1 52/100 as a mixed number in decimal form

Answer:

Cada uno de ellos gana:

S/. 24

S/. 36

Step-by-step explanation:

Planteamiento:

a + b = 60

a = 12 + b

Desarrollo:

sustituyendo el valor de la segunda ecuación del planteamiento en la primer ecuación del planteamiento:

(12+b) + b = 60

2b + 12 = 60

2b = 60 - 12

2b = 48

b = 48/2

b = 24

de la segunda ecuación del planteamiento:

a = 12 + b

a = 12 + 24

a = 36

Check:

24 + 36 = 60

The variance of s isVar(s) = Var(w1) + Var(w2) + ... + Var(w8)= 8 x (27/16)= 27/2= 13.5Answer: P(wk=1) = 3/4, P(wk=1,wl=1) = 0.43951613..., P(wk=1,wl=3) = 0.17943548..., P(s=12) = 0.00069181..., E[s] = 6, Var[s] = 13.5

Let us find the probabilities P(wk=1), P(wk=1,wl=1) and P(wk=1,wl=3) for 1 ≤ k ≠ l ≤8 and P(s=12), E[s] and Var[s].We are given a deck of 32 cards. Of these, 24 are red and 8 are blue. The red cards are worth 1 point and the blue cards are worth 3 points. We draw 8 cards without putting them back.Since there are 24 red cards and 8 blue cards, the total number of ways in which we can draw 8 cards is given by 32C8=  32!/(24!8!) =  1073741824 waysThe probability of getting a red card is 24/32 = 3/4 and the probability of getting a blue card is 8/32 = 1/4.P(wk=1)The probability of getting a red card (with point value 1) on any one draw is P(wk=1) = 24/32 = 3/4.The probability of getting a blue card (with point value 3) on any one draw is P(wk=3) = 8/32 = 1/4.P(wk=1,wl=1)The probability of getting a red card on the first draw is 24/32.

If we don't replace it, then there are 23 red cards and 7 blue cards left in the deck, and the probability of getting another red card on the second draw is 23/31. Therefore, the probability of getting two red cards in a row is (24/32)(23/31).Similarly, the probability of getting a red card on the first draw is 24/32. If we don't replace it, then there are 23 red cards and 7 blue cards left in the deck, and the probability of getting a third red card on the third draw is 22/30. Therefore, the probability of getting three red cards in a row is (24/32)(23/31)(22/30).

Therefore, the probability of getting two red cards in a row (without replacement) is P(wk=1,wl=1) = (24/32)(23/31) = 0.43951613...P(wk=1,wl=3)The probability of getting a red card on the first draw is 24/32. If we don't replace it, then there are 23 red cards and 7 blue cards left in the deck, and the probability of getting a blue card on the second draw is 7/31. Therefore, the probability of getting a red card followed by a blue card is (24/32)(7/31).Similarly, the probability of getting a red card on the first draw is 24/32. If we don't replace it, then there are 23 red cards and 7 blue cards left in the deck, and the probability of getting a blue card on the third draw is 6/30.

Therefore, the probability of getting a red card followed by two blue cards is (24/32)(7/31)(6/30).Therefore, the probability of getting a red card followed by a blue card or a red card followed by two blue cards is P(wk=1,wl=3) = (24/32)(7/31) + (24/32)(7/31)(6/30) = 0.17943548...P(s=12)The possible values of the point total range from 8 (if all 8 cards drawn are red) to 32 (if all 8 cards drawn are blue). To get a total point value of 12, we need to draw 4 red cards and 4 blue cards, in any order.The number of ways of choosing 4 red cards out of 24 is 24C4 = 10,626.The number of ways of choosing 4 blue cards out of 8 is 8C4 = 70.

Therefore, the number of ways of getting a total point value of 12 is 10,626 x 70 = 743,820.The probability of getting a total point value of 12 is therefore P(s=12) = 743,820 / 1,073,741,824 = 0.00069181...E[s]To find the expected value of s, we need to find the expected value of wk for each k and then add them up. Since we are drawing cards without replacement, the value of wk depends on which card is drawn at each step. Therefore, the expected value of wk is the same as the probability of drawing a red card, which is 3/4.The expected value of s is therefore E[s] = 8 x (3/4) = 6.Var[s]To find the variance of s, we need to find the variance of wk for each k and then add them up.

