.606)^2+(19.39)^2}\\\left | v_y\right |=22.101\ m/s\)

Answer:

196

Explanation:

subtract 24 from 220 to get your answer.

Answer:

100 beats for minute

Explanation:

Adults ( age 18 and over) 60 - 100 beats per minute

1. The purpose of the investigation was to study the relationship between the Sun, Earth, and Moon.

2. The bright part of the moon appears bright due to the reflection of sunlight.

Introduction: The purpose of the investigation was to study the relationship between the Sun, Earth, and Moon. By creating models of the three celestial bodies, we aimed to understand how their movements and positions influence the phases of the moon and eclipses.The bright part of the moon appears bright due to the reflection of sunlight. As sunlight hits the moon's surface, it bounces back and reflects into space. This reflected light is what we see as the bright part of the moon.

Experimental Methods: To create our model, we used a lamp to represent the Sun, a ball to represent the Earth, and a smaller ball to represent the Moon. We also used a ruler, tape, and a protractor to measure distances and angles.We created our model by placing the lamp at one end of a table, the Earth in the middle, and the Moon at the other end. We attached the Moon to a string and moved it around the Earth to simulate the Moon's orbit around the Earth.

Develop a Model: Our model consists of a lamp, a ball, and a smaller ball on a string. The lamp represents the Sun, the ball represents the Earth, and the smaller ball on the string represents the Moon. As the Moon moves around the Earth, it goes through phases, from a new moon to a full moon and back again.We used diagrams and pictures to label the components of our model and describe causal accounts for the phases of the moon and eclipses.

Use a Model: When the Moon is full, it is in a direct line with the Earth and the Sun. Using our model, we can predict that the Moon would be directly opposite the Sun in the sky during a full moon. A lunar eclipse does not occur every month when there is a full moon because the Moon's orbit around the Earth is tilted at an angle of about 5 degrees to the Earth's orbit around the Sun. Therefore, the Moon is not always in a direct line with the Earth and the Sun during a full moon, which is necessary for a lunar eclipse to occur.

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Polarization of light can be achieved using a dichroic material like Polaroid by Selective absorption.

What is polarization?

Polarization is a characteristic of some electromagnetic radiations in which there is a specific relationship between the direction and strength of the vibrating electric field.

Because each wave's associated vibrating electric vector is perpendicular to the direction of transmission, light waves are transverse. Unpolarized light is made up of waves that are all traveling in the same direction while having their electric vectors oriented in a random manner around the propagation axis. All of the waves in plane polarized light have the same direction of vibration. The electric vector rotates in circular polarization with respect to the wave's direction of propagation. By reflecting light or passing it via crystals or other filters that only allow vibrations in one plane to flow through, light can be polarized.

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Answer:

gravitational potential energy at point A.

A) The gravitational potential energy at point A is; 705600 J

B) The velocity at point C, if the work done to move the roller coaster from point B to C is 264870 J is; v = 31.295 m/s

A) Formula for gravitational potential energy is;

PE = mgh

At point A;

mass; m = 900 kg

height; h = 80 m

Thus;

PE = 900 × 9.8 × 80

PE = 705600 J

B) Kinetic energy of the roller coaster at point C is given as;

KE = PE - W

We are given Workdone; W = 264870 J

Thus;

KE = 705600 - 264870

KE = 440730 J

Thus, velocity at point C is gotten from the formula of kinetic energy;

KE = ½mv²

v = √(2KE/m)

v = √(2 × 440730/900)

v = 31.295 m/s

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Answer:

Final Velocity:  109.615 m/s

Acceleration:  21.08 m/s²

Explanation:

Distance traveled is given by

Velocity v = Δx/Δt

where Δx is the distance covered and Δt the time to cover that distance

Here Δx = 5.7 x 10² m and t = 5.2 seconds

So v = 5.7 x 10²/5.2 = 109.615 m/s

Acceleration is Δv/Δt where Δv is the change in velocity from an initial velocity and Δt the time taken to reach that initial velocity

Here initial velocity is 0, so Δv= 109.615 - 0 = 109.615m/s

Time to reach this velocity = 5.2 s

So acceleration a =  109.615/5.2 = 21.08 m/s²

To find the distance between two charges, we can use Coulomb's law, which states that the force between two charges is proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.

The formula for Coulomb's law is:

F = (k * |q1| * |q2|) / r^2

where:

F is the force between the charges,

k is the electrostatic constant (k = 8.99 × 10^9 N m^2/C^2),

|q1| and |q2| are the magnitudes of the charges, and

r is the distance between the charges.

Given:

|q1| = 2 × 10^-7 C

|q2| = 4.5 × 10^-7 C

F = 0.1 N

k = 8.99 × 10^9 N m^2/C^2

We can rearrange the equation to solve for r:

r^2 = (k * |q1| * |q2|) / F

Plugging in the values:

r^2 = (8.99 × 10^9 N m^2/C^2 * 2 × 10^-7 C * 4.5 × 10^-7 C) / 0.1 N

r^2 = (8.99 × 2 × 4.5) * (10^9 * 10^-7 * 10^-7) / 0.1

r^2 = 80.91 * (10^9 * 10^-7 * 10^-7) / 0.1

r^2 = 80.91 * 10^(-7 + 9 - 1)

r^2 = 80.91 * 10^1

r^2 = 809.1

Taking the square root of both sides:

r = √809.1

r ≈ 28.46

Therefore, the distance between the two charges is approximately 28.46 units.

Answer:

Explanation:

The simplest kinetic model is based on the assumptions that:

(1) the gas is composed of a large number of identical molecules moving in random directions, separated by distances that are large compared with their size;

(2) the molecules undergo perfectly elastic collisions (no energy loss) with each other and with the walls of the container, but otherwise do not interact; and

(3) the transfer of kinetic energy between molecules is heat. These simplifying assumptions bring the characteristics of gases within the range of mathematical treatment.

Answer:

Mass of Exoplanet =  0.58 kg

Explanation:

First, we will calculate the speed of the forest moon:

\(speed = v = \frac{Circumference}{time}\\\)

circumference = 2πr = 2π(14441566 m) = 90739035.3 m

time = 6 days 10 hr = (6 days)(24 h/1 day)(3600 s/1 h) + (10 h)(3600 s/1 h)

time = 554400 s

Therefore,

\(v = \frac{90739035.3\ m}{554400\ s}\\\\v = 163.67\ m/s\)

We know that the centripetal force on forest moon will be equal to the gravitational force given by Newton's Gravitational Law, as follows:

\(Centripetal\ Force = Gravitational\ Force\\\frac{m_{moon}v^2}{r} = \frac{Gm_{moon}m_{exoplanet}}{r^2}\\\\m_{exoplanet} = \frac{v^2r}{G}\\\\m_{exoplanet} = \frac{(163.67\ m/s)^2(14441566)}{6.67\ x\ 10^{-11}\ N.m^2/kg^2}\)

Mass of Exoplanet =  0.58 kg

Answer:

an acronym because it is shorted to remember like mvemjsun it's the planet

If the output work of a simple machine equals the input work, the machine is said to have 100% efficiency.

\(\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘\)

The airplane will strike the ground at a horizontal distance of 490 meters.

To determine how far the airplane will strike on the ground, we need to consider the horizontal distance traveled by the airplane during its flight.

The horizontal distance traveled by an object can be calculated using the formula:

Distance = Speed × Time

In this case, the speed of the airplane is given as 100 meters per second and the time it takes to cover the distance of 490 meters is unknown. Let's denote the time as t.

Distance = 100 m/s × t

Now, to find the value of time, we can rearrange the equation as follows:

t = Distance / Speed

t = 490 m / 100 m/s

t = 4.9 seconds

Therefore, it takes the airplane 4.9 seconds to cover a horizontal distance of 490 meters.

Now, to calculate the distance on the ground where the airplane will strike, we can use the formula:

Distance = Speed × Time

Distance = 100 m/s × 4.9 s

Distance = 490 meters

It's important to note that this calculation assumes a constant speed and a straight flight path. In reality, various factors such as wind conditions, changes in speed, and maneuvering can affect the actual distance traveled by the airplane.

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Answer:

the required current is 0.12 A

Option b) 0.12 A is the correct answer

Explanation:

Given the data in the question,

to determine the current needed in the wire, we use the following relation;

B = μ₀n\(I\)

\(I\) = B / μ₀n

where μ₀ is the magnetic constant   ( 4π × 10⁻⁷ T.m/A )

n is the number of turns ( 1 / 1mm\(\frac{10^{-3}m}{1 mm}\)) = 1000 m⁻¹

B is magnitude ( 150μT ( \(\frac{10^{-6}m}{1uT}\)) )

so we substitute

\(I\) =  [ 150μT ( \(\frac{10^{-6}m}{1uT}\)) ] / [ ( 4π × 10⁻⁷ T.m/A ) × 1000 m⁻¹ ]

\(I\) =  [ 0.00015 ] / [ 0.00125 ]

\(I\) = 0.12 A

Therefore, the required current is 0.12 A

Option b) 0.12 A is the correct answer

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{f}{m} \\ \)

m is the mass

f is the force

From the question we have

\(a = \frac{150}{160} = \frac{15}{16} \\ = 0.9375\)

We have the final answer as

Hope this helps you

Given that two large parallel plates are separated by 0.20 m and that the potential difference is 12V.