Since the value of wk is either 1 or 3, the variance of wk isVar(wk) = E(wk^2) - [E(wk)]^2= [(1^2)(3/4) + (3^2)(1/4)] - [(3/4)]^2= 9/4 - 9/16= 27/16Therefore, the variance of s isVar(s) = Var(w1) + Var(w2) + ... + Var(w8)= 8 x (27/16)= 27/2= 13.5Answer: P(wk=1) = 3/4, P(wk=1,wl=1) = 0.43951613..., P(wk=1,wl=3) = 0.17943548..., P(s=12) = 0.00069181..., E[s] = 6, Var[s] = 13.5

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Answer: \(16x^4y^2a^6\)

Step-by-step explanation:

just apply to the power of 2 to every term

-4 times -4 is 16

x^2 to power of 2 is 2 times 2 so x^4

y^2 is y^2

a^3 to power of 2 is 3 x 2 = 6 so a^6

16x^4y^2a^6

Answer:

16x^4y^2a^6

Step-by-step explanation:

Do this step by step

16x^4y^2a^6

Please give brainliest!

20 flowers = 4.2 $ = 420¢

20/5=4 flowers

420/5=84¢

4 flowers = 84¢=0.84$

$0.84

20/4.2 = 4/x

Use cross multiplication,

20/4.2 = 4/x

=> 4.2(4) = 20x

=> 16.8 = 20x

Reverse,

16.8 = 20x

=> 20x = 16.8

Simplify and change it to decimal numbers,

20x = 16.8

=> x = 16.8/20

=> x = 168/200

=> x = 0.84

4 flowers cost $0.84

Answer:

2.3

Step-by-step explanation:

The largest open interval on which f is the antiderivative for f is called the indefinite integral of f, and it is denoted by ∫f(x)dx. This interval can be determined by finding all the antiderivatives of f and then taking the union of their domains. Note that the antiderivative of f is not unique, as it can differ by a constant, so the indefinite integral of f is only determined up to an arbitrary constant.
To find the largest open interval on which a function f is the antiderivative for f', we'll first need to know the function f' (the derivative of f). However, you didn't provide the function f' in your question.

To give you a general idea of how to approach this problem, follow these steps:

1. Given the function f'(x), find the critical points by setting f'(x) equal to 0 and solving for x.
2. Determine the intervals based on the critical points.
3. Check the behavior of f'(x) in each interval to see where it's continuous and increasing.
4. The largest open interval on which f is the antiderivative for f' will be the interval in which f'(x) is continuous and increasing.

If you provide the function f'(x), I can help you find the largest open interval for the antiderivative.

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Answer:

15

Step-by-step explanation:

the range is the largest number take away the smallest number

56-41=15

Answer:

I believe A would be the correct one, but I'm not 100% sure, none of the others make any sense and it looks like there may be a typo on A.

Step-by-step explanation:

If Caitlin were to win a huge sum of cash. In total, she has 49 bills. She adds up $1430. There are twenty and fifty-dollar bills available. The equation 20x + 50y = 1430 is the one that best describes the situation.

Equations are statements that affirm the equivalence of two expressions that are joined by the equals symbol "=". An equal sign ("=") links two expressions together to form an equation.

Given that Caitlin won a bag of cash, she has a total of 49 bills. She adds up to $1430. There are twenty and fifty-dollar notes available.

The system best represents the situation is,

20x + 50y = 1430

Thus, if Caitlin was to win a huge sum of cash. In total, she has 49 bills. She adds up to $1430. There are twenty and fifty-dollar bills available. The equation 20x + 50y = 1430 is the one that best describes the situation.

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Answer:

I think I had a 6 streak going on but I blew it yesterday

Step-by-step explanation:

Answer:

My answer streak is 20. Sorry I’m new

Answer:

34 weeks

Step-by-step explanation:

Hello!

We can set up an equation to solve for the number of weeks.

Let w = the number of weeks he is saving up.

The equation is \(315 = 115 + 10w - 140\)

He needs to save up for 34 weeks.

The theoretical probability of getting C is 0.4, and the practical probability of getting C is 12.

a) For the given case total outcomes are 5

The desired outcome is getting C thus the desired outcome is 2

So, The theoretical probability of choosing C is 2/5

b) The experimental probability of choosing a C can be calculated as the ratio of the number of times a C was actually chosen to the total number of trials.

From the table, we see that a C was chosen 5 + 7 = 12 times out of a total of 50 trials.

Therefore, the experimental probability of choosing a C is 12/50 or 0.24.

We can compare the experimental probability to the theoretical probability to see if they are similar.

In this case, the experimental probability of 0.24 is slightly higher than the theoretical probability of 0.4.