(a) Describe the motion of an electron released from rest at a distance "d" from the negative plate.

(b) What distance from the positive plate will the electron have a speed of 1 x 10^6 m/s?

For part (a):

The magnitude of an electric field can be given as  \(||\vec E||=\frac{\Delta V}{d}\), where "ΔV" is the potential difference and "d" is the distance between the plates.

So, \(||\vec E||=\frac{12 \ V}{0.20 \ m} \Longrightarrow \boxed{||\vec E||=60 \ \frac{N}{C} }\)

An electric field is created between the plates pointing from positive towards negative. We know that negative charges accelerate opposite the direction of electrical fields. So the electron placed "d" meters away from the negative plate will accelerate towards the positive plate at a constant rate.

For part (b):

We know that...

- the charge of an electron is \(\bold{-1.602 \times10^{-19} \ C}\).

- the mass of an electron is \(\bold{9.11 \times10^{-31} \ kg}\).

- \(\vec F_e=q\vec E\)

- \(\vec F =m\vec a\)

\(\Longrightarrow \vec F_e=(-1.602 \times10^{-19} \ C)(60 \ \frac{N}{C} }) \Longrightarrow \boxed{\vec F_e= -9.612 \times10^{-18} \ N}\)

\(\Longrightarrow \vec F =m\vec a \Longrightarrow \vec a=\frac{\vec F}{m} \Longrightarrow \vec a=\frac{-9.612 \times10^{-18}}{9.11 \times10^{-31} \ kg} \Longrightarrow \boxed{\vec a=-1.06 \times10^{13} \ m/s^2}\)

Kinematic Equation: \(\vec v_f^2=\vec v_0^2+2\vec a \Delta \vec x\)

\(\Longrightarrow 1 \times10^{12} \ m^2/s^2=-2.11 \times10^{13} \ m/s^2 \Delta \vec x \Longrightarrow \Delta \vec x= \frac{1 \times10^{12} \ m^2/s^2}{-2.12 1\times10^{13} \ m/s^2}\)

\(\Longrightarrow \boxed{\Delta \vec x= -0.047 \ m}\)

The distance from the positive plate we'll call, "D."

\(D=0.20+\Delta \vec x\)

\(\Longrightarrow D=0.20+\Delta \vec x \Longrightarrow D=0.20 \ m+(-0.047 \ m) \Longrightarrow \boxed{D=0.153 \ m} \therefore Sol.\)

Answer:

add molecules

Answer:

All other SI units are derived by multiplying, dividing or powering the base units in various combinations, For example: mechanical work is force applied multiplied by distance moved and has the unit newton metre written as Nm.

Explanation:

please mark me as the brainliest

Answer:

Is pushed by another object

Explanation:

According to Newton's third law

Every action in the universe has opposite and equal reaction.

Or

\(\\ \sf\dashrightarrow F_A=-F_B\)

An object exerts a reaction force when it ____.

A. is pulled by another object

B. maintains its direction of motion

C. has a net force of zero

D. is pushed by another object

Your answer will be (D)

Newton's second law of motion:The acceleration of an item caused by a net force is directly proportional to its magnitude, in the same direction as the net force, and inversely proportional to its mass. The acceleration of the active body is proportional to the force and inversely proportional to the mass of the body. As a result, as the force exerted on a body rises, so does the acceleration. Similarly, when the body's mass increases, the acceleration decreases.

Newton's second law states that the rate of change of momentum is directly proportional to the applied force, thus. The unit of force is selected in such a way that k equals one. If m equals 1, an equals 1, and F equals 1, then A unit force is defined as the force that creates a unit acceleration in a body of unit mass.

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Answer:

If theta is equal to 90, then both projectiles strike at the same distance from the projection point and projectiles are in air for the same time interval.

Explanation:

The effective resistance of the combination when two resistors are connected in series is 2+x²/x.

The resistance is a quantity that offers obstruction to the current flow and the unit of resistance is the ohm. The resistors are connected in series and parallel. The effective resistance of series connections, R(eff) = R₁+R₂+...+Rₙ. The effective resistance of parallel connections are, 1/R(eff) = 1/R₁+1/R₂+.....+1/Rₙ.

From the given,

the parallel resistance of two-ohm x, the effective resistance,

1/R(eff) = 1/x+1/x = 2/x.

The effective resistance in a series combination of resistors, 2/x, and x are,

R(eff) = R₁+R₂ = 2/x + x = 2+x²/x.

Hence, the effective resistance is 2+x²/x.

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Answer:30

Explanation:

Current=60 milliamps

Current=(voltage)/(resistance)

60=(voltage)/(resistance)

Doubling the resistance means multiplying both sides by 1/2

60x1/2=(voltage)/(resistance) x 1/2

30=(voltage)/2(resistance)

Therefore the resistance would be 30 milliamp if we double the resistance

Answer:

The bulb with higher temperature(4000 K) will be brighter

Explanation:

From the question we are told that

     The color temperature  for first bulb is  \(T_1 = 2000K\)

        The color temperature  for second bulb is  \(T_2 = 4000K\)

Generally the emission power of black body radiation is mathematically represented as

     \(E = \sigma T^4\)

Where  \(\sigma\) is the Stefan-Boltzmann constant  with a value \(\sigma = 5.67 * 10^{-8} W m^{-2} K^{-4.}\)

Now for \(T_1 = 2000K\)

      \(E_1 = 5.67*10^{-8} * (2000)^4\)

       \(E_1 = 907.2 \ W/m^2\)

At  \(T_2 = 4000K\)

       \(E_2 = 5.67*10^{-8} * 4000\)

        \(E_2 = 14515.2 \ KW/m^2\)

Looking at the result we got we see that  the emission power  for the higher temperature bulb is higher, this means that its power to emit in the visible spectrum range would be higher  

So the bulb with higher temperature will be brighter

To find the mass of the object, we can use the formula for kinetic energy:

Kinetic energy (KE) = (1/2) * mass * velocity^2

Given that the kinetic energy is 426 J and the velocity is 13 m/s, we can rearrange the equation to solve for the mass:

mass = (2 * KE) / (velocity^2)

Substituting the given values:

mass = (2 * 426 J) / (13 m/s)^2

mass = (2 * 426 J) / (169 m^2/s^2)

mass = 852 J / 169 m^2/s^2

mass = 5.04 kg

Therefore, the mass of the object is 5.04 kg.

Answer:

a    \(D = 3.9 *10^{-12} \ m\)

b    \(\tau_{max} = 1.24 *10^{-25} \ N\cdot m\)

c   \(W = 2.48 *10^{-25} J\)

Explanation:

From the question we are told that

   The magnitude of electric dipole moment is  \(\sigma = 6.2 *10^{-30} \ C \cdot m\)

     The electric field is \(E = 2*10^{4} \ N/C\)

The distance between the positive and negative charge center is mathematically evaluated as

     \(D = \frac{\sigma }{10 e}\)

Where  e is the charge on one electron which has a constant value of  \(e = 1.60 *10^{-19} \ C\)

  Substituting values

     \(D = \frac{6.20 *10^{-30}}{10 * (1.60 *10^{-19})}\)

      \(D = 3.9 *10^{-12} \ m\)

The maximum torque is mathematically represented as

       \(\tau_{max} = \sigma * E * sin (\theta)\)

Here  \(\theta = 90^o\)

This because at maximum the molecule is perpendicular to the field

    substituting values

       \(\tau_{max} = 6.2 *10^{-30} * 2*10^{4} sin ( 90)\)

       \(\tau_{max} = 1.24 *10^{-25} \ N\cdot m\)

The workdone is mathematically represented as

      \(W = V_{(180)} - V_{0}\)

where   \(V_{(180)}\) is the potential energy at 180° which is mathematically evaluated as

     \(V_{(180) } = - \sigma * E cos (180)\)

Where the negative signifies that it is acting against the  field

   substituting values

     \(V_{(180) } = - 6.20 *10^{-30} * 2.0 *10^{4} cos (180)\)

      \(V_{(180) } = 1.24*10^{-25} J\)

and

     \(V_{(0)}\) is the potential energy at 0° which is mathematically evaluated as

            \(V_{(0) } = - \sigma * E cos (0)\)

   substituting values

     \(V_{(0) } = - 6.20 *10^{-30} * 2.0 *10^{4} cos (0)\)

      \(V_{(0) } =- 1.24*10^{-25} J\)

So \(W = 1.24 *10^{-25} - [-1.24 *10^{-25}]\)

    \(W = 2.48 *10^{-25} J\)

Answer:

\(5.997m/s\)

Explanation:

We were told to calculate the speed of the ball,

Given speed of sound as 340 m

And we know that the sound of the ball hitting the pins is at 2.80 s after the ball is released from his hands.

Speed of ball = distance traveled/(time of hearing - time the sound travels).

Speed= S/t

Where S= distance traveled

t= time of hearing - time the sound travels

time=time for ball to roll+timefor sound to come back.

time of sound=16.5/340

=0.048529secs

solving for speedof ball

Then,Speed of ball = distance traveled/(time of hearing - time the sound travels).

=16.5/(2.80-0.048529) m/s = 5.997m/s

Therefore, the speed of the ball is

5.997m/s