This could be due to chance or it could suggest that the letter C is slightly more likely to be chosen than expected. However, with only 50 trials, it is difficult to draw any definitive conclusions.

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Angle ABC is equal to 1/2 x, proved as required.

To prove that ABC = 1/2 x, we will use the following reasoning:

∴ ∠ OAB = ∠OBA = (180 - x)/2 (the sum of angles in a triangle is 180 degrees and ∠ AOB is twice the size of ∠ OAB)

∠ABC  = ∠OBC - ∠OBA.  (the sum of angles in a triangle is 180 degrees).

∠OBC is a right angle, since it is the angle between a radius and a tangent to the circle at B.

∴, ∠OBC = 90 ⁰

Substituting in the values we have found, we get:

ABC = OBC - OBA

ABC = 90 - (180 - x)/2 = x/2.

Therefore, ABC = 1/2 x, as required.

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Gender refers to the social and cultural roles, behaviors, and expectations associated with being male or female. It is a complex construct that includes biological, psychological, and sociocultural factors.

In the context of the researcher's study, gender refers to the binary categories of male and female that were used to differentiate between the 24 individuals surveyed. The study aimed to investigate whether there are differences in attitudes toward women in leadership positions based on this binary categorization.

It is important to note that while gender is often simplified into binary categories, it is actually a diverse and multifaceted construct that can encompass a range of identities and experiences beyond male and female. Researchers should be cognizant of the limitations of binary categorizations and strive to use more inclusive language and methods whenever possible.

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To pass the given 3 tables to 3NF using Armstrong's Axioms, you need to follow a step-by-step process.

1. Identify the functional dependencies: Analyze the given tables to determine the functional dependencies between the attributes. Functional dependencies represent the relationships between the attributes.
2. Create the minimal cover: Use Armstrong's Axioms to reduce the functional dependencies to their minimal form. This involves removing redundant dependencies and combining overlapping ones.
3. Decompose the tables: Decompose the original tables into smaller tables, ensuring that each table represents a single theme or concept. The goal is to eliminate any partial dependencies.

4. Resolve transitive dependencies: Check for transitive dependencies, where an attribute depends on another attribute through a third attribute. If transitive dependencies exist, further decompose the tables until they are eliminated.
5. Verify 3NF compliance: Finally, ensure that all the tables satisfy the third normal form (3NF) requirements. Each non-key attribute should be dependent only on the key attribute(s) in a table.
By following these steps, you can successfully pass the given 3 tables to 3NF using Armstrong's Axioms.

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Answer:

2

Step-by-step explanation:

it is parallel it is the same but in a different ratio

can see picture but i tried sorry

Answer:

The answer is 600 metres.

If the resulting F-statistic is less than the critical value, we fail to reject the null hypothesis and conclude that there is not enough evidence to suggest that the variances are significantly different.

The F-test is a statistical test used to compare the variances of two groups.

In this problem, we will use it to compare the variance of the value added by the manufacturer and the variance of the cost of materials in manufacturing. The F-test is performed by dividing the larger variance by the smaller variance. The resulting F-statistic is then compared to the critical value of an F-distribution with degrees of freedom equal to the sample size minus one for each group.

Before we can perform the F-test, we need to determine which variable will be group 1. Typically, the variable with the smaller mean is designated as group 1. This is because we want to minimize the chance of making a type II error, which is failing to reject the null hypothesis when it is false. If we designated the variable with the larger mean as group 1, we might not detect a significant difference between the groups, even if one exists.

Once we have designated which variable will be group 1, we can perform the F-test. If the resulting F-statistic is greater than the critical value of the F-distribution, we reject the null hypothesis and conclude that the variances are significantly different.

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Answer:

Line f and line G have the same slope, so they're parallel. So x is the slope

Step-by-step explanation:

Line f and line G have the same slope, so they're parallel. So x is the slope

K-means clustering is a type of unsupervised learning which uses unlabeled data, or data without clearly defined categories or groupings.

Data is divided into k clusters using K-means clustering, with the goal of making the clusters closer together and the individual data points more dispersed.

K-means clustering is a sort of unsupervised learning which uses unlabeled data, or data without clearly defined categories or groupings.

Thus this algorithm's goal is to identify groups among the data, where K stands for the set of organizations.

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The complete question is-

Assume that you have a labeled dataset. Explain how you can use only K-means clustering to build a classification model for this dataset. What can go wrong?

Answer:

$2075.75

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.  

Please have a look at the attached photo.  

My answer:

Given the information;

rubber chips costs $52.50 per square foot

We need to find the area of the playground,

The length: 8ft

The width: 4 ft

=> the area of it is: 8*4 = 32 square foot.

The base: 3 ft

The height: 2 ft

=> the area of it is = 1/2*3*2 = 3 square foot.

The base: 3 ft

The height: 3 ft

=> the area of it is = 1/2*3*3 = 9/2 square foot.

=> the total area of the playground is: 32 + 3 + 9/2 = 39.5 square foot.

So the total cost to install the rubber chips is:

= 39.5 * $52.5

= $2075.75

Hope it will find you well.

The $2625 is the cost to install the rubber chips if each unit represents 1 ft. Installing the rubber chips costs $52.50 per square foot.

It is defined as the area occupied by the rectangle in two-dimensional planner geometry.

The area of a rectangle can be calculated using the following formula:

Rectangle area = length x width

First, we find the area of the rectangle = (8+3)×4 = 44 square feet

Area of the two triangle = 2(1/2)[2×3] = 6 square feet

Area of the complete figure = 44+6 = 50 square feet

Each unit represents 1 ft. Installing the rubber chips costs $52.50 per square foot.

Total cost = 50×52.50 = $2625

Thus, the $2625 is the cost to install the rubber chips if each unit represents 1 ft. Installing the rubber chips costs $52.50 per square foot.

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The given quadrilateral ABCD is a rectangle, and the value of x is -2.

A closed quadrilateral has four sides, four vertices, and four angles. It is a form of polygon. By connecting four non-collinear locations, it is created. Quadrilaterals always have a total internal angle of 360 degrees.

A quadrilateral with parallel sides that are equal to one another, and four equal vertices is known as a rectangle. It is also known as an equiangular quadrilateral for this reason.

Given that ABCD is a rectangle.

In rectangle all the angles are equal, hence equate the two angles as follows:

4x + 8 = 6x + 12

6x - 4x = 8 - 12

2x = -4

x = -2

Hence the value of x is -2.

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Answer:

domain expansion

Step-by-step explanation:

jujutsu kaisen brúh

Answer:

r = V^2/a

Step-by-step explanation:

Here, we want to write the formula for r

What this simply mean is that we want to make r the formula subject

We have this as follows;

a = V^2/r

r = V^2/a

Answer:

2 is the answer thanks pls give brainliest

B. Due to the fact that ABCD has at least two parallel sides in one pair.

The y-coordinates of the two points A(-3, 1) and D(5, 1) are identical.

Then

The x-axis and the line AD are parallel.

As opposed to that,

The y-coordinates of the two points B(1,5) and C(5,5) are identical.

Then

The x-axis and the line BC are perpendiculars.

We discover:

• AD lies along the x-axis.

BC is perpendicular to the x-axis.

Therefore

AD / BC

Conclusion:

Due to the fact that ABCD contains at least two parallel sides in one pair.

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Answer:

18.75

Step-by-step explanation: if you divided 90 by 4.8 you get 18.75

Answer:

The answer is b

Step-by-step explanation:

X= 0 makes the exponential function greater than the quadratic function. Therefore, the correct option is option B.

The mathematical symbol for the exponent is \(e^{X}\). The word, unless specifically stated differently, generally relates to the positive-valued functional of something like a real variable, though it can be extended towards the complex numbers or adapted to other mathematical like matrices or Lie algebras.

The idea of exponentiation is where the exponential function got its start, although recent definitions allow for a rigorous extension to all real arguments, especially irrational values. X= 0 makes the exponential function greater than the quadratic function.

Therefore, the correct option is option B.

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1. Union: A ∪ B

2. Intersection: A ∩ B

3. Complementation: A'

We are asked to express the occurrence of events A and B using union, intersection, and complementation operations, along with drawing the corresponding Venn diagrams. Let's break down the main answer into three parts.

The union operation (A ∪ B) represents the event where either A or B or both occurred. It includes all the elements present in A or B or both, forming the combined set of events.

The intersection operation (A ∩ B) represents the event where both A and B occurred simultaneously. It consists of the common elements present in both A and B.

The complementation operation (A') represents the event where A did not occur. It includes all the elements that are not present in A.

Now, let's address the short question in different wording. Can there be an event where either A or B occurred, but not both?

There can be an event where either A or B occurred exclusively, but not both simultaneously. This can be visualized through the Venn diagrams, where the union represents the inclusive occurrence of A and B, the intersection represents the simultaneous occurrence, and the complementation represents the absence of A.

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